CHECK MY ANSWERS PLEASE
____
The sequence is geometric:
3, 13, 23, 33,...

True
False***
_____________________
The sequence is geometric:
5, -25, 125, -625,...

True***
False

Answers

Answer 1

Step-by-step explanation:

For a geometric sequence,

[tex]\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}[/tex]

1. The sequence is :

3, 13, 23, 33,...

[tex]\dfrac{13}{3}\ne \dfrac{23}{13}[/tex]

It is not geometric. It is false

2. The sequence is :

5, -25, 125, -625

[tex]\dfrac{-25}{5}=\dfrac{125}{-25}\\\\-5=-5[/tex]

So, the sequence is geometric as the common ratio is same. It is true.


Related Questions

work out the area of this shape

Answers

Answer:

75.5

Step-by-step explanation:

First, the picture is not to scale.

The Area of the bottom (2) rectangle is 33

base x height = A

11 x 3 = 33      (where did I get 3? Total height of shape is 8. Trapezoid is 5)

                      (8-5 = 3)

Area of the trapezoid:

A = [tex]\frac{h (B_{1} + B_{2}) }{2}[/tex]

  =  [tex]\frac{(5)(6 + 11)}{2}[/tex]

  =  [tex]\frac{5(17)}{2}[/tex]

  = [tex]\frac{85}{2}[/tex]

  = 42.5

42.5 + 33 = 75.5

A bus started from Kathmandu and reached khanikhola,26km far from Kathmandu, in one hour. if the bus had uniform acceleration, calculate the final velocity of the bus and acceleration. ​

Answers

Answer:

a = 0.0040 m/s², v = 14.4 m/s.

Step-by-step explanation:

Given that,

The distance between Kathmandu and Khanikhola, d = 26 km = 26000 m

Time, t = 1 hour = 3600 seconds

Let a is the acceleration of the bus. Using second equation of motion,

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

Where

u is the initial speed of the bus, u = 0

So,

[tex]d=\dfrac{1}{2}at^2\\\\a=\dfrac{2d}{t^2}\\\\a=\dfrac{2\times 26000}{(3600)^2}\\\\a=0.0040\ m/s^2[/tex]

Now using first equation of motion.

Final velocity, v = u +at

So,

v = 0+0.0040(3600)

v = 14.4 m/s

Hence, this is the required solution.


Find the missing number?

Answers

Answer:

65 solve theprob

Step-by-step explanation:

sinolove ko po yan paki brainly

Question 1a) Suppose you sample 100 times at random with replacement from a population in which 26% of the individuals are successes. Write a Python expression that evaluates to the chance that the sample has 20 successes.

Answers

Answer:

from math import comb

n = 100

x = 20

p = 0.26

q = 0.76

print(comb(n, x)*(p**x)*(q**(n-x)))

Step-by-step explanation:

Given that :

Number of trials, n = 100

P(success), p = 26% = 0.26

P(success)' = 1 - p = 1 - 0.26 = 0.74

Chance that sample has 20 successes = x

This problem meets the condition for a binomial probability distribution :

p(x = 20)

Recall :

P(x = x) = nCx * p^x * q^(n-x)

Using python :

comb is an built in function which calculate the combination of two arguments it takes ; and returns the combination value.

** mean raised to the power and

* is used for multiplication

The Python code as per the given question is provided below.

Program explanation:

The number of trials,

100

Probability of success,

20% or 0.26

Size of array generated,

2000

The output that shows chances of 20 success,

S

Program code:

import numpy as np

S=sum(np.random.binomial(100,0.26,2000)==20)/2000

S

Learn more about Python expression here:

https://brainly.com/question/21645017

A machine has two components both of which have a lifespan, in months, that is exponentially distributed with mean 8. The lifespan of the two components are independent. Find the probability both components are functioning in 12 months.

Answers

Answer:

0.0498

Step-by-step explanation:

In this question,

x~exponential

we have

mean = 1/λ = 8

from here we cross multiply, when we do

such that

λ = 1/8

probability of x functioning in 8 months

= e^-λx

= e^-1/8x12

= e^-1.5

= 0.2231

i got this value through the use of a scientific calculator

then the probability that these two are greater than 12

= 0.2231²

= 0.04977

= approximately 0.0498

therefore the probability that both components are functioning in 12 months is 0.0498

13, 5, 4, 9, 7, 14, 4 The deviations are _____.
A. "5, -3, -4, 0, 1, 6, 4"
B."5, -3, -4, 1, -1, 6, -4"
C."6, -3, -4, 1, 2, 6, -4"
D."-5, 3, 4, -1, 1, 6, 4 "

Answers

Answer:

B."5, -3, -4, 1, -1, 6, -4"

Step-by-step explanation:

We are given that

13,5,4,9,7,14,4

We have to find the deviation.

