Choose the options below that are true.
A. The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.
B. The rate laws of all chemical reactions can be determined directly from their net chemical equations.
C. The rate laws of bimolecular elementary reactions are second order overall.
D. The rate law for a given reaction can be determined from its reaction mechanism, without the accompanying rates of each elementary step in the mechanism.

Answers

Answer 1

Answer:

The options (A) -The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.  and (C) -The rate laws of bimolecular elementary reactions are second order overall ,is true.

Explanation:

(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.

(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.

(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.

(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.

Therefore , the first and third statement is true.


Related Questions

A scientist wants to display the numbers of gallons of fuel that were used up
in a one-hour period by three different types of motors. What type of visual
display should the scientist use?


Help please

Answers

Answer:

bar graph

Explanation:

Which one is it for a brialiest

Answers

I’m confused about the question

If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
rate of production of nitrogen and hydrogen? Given 2NH3 3H2 + N2

Answers

Answer:

3.15 × 10⁻⁶ mol H₂/L.s

1.05 × 10⁻⁶ mol N₂/L.s

Explanation:

Step 1: Write the balanced equation

2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

The Answer is: 3.15 × 10⁻⁶ mol H₂/L.s; 1.05 × 10⁻⁶ mol N₂/L.s

Step 1:  When we Write the balanced equation

Then 2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

After that, The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:Now 2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

After that, The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:Now 2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

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Convert 8.19 x 10-14 moles of gold to atoms.

Answers

Answer:

4.932018 × 10¹⁰ atoms

Explanation:

Recall that:

1 mole = 6.022 × 10²³ atoms

To change 8.19× 10⁻¹⁴ moles to atoms;

Then, we have:

= (8.19× 10⁻¹⁴× 6.022 × 10²³ atoms)

= 4.932018 × 10¹⁰ atoms

Only 5 minutes to answer!
Why are the weather satellites important on Mars?

Answers

Answer:

they can track the weather which can show if it would be posssible to live or have life on mars

Explanation:

A balloon has a pressure of 3.5atm and a volume of 4.2L. What will the volume of the balloon be if the pressure is increased to 7.0atm? Assume that temperature remains constant. SHOW ALL WORK FOR FULL CREDIT!​

Answers

2.1 L

P1V1 = P2V2

P1 = 3.5 atm
V1 = 4.2 L
P2 = 7.0 atm
V2 = ?

Solve for V2 —> V2 = P1V1/P2
V2 = (3.5 atm)(4.2 L) / (7.0 atm) = 2.1 L

The volume of the balloon is 2.1L.

What is volume?

Volume is the amount of space the matter occupies. The SI unit of volume is cubic meter.

Using Boyles law equation,

P1V1 = P2V2

Where P1 and V1 are the initial pressure and volume of the gas

           P2 and V2 are the final pressure and volume of the gas

Given:

P1 = 3.5atm

V1 = 4.2L

P2 = 7.0atm

V2 = ?

Solve for V2 ,

V2 = P1V1/P2

V2 = (3.5atm x 4.2 L) / (7.0atm)

     = 2.1L

Hence, the volume of the balloon is 2.1L.

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why do we need digital technology in school?​

Answers

Answer: See explanation

Explanation:

Digital technologies refers to the electronic tools, or devices that can be used to generate data, store them or process data. e.g. mobile phones, ebooks etc.

Digital learning makes use of technology. Effective use of digital learning tools can help increase the engagement of students. This csn.aksi be used by the teachers to enhance personalized learning and also improve the lesson plans.

Digital technology can enhance collaboration, and communication with the students. The use of videos, robots, virtual classrooms, augmented reality and other technologies can bring about fun and foster inquisitiveness.

Why do scientists think that liquid water might have once existed on Mars?

Answers

Answer: The discovery of three buried lakes. Scientists think that a long time ago there were lakes and rivers, etc on Mars. Now of course, you can't see any visible water sources on the surface.

