compute is an electronic devices
HELPP
-1-3(5m+8) ≥-85
i need help :D
Answer:
- 1 - 3(5m + 8) ≥ -85
-1 - 15m - 24 ≥ -85
-15m ≥ -85 + 1 + 24
-15m ≥ 25 - 85
-15m ≥ -60
(-1)(-15)m ≤ -60(-1)
15m ≤ 60
m ≤ 4
______are used to represent an unknown quantity in a mathematical expression.
Answer:
Variables are used to represent an unknown quantity in a mathematical expression.
Step-by-step explanation:
Variables are used to represent an unknown quantity in a mathematical expression.For example : x + 2 = 4, here x is the variable.We can denote variable by any alphabet i.e, a,b,c,d etc.What does y equal in the solution of the system of equations below? 5y-3x-4z=22 2z-2x=-6 2z+3x=-6
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Answer:
y = 2
Step-by-step explanation:
Subtracting the second equation from the third gives ...
(2z +3x) -(2z -2x) = (-6) -(-6)
5x = 0
x = 0
Using this in the third equation, we have ...
2z +0 = -6
z = -3
And substituting these values into the first equation, we have ...
5y -3(0) -4(-3) = 22
5y = 10 . . . . . subtract 12
y = 2
__
The solution to the system is (x, y, z) = (0, 2, -3).
remove bracket and simplify 6x-(3x+2)
Answer: 3x - 2
Step-by-step explanation:
First to solve this, we need to know some basic information such as:
1. (-) × (-) = +
2. (+) × (-) = -
3. (+) × (+) = +
Therefore, 6x-(3x+2)
= 6x - 3x - 2
= 3x - 2
The answer to the question after removing the bracket will be 3x - 2.
Solve the equation x^2+6x+1=0
Hello!
x² + 6x + 1 = 0 <=>
<=> x = -6±√6²-4×1×1/2×1 <=>
<=> x = -6±√36-4/2 <=>
<=> x = -6±√32/2 <=>
<=> x = -6±2²√2/2 <=>
<=> x = -6±4√2/2 <=>
<=> x = -6+4√2/2 <=>
and
<=> x = -6-4√2/2 <=>
<=> x = -3+2√2 <=>
and
<=> x = -3-2√2 <=>
x1 = -3-2√2 and x2 = -3+2√2
Good luck! :)
In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $42 and standard deviation of $2. Construct a confidence interval at a 98% confidence level.
Answer:
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 24 - 1 = 23
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 2.5
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.5\frac{2}{\sqrt{24}} = 1.02[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.
The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Olivia rides her scooter 3/4 mile in
1/3 hour. How fast, in miles per hour,
does she ride her scooter?
Answer:
2.25 miles per hr
Answer:
2.25 miles per hour
Step-by-step explanation:
speed = distance / time
speed = [tex]\frac{3}{4} / \frac{1}{3}[/tex] (take the reciprocal of [tex]\frac{1}{3}[/tex])
= [tex]\frac{3}{4} * 3[/tex]
= [tex]\frac{9}{4}[/tex] = 2.25 miles per hour
Which statements below represent the situation? Select three options.
Answer:
where is the statement
Step-by-step explanation:
its incomplete po
The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.
Answer:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 5x + 1[/tex]
Required
Complete the table (see attachment)
When x = -5
[tex]f(-5) = 5 * -5 + 1 = -24[/tex]
When x = -1
[tex]f(-1) = 5 * -1 + 1 = -4[/tex]
When x = 2
[tex]f(2) = 5 * 2 + 1 = 11[/tex]
When x = 3
[tex]f(3) = 5 * 3 + 1 = 16[/tex]
When x = 4
[tex]f(4) = 5 * 4 + 1 = 21[/tex]
So, the table is:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
1. S = 10 mm
V= S×S×S
=___×___×___
=____ mm3
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]V=1000\text{mm}^3[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
I am assuming by the infomation given that the figure is a cube.
⸻⸻⸻⸻
[tex]\boxed{\text{Finding the volume of the cube...}}\\\\S = 10mm; V= s^3\\--------------\\\rightarrow V = 10^3\\\\\rightarrow V = 10 * 10 * 10\\\\\rightarrow \boxed{V=1000\text{mm}^3}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
A case of 6 cost 7.5 what it the price per item
Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width.
Complete the equation that can be used to determine the dimensions of the monitor in terms of its width, w.
Answer:
w= 103.5 inches
Step-by-step explanation:
384=w+3w-30
414=4w
w=414/4=103.5 inches
Answer:
first drop box 384
second drop box 3
third drop boc 30
384 = 3 [tex]w^{2}[/tex] – 30 w
Step-by-step explanation:
Correct answer on Plato/Edmentum test
Read the following scenario, and then answer the question.
Juan assumes that the temperature of the hot tea cooling on his desk can be modeled with an exponential function like this one: T(t)=179(0.92)t. He bases his assumption on the following: The tea cools about 8% every minute. The tea's current temperature is around 179 degrees Fahrenheit.
Which explanation correctly addresses Juan's assumption?
He is incorrect. The tea will cool linearly since it cools at the same number of degrees every minute.
