[tex]\boxed{\sf a_n=\dfrac{a_{n-1}}{10}\times 4,n\gt 1}[/tex]
Lets verify
[tex]\\ \sf\longmapsto a_2=\dfrac{a_1}{10}\times 4[/tex]
[tex]\\ \sf\longmapsto a_2=\dfrac{500}{10}\times 4=50(4)=200[/tex]
And
[tex]\\ \sf\longmapsto a_3=\dfrac{a_2}{10}\times 4[/tex]
[tex]\\ \sf\longmapsto a_3=\dfrac{200}{10}\times 4=20(4)=80[/tex]
And
[tex]\\ \sf\longmapsto a_4=\dfrac{a_3}{10}\times 4[/tex]
[tex]\\ \sf\longmapsto a_4=\dfrac{80}{10}\times 4=8(4)=32[/tex]
Hence verified
Lets predict next term
[tex]\\ \sf\longmapsto a_5=\dfrac{a_4}{10}\times 4[/tex]
[tex]\\ \sf\longmapsto a_5=\dfrac{32}{10}\times 4=3.2\times 4=12.8[/tex]
Answer the question please
Plss tell me guy's plssssssssssssssssssssssssssssssssssssssssssssss
Answer:
According to my equation it's 20°
You withdraw $40 each month from your savings account. what integer represents the change in your balance after 4 months?
Answer:
The balance would be $160 from whatever it was before the 4 months.
Step-by-step explanation:
Since the bank balance is being added by 40 for each month for 4 months, 4 * 40 is just 4*4 with an extra zero on the end. so that would be $160.
So if the balance before was $40, then the new balance after 4 months would be $200.
If there's no money previously, then there is now $160 after 4 months.
If there's a value before the $40 for 4 months, let me know and I will explain and tell you what it is.
A cereal manufacturer has a tolerance of 0.75 oz for a box of cereal that is supposed to weigh 20 oz. Determine the compound inequality solution that describes the acceptable weights for a 20 oz box.
I hope it helps you
An compound inequality that describes the acceptable weights for a 20 oz box is 19.25 ≤ x ≤ 20.75.
What is an absolute value?The absolute value of a number is defined as its magnitude irrespective of the sign of the number. To determine the absolute value of a real number, we consider only the number and remove the sign. It can only be a non-negative value.
We are Given that, cereal manufacturer has a tolerance of 0.75 oz for a box of cereal that is supposed to weigh 20 oz.
Let the weight of cereal box be; w
Now, the inequality is
20-0.75 ≤ x ≤ 20+0.75
Add 20 on both sides of an inequality, we get
19.25 ≤ x ≤ 20.75
Here, 19.25 ≤ x ≤ 20.75
Therefore, an absolute value inequality to find the range of acceptable weights is 19.25 ≤ x ≤ 20.75.
To learn more about an absolute value visit:
brainly.com/question/1301718.
#SPJ2
Julie is arranging pictures in a photo album one time she arranges them into six on each page she rearrange them with eight on each page what is the least number of photos Julie could have put in her album
Answer:
Step-by-step explanation:
Solve for inequality:
n/-4 >= 7
Answer:
n ≤ − 28
Step-by-step explanation:
Multiply to remove the fraction, then set equal to
0 and solve.
If a=b+7 and b+7=9, then a=9
Answer:
a = 9
b = 2
Step-by-step explanation:
Given : a = 9
a = b + 7
9 = b + 7
b = 9 - 7 = 2
Help with this question. Will give brainliest.
Step-by-step explanation:
x = elsie ticket
[tex] \frac{2}{3} x + 10 = 21[/tex]
Answer:
No I am pretty sure it is the 4th answer my guy.
Step-by-step explanation:
2/3x-10=21
Jenny's aquarium holds 25 quarts of water. She buys a new one that holds 32 quarts.
How much additional water can the new aquarium hold?
Answer:
7 quarts
Step-by-step explanation:
you subtract the amount that the first aquarium can hold from the second amount
10 divide 6.0 please
Answer:
1.6667
Step-by-step explanation:
It took awhile to get this
What is 18/12 as a mixed number in simplest form
Answer: 1 1/2
You can write this as 1 & 1/2
The whole part is 1. The fractional part is 1/2
==========================================================
Explanation:
Let's say we had 18 cookies to hand out to 12 students.
How many cookies does each student get?
Using a calculator shows that 18/12 = 1.5 which means they get one whole cookie each
The leftovers is 18-12 = 6
Then notice how 6/12 = 1/2
So that's how the improper fraction 18/12 becomes the mixed number 1 & 1/2
So each student gets 1 full cookie, plus half a cookie.