Mean=[tex]\frac{sum\;of\;data}{total\;number\;of\;data}[/tex]

Using the formula

[tex]Mean,\mu=\frac{13+5+4+9+7+14+4}{7}[/tex]

[tex]Mean,\mu=\frac{56}{7}=8[/tex]

Deviation=[tex]x_i-\mu[/tex]

         [tex]x_i-\mu[/tex]

13          5

5           -3

4           - 4

9            1

7             -1

14            6

4            - 4

Hence, option  B is correct.


The circumference of a circle is 14 inches. Find the circle's radius and diameter.


Please help :)

Answers

circumference = 2(pi)(r)
14 = 2(pi)(r)
14/2pi = r
7pi = radius
diameter = 2r
diameter = 14pi

what number must you add to complete the square x^2+12x=40

Answers

Step-by-step explanation:

x²+12x=40

(x+6)²-6²-40=0

(x+6)²-76 = 0

Express each ratio as a fraction in its lowest terms.
18 hours to 2 days​

Answers

Answer:

3/8.

Step-by-step explanation:

First convert days to hours:

2 days = 2 * 24 = 48 hours.

The greatest common factor of 18 and 48 = 6 so the required fraction is

18/48

= (18/6) / (48/6)

= 3/8.

Write the quadratic equation in standard form:
3x2 – 3x = 11

Answers

Answer:

[tex]3x^{2} -3x-11 = 0[/tex]

Step-by-step explanation:

Dada la función f(x)=1+6Sen(2x+π/3) . Halle: Período, amplitud y desfase (1.5 puntos) Dominio y rango de la función (1.5 puntos) Grafique la función trigonométrica (2 puntos)

Answers

Dada una ecuación de la forma

y = A sin(B(x + C)) + D

Tenemos que:

la amplitud es Ael periodo es 2π/Bel desfase es C (a la izquierda es positivo)el desplazamiento vertical es D

Sabemos que:

f(x)=1+6Sen(2x+π/3)

Y podemos reescribirla como:

f(x)=6Sen(2(x+π/6))+1

Siendo:

A = 6 → AmplitudT = 2π/B = 2π/2 = π → PeríodoC = π/6 → DesfaseEl dominio de un a función trigonométrica es todo el conjunto de los números reales (x ∈ R ).

La imagen de una función trigonométrica de esta forma es:

y ∈ [-A+D,A+D]

y ∈ [-6+1, 6+1]

y ∈ [-5,7]

La gráfica se adjunta.

The sum of two numbers is 125. Their difference is 47. The two numbers are:
a)39 and 86.
b)40 and 85.
c)47 and 78.
d)None of these choices are correct.

Answers

Answer:

let x represent the bigger number

x+x-47=125

2x-47=125

2x=125+47

2x=172

2x/2=172/2

x=86

the smaller number=x-47

86-47

39

therefore the answer is a) 39 and 86

Answer:

A

Step-by-step explanation:

To find the sum of 125, you have to add the numbers.

39+86 = 125

To find the difference of 47, you have to subtract the numbers.

86-39 = 47


How is the graph of
y=-3(5)*-
- 3 translated from the graph of y=
=30594?

A. reflected across the y-axis and 3 units down
B. reflected across the x-axis and 3 units down
C. reflected across the x-axis and 3 units left
D. reflected across the y-axis and 3 units right

Answers

Answer:

Purplemath

Introduces reflections in the x- and y-axes. ... To see how this works, take a look at the graph of h(x) = x2 + 2x – 3. ... The previous reflection was a reflection in the x-axis. ... f (x – b) shifts the function b units to the right.

integrate G(x,y,z)=yz over the surface of x+y+z=1 in the first octant.​

Answers

Parameterize the surface (I'll call it S) by

r(u, v) = (1 - u) (1 - v) i + u (1 - v) j + v k

with 0 ≤ u ≤ 1 and 0 ≤ v ≤ 1.