Answer:

Almost all water on Mars today exists as ice, though it also exists in small quantities as vapor in the atmosphere.[5] What was thought to be low-volume liquid brines in shallow Martian soil, also called recurrent slope lineae may be grains of flowing sand and dust slipping downhill to make dark streaks.The only place where water ice is visible at the surface is at the north polar ice cap. Abundant water ice is also present beneath the permanent carbon dioxide ice cap at the Martian south pole and in the shallow subsurface at more temperate conditions. More than 5 million km3 of ice have been detected at or near the surface of Mars, enough to cover the whole planet to a depth of 35 meters. Even more ice is likely to be locked away in the deep subsurface.

Some liquid water may occur transiently on the Martian surface today, but limited to traces of dissolved moisture from the atmosphere and thin films, which are challenging environments for known life. No large standing bodies of liquid water exist on the planet's surface, because the atmospheric pressure there averages just 600 pascals , a figure slightly below the vapor pressure of water at its melting point; under average Martian conditions, pure water on the Martian surface would freeze or, if heated to above the melting point, would sublime to vapor. Before about 3.8 billion years ago, Mars may have had a denser atmosphere and higher surface temperatures, allowing vast amounts of liquid water on the surface, possibly including a large ocean that may have covered one-third of the planet.Water has also apparently flowed across the surface for short periods at various intervals more recently in Mars' history. Aeolis Palus in Gale Crater, explored by the Curiosity rover, is the geological remains of an ancient freshwater lake that could have been a hospitable environment for microbial life.Many lines of evidence indicate that water ice is abundant on Mars and it has played a significant role in the planet's geologic history.The present-day inventory of water on Mars can be estimated from spacecraft images, remote sensing techniques (spectroscopic measurements, radar, etc.), and surface investigations from landers and rovers.Geologic evidence of past water includes enormous outflow channels carved by floods, ancient river valley networks, deltas and lakebeds,and the detection of rocks and minerals on the surface that could only have formed in liquid water. Numerous geomorphic features suggest the presence of ground ice (permafrost)and the movement of ice in glaciers, both in the recent past and present. Gullies and slope lineae along cliffs and crater walls suggest that flowing water continues to shape the surface of Mars, although to a far lesser degree than in the ancient past.Although the surface of Mars was periodically wet and could have been hospitable to microbial life billions of years ago, the current environment at the surface is dry and subfreezing, probably presenting an insurmountable obstacle for living organisms. In addition, Mars lacks a thick atmosphere, ozone layer, and magnetic field, allowing solar and cosmic radiation to strike the surface unimpeded. The damaging effects of ionizing radiation on cellular structure is another one of the prime limiting factors on the survival of life on the surface. Therefore, the best potential locations for discovering life on Mars may be in subsurface environments. Large amounts of underground ice have been found on Mars; the volume of water detected is equivalent to the volume of water in Lake Superior. In 2018, scientists reported the discovery of a subglacial lake on Mars, 1.5 km (0.93 mi) below the southern polar ice cap, with a horizontal extent of about 20 km (12 mi), the first known stable body of liquid water on the planet.Understanding the extent and situation of water on Mars is vital to assess the planet’s potential for harboring life and for providing usable resources for future human exploration. For this reason, "Follow the Water" was the science theme of NASA's Mars Exploration Program (MEP) in the first decade of the 21st century. NASA and ESA missions including 2001 Mars Odyssey, Mars Express, Mars Exploration Rovers (MERs), Mars Reconnaissance Orbiter (MRO), and Mars Phoenix lander have provided information about water's abundance and distribution on Mars.Mars Odyssey, Mars Express, MRO, and Mars Science Lander Curiosity rover are still operating, and discoveries continue to be made.

What is the entropy of this collection of training examples with respect to the positive class B. What are the information gains of A1 and A2 relative to the training dataset For A3, which is a continuous attribute, compute the information gain for every possible split. C. What is the best split (among A1,A2, and A3) according to the information gain

Answers

The data set is missing in the question. The data set is given in the attachment.

