Combine like terms and write the simplified

third option:- a^m-n

your welcome.

Answer:

r = [tex]\sqrt{\frac{a}{3}}[/tex]

Step-by-step explanation:

1. A = 3r²

(Divide 3 by both sides)

2. A/3 = r²

(Square root both sides)

√A/3 = r

On solving for 'r' we get -  r = [tex]\sqrt{\frac{A}{3} }[/tex].

We have the following expression -

[tex]$A=3r^{2}[/tex]

We have to solve for r.

On solving, we get -

x = [tex]$\pm\sqrt{9}[/tex]

x = [tex]$\pm3[/tex]

According to the question, we have -

[tex]$A=3r^{2}[/tex]

[tex]$r^{2} = \frac{A}{3}[/tex]

r = [tex]\pm\sqrt{\frac{A}{3} }[/tex]

Since, the area cannot be negative, therefore -

r = [tex]\sqrt{\frac{A}{3} }[/tex]

Hence, on solving for 'r' we get -  r = [tex]\sqrt{\frac{A}{3} }[/tex].

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Answer:

they travel 115 km/h long

Answer:

distributive property

Step-by-step explanation:

Let [tex]P_1(-1, -8)\:\text{and}\:P_2(-4, -9)[/tex]

The slope of the line through these two points is

[tex]m = \dfrac{y_2 - y_1}{x_2 - x_1} = \dfrac{(-9 + 8)}{(-4 + 1)} = \dfrac{1}{3}[/tex]

So the slope-intercept form of the line passing through the two points is

[tex]y = mx + b = \frac{1}{3}x + b[/tex]

To find b, we use either point into our equation. Let's use (-1, -8):

[tex]-8 = \frac{1}{3}(-1) + b \Rightarrow b = -\dfrac{23}{3}[/tex]

Therefore, the slope-intercept form of the equation for the line is

[tex]y = \dfrac{1}{3}x - \dfrac{23}{3}[/tex]

The standard form of the equation can be written as

[tex]x + 3y + 23 = 0[/tex]

Answer:

Sorry

Step-by-step explanation:

For my Poor H. And Coordinates

Answer:

c) ten thousand dollars

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

You have to calculate the boys name using ratio expression.

3/5 × 25

= 15

Answer:

-5,4

Step-by-step explanation:

midpoint x is a 3 point difference. 3 points in the opposite direction is -5

midpoint y is also a 3 point difference. 3 points in the opposite direction of that is 4

so I believe the correct answer should be (-5,4)

[tex]x^2\gt2x-2[/tex]

[tex]x^2-2x+2\gt0[/tex]

You are essentially asking at this point where is the quadratic function greater than 0. To get the interval find the roots. Between the roots the function is guaranteed to be LESS THAN zero. Everywhere else the function is greater than 0.

[tex]x^2-2x+2=0[/tex]

Use Vieta's rule to get the roots,

[tex](x-1)(x-1)=0[/tex]

Both roots are the same so no value is less than 0 which means all values except at the point of root are strictly greater, the point of root is at [tex]x_{1,2}=1[/tex] which means the set for which the quadratic function is greater than 0 is [tex]\mathbb{R}-\{1\}[/tex] "all real numbers except 1".

To convert this into interval notation use all numbers up to 1 but not including and all numbers after 1 but not including,

[tex](-\infty,1)\cup(1,\infty)[/tex]

Hope this helps :)

Answer:YA IM THAT KIND OF GUY I NEED POINTS

Step-by-step explanation:

YA IM THAT KIND OF GUY I NEED POINTS

5−33−32+39+3

Not sure?

Answer:

Step-by-step explanation:

the median is 89, the mode is 94, and the mean is 84

Answer:

78,000

Step-by-step explanation:

Answer:

if he work 3 hours and earn 40.50

then the money he earn per hour is 40.50/3=13.5 ans

Answer:

the answer is-2p-3

hope is helpful

Answer:

2p – 10 – 4p –7

–2p –17

I hope I helped you^_^

Answer:

25/100

Step-by-step explanation:

0.25=25/100

Hope this helps! Thanks.

Answer:

i dont know

Step-by-step explanation:

Answer:

what are we finding

Are we to derive an equation of a straight line

Answer:

Step-by-step explanation:

Given function:

This is a quadratic function with positive leading coefficient, therefore it is an increasing function with its minimum at vertex. It has no maximum value.

The vertex is at x = -b/2a:

The minimum value is:

The range of the function is:

f(x)=x^2+8x+8

[tex]\\ \sf\longmapsto \dfrac{-b}{2a}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-8}{2(1)}[/tex]

[tex]\\ \sf\longmapsto \dfrac{-8}{2}[/tex]

[tex]\\ \sf\longmapsto -4[/tex]

[tex]\\ \sf\longmapsto f(-4)[/tex]

[tex]\\ \sf\longmapsto (-4)^2+8(-4)+8[/tex]

[tex]\\ \sf\longmapsto 16-32+8[/tex]

[tex]\\ \sf\longmapsto -16+8[/tex]

[tex]\\ \sf\longmapsto -8[/tex]

The range is

[tex]\\ \sf\longmapsto (8,\infty)[/tex]

This is simply done by Method of Completing the Square.

