Answer:
577.6 mmHg
Explanation:
What is the conversion between atm (standard atmosphere) and mmHg (millimeters of mercury)?
Multiply the atm amount by 760 to get the mmHg amount.
19/25 * 760/1
19/5 * 152/1
(19*152)/5
2888/5
577 3/5 or 577.6 mmHg
Based on the molecular formula, determine whether each of the following is an alkane, alkene, or alkyne. (Assume that the hydrocarbons are noncyclical and there is no more than one multiple bond.)
a. C3H6
b. C6H12
c. H8H18
d. C7H12
Answer:
C₃H₆ is an alkene
C₆H₁₂ is an alkene
C₈H₁₈ is an alkane
C₇H₁₂ is an alkyne
Explanation:
To determine which of the compound is alkane, alkene, or alkyne,we shall use the general formula of alkane, alkene, and alkyne. This is illustrated below:
General formula for alkane => CₙH₂ₙ₊₂
General formula for alkene => CₙH₂ₙ
General formula for alkyne => CₙH₂ₙ₋₂
For C₃H₆:
n = 3
Alkane => CₙH₂ₙ₊₂ => C₃H₂₍₃₎₊₂ => C₃H₈
Alkene => CₙH₂ₙ => C₃H₂₍₃₎ => C₃H₆
Alkyne => CₙH₂ₙ₋₂ => C₃H₂₍₃₎₋₂ => C₃H₄
Thus, C₃H₆ is an alkene
For C₆H₁₂:
n = 6
Alkane => CₙH₂ₙ₊₂ => C₆H₂₍₆₎₊₂ =>C₆H₁₄
Alkene => CₙH₂ₙ => C₆H₂₍₆₎ => C₆H₁₂
Alkyne => CₙH₂ₙ₋₂ => C₆H₂₍₆₎₋₂ => C₆H₁₀
Thus, C₆H₁₂ is an alkene
For C₈H₁₈:
n = 8
Alkane => CₙH₂ₙ₊₂ => C₈H₂₍₈₎₊₂ => C₈H₁₈
Alkene => CₙH₂ₙ => C₈H₂₍₈₎ => C₈H₁₆
Alkyne => CₙH₂ₙ₋₂ => C₈H₂₍₈₎₋₂ => C₈H₁₄
Thus, C₈H₁₈ is an alkane.
For C₇H₁₂:
n = 7
Alkane => CₙH₂ₙ₊₂ => C₇H₂₍₇₎₊₂ => C₇H₁₆
Alkene => CₙH₂ₙ => C₇H₂₍₇₎ => C₇H₁₄
Alkyne => CₙH₂ₙ₋₂ => C₇H₂₍₇₎₋₂ => C₇H₁₂
Thus, C₇H₁₂ is an alkyne.
SUMMARY:
C₃H₆ is an alkene
C₆H₁₂ is an alkene
C₈H₁₈ is an alkane
C₇H₁₂ is an alkyne
Which of these can be found in a plant cell, but not in an animal cell?
Answer:
Hey!
Explanation:
I dont know the answers but Cell walls and Cloroplasts are only in plant cells. I hope this helps!
Which macromolecules break apart by hydrolysis?
Answer:
Dehydration synthesis reactions build molecules up and generally require energy, while hydrolysis reactions break molecules down and generally release energy. Carbohydrates, proteins, and nucleic acids are built up and broken down via these types of reactions, although the monomers involved are different in each case.
Explanation:
A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off at and the temperature of the water starts off at . When the temperature of the water stops changing it's . The pressure remains constant at . Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits.
Answer:
Therefore, the specific heat capacity of the iron is 0.567J/g.°C.
Note: The question is incomplete. The complete question is given as follows:
A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.
Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits
Explanation:
Using the formula of heat, Q = mc∆T
where Q = heat energy (Joules, J), m = mass of a substance (g)
c = specific heat capacity (J/g∙°C), ∆T = change in temperature (°C)
When the hot iron is placed in the water, the temperature of the iron and water attains equilibrium when the temperature stops changing at 27.6 °C. Since it is assumed that heat exchange occurs only between the iron metal and water; Heat lost by Iron = Heat gained by water
mass of iron = 59.1 g, c = ?, Tinitial = 85.0 °C, Tfinal = 27.6 °C
∆T = 85.0 °C - 27.6 °C = 57.4 °C
mass of water = 100.0 g, c = 4.184 J/g∙°C, Tinitial = 23.0 °C, Tfinal = 27.6 °C
∆T = 27.6°C - 23.0°C = 4.6 °C
Substituting the values above in the equation; Heat lost by Iron = Heat gained by water
59.1 g * c * 57.4 °C = 100.0 g * 4.184 J/g.°C * 4.6 °C
c = 0.567 J/g.°C
Therefore, the specific heat capacity of the iron is 0.567 J/g.°C.
Jill graphs the speed of a model train that is travelling at a speed of 15 kilometers per hour. Which graph shows the speed of the model train?
Answer:c
Explanation:
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.8635 g of CO2 and 0.1767 g of H2O. What is the empirical formula of the compound?
Answer: The empirical formula is [tex]C_3H_3O_2[/tex].
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of [tex]CO_2[/tex] = 0.8635
Mass of [tex]H_2O[/tex]= 0.1767 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 0.8635 g of carbon dioxide, =[tex]\frac{12}{44}\times 0.8635=0.2355g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 0.1767 g of water, =[tex]\frac{2}{18}\times 0.1767=0.0196g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (0.4647) - (0.2355+0.0196) = 0.2096 g
Mass of C = 0.2355 g
Mass of H = 0.0196 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{0.2355g}{12g/mole}=0.0196moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.0196g}{1g/mole}=0.0196moles[/tex]
Moles of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{0.2096g}{16g/mole}=0.0131moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.0196}{0.0131}=1.5[/tex]
For H =[tex]\frac{0.0196}{0.0131}=1.5[/tex]
For O = [tex]\frac{0.0131}{0.0131}=1[/tex]
The ratio of C : H: O = 1.5 : 1 .5 : 1
Converting to simple whole number ratio:
The ratio of C : H: O = 3 : 3: 2
Hence the empirical formula is [tex]C_3H_3O_2[/tex].
How do I round 74,000 to have only one significant figure?
Answer:
7x10⁴.
Explanation:
Hello!
In this case, when rounding big number to a representation with less significant figures than it, we need to make sure we remove the spare figures and round up whether the next digit is five or more.
In such a way, for 74,000, we notice that 4 is not enough to round up the 7, that is why the number would contain a 7 only; moreover, to get rid of the thousand places, we need to introduce an exponent in 4 places, which means that the result would be:
7x10⁴.
Best regards!
The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process.
2N2O5(g) = 4NO2(g) + O2
[N2O5] Time (s)
0.100 0.00
0.066 200.00
0.044 400.00
a) Find the rate of disappearance of N2O5 from t=0 s to t=200s
b) Find the rate of appearance of NO2 from t=0 s to t =200s
Answer: a) [tex]1.7\times 10^{-4}[/tex]
b) [tex]3.4\times 10^{-4}[/tex]
Explanation:
The reaction is :
[tex]2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)[/tex]
Rate = Rate of disappearance of [tex]N_2O_5[/tex] = Rate of appearance of [tex]NO_2[/tex]
Rate = [tex]-\frac{d[N_2O_5]}{2dt}[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]
Rate of disappearance of [tex]N_2O_5[/tex] = [tex]\frac{\text {change in concentration}}{time}[/tex] = [tex]\frac{0.100-0.066}{200-0}=1.7\times 10^{-4}[/tex]
a) Rate of disappearance of [tex]N_2O_5[/tex] = [tex]-\frac{d[N_2O_5]}{2dt}[/tex]
Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]
b) Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}[/tex]
A) Find the rate of disappearance of [tex]N_2O_5[/tex] from t = 0 s to t = 200s
[tex]Rate = \frac{1}{2}(\frac{-\delta N_2O_5}{\delta t})\\\\Rate = -\frac{1}{2}(\frac{0.066 - 0.100}{200 - 0})\\\\Rate = 8.5*10^{-5}[/tex]
B) Find the rate of appearance of [tex]NO_2[/tex] from t = 0 s to t = 200s
According to rate law,
[tex]\frac{1}{2}(\frac{-\delta N_2O_5}{\delta t}) = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\8.5*10^{-5} = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\\frac{\delta NO_2}{\delta t} = 4 * 8.5*10^{-5}\\\\Rate = 3.4*10^{-4}[/tex]
For more information on rate of disappearance
https://brainly.com/question/20708865?referrer=searchResults
Sulfur dioxide (SO2) is an unwelcome result
of burning soft coal in power plants. Some
of the SO2 ends up as sulfuric acid in acid
precipitation. The net reaction is
2 SO2(g) + O2(g) + 2 H2O(l) —— 2 H2SO4(l)
What mass in grams of SO2 is needed to
react with 1771 g of O2?
