Complete the proof. PROVE:△VWY≅△UXY

Answer:

82.9+38.6=121.5 miles far away.

Answer:

C.35⁰

Step-by-step explanation:

C= 180⁰-145⁰= 35⁰

Answer:

ygftyhhhhgffyujhhgyjjjhhguj

Answer:

h = 7.5 cm

Step-by-step explanation:

Firstly, we find the area of the triangular base

Mathematically, we have the area of a triangle as;

A = 1/2 * b * h

A = 1/2 * 5 * 8 = 20 cm^2

Mathematically, we have the formula as;

V= 1/3 * A * h

A is base area and h is height

50 = 1/3 * 20 * h

20h = 3 * 50

20h = 150

h = 150/20

h = 7.5 cm

Answer:

5r³ - 34r² + 44r - 16

Step-by-step explanation:

[tex] \small \sf \: (5r − 4)(r² − 6r + 4)[/tex]

use the distributive property

5r × (r² − 6r + 4) - 4× (r² − 6r + 4)

5r³ - 30r² + 20r - 4r² + 24r - 16

combine like terms

5r³ - 30r² - 4r² + 20r + 24r - 16

5r³ - 34r² + 44r - 16

The product of the expressions is 5r^3 - 34r^2 + 44r - 16

The product of two expression is done by multiplying the expressions

The product expression is given as:

[tex](5r - 4)(r^2 - 6r + 4)[/tex]

Expand the expression

[tex]5r^3 - 30r^2 + 20r - 4r^2 + 24r - 16[/tex]

Collect like terms

[tex]5r^3 - 30r^2 - 4r^2 + 20r + 24r - 16[/tex]

Evaluate the like terms

[tex]5r^3 - 34r^2 + 44r - 16[/tex]

Hence, the product of the expressions is 5r^3 - 34r^2 + 44r - 16

Read more about product at:

https://brainly.com/question/4344214

Answer:

D.

Step-by-step explanation:

You need to use a graphing calculator to figure it out.

p+q = 12

Squaring both the sides

(p+q)^2 = 12^2

p2 + q2 + 2pq = 144

p2 + q2 + 2x 22 = 144

p2 + q2 = 144 - 44

p2 + q2 = 100

Answer:

q2=

Step-by-step explanation:

The formula for p^2+q^2p

2

+q

2

is

p^2+q^2 = (p+q)^2 -2pqp

2

+q

2

=(p+q)

2

−2pq

Answer:2. okra

Step-by-step explanation:

Answer:

C. Add 9.6, then divide by 3.2.

Step-by-step explanation:

[tex]3.2x−9.6=38.4[/tex]

[tex]3.2x=38.4+9.6[/tex]

[tex]3.2x=48[/tex]

[tex]x = 15[/tex]

Answer:

4th option

Step-by-step explanation:

in geometric sequences the number is multiplied or divided by same number continuously

in the 4th option we can see that the number 1 is multiplied by 4 continuously so the correct answer would be that.

Answer:

(f + g) (x) = 14x-11

Step-by-step explanation:

From the question, what we have to do is to add the two given polynomials

We have this as;

(8x-7) + (6x-4) = 8x + 6x -7-4 = 14x -11

Answer:

the answer for this one is 39.2f. me being a Canadian and knowing that 0c is 32 Celsius it had to be larger and putting 4 Celsius thru a converter gives you 39.2

Step-by-step explanation:

For this case we have the following variables:

x: represents time, in seconds at the start of the test.

y: represents the speed, in miles per hour.

We have then that:

x = 0 ---> y = 0

x = 12 ---> y = 0

Answer:

the electric car is not moving at 0 seconds and 12 seconds

I hope this helps!

the electric car is not moving at 0 seconds and 12 seconds

I hope this helps!

Answer:

☆ y=kx

Example: if we have x= 3 and y= 15

Find y?

y= kx

*We know that y= 15 and x= 3

So,

15=k(3)

15=3k

*divide 3 from both sides

K=5

y=5x

y=5(5)=25

☆▪☆▪☆▪☆▪☆

Hope it helps..

Have a great day!!

Answer:

cos(2π/35)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Pre-Calculus

Step-by-step explanation:

Step 1: Define

Identify

cos(π/5)cos(π/7) + sin(π/5)sin(π/7)

Step 2: Simplify

Answer:

(x, y) = (-1/2, 1/3)

Step-by-step explanation:

Given the simultaneous equation

x+y/ху=1. ...1

x-y/xy = 5 .... 2

From 1; x+y = xy ...3

From 2; x - y = 5xy ...4

Substituting 3 into 4

x - y = 5(x+y)

x - y = 5x + 5y

x - 5x = 5y + y

-4x = 6y

-2x = 3y

x = -3y/2 ... 4

Add 3 and 4

2x = 6xy

2 = 6y

y = 2/6

y = 1/3

x = -3(1/3)/2

x = -1/2

Hence (x, y) = (-1/2, 1/3)

Answer:

V = 125 cm³

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Geometry

Volume of a Cube Formula: V = a³

Step-by-step explanation:

Step 1: Define

Identify variables

a = 5 cm

Step 2: Find Volume

Answer:

125cm^3

Step-by-step explanation:

Volume of a cube = l^3

Where l = length of cube

The given length of the cube is 5cm

Hence Volume = 5^3 = 125cm^3

Answer: 0.662201

Step-by-step explanation:

Number of five thousand dollar bills in circulation = 1,765,000

Number of ten thousand dollar bills in circulation = 3,460,000

Total bills in circulation = 1,765,000 + 3,460,000 = 5225000

If one one bill is chosen at random, the probability that it is a ten thousand dollar bill will be:

= Number of ten thousand dollar bills in circulation / Total bills in circulation

= 3,460,000 / 5225000

= 0.662201

The probability that it is a ten thousand dollar bill is 0.662201.

