Answer:
The correct answer is - 1 and 3 are true.
Explanation:
Hydrogen bonds require a lot of energy to be broken as these bonds are relatively strong intermolecular forces which makes the boiling point of liquid like water very high, as it requires a lot of heat to break the intermolecular bonds holding the water molecules together.
An increase in the surface area of the liquid also increases the rate of evaporation as it takes place among the molecules of the liquid on the surface.
A balloon originally has 0.100 moles of helium and has a volume of 0.500 L. If 0.590 grams of He are added to the balloon, what will the new volume be, in L? (Assume temperature and pressure do not change.)
Answer:
1.24 L
Explanation:
Avogadro's Law
[tex]\frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} }[/tex]
Convert 0.590 g of He to moles.
0.590 g x (1 mol/4.00 g) = 0.1475 mol He
Add 0.1475 mol to 0.100 mol since the initial moles (n1) increases by this amount.
0.100 mol + 0.1475 mol = 0.2475 mol He
This will represent the final moles (n2)
The initial volume is given, 0.500 L. Plug in the values.
[tex]\frac{0.500 L}{0.100 mol} = \frac{V_{2} }{0.2465 mol}[/tex]
[tex]V_{2} = \frac{(0.500 L)(0.2475 mol)}{(0.100 mol)} \\V_{2} = 1.2375\\V_{2} = 1.24 L[/tex]
Taking into account the Avogadro's law, the new volume will be 1.24 L.
Avogadro's law establishes the relationship between the amount of gas and its volume when the temperature and pressure are held constant. Remember that the amount of gas is measured in moles.
This law states that constant pressure and temperature, the same amount of gas has the same volume regardless of the chemical element that forms it.
On the other hand, Avogadro's law establishes that the volume is directly proportional to the quantity of gas: if the quantity of gas increases, the volume will increase; whereas if the amount of gas decreases, the volume decreases.
Mathematically, this law states that the ratio between the volume and the quantity of gas is constant:
[tex]\frac{V}{n} =k[/tex]
Assuming that you have an initial state 1 and the conditions are modified to a final state 2, it is true:
[tex]\frac{V1}{n1} =\frac{V2}{n2}[/tex]
In this case, being the molar mass of He 4 g/mole, 0.590 grams of He are contained in the following amount of moles:
[tex]0.590 gramsx\frac{1 mole}{4 grams} =0.1475 moles[/tex]
Then, you know:
V1= 0.500 Ln1= 0.100 molesV2= ?n2= 0.100 mol + 0.1475 mol = 0.2475 mol He because 0.590 grams are added, this is 0.1475 moles, of He to the balloonReplacing in Avogadro's Law:
[tex]\frac{0.500 L}{0.100 moles} =\frac{V2}{0.2475 moles}[/tex]
Solving:
[tex]V2=0.2475 molesx\frac{0.500 L}{0.100 moles}[/tex]
V2= 1.2375 L≅ 1.24 L
Finally, the new volume will be 1.24 L.
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Imagine that you have a sample of a substance. You cannot physically separate that substance into components. You also cannot chemically separate that substance into components. Which of the following are true about your sample?
The sample is made up of multiple elements. t or f
The sample is made up of one type of atom. t or f
The sample is made up of several types of atoms. t or f
The sample is made up of a single element. t or f
Answer:
The sample is made up of a single element. t or f
Explanation:
Forgot about the t or f! Its true.
Dam bro.....
1. T
2. F
3. T
Answer:
i think its the 3 thired one sorry if rong but good luck
Explanation:
A chemistry student is given 3.00 L of a clear aqueous solution at 17 C . He is told an unknown amount of a certain compound X is dissolved in the solution. The student allows the solution to cool to 17 C . The solution remains clear. He then evaporates all of the water under vacuum. A precipitate remains. The student washes, dries and weighs the precipitate. It weighs 0.15 kg . Using the above information can you calculate the solubility, X, in water at 17 C.
