Consider the initial value problem
y' + 6y = {0 if 0 < or equal to t < or equal to 2
12 if 2 < or equal to t < or equal to 6
0 if 6 < or equal to t < or equal to infinity}
a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below).
b. Solve your equation for Y(s).
c. Take the inverse Laplace transform of both sides of the previous equation to solve for y(t).

Answers

Answer 1

y' + 6y = f(t)

where

[tex]f(t)=\begin{cases}0&\text{if }0\le t\le2\\12&\text{if }2<t\le6\\0&\text{if }6<t<\infty\end{cases}[/tex]

You can write f(t) in terms of the unit step (i.e. Heaviside theta) function u(t), which is defined as

[tex]u(t)=\begin{cases}0&\text{if }t<0\\1&\text{if }t\ge0\end{cases}[/tex]

Then the DE is written as

y' + 6y = 12 u (t - 2) - 12 u (t - 6)

(a) Take the Laplace transform of both sides:

LT[y' + 6y] = LT[12 u (t - 2) - 12 u (t - 6)]

s Y - y (0) + 6Y = 12 (exp(-2s) - exp(-6s))/s

(b) Solve for Y :

(s + 6) Y = 12 (exp(-2s) - exp(-6s))/s + y (0)

Y = 12 (exp(-2s) - exp(-6s))/(s (s + 6)) + y (0)/(s + 6)

(c) Take the inverse transform:

LT⁻¹ [Y] = LT⁻¹[12 (exp(-2s) - exp(-6s))/(s (s + 6)) + y (0)/(s + 6)]

y = 12 LT⁻¹ [(exp(-2s) - exp(-6s))/(s (s + 6))] + y (0) LT⁻¹ [1/(s + 6)]

y = 12 u (t - 2) LT⁻¹ [1/(s (s + 6))] - 12 u (t - 6) LT⁻¹ [1/(s (s + 6))] + y (0) exp(-6t )

For the remaining inverse transform, break up into partial fractions:

1/(s (s + 6)) = a/s + b/(s + 6)

1 = a (s + 6) + bs

1 = (a + b) s + 6a

==>   6a = 1, a + b = 0   ==>   a = 1/6, b = -1/6

y = 2 u (t - 2) LT⁻¹ [1/s - 1/(s + 6)] - 2 u (t - 6) LT⁻¹ [1/s - 1/(s + 6)] + y (0) exp(-6t )

y = 2 u (t - 2) (1 - exp(-6t )) - 2 u (t - 6) (1 - exp(-6t )) + y (0) exp(-6t )


Related Questions

lim(x-0) (sinx-1/x-1)

Answers

lim ( sinx-1)/(x-1)

x=>0

apply x=0

(sin(0)-1)/(0-1)

(0-1)/(-1)

=1

I) Find the volume in terms of pie

ii) curved surface area in terms of pie

iii) capacity in litres (correct to nearest litre)

Answers

Answer:

i) pi×4500 cm³

ii) pi×600 cm²

iii) 14 liters

Step-by-step explanation:

in general : the diameter is 30 cm, the radius is half of that (15 cm)

i)

the volume of a cylinder is base area times height.

Vc = pi×r²×h = pi×15²×20 = pi×225×20 = pi×4500 cm³

ii)

similar to volume, the side "mantle" area of the cylinder is the circumference of the base area times height.

surface area of the cylinder mantle is

Scm = 2×pi×r×h = 2×pi×15×20 = pi×30×20 = pi×600 cm²

iii)

for this we need now to do the multiplication with pi and then convert the cm³ to liters.

1 liter = a cube of 10 cm side length = 10×10×10 = 1000 cm³

pi×4500 = 14137.17 cm³ = 14.13717 liters or rounded 14 liters

Please help on 25 it’s confusing me I need the correct answer

Answers

Answer:

X * 0.8 = $64

x = $80

Step-by-step explanation:

Answer:

$80 (D)

Step-by-step explanation:

If Richard is getting a discount and his final price is $64 that means the answer must be above 64. That eliminates A, B, and C.

Use the formula: 20% of x = $64 and substitute the other two options. 20 percent of 84 is 16.8. 84-16.8=67.2 (not the correct answer). 20 percent of 80 is 16. 80-16=64(The Correct Answer).The answer must be $80 (D)    

The length of a rectangle is four more than three times the width. If the perimeter of this rectangle is at least 70 square centimeters. Write an inequality that can be solved to find the width of the rectangle

Answers

Answer:

Step-by-step explanation:

Let L represent the length of the triangle.

Let W represent the width of the triangle.

The length of a rectangle is four more than three times the width. This means that

L = 3W + 4

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

If the perimeter of this rectangle is at least 70 square centimeters, an inequality that can be solved to find the width of the rectangle is

2(L + W) ≥ 70

L + W ≥ 70/2

L + W ≥ 35

Answer:

6w +8 ≥70

Step-by-step explanation:

Let w be the width

The length is then 3w+4 ("the length is 4 more than 3 times the width")

Since a rectangle has opposite sides equal, the perimeter would be 2(l+w) or 2(w+3w+4) which would be 6w +8.  If the perimeter is at least 70, that is, 70 or more, the inequality would be

  6w + 8 ≥ 70.  