Take the normal vector to this surface to be

n = ∂r/∂u × ∂r/∂v = ((v - 1) i + (1 - v) j) × ((u - 1) i - u j + k) = (1 - v) (i + j + k)

with magnitude

||n|| = √3 (1 - v)

Then in the integral, we have

[tex]\displaystyle\iint_SG(x,y,z)\,\mathrm ds = \int_0^1\int_0^1 G((1-u)(1-v),u(1-v),v) \|\mathbf n\| \,\mathrm du\,\mathrm dv \\\\= \sqrt3 \int_0^1\int_0^1uv(1-v)^2\,\mathrm du\,\mathrm dv \\\\= \boxed{\frac1{8\sqrt3}}[/tex]

Alternatively, if you're not familiar with parameterizing surfaces, you can use the "projection" formula:

[tex]\displaystyle\iint_S G(x,y,z)\,\mathrm ds = \int_{S_{xy}}G(x,y,z)\sqrt{1+\left(\frac{\partial f}{\partial x}\right)^2+\left(\frac{\partial f}{\partial y}\right)^2}\,\mathrm dx\,\mathrm dy[/tex]

where I write [tex]S_{xy}[/tex] to mean the projection of the surface onto the (x, y)-plane, and z = f(x, y). We would then use

x + y + z = 1   ==>   z = f(x, y) = 1 - x - y

and [tex]S_{xy}[/tex] is the triangle,

{(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1 - x}

Then the integral becomes

[tex]\displaystyle\int_0^1\int_0^{1-x}y(1-x-y)\sqrt{1+(-1)^2+(-1)^2}\,\mathrm dy\,\mathrm dx \\\\= \sqrt3\int_0^1\int_0^{1-x} y(1-x-y)\,\mathrm dy\,\mathrm dx \\\\= \frac{\sqrt3}{24} \\\\= \boxed{\frac1{8\sqrt3}}[/tex]

A, B and C are collinear points. B is between A and C. AB=3x+4 BC=4x-1 AC=8x-9 Find AC

Answers

Answer:

[tex]AC = 87[/tex]

Step-by-step explanation:

Given

[tex]AB = 3x + 4[/tex]

[tex]BC = 4x -1[/tex]

[tex]AC = 8x - 9[/tex]

Required

The value x

Since A, B and C are collinear, then;

[tex]AC = AB + BC[/tex]

This gives:

[tex]8x - 9 =3x+4+4x-1[/tex]

Collect like terms

[tex]8x - 3x - 4x = 9 + 4-1[/tex]

[tex]x = 12[/tex]

We have:

[tex]AC = 8x - 9[/tex]

[tex]AC = 8*12 - 9[/tex]

[tex]AC = 87[/tex]

Can someone help asap?

Answers

Answers:

sin = -5/13tan = 5/12csc = -13/5sec = -13/12cot = 12/5

=============================================

Explanation:

The angle theta is between pi and 3pi/2, excluding both endpoints.

This places theta in the third quadrant (Q3) between 180 degrees and 270 degrees. The third quadrant is in the southwest.

Plot point A at the origin. 12 units to the left of this point, will be point B. So B is at (-12,0). Then five units lower is point C at (-12,-5). Refer to the diagram below. Notice how triangle ABC is a right triangle.

The angle theta will be the angle BAC, or simply angle A.

Since cos(theta) = -12/13, this indicates that

AB = -12 = adjacent

AC = 13 = hypotenuse

Technically, AB is should be positive, but I'm making it negative so that we can then say

cos(angle) = adjacent/hypotenuse

cos(theta) = AB/AC

cos(theta) = -12/13

------------------

If you apply the pythagorean theorem, you should find that BC = 5, which I'll  make negative since we're below the x axis. Then we can say

sin(theta) = opposite/hypotenuse

sin(theta) = BC/AC

sin(theta) = -5/13

------------------

If you divide sine over cosine, then you'll get 5/12. The 13's cancel out. This is the value of tangent.

Or you could say

tan(theta) = opposite/adjacent

tan(theta) = BC/AB

tan(theta) = (-5)/(-12)

tan(theta) = 5/12

------------------

To find csc, aka cosecant, you apply the reciprocal to sine

sin = -5/13 which means csc = -13/5

sec, or secant, is the reciprocal of cosine

cos = -12/13 leads to sec = -13/12

and finally cotangent (cot) is the reciprocal of tangent

tan = 5/12 leads to cot = 12/5

------------------

Note: everything but tan and cot is negative in Q3.