Answer:
The right approach is "50 g/l".
Explanation:
The given values are:
Mass or solute or precipitation,
= 0.15 kg
on converting it into "g", we get
= [tex]0.15 \ kg\times \frac{1000 \ g}{1 \ kg}[/tex]
= [tex]150 \ g[/tex]
Volume of solution,
= 3.00 L
Now,
The solubility of X will be:
= [tex]\frac{Mass \ of \ X}{Volume \ of \ solution}[/tex]
On substituting the values, we get
= [tex]\frac{150}{3}[/tex]
= [tex]50 \ g /l[/tex]
Investigation Question: How do organisms get their genes?
THIS ANSWER SHOULD BE 3 OR MORE SENTENCES.
Answer:
from the chromosome..l dont know
Convert 6.62 X 10^23 atoms to moles
Answer:
1.099
Explanation:
Hope this helps
Answer:
1.09944660051578e-23
Explanation:
1. The octane present in gasoline burns according to the following equation:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
(a) How many moles of O2 are needed to react fully with 27.5 moles of octane?
Answer:
[tex]n_{O_2}=343.75molO_2[/tex]
Explanation:
Hello there!
In this case, according to the combustion of octane:
[tex]2C_8H_1_8+25O_2\rightarrow 16CO_2+18H_2O[/tex]
We can see there is a 2:25 mole ratio of octane to oxygen; therefore, we can calculate the moles of oxygen via the following stoichiometric factor:
[tex]n_{O_2}=27.5molC_8H_1_8*\frac{25molO_2}{2molC_8H_1_8} \\\\n_{O_2}=343.75molO_2[/tex]
Best regards!
why Bohr's theory was inadequate?
Classify each statement as a property of ethers, alcohols, or both ethers and alcohols?
1. These compounds form hydrogen bonds between themselves and with other compounds containing an O-H, N-H, or F-H bond, such as water.
2. These compounds are water soluble if they have fewer than four carbon atoms.
3. When comparing ethers and alcohols of similar molecular weights, these compounds have the lower boiling point.
Explanation:
1. Only alcohols forms hydrogen bond between themselves and with other compounds containing an O-H, N-H, or F-H bond, such as water.
2. Alcohols up to 4 carbons are miscible in water because they have hydrogen bonded to oxygen and can form hydrogen bond with water. However, it is not possible for ethers.
3. When comparing ethers and alcohols of similar molecular weights, ethers have lower boiling point than alcohol. This is because of the presence of hydrogen bond in alcohols.
The given statements can be classified as a property of both(ether and alcohol), both(ether and alcohol), and ether, respectively.
The given property of ethers, alcohols, or both ethers and alcohols are classified as:
This statement is a property of both ethers and alcohols. Both ethers and alcohols can form hydrogen bonds due to the presence of oxygen atoms in their molecules, which can interact with other compounds containing O-H, N-H, or F-H bonds, such as water.This statement is a property of both ethers and alcohols. Both ethers and alcohols can be water-soluble if they have fewer than four carbon atoms. The presence of the oxygen atom in ethers and alcohols allows them to form hydrogen bonds with water molecules, increasing their solubility.This statement is a property of ethers. When comparing ethers and alcohols of similar molecular weights, ethers generally have lower boiling points than alcohols. This is because ethers do not have hydrogen atoms directly bonded to the oxygen atom, which reduces the strength of intermolecular hydrogen bonding compared to alcohols. As a result, ethers have weaker intermolecular forces and lower boiling points.Hence, the statements can be classified as shown above.