Solution :

a). In the table, there are four positive examples and give number of negative examples.

Therefore,

[tex]$P(+) = \frac{4}{9}$[/tex]   and

[tex]$P(-) = \frac{5}{9}$[/tex]

The entropy of the training examples is given by :

[tex]$ -\frac{4}{9}\log_2\left(\frac{4}{9}\right)-\frac{5}{9}\log_2\left(\frac{5}{9}\right)$[/tex]

= 0.9911

b). For the attribute all the associating increments and the probability are :

  [tex]$a_1$[/tex]   +   -

  T   3    1

  F    1    4

Th entropy for   [tex]$a_1$[/tex]  is given by :

[tex]$\frac{4}{9}[ -\frac{3}{4}\log\left(\frac{3}{4}\right)-\frac{1}{4}\log\left(\frac{1}{4}\right)]+\frac{5}{9}[ -\frac{1}{5}\log\left(\frac{1}{5}\right)-\frac{4}{5}\log\left(\frac{4}{5}\right)]$[/tex]

= 0.7616

Therefore, the information gain for [tex]$a_1$[/tex]  is

  0.9911 - 0.7616 = 0.2294

Similarly for the attribute [tex]$a_2$[/tex]  the associating counts and the probabilities are :

  [tex]$a_2$[/tex]  +   -

  T   2    3

  F   2    2

Th entropy for   [tex]$a_2$[/tex] is given by :

[tex]$\frac{5}{9}[ -\frac{2}{5}\log\left(\frac{2}{5}\right)-\frac{3}{5}\log\left(\frac{3}{5}\right)]+\frac{4}{9}[ -\frac{2}{4}\log\left(\frac{2}{4}\right)-\frac{2}{4}\log\left(\frac{2}{4}\right)]$[/tex]

= 0.9839

Therefore, the information gain for [tex]$a_2$[/tex] is

  0.9911 - 0.9839 = 0.0072

[tex]$a_3$[/tex]     Class label      split point       entropy        Info gain

1.0         +                        2.0            0.8484        0.1427

3.0        -                         3.5            0.9885        0.0026

4.0        +                        4.5            0.9183         0.0728

5.0        -

5.0        -                        5.5            0.9839        0.0072

6.0        +                       6.5             0.9728       0.0183

7.0        +

7.0        -                        7.5             0.8889       0.1022

The best split for [tex]$a_3$[/tex]  observed at split point which is equal to 2.

c). From the table mention in part (b) of the information gain, we can say that [tex]$a_1$[/tex] produces the best split.

What is the volume of 0.200 moles of O2 gas at STP?

Answers

Answer:

4.48 L O2

Explanation:

At STP, a mole of any gas contains 22.4 liters. Therefore, we simply have to multiply the amount of moles by 22.4

0.2mol O2 ( 22.4 L) = 4.48 L O2

What is the ratio by atoms of elements present in technetium (VII) peroxide? (peroxide
is a polyatomic ion)
1:7
2:8
4:9
3:1

Answers

Answer: 1:7

Explanation: 2 Tc^+7 + 7 O2^-2 -> Tc2 (O2)7

Also 2 Tc to 14 O

Which element had the smallest atomic radius

Answers

Answer:

helium is the answer

Explanation:

helium is the smallest element in francium is the largest hope this helps

A reaction vessel for synthesizing ammonia by reacting nitrogen and hydrogen is charged with 5.54 kg of H2 and excess N2. A total of 25.6 kg of NH3 are produced. What is the percent yield of the reaction?

Answers

Answer:

81.5

Explanation:

smartworks

When P4O10(s) reacts with H2O(l) to form H3PO4(aq) , 453 kJ of energy are evolved for each mole of P4O10(s) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation.

Answers

Answer:

P4O10 + 6H2O → 4H3PO4         ΔH = 453 kJ

Explanation:

A thermochemical reaction is one in which the amount of heat gained/evolved is written as part of the reaction equation.

