Answer:
The limiting reactant is CrCl3
Explanation:
In a reaction, the limiting reactant is that reactant which is present in a quantity that is less than the quantity required.
The amount of product formed depends on the concentration of the limiting reactant.
The excess reactant still remains even after the reaction is completed.
Since the purple product still had some white spots, then KCl was definitely in excess.
If that is the case, then CrCl3 is the limiting reactant.
The drugs Prilosec and Nexium both contain the same active ingredient. Nexium contains a single enantiomer, but Prilosec is a racemic mixture. Which of the following is probably true regarding 20 mg doses of the two different drugs?
a. both drugs will be equally effective
b. both drugs can be prepared using the same synthetic procedure
c. Nexium will be more effective than Prilosec
d. Prilosec will be more effective than Nexium
Answer:
both drugs will be equally effective
Explanation:
A racemic mixture is a substance that contains a 50/50 mixture of the (+) and (-) enantiomers of an optically active compound.
It is important to note that even if a drug occurs as a racemic mixture, only the biologically active enantiomer will interact with the substrate on which the drug acts. The other enantiomer present is just irrelevant. Similarly, its presence does not affect the biological activity of the active enantiomer.
Hence, both Prilosec and Nexium are both equally effective.
Express as ordinary numbers.
3 x 10^0 =
Answer:
the answer is 3
Explanation:
hope this works
The sp of strontium carbonate, SrCO3, is 5.60×10−10 . Calculate the solubility of this compound in g/L.
Answer:
3.50 × 10⁻³ g/L
Explanation:
Step 1: Make an ICE chart for the solution of SrCO₃
"S" represents the molar solubility.
SrCO₃(s) ⇄ Sr²⁺(aq) + CO₃²⁻(aq)
I 0 0
C +S +S
E S S
The solubility product constant (Ksp) is:
Ksp = [Sr²⁺] [CO₃²⁻] = S²
S = √Ksp = √5.60 × 10⁻¹⁰ = 2.37 × 10⁻⁵ M
Step 2: Convert "S" to g/L
The molar mass of SrCO₃ is 147.63 g/mol.
2.37 × 10⁻⁵ mol/L × 147.63 g/mol = 3.50 × 10⁻³ g/L
To what Celsius temperature does 750. mL of gas originally at −12°C need to be heated to bring the volume to 2.10 L?
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Calculate the molarity of a potassium hydroxide solution if 25.0 ml of this solution was completely neutralized by 23.3 ml of 0.506 M sulfuric acid.
Answer: 0.943 M of potassium hydroxide solution is required.
Explanation:
A neutralization reaction is defined as the reaction in which an acid reacts with a base to form a salt and water molecule.
To calculate the molarity of potassium hydroxide, the equation used is:
[tex]n_1M_1V_1=n_2M_2V_2[/tex] ........(1)
where,
[tex]n_1, M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid that is [tex]H_2SO_4[/tex]
[tex]n_2, M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of the base that is KOH
We are given:
[tex]n_1=2\\M_1=0.506M\\V_1=23.3mL\\n_2=1\\M_2=?M\\V_2=25.0mL[/tex]
Putting values in equation 1, we get:
[tex]2\times 0.506\times 23.3=1\times M_2\times 25.0\\\\M_2=\frac{2\times 0.506\times 23.3}{1\times 25.0}\\\\M_2=0.943M[/tex]
Hence, 0.943 M of potassium hydroxide solution is required.
What type of reaction is the following
chlorine +
potassium nitride
- nitrogen
+
potassium chloride
Explanation:
Answer
Open in answr app
Correct option is
A
Precipitation reaction
B
Double displacement reaction
Balanced equation for the reaction is:
KCl(s)+AgNO3(aq)→AgCl(s)+KNO3(aq)
It is a double displacement reaction as both reactants exchange ions to form new products. Also, it is a precipitation reaction as white precipitates of silver chloride(AgCl) are formed.
Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN
Answer:
CH3CH2CH3
Explanation:
Dipole moment is the measure of the polarity of a chemical bond. It is the extent of charge separation in a molecule.
Dipole moment is the product of the magnitude of charge and the distance separating the charges from each other.
The molecule having the lowest dipole moment among the options is the molecule that has the least polarity. The least polar molecule among the options is CH3CH2CH3, it has no polar bonds in its structure.