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how many moles of ammonia can be formed from 4.0 mol H2
how many moles of hydrogen are required to form 8.0 mol NH3
how many moles of nitrogen are required to react with 6.0 mol H2
Answer: 1. 2.7 moles of ammonia are formed
2. 12.0 moles of hydrogen are required
3. 2.0 moles of nitrogen are required
Explanation:
The balanced chemical equation is:
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
According to stoichiometry:
3 moles of hydrogen form = 2 moles of ammonia
Thus 4.0 moles of hydrogen form =[tex]\frac{2}{3}\times 4.0=2.7moles[/tex] of ammonia
According to stoichiometry:
2 moles of ammonia are formed by = 3 moles of hydrogen
Thus 8.0 moles of ammonia are formed by =[tex]\frac{3}{2}\times 8.0=12.0moles[/tex] of hydrogen
According to stoichiometry:
3 moles of hydrogen react with = 1 mole of nitrogen
Thus 6.0 moles of hydrogen react with =[tex]\frac{1}{3}\times 6.0=2.0moles[/tex] of nitrogen
Name the following alkene:
CH3C = CH2
1
CH3
A. 2-methyl-1-propene
B. 2-methyl-2-propene
C. 1-propyl-2-methene
D. 2-methyl-1-propane
Pls help
The name of the given alkene is 2-methyl-1-propene. The correct option is A.
What are alkenes?
Alkenes are inorganic compounds. They are the series of hydrocarbons, that are formed by carbon-carbon double bonds. To find out alkenes, you have to see that the number of hydrogen atoms is always double the number of carbons.
Propene is an unsaturated compound, which is the second-simplest compound, and it contains a single double bond, and it is a colorless gas and has a texture of petroleum jelly.
CH₃C = CH₂
I
CH₃
Here, the three CH₃ are shown in the diagram, so it will be the methyl because it contains 3 CH₂, and now see the propene means one double bond and four carbon atoms. So it will be the 2-methyl-1-propene.
Thus, the correct option is A. 2-methyl-1-propene.
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what is one property of skim milk indicating that it is a colloidal dispersion?
Answer:
it's dairy
Explanation
Identify the Lewis acid in this balanced equation: SnCl4 + 2Cl− → SnCl62−
Answer:
The answer is SnCI4.
Explanation:
Answer:
it is a
cause it is and cause i'm right
How many oxygen atoms are in 3.30 g of quartz?
Answer:
3.30 gSiO2 / 60.085g SiO2 x 2 mol 0 / 1 mol SiO2 x (6.022*1023 ) = 6.61*1022 O atoms
Explanation:
Using 1.8x10-5 for the Ka for acetic acid, along with the weight of sodium acetate and volume of acetic acid used to prepare the buffer, calculate the expected pH of the buffer. Show your work for full credit. How well does it compare to the observed value
Answer:
pH = 4.95
Explanation:
The buffer was created using 4.0082g sodium acetate, mixed with 10.0 mL of 3.0 M acetic acid and 90 mL of deionized water.
Using H-H equation for acetic buffer:
pH = pKa + log [Acetate] / [Acetic acid]
Where pH is the pH of the buffer
pKa = -log Ka = 4.74
[] Are molar concentration of each specie -The volume of the solution is 100mL = 0.1L-:
[Sodium acetate] = 4.0082g * (1mol / 82.03g) = 0.04886 moles / 0.1L
= 0.4886M
[Acetic acid] = 3.0M * (10mL / 100mL) = 0.300M
pH = 4.74 + log [0.4886M] / [0.300M] =
pH = 4.95
Oxalic Acid, a compound found in plants and vegetables such as rhubarb, has a mass percent composition of 26.7% C, 2.24% H, and 71.1% O. Oxalic acid can interfere with respiration and cause kidney or bladder stones. If a large quantity of rhubarb leaves is ingested, the oxalic acid can be toxic. The lethal dose (LD50) in rats for oxalic acid is 375 mg/kg. Rhubarb leaves contain about 0.5% by mass of oxalic acid. (Show your work, using the insert equation tool :) What is the empirical formula of oxalic acid
Answer:
HCO₂
Explanation:
From the information given:
The mass of the elements are:
Carbon C = 26.7 g; Hydrogen H = 2.24 g Oxygen O = 71.1 g
To determine the empirical formula;
First thing is to find the numbers of moles of each atom.