3x - x²

Add and subtract half the coefficient of x and square it.

( This is done so there'd be no alterations to the quadractic Expression)

So To start

We'd like x² to be positive...(So factor out a negative).

–(x² - 3x )

Now In this case

You see there's a Negative Outside the the bracket

Instead of adding and Subtracting squared values of half the coefficient of X... We'd Add Twice and do not subtract.

Reason: If you add outside the bracket and subtract the other inside the bracket... This will be wrong because there's a negative patiently waiting outside the bracket to Interact with the negative you subtracted to make it Positive.

See what I mean.

Let's say you added 2² and subtracted 2² in this problem

2² – ( x² - 3x - 2²)

If you decide to open the bracket

You'll have

2² – x² + 3x + 2²

NOW THIS IS WRONG BECAUSE WE ALTERED THIS EXPRESSION. WHERE'D 2² + 2² COME FROM?

THIS IS WHY YOU'LL ADD THE SQUARED COEFFICIENT OF X TWICE IN CASES LIKE THESE.

SO GOING BACK TO THE ORIGINAL QUESTION.

– (x² - 3x )

Adding the half the coefficient of x twice and squaring them...

Coefficient of x = 3

Half of 3 = 3/2

Squaring it gives (3/2)²

NOW PROCEEDING

(3/2)² – [ x² - 3x + (3/2)²]

If you open this bracket... (3/2)² will cancel out with —(3/2)²

Meaning that we haven't altered the expression in any way

Moving On...

Applying basic factorizing principle

9/4 – ( x - 3/2)².

Answer = 9/4 – ( x - 3/2)² Which is in the Form m – ( x - n )²

Therefore m = 9/4 and n = 3/2.

Hope This Helps

Answer:

10boys, 17 girls

Step-by-step explanation:

10+17=27,

17-10=7

Answer: there are 17 girls in the class

Step-by-step explanation:

let the number of boys be x

and the number of girls be re[presented as 7+x

Since there are a class of 27 containing the sum of the boys and girls, we have our equation as

boys +girls =27

x+ 7+x=27

7+2x =27

2x=27-7

2x=20

x=20/2=10

Boys =x=10

girls= 7+x=7+10=17

See similar question here: https://brainly.com/question/21953702

Answer:

.48 * 159 = 76.32

Step-by-step explanation:

Answer:

Question unclear

Step-by-step explanation:Your probally asking what times 8 gives us 80. If you are than 10!

Answer:

28

Step-by-step explanation:

x=blue

y=white

x+y=40

30x+20y=920

30(x+y=40) ; 30x+30y=1200___[1]

30x+20y=920 ; 30x+20y=920___[2]

[1]-[2] : 30x+30y-30x-20y=1200-920

       10y=280

       y=28

painter buys 28 white gallons

Answer:

D = 8y-15

Step-by-step explanation:

-y-9y-15 than combine -y and -9y

so = 8y-15

Answer:  [tex]\sqrt{75}[/tex]

================================================

Explanation:

Square both 8 and 9 to get

Since 75 is between 64 and 81, this means [tex]\sqrt{75}[/tex] is between 8 and 9

Put another way, we can say this:

[tex]64 < 75 < 81\\\\\sqrt{64} < \sqrt{75} < \sqrt{81}\\\\\sqrt{8^2} < \sqrt{75} < \sqrt{9^2}\\\\8 < \sqrt{75} < 9\\\\[/tex]

Or we could use a calculator to find that:

Which is another way to see why [tex]\sqrt{75}[/tex] is between 8 and 9.

The equivalent form of the given expression is 1 /(x + y)

The given expression:

[tex]\frac{1}{x+y}[/tex]

To find:

The equivalent form of the expression can be written as follows:

[tex]\frac{1}{x+y} = 1 /(x + y)[/tex]

For example, if x = 1 and y = 2, the inverse of the expression can be written as;

[tex]\frac{1}{x + y} = \frac{1}{(1 + 2)} = \frac{1}{3}[/tex]

Also, if x = 2 and y = 3, the inverse of the expression can be written as;

[tex]\frac{1}{x + y} = \frac{1}{(2 + 3)} = \frac{1}{5}[/tex]

Thus, the equivalent form of the given expression is 1 /(x + y)

Learn more here: https://brainly.com/question/15469690

Answer:

1st expression= rational 2nd expression= rational 3rd expression = irrational

Step-by-step explanation:

The first and second expressions are rational because they both equal whole numbers (4 and 3) while the last expression equals a decimal that goes on forever with no end, thus making it irrational.