Round 948070 to the nearest hundred? Hurry please

Answers

Answer:

9.48

Step-by-step explanation:

The following measurements (in picocuries per liter) were recorded by a set of argon gas detectors installed in a research facility:

381.3,394.8,396.1,380
Using these measurements, construct a 95% confidence interval for the mean level of argon gas present in the facility. Assume the population is approximately normal.

Answers

Answer:

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

Step-by-step explanation:

Before building the confidence interval, we have to find the sample mean and the sample standard deviation.

Sample mean:

[tex]\overline{x} = \frac{381.3+394.8+396.1+380}{4} = 388.05[/tex]

Sample standard deviation:

[tex]s = \sqrt{\frac{(381.3-388.05)^2+(394.8-388.05)^2+(396.1-388.05)^2+(380-388.05)^2}{3}} = 8.58[/tex]

Confidence interval:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 3.1824

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 3.1824\frac{8.58}{\sqrt{4}} = 13.65[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 388.05 - 13.65 = 374.4

The upper end of the interval is the sample mean added to M. So it is 388.05 + 13.65 = 401.7

The 95% confidence interval for the mean level of argon gas present in the facility is (374.4, 401.7).

Please help NO LINKS

Answers

[tex]\bar{x} = 0[/tex]

[tex]\bar{y} =\dfrac{136}{125}[/tex]

Step-by-step explanation:

Let's define our functions [tex]f(x)\:\text{and}\:g(x)[/tex] as follows:

[tex]f(x) = x^2 + 1[/tex]

[tex]g(x) = 6x^2[/tex]

The two functions intersect when [tex]f(x)=g(x)[/tex] and that occurs at [tex]x = \pm\frac{1}{5}[/tex] so they're going to be the limits of integration. To solve for the coordinates of the centroid [tex]\bar{x}\:\text{and}\:\bar{y}[/tex], we need to solve for the area A first:

[tex]\displaystyle A = \int_a^b [f(x) - g(x)]dx[/tex]

[tex]\displaystyle \:\:\:\:\:\:\:=\int_{-\frac{1}{5}}^{+\frac{1}{5}}[(x^2 + 1) - 6x^2]dx[/tex]

[tex]\displaystyle \:\:\:\:\:\:\:=\int_{-\frac{1}{5}}^{+\frac{1}{5}}(1 - 5x^2)dx[/tex]

[tex]\displaystyle \:\:\:\:\:\:\:=\left(x - \frac{5}{3}x^3 \right)_{-\frac{1}{5}}^{+\frac{1}{5}}[/tex]

[tex]\:\:\:\:\:\:\:= \dfrac{28}{75}[/tex]

The x-coordinate of the centroid [tex]\bar{x}[/tex] is given by

[tex]\displaystyle \bar{x} = \dfrac{1}{A}\int_a^b x[f(x) - g(x)]dx[/tex]

[tex]\displaystyle \:\:\:\:\:\:\:= \frac{75}{28}\int_{-\frac{1}{5}}^{+\frac{1}{5}} (x - 5x^3)dx[/tex]

[tex]\:\:\:\:\:\:\:=\dfrac{75}{28}\left(\dfrac{1}{2}x^2 -\dfrac{5}{4}x^4 \right)_{-\frac{1}{5}}^{+\frac{1}{5}}[/tex]

[tex]\:\:\:\:\:\:\:= 0[/tex]

The y-coordinate of the centroid [tex]\bar{y}[/tex] is given by

[tex]\displaystyle \bar{y} = \frac{1}{A}\int_a^b \frac{1}{2}[f^2(x) - g^2(x)]dx[/tex]

[tex]\displaystyle \:\:\:\:\:\:\:=\frac{75}{28}\int_{-\frac{1}{5}}^{+\frac{1}{5}} \frac{1}{2}(-35x^4 + 2x^2 + 1)dx[/tex]

[tex]\:\:\:\:\:\:\:=\frac{75}{56} \left[-7x^5 + \frac{2}{3}x^3 + x \right]_{-\frac{1}{5}}^{+\frac{1}{5}}[/tex]

[tex]\:\:\:\:\:\:\:=\dfrac{136}{125}[/tex]

XYZ has side lengths that measure 20 centimeters each. Which of the
following best describes this type of triangle?
A. Obtuse triangle
B. Right triangle
C. Scalene triangle
D. Equilateral triangle

Answers

Answer:

it's and equilateral triangle because

all sides are equal

Answer:

equilateral triangle i have a math proffesor helping me

Step-by-step explanation:

I have a math proffesor helping me

Rearrange 2x = y/w to make w the subject​

Answers

Yes i think that is the answer good boj

What is the area of area of 7 meters, 15 meters and 9 meters?​

Answers

Answer:

10

Step-by-step explanation:

10-7 do it yourself and don't vheat

Can you be more specific?