We have that for the Question "Identify the compound with the lowest dipole moment. Identify the compound with the lowest dipole moment. CH3CH2CH3 CH3OCH3 CH3CHO CH3OH CH3CN "
it can be said that
[tex]CH_3CH_2CH_3 have the lowest dipole moment[/tex]From the question we are given
CH3CH2CH3
CH3OCH3
CH3CHO
CH3OH
CH3CN
Generally alkanes have the lowest dipole moment, they have C-H bond which are non polar.
Therefore,
[tex]CH_3CH_2CH_3[/tex] have the lowest dipole moment
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What is the heat of a reaction, in joules, with a total reaction mixture volume of 61.2 mL if the reaction causes a temperature change of 4.6 oC in a calorimeter
Answer:
1178J is the heat of the reaction
Explanation:
Assume that the reaction mixture has a density of 1.00 g/mL and a specific heat of 4.184 J/g-oC. The calorimeter has a heat capacity of 10.0 J/oC
The heat of a reaction follows the equation:
Q = m*S*ΔT
Where Q is the heat of the reaction,
m is the mass:
61.2mL * (1.00g/mL) = 61.2g
S is specific heat = 4.184J/g°C
ΔT = 4.6°C
Replacing:
Q = 61.2g*4.184J/g°C*4.6°C
Q = 1178J is the heat of the reaction
CaCl2 + Na2C2O4 ⇒ CaC2O4 + NaCl
a. Write a balance equation.
b. Find the molar mass for CaCl2.
c. Find the molar mass of CaC2O4.
d. How many grams of CaC2O4 is produced from 30.0 g of CaCl2.
Please show work
Answer:
everything can be found in the picture
Why is iodine always Used in a solution containing excess I2
Answer:
If a standard iodine solution is used as a titrant for an oxidizable analyte, the technique is iodimetry. If an excess of iodide is used to reduce a chemical species while simultaneously forming iodine.
Iodine always used in a solution excess KI is given to aid in the solubilization of free iodine, which would be insoluble in clean water during normal circumstances.
What is Iodine?
Iodine is a kind of element which are mainly used in iodometry titration. It can be represented by I.
What is solution?A solution would be a homogenous mixture of two components, usually a solute as well as a solvent.
Iodimetry would be a technique that uses a standard iodine solution as a titrant for such an oxidizable analyte. When an excessive amount of iodide is used to decrease a chemical while somehow producing iodine.
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If the n quantum number of an atomic orbital is 4, what are the possible values of 1?
If the 1 quantum number is 3, what are possible values of m1?
Answer:
1,2,3
Explanation:
using values of l is/are (n-1)
Name the parts of an electromagnet
Answer:
The iron core, copper wire, and an electricity source.
Explanation: Me
25.0 mL of nitrous acid (HNO2) is titrated with a 1.235 M solution of KOH. The equivalence point (stoichiometric point) is observed after 9.26 mL of base is added. What is the original concentration of the acid
Answer:
0.456 M
Explanation:
Step 1: Write the balanced neutralization equation
HNO₂ + KOH ⇒ KNO₂ + H₂O
Step 2: Calculate the reacting moles of KOH
9.26 mL of 1.235 M KOH react.
0.00926 L × 1.235 mol/L = 0.0114 mol
Step 3: Calculate the reacting moles of HNO₂
The molar ratio of HNO₂ to KOH is 1:1. The reacting moles of HNO₂ are 1/1 × 0.0114 mol = 0.0114 mol.
Step 4: Calculate the initial concentration of HNO₂
0.0114 moles of HNO₂ are in 25.0 mL of solution.
[HNO₂] = 0.0114 mol / 0.0250 L = 0.456 M
ose you has aniline as your unknown. What kind of solid derivative would be suitable to synthesize for aniline
Answer:
Amides are suitable to synthesize aniline
Explanation:
Amide are basically used to synthesize aniline.
The chemical formula of Aniline is C6H5NH2 while that of Amide is RCONH2
Amide are solids that can be easily converted to amines.
A 0.288 g sample of an unknown monoprotic acid is dissolved in water and titrated with a 0.115 M NaOH solution. After the addition of 17.84 mL of base, a pH of 4.92 is recorded. The equivalence point is reached when a total of 33.83 mL of NaOH is added. What is the molar mass of the acid
Answer:
74.0 g/mol
Explanation:
Step 1: Write the generic neutralization reaction
HA + NaOH ⇒ NaA + H₂O
Step 2: Calculate the reacting moles of NaOH
At the equivalence point, 33.83 mL of 0.115 M NaOH react.