------------------
Or we could do the problem like this
18/12 = (12+6)/12
18/12 = (12/12)+(6/12)
18/12 = 1 + (1/2)
18/12 = 1 & 1/2
(Please help, I don't understand) Use the distance formula to find the distance between each pair of points:
Step-by-step explanation:
Distance = √(x_2 - x_1)² + (y_2 - y_1)²
Distance = √[(-a) - a]² + (b - b)²
Distance = √[-2a]² + (0)²
Distance = √4a²
Distance = 2a
P, Q, V, and K are collinear with V between K and P, and Q between V and K. If VP = 14x + 4, PK = x + 630, VQ = 17x + 6, and KQ = 11x + 5, solve for VP.
If the points P, Q, V and K are collinear, they will follow the segment addition postulate.
Measure of segment VP will be 214 units.
It's given in the question,
P, Q, V and K are collinear.VP = 14x + 4PK = x + 630VQ = 17x + 6KQ = 11x + 5By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x = [tex]\frac{615}{41}[/tex]
x = 15
Therefore, measure of VP = (14x + 4)
= 14(15) + 4
= 214 units
Measure of segment VP will be 214 units.
Learn more,
https://brainly.com/question/628239
….."………….."……how do u do dis?
Answer:
x = -25
Step-by-step explanation:
[tex]3 - \frac{x}{5} = 8[/tex]
[tex]5(3 - \frac{x}{5} ) = 5 \times 8[/tex]
[tex]5 \times 3 - 5 \times \frac{x}{5} = 5 \times 8[/tex]
[tex]15 - 5 \times \frac{x}{5} = 40[/tex]
[tex]15 - x = 40[/tex]
[tex] - x = 40 - 15[/tex]
[tex] - x = 25[/tex]
[tex]x = - 25[/tex]
Answer:
x = - 25
Step-by-step explanation:
Given
3 - [tex]\frac{x}{5}[/tex] = 8 ( subtract 3 from both sides )
- [tex]\frac{x}{5}[/tex] = 5 ( multiply both sides by 5 to clear the fraction )
- x = 25 ( multiply both sides by - 1 )
x = - 25
Find the missing number so that the equation has no solutions.
x–10=
–
2x–15
Answer:
X=-5/3
Step-by-step explanation:
How do heck do u solve metric conversions?? lol
Answer:
You cant check your answer by yourself
if your procces is Right then obviously your answer will be correct
I hope you will understand
thank you
jay Nepal
(a)/(2a)+(4)/(3a^(2)) ayuda por favor
Answer:
3a^2+8/6a^2
Step-by-step explanation:
there ya go hope this helps
please helpppppp!!!!!!!!!
Answer:
64w^2
Step-by-step explanation:
Because 8w is in parentheses, you must apply the exponent to both the 8 and w.
So, it becomes (8*8)(x*x) which equals (64)(x^2).
Which then gives you your final answer, 64x^2.
WILL MARK BRAINIEST
Zach and Ginny are building model cars. Ginny's car is 2 more than 3 times the length of Zach's car. The sum of the lengths of both cars is 30 inches. Write an equation to determine the lengths of Zach's and Ginny's cars.
3x + 2 = 30
x + 2 + 3x = 30
2x + 3 = 30
x + 2x + 3 = 30
Answer:
x + 2 + 3x = 30
Step-by-step explanation:
Both lengths are unknown, but Ginny's car length is described in terms of Zach's car length, so we choose a variable for Zach's car length.
Let x = Zach's car length.
Zach's car length is x.
"Ginny's car is 2 more than 3 times the length of Zach's car."
Ginny's car length is 2 + 3x.
Add the lengths:
x + 2 + 3x
"The sum of the lengths of both cars is 30 inches."