Answer:

D. 12m^3n^5

Step-by-step explanation:

Answer:

12m³n⁵

Step-by-step explanation:

3 · 4 = 12

m² · m = m³

n³ · n² = n⁵

Therefore, 3m²n³ · 4mn² = 12m³m⁵

Answer:

x^2 - 10x + 24

Step-by-step explanation:

(x - 4)(x - 6)

x(x - 6) -4(x - 6)

x^2 -6x -4x + 24

x^2 - 10x + 24

Answer:

[tex] {x}^{2} - 10x + 24[/tex]

Step-by-step explanation:

[tex](x - 4)(x - 6) \\ = x(x - 6) - 4(x - 6) \\ = {x}^{2} - 6x - 4x + 24 \\ = {x}^{2} - 10x + 24 \\ [/tex]

Answer:

$4.7 (approx)

Step-by-step explanation:

Simple interest = (principle * time * rate) / 100

Answer:

1. acute

2. Right

3. maybe acute

4. obtuse

5. acute

6. obtuse

7. straight

8. obtuse

9. acute

10. obtuse

11. acute

12. acute

13. obtuse

14. obtuse

Answer: 251.2 inches.

Step-by-step explanation: You have to multiply 4*2*π*radius. So, simply multiply 4*2*3.14*10. It would come out as 251.2 inches.

Answer:

Step-by-step explanation:

The formula to figure this out is

[tex]C=66.99(1-.2)[/tex] where .2 is 1/5 in decimal form. What this means is that you may be saving 1/5 but you're still spending 4/5.

C = 66.99(.8) so

Cost = $53.59

Answer:

-4x+161

Step-by-step explanation:

why-

because it is correspondoing so that is the answer

Answer:

(a) [tex]\frac{1}{7}[/tex]

(b) [tex]\frac{4}{7}[/tex]

(c) [tex]\frac{5}{7}[/tex]

Step-by-step explanation:

Probability (P) of an event is the likelihood that the event will occur. It is given by;

P = number of favourable outcomes ÷ total number of events in the sample space.

Given letters of cards:

A B C D E F G H J

∴ Total number of events in sample space is actually the number of cards which is 7

If a card is picked at random;

(a) the probability P(F), that it is labelled F is given by;

P(F) = number of favourable outcomes ÷ total number of events in the sample space.

The number of favourable outcomes for picking an F = 1 since there is only one card labelled with F.

∴ P(F) = 1 ÷ 7

=> P(F) = [tex]\frac{1}{7}[/tex]

(b) the probability P(N), that it is labelled with a letter in her name JADE is given by;

P(N) = P(J) + P(A) + P(D) + P(E)

Where;

P(J) = Probability that it is labelled J

P(A) = Probability that it is labelled A

P(D) = Probability that it is labelled D

P(E) = Probability that it is labelled E

P(J) = [tex]\frac{1}{7}[/tex]

P(A) = [tex]\frac{1}{7}[/tex]

P(D) = [tex]\frac{1}{7}[/tex]

P(E) = [tex]\frac{1}{7}[/tex]

∴ P(N) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]

∴ P(N) = [tex]\frac{4}{7}[/tex]

(c) the probability P(S), that it is labelled with a letter that has at least one line of symmetry is;

P(S) = P(A) + P(B) + P(C) + P(D) + P(E) + P(H)

Where;

P(A) = Probability that it is labelled A

P(B) = Probability that it is labelled B

P(C) = Probability that it is labelled C

P(D) = Probability that it is labelled D

P(E) = Probability that it is labelled E

P(H) = Probability that it is labelled H

Cards with letters A, B, C, D, E and H are selected because these letters have at least one line of symmetry. A line of symmetry is a line that cuts an object into two identical halves. Letters A, B, C, D, E and H can each be cut into two identical halves.

P(A) = [tex]\frac{1}{7}[/tex]

P(B) = [tex]\frac{1}{7}[/tex]

P(C) = [tex]\frac{1}{7}[/tex]

P(D) = [tex]\frac{1}{7}[/tex]

P(E) = [tex]\frac{1}{7}[/tex]

P(H) = [tex]\frac{1}{7}[/tex]

∴ P(S) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]

∴ P(S) = [tex]\frac{5}{7}[/tex]

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

=> Factor.

When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a factor of the given expression.

[tex] \sf \: It's \: called \: a \: \boxed{\underline{\bf \: factor}}[/tex]

When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a [tex]\boxed{\underline{\bf \: factor}}[/tex]of the given expression.