The graph shows a line of best fit for data collected on the average temperature, in degrees Fahrenheit, during a month and the
number of inches of rainfall during that month.
у
90
801
70
Average Temp
20
10
Inches of Rain
The equation for the line of best fit is y=-3.32x +97.05.
Based on the line of best fit, what would be the prediction for the average temperature during a month with 13.25 inches of rainfall?

Answers

Answer:

53.06°F

Step-by-step explanation:

Given the equation of best fit :

y=-3.32x +97.05.

The average temperature for a month with 13.25 inches of Rainfall

Amount of Rainfall = x

Average temperature = y

To make our prediction ; put x = 13.25 in the equation and solve for y ;

y = -3.32x +97.05

Put x = 13.25

y = -3.32(13.25) +97.05

y = - 43.99 + 97.05

y = 53.06°F

remove bracket and simplify 6x-(3x+2)​

Answers

Answer: 3x - 2

Step-by-step explanation:

First to solve this, we need to know some basic information such as:

1. (-) × (-) = +

2. (+) × (-) = -

3. (+) × (+) = +

Therefore, 6x-(3x+2)​

= 6x - 3x - 2

= 3x - 2

The answer to the question after removing the bracket will be 3x - 2.

HW HELP PLZZZZ ASAPPPP

Answers

Answer:

[tex]\frac{3v}{a^{2}} = h[/tex]

Step-by-step explanation:

[tex]v = \frac{1}{3} a^{2} h[/tex]

[tex]3v = a^{2} h[/tex]

[tex]\frac{3v}{a^{2}} = h[/tex]

A paper weight is made in the shape of a triangular pyramid.The dimensions of the paper weight are shown The formula for the volume of a triangular pyramid is V = 1/3 Bh .Which expression can be usef to find the value of B the area of the base of the pyramid

Answers

Answer:

[tex]B = \frac{3V}{h}[/tex]

Step-by-step explanation:

Given

[tex]V = \frac{1}{3}Bh[/tex]

Required

Solve for B

We have;

[tex]V = \frac{1}{3}Bh[/tex]

Multiply by 3

[tex]3V = Bh[/tex]

Make B the subject

[tex]B = \frac{3V}{h}[/tex]

Which of the following is the solution set of -2|x| < -8 {x | -4 > x > 4} {x | x < -4 or x > 4} {x | -4 < x < 4}

Answers

Answer:

the second one

Step-by-step explanation:

For the function, tell whether the graph opens up or opens down, identify the vertex, and tell whether the graph is wider, narrower, or the same width as the graph of y = |x|.

y = 2|x – 1| - 3



opens up, (1, 3), wider

opens up, (1, 3), narrower

opens up, (-1, -3), wider

opens up, (1, -3), narrower

Answers

Answer:

The answer is D, the last one.

9514 1404 393

Answer:

  (d)  opens up, (1, -3), narrower

Step-by-step explanation:

The factor of +2 multiplying the function tells you the graph is expanded vertically by a factor of 2. The parent function opens upward, and the positive sign on this expansion factor does not change that. The expansion means that y-values will be farther from the vertex for the same x-value distance from the vertex. This give the appearance of a narrower graph.

As always, the transformation ...

  f(x -h) +k

moves the vertex from (0, 0) to (h, k). Here, you have (h, k) = (1, -3), so that is the location of the vertex of the transformed function.

PLEASE ANSWER QUICKLY Find the distance between points (4, 2) and (7, 2) on the coordinate
plane.

Answers

Answer:

3 units

Step-by-step explanation:

(4,2) (7,2)

Subtract 4 from 7 = 3

Subtract 2 from 2 = 0

This means that (7,2) is 3 units up from (4,2).