He is correct. The tea will cool exponentially since it cools at a percentage rate every minute.
He is incorrect. The tea will cool along the curve of a parabola since it cools at an increasing percentage rate every minute.
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Answer:
(b) He is correct. The tea will cool exponentially since it cools at a percentage rate every minute.
Step-by-step explanation:
Newton's Law of Cooling says the change in temperature is proportional to the temperature. This relation gives rise to an exponential function describing the temperature.
In this description, the temperature referred to is the difference between the temperature of the object and the temperature of the environment to/from which heat is being transferred.
Juan is only partially correct. The function is exponential, but the temperature that should be used in his equation is not the temperature of the tea, but the temperature difference between the tea and his desk.
__
The curve is not linear and not parabolic, excluding the other answer choices.
I am having trouble with this problem. If anyone could help that would be great.
Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^2+y^2=16, 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1. For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.
Answer:
Ok... I hope this is correct
Step-by-step explanation:
Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^(2)+y^(2)=16
Center: ( 0 , 0 )
Vertices: ( 4 , 0 ) , ( − 4 , 0 )
Foci: ( 4 √ 2 , 0 ) , ( − 4 √ 2 , 0 )
Eccentricity: √ 2
Focal Parameter: 2 √ 2
Asymptotes: y = x , y = − x
Then 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1.
Simplified
0 ≤ z ≤ 1 , x ^2 + y ^2 + z ^2 − 2 ^z + 1 = 16 , z ≥ 1
For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.
Vector:
csc ( x ) , x = π
cot ( 3 x ) , x = 2 π 3
cos ( x 2 ) , x = 2 π
Since
( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x ^2 ) is constant with respect to F , the derivative of ( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x 2 ) with respect to F is 0 .
Write the rule that describes the first transformation?
RED —> BLUE
Looking at Point A to A', the rectangle moves 5 places to the left which is the x value + 5 and it shifts 1 place down which would be the y value - 1
This gets written as:
(x+5, y-1)
Please answer!<333 xx
12. X= 6
14. B= -11
16. N= 15
Answer:
q12. [tex]x=6[/tex]
q14. [tex]b=-11[/tex]
q16. [tex]n=15[/tex]
Step-by-step explanation:
Q12.
[tex]-1=\frac{x}{-6}[/tex]
Flip the equation:
[tex]\frac{x}{-6} =-1[/tex]
Multiply both sides by 6/(-1)
[tex](\frac{6}{-1} )[/tex] × [tex](\frac{-1}{6}x )[/tex] = [tex](\frac{6}{-1} )[/tex] × [tex](-1)[/tex]
[tex]x=6[/tex]
Q14.
[tex]5b=-55[/tex]
[tex]b=\frac{-55}{5}[/tex]
[tex]b=-11[/tex]
Q16.
[tex]-3n=-45[/tex]
[tex]n=\frac{-45}{-3}[/tex]
[tex]n=15[/tex]
hope this helps.....
Given n(A) = 1300, n(A U B) = 2290, and n(A n B) = 360, find n(B).
Answer:
n(B) = 1350
Step-by-step explanation:
Using Venn sets, we have that:
[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]
Three values are given in the exercise.
The other is n(B), which we have to find. So
[tex]n(A \cup B) = n(A) + n(B) - n(A \cap B)[/tex]
[tex]2290 = 1300 + n(B) - 360[/tex]
[tex]940 + n(B) = 2290[/tex]
[tex]n(B) = 2290 - 940 = 1350[/tex]
So
n(B) = 1350
Which terms in the following expression are like terms?
x3 + 5x - 3x + 3y + 4 - 1
3x and 3y
x 3, 3x, and 3y
5x and 3x, and 4 and 1
x 3 and 3x, and 4 and 1
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Answer:
(c) 5x and 3x, and 4 and 1
Step-by-step explanation:
Like terms have the same variable(s) to the same power(s).
The terms of this expression are ...
x^3: variable x, power 35x: variable x, power 1-3x: variable x, power 13y: variable y, power 14: no variable-1: no variableThe like terms are {5x, -3x}, which have the x-variable to the first power, and {4, -1}, which have no variable.
Can I get the answer for those
Answer:
1) 5.64
2) 17.321
1) [tex]\frac{21}{28}[/tex]
2) [tex]\frac{16}{34}[/tex]
3) [tex]\frac{28}{35}[/tex]
4) [tex]\frac{32}{24}[/tex]
Step-by-step explanation:
SOH - CAH - TOA
Sin = [tex]\frac{O}{H}[/tex] Cos = [tex]\frac{A}{H}[/tex] Tan = [tex]\frac{O}{A}[/tex]
O = opposite, A = adjacent, H = hypotenuse
First two, use Pythagorean Theorem
If you want to calculate the angle on the last 4, use inverse of function and put in the ratio.