The units, however, would not be SQUARE centimeters, just centimeters.  If the question were asking for area, the units would be square units, but since perimeter is a linear measurement,  the units would have to be linear.

help asap pleaseeee asap

Answers

-63/7 = -9
The 3rd answer is correct

Please help!!!!! Nowwww

Answers

Answer:

It has 1 term and a degree of 4.

Step-by-step explanation:

3j⁴k-2jk³+jk³-2j⁴k+jk³

= 3j⁴k-2j⁴k-2jk³+jk³+jk³

= j⁴k

So, in this expression, there is 1 term, and it has a degree of 4.

if f(x)=3x²-7 and f(x+n)=3x²+24x+41, what is the value of n?

Answers

Answer:

n=4

Step-by-step explanation:

f(x+n)=3(x+n)^2-7=3x^2+24x+41

3x^2+3n^2+6xn-7=3x^2+24x+41

Comparing and we will get, n=4

Matematykakdbebox
Jaggbn

Answers

Answer:

theres no question....

Step-by-step explanation:

???

A variety of trigonometric functions are shown in the answer choices below.


Which trigonometric function has an inverse over the domain x2≤x≤3x2


A-f(x)=cos(x−1/2)+3/2

B-f(x)=cos(x+π/2)

C-f(x)=sin(x−1/2)+3/2

D-f(x)=sin(x+π/2)

Answers

Not 100 hundred percent sure but I believe the answer is c

Car drove 2hours at a speed of 100km per hour & 3 hour at a speed of 50 km per hour . What was the average speed of the car during the trip?

Answers

Answer:

200 kilometers and 150 kilometers

3/8n+5(n-6)=1 7/8n-2

Answers

Answer:

n = 112/13 = 8.615

Step-by-step explanation:

(3/8) n + 5n - 30 = (17/8)n - 2

(3/8)n +5n - (17/8)n = 30-2

(13/4)n = 28

n = 28 * 4/13

n = 112/13

n = 8.615

Find the value of x. Round to the nearest tenth.

Answers

Answer:

1.6 ft

Step-by-step explanation:

If you use the Pythagorean Theorem to solve for x, you get:

[tex]x=\sqrt{2.1^2-1.4^2}[/tex]

[tex]x=\sqrt{2.45} = 1.56524758425[/tex]

Rounded to the nearest tenth, the answer is 1.6

7x to the power of 2 is a what is it
a) monomial
b) binomial
c) Trinomial​

Answers

You can use the prefixes to figure this out:
Mono: one
Bi: two
Tri: three

So, because there is only one term, it is a monomial.

Two trains are 500 miles apart when they first start moving towards each other. If in two hours the distance between them is 300 miles and one train goes 20 miles faster than another, find the speed of the faster train. (Note: there are two possible solutions. Could you please find both?)

Answers

Answer:

Step-by-step explanation:

They travel 500 - 300 = 200 miles in 2 hours so their combined speed is

100 mph.

If their respective speed are x and y mph then we have the system

x + y = 100

x - y = 20

Adding the 2 equations

2x = 120

x = 60

and y = 40.

The other solution is that y = 60 mph and x = 40 mph.

Every high school senior takes the SAT at a school in St. Louis. The high school guidance director at this school collects data on each graduating senior’s GPA and their corresponding SAT test score. The guidance director is conducting a _________ in this experimental design.

A. sample survey
B. census
C. sample poll
D. random sample

Answers

Voće Eu tudo bem yea Iliana buns iOS build. Lbvac la vaca leche 457 sample poll

The guidance director is conducting a sample poll in this experimental design.

What is sample?

Sample is a part of population. It does not comprises whole population. It is representatitive of whole population.

How to fill blank?

We are required to fill the blank with appropriate term among the options.

The correct option is sample poll because the guidance director collects data in his school only.

Census collects the whole population of the country.

Sample poll means collecting data from small population.

Random sample means collecting data from a part of popultion without identifying any variable.

Hence we found that he was doing sample poll.

Learn more about sample at https://brainly.com/question/24466382

#SPJ2

Let a submarine be at a constant depth of 5 km. It is headed in the direction of a lighthouse. If the distance between the submarine and the base of the lighthouse is decreasing at a rate of 24 km/h when the sub is 13 km away from the base, then what is the speed of the submarine

Answers

Answer:

24 km/h

Step-by-step explanation:

Given:

Constant speed of submarine = 24 km/h

Depth under sea = 5 km

Distance of submarine from lighthouse = 13 km

Find:

Speed of the submarine

Computation:

At steady speed, the distance between both the submarine and the lighthouse base decreases at a rate of 24 km/hr.

So, when it is 13 kilometres from its starting point, the speed remains constant at 24 kilometres per hour.

Is it true that every whole number is a solution of x > 0? Use complete sentences to explain your reasoning.