0.03383 L × 0.115 mol/L = 3.89 × 10⁻³ mol
Step 3: Calculate the moles of HA that completely react with 3.89 × 10⁻³ moles of NaOH
The molar ratio of HA to NaOH is 1:1. The reacting moles of HA is 1/1 × 3.89 × 10⁻³ mol = 3.89 × 10⁻³ mol.
Step 4: Calculate the molar mass of the acid
3.89 × 10⁻³ moles of HA have a mass of 0.288 g.
M = 0.288 g / 3.89 × 10⁻³ mol = 74.0 g/mol
Significant number of
A) 2348
B) 7.0001
C) 0.0023
D)24,500
E) 0.1060
Answer:
significant number of what
What is the pH of a sodium hydroxide solution that has an OH- concentration of 1.5 × 10^-10?
Explanation: hi go to hell
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction
The question is incomplete, the complete question is;
Decide whether a chemical reaction happens in either of the following situations. If a reaction does happen, write the chemical equation for it. Be sure your chemical equation is balanced and has physical state symbols. situation chemical reaction? chemical equation A strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution. yes no A strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution.
Answer:
No
Yes
Explanation:
A single replacement reaction occurs when a metal that is higher in the electrochemical series is placed in a solution of the salt of a metal which is lower than it in the electrochemical series.
For instance, when a strip of solid iron metal is put into a beaker of 0.044M Pb(NO3)2 solution, a reaction occurs as follows;
Fe(s) + Pb(NO3)2(aq) ---------> Fe(NO3)2(aq) + Pb(s)
However, when a strip of solid lead metal is put into a beaker of 0.043M Fe(NO3)2 solution no reaction occurs because lead is lower than iron in the electrochemical series hence it can not displace iron from an aqueous solution of its salt.
What causes heat energy when you rub two objects against each other? (2 points)
Group of answer choices
The air around the objects
The flow of heat from one object to the other
The friction between the two objects
The pull of gravity on the two objects
C2H6O2 is infinitely miscible (soluble) in water. Ethylene glycol is a nonelectrolyte that is used as antifreeze. What is the lowest possible melting point for engine coolant that is 27.1 % (by mass) ethylene glycol
Answer:
-11.13 Degree Celsius
Explanation:
Here
Kf for H20 is 1.86 C/m
Mass of ethylene glycol = 27.1/100 * 100 = 27.1 grams
Number of moles of ethylene in 30 grams of ethylene = 27.1 g/molar mass of ethylene glycol = 27.1/62.07 = 0.4366 mol
Mass of water = 100 – 27.1 = 72.9 grams
Molality = Moles/Mass of water in Kg = 0.4366 /0.0729 = 5.989 m
Melting Point Depression = Kf * Molality = 1.86 *5.989 = 11.13 deg C
Melting point of solution = Melting point of water - Melting Point Depression
= 0 – 11.13 = -11.13 Degree Celsius
if a cold piece of metal is added to hot water, the water will
Answer:
Over time the metal will cool and the water will heat up. Eventually the two objects will have the same temperature
Explanation:
31. Adding an additional oxygen atom to 02 creates....
ozone
oxygen
methane
CFC
PLEASE HELP
Answer:
a
Explanation:
If you have 9.06 x 10^24 molecules of NaNO3, how many grams do you have of NaNO3
Answer:
Explanation:
1 mol of anything is 6.02 * 10^23 (in this case molecules)
x mol has 9.06 * 10^24 molecules of NaNO3
x * 6.02 * 10^23 = 9.06 * 10^24 * 1 Divide by 6.02 * 10^23
x = 9.06 * 10^24/6.02 * 10^23
x = 1.5 * 10
x = 15 mols of NaNO3
1 mol of NaNO3
Na = 23
N = 14
O3 = 48
Total = 85
1 mol of NaNO3 = 85 grams
15 mols = x Cross Multiply
x = 15 * 85
x = 1275 grams
Note: these numbers are approximate but they are very close. You have to use your own values from your periodic table to find the mass of NaNO3. Your answer will be very close to 85.
Which two terms represent major categories of compounds?
A
ionic and nuclear
B.
ionic and molecular
C.
empirical and nuclear
D.
empirical and molecular
Answer: B- ionic and molecular
Explanation:
The two terms represent major categories of compounds are ionic and molecular. The correct option is b.
