Click on the number line below to show the approximate location of 19 on the number line.

Answer:

9 and 10

Step-by-step explanation:

square root of 86 is 9.2 (ish)

Answer: 2760

Step-by-step explanation:

Answer:

Using it's concept, it is found that the marginal relative frequency of survey participants who are girls is of 0.43.

A relative frequency is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that there were 2 + 3 + 5 + 4 + 3 + 8 + 2 + 6 + 4 + 3 = 40 participants, of which 17 are girls, hence the relative frequency is given by:

f = 17/40 = 0.425

Which is rounded to 0.43.

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Answer:

D.(4^1/2)^4

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

Solution

Step-by-step explanation:

Hope this helped :)

Answer:

Step-by-step explanation:

(1,2) and (2,1) are not equal ordered pairs becasue their corresponding elements are not equal.

Two Ordered Pairs are said to be equal if the corresponding first components are equal alongside the corresponding second components are equal.

for example:

(3,1) and (3,1)

here corresponding element of 3 is 3 and of 1 is 1 .so they are called equal ordered pairs.

Answer:

111

hope that helps!

Answer:

a four sided parallelogram where all angles are the same and all sides are the same length

Answer: A.46

Step-by-step explanation: because it jus is dawg

Note: The image of G after the dilation must be G'(5,-5) instead of G'(5,5).

Given:

The vertices of a rectangle are E(4,8), F(2,8), G(2,-2) and H(-4,-2).

The rectangle is dilated with the origin as the center of dilation so that G's is located at (5,-5).

To find:

The algebraic representation that represents this dilation.

Solution:

If a figure is dilated by factor k with origin as the center of dilation, then the dilation is defined as:

[tex](x,y)\to (kx,ky)[/tex]              ...(i)

Let the given rectangle is dilated by factor k with origin as the center of dilation. Then,

[tex]G(2,-2)\to G'(k(2),k(-2))[/tex]

[tex]G(2,-2)\to G'(2k,-2k)[/tex]

The image of G after dilation is G'(5,-5). So,

[tex](2k,-2k)=(5,-5)[/tex]

On comparing both sides, we get

[tex]2k=5[/tex]

[tex]k=\dfrac{5}{2}[/tex]

So, the scale factor is [tex]k=\dfrac{5}{2}[/tex].

Substituting [tex]k=\dfrac{5}{2}[/tex] in (i), we get

[tex](x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)[/tex]

Therefore, the required algebraic representation to represents this dilation is [tex](x,y)\to \left(\dfrac{5}{2}x,\dfrac{5}{2}y\right)[/tex].

Answer:

x = -1 , - 11,

Step-by-step explanation:

| x | = x

|- x | = x

f(x) = 2 | x + 6 | - 4

x = - 1 , f( - 1) = 2 | - 1 + 6 | - 4 = 2 | 5 | - 4 = 10 - 4 = 6 , True

x = 1 , f( 1 ) = 2 | 1 + 6 | - 4 = 2 | 7 | - 4 = 14 - 4 = 10 , False

x = 11, f( 11 ) = 2 | 11 + 6 | - 4 = 2 | 17 | - 4 = 34 - 4 = 30 , False

x = - 11, f( - 11) = 2 | -11 + 6 | - 4 = 2 | - 5 | - 4 = 10 - 4 = 6 , True

x = 14 , f( 14 ) = 2 | 14 + 6 | - 4 = 2 | 20 | - 4 = 40 - 4 = 36 , False

x = -14 , f( - 14 ) = 2 | - 14 + 6 | - 4 = 2 | - 8 | - 4 = 16 - 4 = 12 , False

x = - 26 , f( - 26) = 2 | -26 + 6 | - 4 = 2 | -20 | - 4 = 40 - 4 = 36 , False

x = 26, f( 26 ) = 2 | 26 + 6 | - 4 = 2 | 32 | - 4 = 64 - 4 = 60 , False

                                                    OR

Given f ( x ) = 6

f( x ) = 2 | x + 6 | - 4

6  = 2 | x + 6 | - 4

6 + 4 = 2 | x + 6| - 4 + 4                 [ adding 4 to both sides ]

10 = 2 | x + 6 | + 0

5 = | x + 6 |                                    [ dividing both sides by 2 ]

[tex]- 5 =\ ( x+ 6) \ = 5\\\\[/tex]                            [tex][ \ | x | = a\ => \ -a \ = x \ = a \ ][/tex]

[tex]- 5 - 6 = \ x + 6 - 6 \ = \ 5 - 6\\[/tex]            [tex][ \ subtracting \ by \ 6 \ ][/tex]

[tex]-11 = \ x \ = - 1[/tex]

Answer:

16 pennies

Step-by-step explanation:

74 - 18 = 56

56 / 7 = 8

1/7 of the pennies is 8 pennies.

2/7 of the pennies are 16 pennies.

Answer:

18 pennies

Step-by-step explanation:

74-18=56

56/7=8

8x2=16

Answer:

$2,000 at 9%

$8,000 at 4%

Step-by-step explanation:

(4x * .04) + (x * .09) = 500

.16x + .09x

.25x = 500

x = $2,000 at 9%

4x = $8,000 at 4%

Answer:

2000 at 9%

8000 at 4%

Step-by-step explanation:

Let the principle at 9% = x

The principle at 4% = 4*x

Together they give 500 dollars.