For Carbon:
[tex]=26.7 \ g\times \dfrac{1 \ mol }{12.01 \ g} \\ \\ =2.22 \ mol \ of \ Carbon[/tex]
For Hydrogen:
[tex]=2.24 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =2.22 \ mol \ of \ Hydrogen[/tex]
For Oxygen:
[tex]=71.1 \ g\times \dfrac{1 \ mol }{1.008 \ g} \\ \\ =4.44 \ mol \ of \ oxygen[/tex]
Now; we use the smallest no of moles to divide the respective moles from above.
For carbon:
[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ carbon[/tex]
For Hydrogen:
[tex]\dfrac{2.22 \ mol \ of \ carbon}{2.22} =1 \ mol \ of \ hydrogen[/tex]
For Oxygen:
[tex]\dfrac{4.44 \ mol \ of \ Oxygen}{2.22} =2 \ mol \ of \ oxygen[/tex]
Thus, the empirical formula is HCO₂
6. Menthol is a member of the terpene family of natural products. It exists in a (1R, 2S, 5R) form and a (IS, 2R, 5S) form. Are these two compounds enantiomers or diastereomers?
One of the reactions used to inflate automobile air bags involves sodium azide (NaN₃).
2NaN₃ --> 2Na + 3N₂
Determine the mass of N₂ produced from 250.0 g NaN₃
Answer:
161.54 g of N₂
Explanation:
The balanced equation for the reaction is given below:
2NaN₃ —> 2Na + 3N₂
Next, we shall determine the mass of NaN₃ that decomposed and the mass of N₂ produced from the balanced equation. This is illustrated below:
Molar mass of NaN₃ = 23 + (3×14)
= 23 + 42 = 65 g/mol
Mass of NaN₃ from the balanced equation = 2 × 65 = 130 g
Molar mass of N₂ = 2 × 14 = 28 g/mol
Mass of N₂ from the balanced equation = 3 × 28 = 84 g
SUMMARY:
From the balanced equation above,
130 g of NaN₃ decomposed to produce 84 g of N₂.
Finally, we shall determine the mass of N₂ produced by the decomposition of 250 g of NaN₃. This can be obtained as follow:
From the balanced equation above,
130 g of NaN₃ decomposed to produce 84 g of N₂.
Therefore, 250 g of NaN₃ will decompose to produce
= (250 × 84)/130 = 161.54 g of N₂
Thus, 161.54 g of N₂ were obtained from the reaction.
According the article , why is it difficult for many cities in the U.S today to recycle
Why recycling isn't working in the U.S.
Many recyclables become contaminated when items are placed in the wrong bin, or when a dirty food container gets into the recycling bin. Contamination can prevent large batches of material from being recycled. Other materials can't be processed in certain facilities.
What is another name for heat?
A
light energy
B.
infrared energy
C
Thermal energy
D
electromagnetic energy
Answer:
C
Explanation:
thermal energy is the another name for heat
Electricity is possible because atoms release and absorb which sub-atomic particle?
Answer:
Electrons
Electric charge is carried by subatomic particles such as electrons and protons, which can be created and destroyed. For example, when particles are destroyed, equal numbers of positive and negative charges are destroyed, keeping the net amount of charge unchanged.
Which of the following is a period 4 representative element?
A. C
B. An
C. Ti
D. K
[tex]\huge{\mathbb{\tt { QUESTION↓}}}[/tex]
Which of the following is a period 4 representative element?