:) ur welcome

Answer:

Step-by-step explanation:

D=√(x2-x1)²+(y2-y1)²

D=√(7-4)²+(2-2)²

D=√(3)²+0

D=3²*½

D=3

Julie and Mona know that that Earth’s average distance from the Sun is approximately 93 million miles and it takes 1 year to complete an orbit of the Sun. A new asteroid has been discovered orbiting the Sun at an average distance of 1,488 million miles. How long will it take for the asteroid, in Earth years, to complete one orbit of the Sun.

Answers

Answer:

16 years

Step-by-step explanation:

Given that :

Earth's distance from sun = 93 million miles

Number of years to complete an orbit = 1 year

Average orbiting distance of new asteroid = 1488 million miles

Number of years to complete an orbit = x

93,000,000 Miles = 1

1488000000 miles = x

Cross multiply :

93000000x = 1488000000

x = 1488000000 / 93000000

x = 16 years

Period taken to orbit the sun = 16 years

Answer: 64 Earth years...

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B America was once great but it will never be great again. C America was never great for those who built it, and it never will be, D America was never great for those who built it, but it can be in the futurefollow me who follows first is markbrainlistI will alsoif you unfollow after sometime I will spam you answeranswer A oil company has a large tank that holds the oil before it is distributed. If it costs $3.20 per cubic meter for oil, how much money would it cost to fill the entire tank?A. $65,280B. $68,000C. $5,440D. $67,200 what are evidence that the himalayas are still risingplz help me with a good explanation 1I will give u branist and rate u 5 star and also give u like.I will also follow u back POINTS!!Draw a diagram of the archway modeled by the equation y = -x2 + 5x + 24. Find and label the y-intercept and the x-intercepts on the sketch. Then find and label the width of the archway at its base and the height of the archway at its highest point, assuming the base of the archway is along the x-axis. Identify the ethical issue(s) in each experiment. Beginning in the 1940s, the Department of Medicine at the University of Chicago tested anti-malaria medications on inmates at the Stateville Penitentiary. Inmates readily volunteered, as their parole would be reviewed upon completion of their sentence. Inmates who participated in the study reported that they were informed of the risks involved in participating in the study, including the possibility of death.In the 1960s, Stanley Milgram studied the willingness of subjects to obey an authority figure, even at the risk of being harmed. The subjects believed they were taking part in a study on learning. They were assigned to the role of teacher and were ordered to administer electrical shocks with increasing voltage to the learner whenever the learner made an error. The learner was an actor who remained unharmed. The subjects were not initially told that it was a study of obedience, as this might affect the outcome, and they were not prepared for possible psychological distress. In the 1950s and 60s, Saul Krugman infected mentally disabled children enrolled at the Willowbrook State School in New York with hepatitis in order to better understand how the disease spread and how it could be combatted. Parents agreed to enroll their children in the study in exchange for admission to the school. Do you think Jim and Della are realistic characters? Are their actions more or less convincing than the actions of Federigo and Monna Giovanna in Federigos Falcon? Give reasons for your response. Choose the sentence that has correct parallel structure,A. The kids who got the sickness first were the kids who had thesickness the longest,B. Misery, sickness, and exhaustion entered my house,C. My housed was invaded by some strange illness, followed bymisery, and in the end, we were all exhausted,D. None of the above are correctHelp ???? A point charge of -3.0 x 10-5C is placed at the origin of coordinates. Find the electric field at the point 3. r= 50 m on the x-axis The Byzantine Empire produced Christian art that was highly abstracted, partially due to what reason? How was Marcus Garvey different from civil rights leaders? A. He did not believe that equality could be achieved in the United States. B. He did not believe in fighting for civil rights. C. He did not support Africa. D. He worked for economic independence. HELPIdentify the domain of the function shown in the graph. You are on patrol running radar and observe an individual speeding. Your radar indicates the suspect is doing 60 in a 35 mph zone. You turn on your lights and pull in behind the suspect's car. The suspect pulls over and brings his car to a full stop while leaving his car running. After you run the plate on the car and everything is O.K., you approach the car on foot. The driver of the car puts down his window and asks why you stopped him. You inform him that he was clocked doing 60 in a 35. You ask to see his license and registration. The driver's breath smells of alcohol and he is slurring his words, so you ask him to step outside the vehicle so you can do a field sobriety test. At the same time you call for back-up. The suspect becomes verbally abusive and refuses to comply. What should you do I need help with 7 and 8 please identity five reason why there is the need for conduction of population census in Ghana "Norms and values do not want remain no more significant because of influence of western culture" Justify this statement.