9% = .09

4% = ,04

Both are invested for 1 year

0.09 * 1 * x + 0.04 * 1 * 4x = 500

0.09x + 0.16x = 500

0.25x = 500

x = 500 / 0.25

x = 2000

She invested 2000 at 9%

She invested 4 * 2000 at 4%

Answer:

You can do it with your eyes closed

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let's FOIL this out and get it into standard form. That gives us:

[tex]h(t)=-4.9t^2+490[/tex] For #1, then:

The height of something when it is on the ground is 0; that means that the h(t) is 0. This allows us to factor the quadratic and solve for t:

[tex]-4.9t^2=-490[/tex] and divide both sides by 4.9 to get

[tex]t^2=100[/tex] so

t = 10. Notice that one of the factors for that quadratic is 10 - t. That factor represents the time it takes to hit the ground. So you might ask why, then, we FOILed this out in the first place if the answer was ight in front of our noses. The reason is becase of #2 that is asking us what the initial height of the object was. That is found in the standard form...in the constant in particular. The initial height is 490 m. That's how you know (because the constant represents the height from which an object is dropped in either free fall, which this is, or in parabolic motion).

Answer:

your answer is D. 24 cubic cm

Step-by-step explanation:

your welcome good day :)

Answer:

--273

Step-by-step explanation:

100th term is equal a1 + 99d so

100th term = 222 + (-5×99) = -273

Answer:

1.5

Step-by-step explanation:

Applying,

Z = (x-μ)/σ................. Equation 1

Where Z = Z score for a height of 67 inches, x = height, μ = mean of the height, σ = standard deviation of the height.

From the question,

Given: x = 67 inches, μ = 64 inches, σ = 2 inches.

Substitute these values into equation 1

Z = (67-64)/2

Z = 3/2

Z = 1.5

Answer:

4/11

Step-by-step explanation:

Let :

x = numerator

x + 7 = denominator [tex]\frac{x}{x + 7}[/tex]

[tex]\frac{x}{x+7} + \frac{1}{4} = \frac{1}{3}[/tex]

[tex]\frac{x + 1}{x + 11} = \frac{1}{3}[/tex]

cross multiply

3(x + 1) = x + 11

3x + 3 = x + 11

combine like terms

3x - x = 11 - 3

2x = 8

x = 4

x + 7 = 4 + 7 = 11

original fraction = 4/11

22 chocolate cookies can be made from 5.50 cups of sugar and 7 lemon cookies can be made from 5.50 cups of sugar

An equation is an expression that shows the relationship between two or more numbers and variables.

The chocolate cookies is given as:

Number of chocolate cookies = 5.50 cups / 0.25 cup per cookie = 22

The lemon cookies is given as:

Number of lemon cookies = 5.50 cups / 0.75 cup per cookie = 7

22 chocolate cookies can be made from 5.50 cups of sugar and 7 lemon cookies can be made from 5.50 cups of sugar

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Answer:

1.27 centimeters

Step-by-step explanation:

brainliest??

Given:

Consider the expression is:

[tex]13-\dfrac{x}{5}+6.2y+20.5x-\dfrac{3}{8}y[/tex]

To find:

The like terms that can be combined in this expression.

Solution:

Two terms are called like terms, if they have same variables of same degree.

We have,

[tex]13-\dfrac{x}{5}+6.2y+20.5x-\dfrac{3}{8}y[/tex]

In the given expression, the pairs of likes terms are:

Pair 1: [tex]-\dfrac{x}{5}[/tex] and [tex]20.5x[/tex]

Pair 2: [tex]6.2y[/tex] and [tex]-\dfrac{3}{8}y[/tex]

It means [tex]-\dfrac{x}{5}[/tex] can be combined with [tex]20.5x[/tex] and  [tex]6.2y[/tex] can be combined with [tex]-\dfrac{3}{8}y[/tex].

Therefore, the correct option is C.

Answer:

11

Step-by-step explanation:

9514 1404 393

Answer:

  1.2 t/m³

Step-by-step explanation:

1 tonne is 1 Mg = 10⁶ g

1 m³ is (100 cm)³ = 10⁶ cm³

The conversion is ...

  (1.2 g/cm³) · (1 t)/(10⁶ g) · (10⁶ cm³)/(1 m³)

  = 1.2(10⁶)/(10⁶) t/m³

  = 1.2 t/m³

__

For this conversion, the numerical value does not change. Megagrams per cubic meter is the same ratio as grams per cubic centimeter.

Answer:

c 52

Step-by-step explanation:

x=10

4 ×10=40

40+12=52

Note that the perpendicular bisector to line PQ is constructed and attached accordingly. Here is how to do it.

Note that the first stage is to draw a line PQ. But this has already been done.

Next is to place the compass on P as shown in the image above. If you allow you compass (locked at the same degree) to rotate about point P, you will get a circle. However, that is not the objective.

If you also place your compass on point Q, locked to the same degree as when it was on P, and take a rotation around point Q, you will also get a circle.

At some point, you will notice that both circles intersect at two point, which we can call AB₁ and AB₂.

Now you are done with the compass. Take up your ruler, and place it such that it meet both AB₁ and AB₂ but allowing you space to mark a line connecting both points.

Next, using your live or online pencil tool, draw the line from AB₁ to AB₂. Now you have the Perpendicular bisector which you can call AB₁₂.

Note that a perpendicular bisector is a line or plane that intersects a line segment at its midpoint, forming a right angle and dividing the segment into two equal parts.

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