A thermochemical equation helps us to judge whether an equation is endothermic or exothermic. For an endothermic reaction, ΔH  is positive while for an exothermic reaction ΔH is negative.

Since, the reaction of one mole of P4O10(s)  with H2O(l) to form H3PO4(aq) evolves 453 kJ of energy for each mole of P4O10(s) that reacts. Then we can write;

P4O10 + 6H2O → 4H3PO4         ΔH = 453 kJ

By examining data from distant stars, astronomers can determine
if a star is moving away from or toward Earth. Which of the
following pieces of data would be most helpful in determining
the motion of a star?
A The star gives off blue-white light.
B
The star gives off mainly radio waves and X-rays.
C
The light spectrum given off by the star is shifted toward the
red end.
.
D
The surface temperature of the star is approximately 10,000°
Celsius.

Answers

Answer:

The answer is A ahahahha

Explanation:

Because it just is

A car generates 2552 N and weighs 2250 kg. What is its rate of acceleration

2 m/s ^2
0.88m/s^2
5,742,000m/s^2
1.13m/s^2

Answers

Answer:

[tex]a=1.134\frac{m}{s^2}[/tex]

Explanation:

Hello there!

In this case, by considering the physical definition of force in terms of mass and acceleration:

[tex]F=m*a[/tex]

Given the generated force and the involved mass, we can compute the required acceleration as shown below:

[tex]a=\frac{F}{m}\\\\a=\frac{2552N}{114kg}[/tex]

Yet it is necessary to break out Newtons to:

[tex]a=\frac{2552\frac{kg*m}{s^2} }{114kg}\\\\a=1.134\frac{m}{s^2}[/tex]

Best regards!

Convert 0.0338 moles of K3PO4 to grams.

Answers

0.0338 K3PO4 212.27 g K3PO4
——————— x ————————-= 7.17g K3PO4
1 1 mol K3PO4

0.0338x 212.27= 7.174726

Answer : 7.17 g K3PO4
7.17 hope this helps bestie

arrange the following group of atoms in order of decreasing atomic size:B,Al,Ga​

Answers

Answer:

B<Ga<Al

Explanation:

Hope this helps

It took 14.50 mL of 0.455M NaOH to fully neutralize 12.0mL of HCl. What is the concentration of the HCl?
HCl + NaOH \rightarrow→ NaCl + H2O

Answers

Answer:

0.550 M HCl

Explanation:

M1V1 = M2V2

M1 = 0.455 M NaOH

V1 = 14.50 mL NaOH

M2 = ?

V2 = 12.0 mL HCl

Solve for M2 --> M2 = M1V1/V2

M2 = (0.455 M)(14.50 mL) / (12.0 mL) = 0.550 M HCl

Answer:

The appropriate answer is "0.549 M".

Explanation:

The given values are:

N₁ = 14.50 mL

V₁ = 0.455 M

N₂ = 12 mL

Let

V₂ = C = ?

As we know,

⇒  [tex]N_1\times V_1=N_2\times V_2[/tex]

On substituting the values, we get

⇒  [tex]14.50\times 0.455 = 12\times C[/tex]

⇒            [tex]6.5975=12\times C[/tex]

⇒                   [tex]C=\frac{6.5975}{12}[/tex]

⇒                       [tex]=0.549 \ M[/tex]

5 ways light changes objects

Answers

1) it can make the object glow, making it more seeable
2) it could make the object hot if the light stays on it for long enough
3) it forms energy, such as light helps makes plants grow
4) it can make it change colors, such as if you put a flashlight underneath a balloon making it a lighter colour
5) it can reflect of the objects, such as a mirror

which of the following, when dissolved in water, forms a weak acid.A. HNO3B. HClO4C. HBrD. HClOE. NH3

Answers

Answer:

The weak acid is - E. [tex]NH_3[/tex]

Explanation:

Ammonia is a strong base, which in turn make it to be a weak acid.