O A. C
O B. An
O C. Ti
O D. K
[tex]\huge{\mathbb{\tt {ANSWER↓}}}[/tex]
[tex]\color{blue}{\tt {A.C ( Carbon )}}[/tex]
[tex]{\boxed{\boxed{\tt { WHAT \: IS \: CARBON?}}}}[/tex]
Carbon (from Latin: carbo "coal") is a chemical element with the symbol C and atomic number 6. It is nonmetallic and tetravalen - making four electrons available to form covalent chemical bonds. It belongs to group 14 of the periodic table. Carbon makes up only about 0.025 percent of Earth's crust.#CarryOnLearning
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→XxKim02xXOzone is three oxygen atoms bonded together. It can sometimes be smelled in the air after a thunderstorm. the smell is a result of
Ozone gas can be smelled in the air after a thunderstorm as a result of reactions between oxides of nitrogen and volatile organic compounds.
How ozone gas be smelled?Ozone gas can be produced due to chemical reactions between oxides of nitrogen and volatile organic compounds. This reaction occurs when pollututed gas is emitted from vehicles react and other activities with each other in the presence of sunlight.
So we can canclude that Ozone gas can be smelled in the air after a thunderstorm as a result of reactions between oxides of nitrogen and volatile organic co
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Which among the following is not required in the synthesis of fatty acids.
A). Acetyl-CoA
B). Biotin
C). Carbon iv oxide
D). NADH
Answer:
D). NADH
Explanation:
.....plllzzz heeelp me fast??
Answer:
Explanation:
It is 11
If a sample of oxygen gas has a pressure of 810 torr at 298 K, what will be its pressure if its temperature is raised to 330K?
Answer:
The pressure is = 897 torr
Explanation:
We use Gay Lussac's Law.
Select all of the answers that apply.
Which of the following characteristics must an air mass have?
It flows as one unit.
It has different temperatures but uniform humidity.
It must be 1,000 miles or more in size.
It must form over a low-pressure area.
It has a uniform temperature and humidity.
Explanation:
it has different temperature but uniform humidity
hope it will help you
4) Which of the following can cause erosion?
- Glaciers, wind, and animals
- Acid rain, animals, and ice wedging
- Wind, water, glaciers
- Glaciers, wind, and acid rain
5) Which factors affect the rate of weathering?
- Temperature, ocean currents, and tides
- Type of rock and amount of precipitation
- Type of plants and animals
- Amount of sunlight
Water, air, and even ice are fluids because they tend to flow from one place to another due to the force of gravity.
Rainfall and temperature can affect the rate in which rocks weather. High temperatures and greater rainfall increase the rate of chemical weathering. 2. Rocks in tropical regions exposed to abundant rainfall and hot temperatures weather much faster than similar rocks residing in cold, dry regions.
17. The equation below represents a chemical reaction that occurs in living cells.
CoH1206 + 602 -- 6002 + 6H20 + energy
How many atoms are represented in the reactants of this equation?
Answer:
36 atoms
Explanation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energyThe reactants are in the left side of the equation. First we determine how many atoms are there in the C₆H₁₂O₆ molecule:
6 C atoms + 12 H atoms + 6 O atoms = 24 atoms in totalThere are two atoms in a O₂ molecule, and there are 6 O₂ molecules in the equation:
2 * (6 O atoms) = 12 atoms in totalThe total number of atoms in the reactants is
24 + 12 = 36 atomsExplain why the upper phase, after reflux, contained the 1-bromopentane, even though its expected density is 1.276 g/cm3, and the density of water is ~1.00 g/cm3. Think what is in the aqueous solution (e.g., what is the density of salt water
Answer:
The water is not pure i.e. It contains some hydroxide and bromobutane ions that is why the upper phase contains 1-bromopentane
Explanation:
The upper phase after reflux will contain 1-bromopentane even when its density is 1.276g/cm^3 because even though the density of water = 1.00g?cm^3 the water is not pure i.e. It contains some hydroxide and bromobutane ions making it to stay at the bottom while 1- bromobutane stays at the upper phase
Which of the following will dissolve the fastest
Answer:
Saturated.
Explanation:
This explains the solute dissolving faster. It links with the definition of soaked with moisture; drenched.
Answer:
I believe the answer would be C. unsaturated. and for part 2 I believe would be A. hope that helps :)