What are molecular and ionic compounds?Molecular compounds are usually composed of two or more nonmetal elements. Molecular compounds are named with the first element first and then the second element by using the stem of the element name plus the suffix - ide. Numerical prefixes are used to specify the number of atoms in a molecule.
Molecular compounds are chemical compounds that take the form of discrete molecules. Examples include such familiar substances as water (H2O) and carbon dioxide (CO2). Ionic compounds are compounds made up of ions. These ions are atoms that gain or lose electrons, giving them a net positive or negative charge. Metals tend to lose electrons, so they become cations and have a net positive charge. Nonmetals tend to gain electrons, forming anions that have a net negative charge.
The most common and most popular example of ionic bonds is the combination of these two elements which produces sodium chloride, commonly known as table salt.
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15. Triglycerides, waxes, and steroids are all ___ lipids because they contain only carbon, hydrogen, and oxygen
A. simple
B. methyl esters
C. complex
D. long-chain compounds
Answer:
A. simple
Explanation:
While studying abroad in France, you offer to bake your grandmother's famous cookies for other students in your program.
have a recipe which calls for 3.95 lb of flour, but, of course, in France you will need to purchase flour in kilograms. How m
kilograms of flour does the recipe call for?
3.95 lb =
Answer:
The mass of the flour required to prepare the cookies is 1.8 kg.
Explanation:
The flour required to prepare the cookies is 3.95 lb.
1 lb = 0.454 kg
So, 3.95 lb = 3.95 x 0.454 kg = 1.8 kg
So, the mass of the flour required to prepare the cookies is 1.8 kg.
A 15.0 mL urine from a dehydrated patient has a density of 1.019g/mL. What is the mass of the sample, reported in mg?
Answer:
Mass of sample in mg = 15,285 mg
Explanation:
Given:
Volume of urine sample = 15 ml
Density of sample = 1.019 g/ml
FInd:
Mass of sample in mg
Computation:
Mass = density x volume
Mass of sample in mg = Volume of urine sample x Density of sample
Mass of sample in mg = 1.019 x 15
Mass of sample in mg = 15.285 gram
Mass of sample in mg = 15.285 x 1,000
Mass of sample in mg = 15,285 mg
1. Complete the following chart for the following atoms:
Element
Mass
number
Number of
electrons
Number of
neutrons
Atomic
Number
(number of
protons)
Potassium
16
56
26
What is the atomic symbol (the nuclide) for the isotope with 15 protons and 16
neutrons? Your answer must be in the form shown:
AX
You must show the correct numbers for A and Z
and have the correct symbol (Z). (3 points)
Explanation:
If there are 15 protons, 15 nuclear particles of unit positive charge, then
Z
=
15
. Now
Z
≡
the atomic number
, and you look at your copy of the Periodic Table, and you find that for
Z
=
15
, the element phosphorus is specified.
But we are not finished. Along with the 15 defining protons, there are also 16 neutrally charged, massive nuclear particles, 16 neutrons, and the protons and neutrons together determine the atomic mass. The isotope is thus
31
P
, which is almost 100% abundant, and an important nucleus for
NMR spectroscopy.
What is the
of a 750 milliliters solution containing 54.0 grams of KBr?
Answer:
0.605 M
Explanation:
What is the molarity of a 750 milliliters solution containing 54.0 grams of KBr?
Step 1: Given data
Mass of KBr (solute): 54.0 gVolume of solution: 750 mL (0.750 L)Step 2: Calculate the moles corresponding to 54.0 g of KBr
The molar mass of KBr is 119.00 g/mol.
54.0 g × 1 mol/119.00 g = 0.454 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.454 mol / 0.750 L = 0.605 M
Cesium-137 is part of the nuclear waste produced by uranium-235 fission. The half-life of cesium-137 is 30.2 years. How much time is required for the activity of a sample of cesium-137 to fall to 9.32 percent of its original value
Answer:
t(9.32% remaining) = 203 yrs (3 sig. figs.)
Explanation:
All radioactive decay follows a 1st order decay profile. This is defined by the expression ...
A =A₀e^-k·t
A = final activity = 9.32%
A₀ = initial activity = 100%
e = base of natural logs
k = rate constant = 0.693/t(1/2) = (0.693/30.2) yrs⁻¹ = 0.023 yrs⁻¹
t = time of decay = ln(A/A₀)/-k = ln(9.32%/100%)/-0.023 yrs⁻¹
= 203.286637 yrs (calc. ans.)
≅ 203 yrs (3 sig. figs.)