For example :
1) Tan Z = [tex]\frac{21}{28}[/tex]
[tex]Tan^{-1}[/tex] ( [tex]\frac{21}{28}[/tex])
Z = 36.9°
A student has test scores of 75 and 82respectively. What is the student’s average score for a third test
Answer:
78.5 (I think 90% sure)
Step-by-step explanation:
sum of both scores
75+82 = 157
average for a third test
157÷2=78.5
1^2 +2^2+••••+n^2=1/6n(n+1)(2n+1)
using maths induction
Hello,
[tex]if\ n=1\ then\ 1^2=1\ and\ \dfrac{1}{6}*1*2*3=1:\ true\ for\ n=1\\[/tex]
We suppose the property true for n:
1²+2²+...+n²=n(n+1)(2n+1) / 6
and we are going to demonstrate that the property is true for n+1:
1²+2²+..+(n+1)²=(n+1)*(n+2)*(2n+3)/6
[tex]1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\[/tex]
Brian, the gorilla, was planning a party for his zoo friends. He sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer. Jamie said there were 40 legs and Nancy said there were 14 heads. How many penguins and reindeer were in the exhibit?
Answer:
There are 8 penguins and 6 reindeers.
Step-by-step explanation:
Since Brian, the gorilla, was planning a party for his zoo friends, and he sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer, and Jamie said there were 40 legs and Nancy said there were 14 heads To determine how many penguins and reindeer were in the exhibit, the following calculation must be performed:
Penguins: 1 head and 2 legs
Reindeers: 1 head and 4 legs
40 - (14 x 2) = X
40 - 28 = X
12 = X
12/2 = 6
14 - 6 = 8
8 x 2 + 6 x 4 = X
16 + 24 = X
40 = X
Therefore, there are 8 penguins and 6 reindeers.
09:30 am - 4:30 pm minus 30 minutes?
How many hours is that ?
0.9.30 am to 4.30 p.m. is 7 hours.
If we minus 30 minutes from it then it is 6 hours 30 minutes.
Round 0.485 to the nearest hundredth
Decimals start at tenths, then hundredths, then thousandths, and so on. When we round, we look at the place value that is one smaller than the one we want to round to.
So, let's take a look at the thousandths place in 0.485. The value in the thousandths place is 5. When rounding, if the value is 5 or over we round up and if the value is 4 or lower we round down. Since the value in the thousandths place is 5, we will round the hundredths place up one.
0.485 rounded to the nearest hundredth is 0.49
Hope this helps!
Answer:
0.49
Step-by-step explanation:
[tex]0<x<5=[/tex] Round down
[tex]x\geq5=[/tex] Round up
In this case, it's a round up, so the answer would be...
0.49
Hope this helped! Please mark brainliest!
A teacher has a 2-gallon (52 cup) container of juice. She gives each student z cup of juice. Which equation represents the amount of juice that remains, y, after x students are served?
Answer:
[tex]y = 32 - \frac{1}{2}x[/tex]
Step-by-step explanation:
Given
[tex]Cups = 32[/tex] ---- not 52
[tex]Students = x[/tex]
[tex]Remainder = y[/tex]
[tex]Each = \frac{1}{2}[/tex] --- not z
Required
The equation for y
The remainder y is calculated as:
[tex]y = Cups - Students * Each\\[/tex]
[tex]y = 32 - \frac{1}{2}x[/tex]
A simple random sample of students could be achieved by stopping every other student who enters the library.
a. True
b. False
if my child had 115 of 149 questions right what percentage is the grade
Answer:
77.18%
Step-by-step explanation:
115:149*100 =
(115*100):149 =
11500:149 = 77.18
જ્યારે જહાંગીરની ઉંમર 18 વર્ષ થશે ત્યારે અકબરની ઉંમર 50 વર્ષ થર્શ.
જ્યારે અકબરની ઉંમર જહાંગીરની ઉંમર કરતા 5 ઘણી હશે ત્યારે
અકબરની ઉમર કેટલી હશે?
A) 36
B) 40
C) 44
D) 48
Answer:
C: 44
Step-by-step explanation:
The difference between seven times a number and 9 is equal to five times
the sum of the number and 2. Find the number. Hint: There will be
parenthesis in your equation.
Answer:
The number is 9.5
Step-by-step explanation:
Look at the picture above, it explains everything
A scientist claims that 4% of viruses are airborne. If the scientist is accurate, what is the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%
Answer:
The probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427
Step-by-step explanation:
We are given that
[tex]\mu_{\hat{p}}=p=4%=0.04[/tex]
n=662
We have to find the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%.
q=1-p=1-0.04=0.96
[tex]\sigma_{\hat{p}}=\sqrt{p(1-p)/n}[/tex]
[tex]\sigma_{\hat{p}}=\sqrt{\frac{0.04(1-0.04)}{662}}[/tex]
[tex]\sigma_{\hat{p}}=0.0076[/tex]
Now,
[tex]P(\hat{p}>0.06)=1-P(\hat{p}<0.06)[/tex]
[tex]=1-P(\frac{\hat{p}-\mu_{\hat{p}}}{\sigma_{\hat{p}}}<\frac{0.06-0.04}{0.0076})[/tex]
[tex]=1-P(Z<2.63)[/tex]
[tex]=1-0.99573[/tex]
[tex]P(\hat{p}>0.06)=0.00427[/tex]
Hence, the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427