Answers

Whole numbers are natural numbers, and natural numbers do not include negatives, decimals, fractions, or roots, so all whole numbers can indeed satisfy the inequality.


Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they charged a total of
$750. What was the rate charged per hour by each mechanic if the sum of the two rates was $105 per hour?

Answers

Step-by-step explanation:

let's convert the statement into equation..

let the charge of 1st mechanic be x and second be y..

by the question..

10x+5y=750...(i)

x+y=105..(ii)

from eqn(ii)..

x+y=105

or, x=105-y...(iii)

substituting the value of x in eqn (i)..

10x+5y=750

or, 10(105-y)+5y=750

or, 1050-10y+5y=750

or, 1050-750=5y

or, y=300/5

•°• y=60

substituting the value of y in eqn(iii).

x=105-y

or, x=105-60

•°• x= 45..

the rate charged by two mechanics per hour was 60$ and 45$

At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen finished in the bottom third of their high school class. Admission standards at the university were tightened in 1995. In 1997, a simple random sample of 100 entering freshmen found that only 10 finished in the bottom third of their high school class. Let p 1 and p 2 be the proportions of all entering freshmen in 1993 and 1997, respectively, who graduated in the bottom third of their high school class. What is a 90% plus four confidence interval for p 1 – p 2?

Answers

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

[tex]p_1 = \frac{20}{100} = 0.2[/tex]

[tex]s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04[/tex]

p2 -> 1997

10 out of 100, so:

[tex]p_2 = \frac{10}{100} = 0.1[/tex]

[tex]s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03[/tex]

Distribution of p1 – p2:

[tex]p = p_1 - p_2 = 0.2 - 0.1 = 0.1[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05[/tex]

Confidence interval:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].  

The lower bound of the interval is:

[tex]p - zs = 0.1 - 1.645*0.05 = 0.01775 [/tex]

The upper bound of the interval is:

[tex]p + zs = 0.1 + 1.645*0.05 = 0.18225 [/tex]

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Elena drank 3 liters of water yesterday. Jada drank 3/4 times as much water as elena. Link drank twice as much as Jada. Did jada drink more or less then elena? Explain how you know

Answers

Answer:

Step-by-step explanation:

3\4 bc on a nuberline it would be 3 3\4

                                                        I--I----(etc)

so yeah hope i helped

Solve the formula for the given variable.
-2x - 6 = 4x
Please helppp

Answers

Answer:

s snsnnssjsjjsnsnsjs

es 17 es

State two similarities and one difference between the graphs of f(x)= 3^x and g (x)= (1/3) ^x

Answers

Answer: the similarities is that they both intercepted at one point (0,1) and the difference is that f(x) is reaching positive infinity but g(x) is reaching negative infinity.

Find the lengths of AD, EF, and BC in the trapezoid below.

Answers

We know that,

[tex]EF=\dfrac{AD+BC}{2}[/tex]

which is

[tex]x=\dfrac{x-5+2x-4}{2}[/tex]

Now solve for x,

[tex]x=\dfrac{3x-9}{2}[/tex]

[tex]2x=3x-9[/tex]

[tex]x=9[/tex]

Since x is 9, the lengths are,

[tex]AD=x-5=9-5=\boxed{4}[/tex]

[tex]EF=x=\boxed{9}[/tex]

[tex]BC=2x-4=18-4=\boxed{14}[/tex]

Hope this helps :)

Please help on my hw

Answers

Answer:

Base is 3 centimeter and hight is 12 cent.

What are the coordinates of point K?
A (-2,4)
B (-2,-4)
C (2,-4)
D (2, 4)

Answers

Answer:

A

Step-by-step explanation:

I guess that is the answer

Find the value of x.
X 9 9 7 x = [?]

Answers

Due to the 2 lines being equal length from the center, the two outer lines are the same, the on is shown as 7, and another 7 bc of the lines that say they’re the same. Answer is 14

Tom and Jerry had a race. Tom started at 0200 running at 4.5km per hour. Jerry started
later at 6:30am running at 6.5km per hour. After five hours, who was ahead, and by how
much (answer in kilometres)

Answers

Answer:

Tom, 10.25

Step-by-step explanation:

Distance covered by Tom=4.5*(4 1/2+5)=81/4=42.75km

Distance covered by Jerry=6.5*(5)=32.5km

Tom is ahead from Jerry by 10.25km

write the equation of the graph, y=? SOMEBODY PLEASE HELP

Answers

Answer:

[tex]y=\left(6\right)^{x}\ -3[/tex]

Step-by-step explanation:

What number x gives maximum value for c(12,x)?

Answers

Answer:

i will say methods try yourself:

How to Determine Maximum Value

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.Since the term with the x2 is negative, you know there will be a maximum point.

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plzz follow and make brainlist

what is the simple definition of realnumbers​

Answers

Answer:

In mathematics, a real number is a value of a continuous quantity that can represent a distance along a line (or alternatively, a quantity that can be represented as an infinite decimal expansion).

In mathematics, a real number is a value of a continuous quantity that can represent a distance along a line (or alternatively, a quantity that can be represented as an infinite decimal expansion).
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