x + 2 + 3x = 30
Answer: x + 2 + 3x = 30
Solve for x. x/3 +7 = 10
Answer:
[tex] \frac{x}{3} + 7 = 10 \\ \frac{x}{3} = 10 - 7 \\ \frac{x}{3 } = 3 \\ x = 3 \times 3 \\ x = 9 \\ thank \: you[/tex]
Answer:
x=9
Step-by-step explanation:
x/3 +7 = 10
Subtract 7 from each side
x/3 +7-7 = 10-7
x/3 = 3
Multiply each side by 3
x/3*3 = 3*3
x=9
plz help me plz and correctly!!!! only 3 questions plz!!! 100 points
Answer:
Step-by-step explanation:
6)b) Sin A - x Cos A = 0
Sin A = x Cos A
[tex]\dfrac{Sin \ A}{Cos \ A} = x[/tex]
[tex]\dfrac{1}{x}=\dfrac{1}{\dfrac{Sin \ A }{Cos \ A}}=1*\dfrac{Cos \ A}{Sin \ A}=\dfrac{Cos \ A}{Sin \ A}[/tex]
[tex]RHS = x +\dfrac{1}{x}\\\\\\[/tex]
[tex]= \dfrac{Sin \ A}{Cos \ A}+\dfrac{Cos \ A}{Sin \ A}\\\\\\=\dfrac{Sin \ A*Sin \ A}{Cos \ A*Sin \ A}+\dfrac{Cos \ A * Cos \ A}{Sin \ A* Cos \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Cos \ A*Sin \ A}+\dfrac{Cos^{2} \ A}{Cos \ A* Sin \ A}\\\\= \dfrac{Sin^{2} \ A+Cos^{2} \ A}{Cos \ A*Sin \ A}\\\\=\dfrac{1}{Cos \A*Sin \ A}\\\\= \dfrac{1}{Cos \ A}*\dfrac{1}{Sin \ A}\\\\=Sec \ A * Cosec \ A[/tex]
= LHS
7a) 1 - Sin A = 1/2
[tex]1 = \dfrac{1}{2}+ Sin \ A\\\\1-\dfrac{1}{2}=Sin \ A\\\\\dfrac{1}{2}=Sin \ A\\[/tex]
⇒ A = 30°
Sec² A = Sec² 30° = [tex](\frac{2}{\sqrt{3}})^{2}=\frac{2^{2}}{(\sqrt{3)^{2}}}=\frac{4}{3}[/tex]
[tex]tan^{2} \ A = tan^{2} 30 = (\dfrac{1}{\sqrt{3}})^{2} = \dfrac{1}{3}[/tex]
LHS = 6 Sec² A + 9 tan² A
[tex]= 6*\dfrac{4}{3}+9*\dfrac{1}{3}\\\\\\=2*4 + 3*1\\\\\\= 8 + 3\\\\= 11 = RHS[/tex]
When completing the sum 5.8×3.87 Dominica forgot to put the decimal point in her answer. She wrote 22446. What should she have written?
Point B is the midpoint of AC. AB=3x and AC=5x+21 . What is the value of AB?
First, let's write down what we know.
AB = 3x
AC = 5x+21
Since B is the midpoint, AB is half the length of AC. The sum of AB + AB is equal to the length of AC.
AB + AB = AC
Let's plug in our values.
3x + 3x = 5x + 21
Simplify the left side.
6x = 5x + 21
Subtract 5x from both sides.
x = 21
Now, let's plug in 21 for x in AB
AB = 3x = 3(21) = 63
Help me on this math questionnn
If $10,000 is invested at a rate of 3.4 percent for 5 years, how much money is in the account at the end of the term?
$340
$3,400
$10,000
$11,700
Answer:
D. $11,700
Step-by-step explanation:
a + (b-4) when a-24 and b-7
Answer:
a=24
b=7
now
24+(7-4)
24+3
27
so the answer is 27
Geometry helppp please
Answer:
17
Step-by-step explanation:
[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]
[tex]8^{2}[/tex] +[tex]15^{2}[/tex] =[tex]c^{2}[/tex]
64 + 225 = [tex]c^{2}[/tex]
289 = [tex]c^{2}[/tex]
[tex]\sqrt{289}[/tex] = [tex]\sqrt{c^{2} }[/tex]
17 = c
Simplify by combining like terms: -11 + 2(4x - 1) + 6 (BRAINLIEST)
Answer:
8x-7
Step-by-step explanation:
-11 + 8x - 2 + 6
8x-7 .........
Write the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) in slope-intercept form.
Answer:
[tex]y=-\frac{5}{2}x-24[/tex]
Step-by-step explanation:
[tex]2x-5y=-12\\5y=2x+12\\y=\frac{2}{5}x+\frac{12}{5}\\[/tex]
if two lines perpendicular,
[tex]m_{1} .m_{2}=-1\\ \frac{2}{5} .m_{2}=-1\\m_{2}=-\frac{5}{2}[/tex]
the line perpendicular to this line is
[tex]y=-\frac{5}{2}x+k[/tex] ; k ∈ R
the line passes through the point (10,-1)
so,
[tex]-1=-\frac{5}{2} (10)+k\\-1=-25+k\\k=-24[/tex]
∴the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1) is
[tex]y=-\frac{5}{2}x-24[/tex]
If 3x = y -5 and x = 4, then y =
Answer:
y = 17
Step-by-step explanation:
3x = y - 5, for x = 4
=> 3(4) = y - 5
=> 12 = y - 5
=> 12 + 5 = y
=> 17 = y