As, the rest of the options are acid and therefore furnish hydrogen ions when dissolved in water, making them strong acid.

And ammonia dissolves in water to form its conjugate ammonium ion and hydroxide ion, therefore making the solution basic.

Hence, from the given options, the correct option is E. [tex]NH_3[/tex]

The compound which when dissolved in water, forms a weak acid is; Choice E: NH3

According to the question;

we are required to determine which compound forms a weak acid when dissolved in water.

Unlike other compounds (HNO3, HClO, HBr, HClO) which dissolve in water to yield H+ ion, Ammonia dissolves in water to form ammonium ion and hydroxide ion, OH-.

In essence, NH3 is a strong base when dissolved in water and consequently, is a weak acid when dissolved in water.

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One method for preparing a nitrile is the dehydration of a primary amide.

a. True
b. False

Answers

true because a dehydration reaction is a conversion that involves the loss of water from the reacting molecule or ion. Dehydration reactions are common processes, the reverse of a hydration reaction. Common dehydrating agents used in organic synthesis include sulfuric acid and alumina. Often dehydration reactions are effected with heating.

Nitrous oxide (N2O), more commonly known as laughing gas, is used as a mild sedatitive during various dental procedures.As a gas, it has a densityof 1.977 x 10-3g/mL.Wheniron is exposed to oxygen it forms rust (Fe2O3), which is a solid and has a density value of 5.25 g/mL.Why are the density values so different among these substances?
a)The metal atoms weigh more than the atoms of the gas.
b)The metal forms metallic bonds which are more greatly affected by gravity, increasing the mass.
c)The metal is a solid, and solids weigh more based on the principles of their states of matter.
d)There are fewer gas particles than solid particles in the same volume.

Answers

Answer:

B.

Explanation:

The metal forms metallic bonds which are more greatly affected by gravity, increasing the mass.

identify the solute in the following: carbon dioxide dissolved in water

a. water
b. carbon dioxide
c. none of the above
d. carbon dioxide and water

Answers

Answer:

B

Explanation:

its solute state is gas and dissolve in (solvent) liquid which is water

Which fossil fuel was formed from the bodies of prehistoric animals and plants?

Answers

Answer:

coal

Explanation:

In order for a roller coaster to work, why does the hill the cart climbs need to be higher than the top of the loop?

Answers

Answer:

Explanation:

At the highest point of the first and tallest slope, your potential energy is at its most elevated it will at any point be on this ride. As you plunge, your potential energy diminishes until it's totally gone at the lower part of the slope." The more limited the slope the exciting ride climbs, the more prominent its active energy.

Another way of saying is that

A roller ride works utilizing gravity. the underlying slope must be sufficiently high that gravity can create sufficient force to finish the course.

Brainliest?

Lab: Measuring pH Table or
Lab Report please ( just link it ) please

Answers

Answer:

sorry my phone died lol but here are the answers

<3

Write a formula and balanced equation for the following: solid copper metal reacts with aqueous silver nitrate to produce solid silver metal and aqueous copper Nitrate. How do I know if it will form copper (I) nitrate CuNO3 or copper (II) nitrate Cu(NO3)2 ?

Answers

Explanation:

copper (II) nitrate

Illustrate variety of substances of which an element can be part:

metal --> blue solution --> blue solid --> black solid --> blue solution (again) --> metal (again).When solid copper reacts with aqueous silver nitrate, the products are copper (II) nitrate and solid silver. and carbon monoxide gas produces solid iron and carbon dioxide gas.

How many grams are in 3.0 moles of sodium chloride (NaCl)?

Answers

Answer:

175.5

Explanation:

What is orbit? A. An increase in centripetal motion and mass friction. B. Resistance of an object to avoid friction. C. Gravity causing a curved path as an object tries to go straight. D. How well an object floats.

Answers

Answer:

C. gravity causing a curved path as an object tries to go straight.

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