Answer in units of g.
Answer:
I believe it is 1771 divided by 4
Explanation:
What type of weather typically results from a low pressure system?
I need help!!!!
Answer:
Storms and hurricanes can be formed with low pressure. It always results into unsettled weather.
Explanation:
Hope this helps!
Increasing the force on an object _________ its acceleration, if the mass of the object stays the same
The element in Period 4 and Group 14 of the Periodic Table would be classified as a
Answer:
Chalcogen
Explanation:
If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the structure Y---:X:------Y could be abbreviated as XY2Z2.Classify these structures by the hybridization of the central atom. XY4Z2, XY4Z, XY5Z, XY2Z3, XY2Z, XY3Z, XY2Z2, XY3Z2,XY2,XY3,XY4,XY5,XY6
Answer:
XY4Z2- dsp2
XY4Z- sp3d
XY5Z- sp3d2
XY2Z3- sp3d
XY2Z- sp2
XY3Z- sp3
XY2Z2- sp3
XY3Z2- sp3d
XY2 - sp
,XY3- sp2
XY4- sp3
,XY5- sp3d
XY6- sp3d2
Explanation:
In the answer box I have shown the hybridization patterns of the various arrangement of bond pairs and lone pairs.
Hybridization was put forward to explain the shapes of molecules under the valence bond theory. All molecules having the same hybridization pattern are based on the same geometry. Deviations from the expected geometry may arise due to the presence of lone pairs.
A chemist prepares a solution of silver (I) perchlorate (AgCIO4) by measuring out 134.g of silver (I) perchlorate into a 50.ml volumetric flask and filling the flask to the mark with water. calculate the concentration in mol/L of the silver (I) perchlorate soluation
Answer:
13 M
Explanation:
Molar mass of AgCIO4 = 207 g/mol
Number of moles of AgCIO4= 134/207= 0.65 moles
Number of moles= concentration × volume
Concentration = number of moles/volume
Concentration = 0.65 × 1000/50 = 13 M
The following is a procedure that was theoretically performed by a student. Read through the procedure and answer the questions below.1.A 10.0 mL graduated cylinder to measure 10.0 mL of a 1.00 M CaCl2 solution into an initially empty 50.0 mL beaker.2.A 50.0 mL graduated cylinder was then used to measure out 25.0 mL of 0.500 M K2CO3. This K2CO3solution was then added to the beaker containing the CaCl2 solution. The solution became cloudy, and the student concluded that a precipitate must have formed. Write a balanced chemical reaction below, including phases, and identify the chemical formula of the precipitate:
Answer:
CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)
Explanation:
We have the reactants as calcium chloride and potassium carbonate. Recall that we are expecting that the reaction will yield a precipitate. We must keep that in mind as we seek to write its balanced chemical reaction equation.
So we now have;
CaCl2 (aq) + K2CO3(aq) ---------> CaCO3(s) + 2KCl(aq)
Recall that the rule of balancing chemical reaction equation states that the number of atoms of each element on the right side of the reaction equation must be the same as the number of atoms of the same element on the left hand side of the reaction equation.
BRAINLLEST! Boiling water for mac and cheese is a physical change. Give 2 pieces of evidence to support this claim
Answer:
In explanation.
Explanation:
Physical changes are generally changes in states of matter. So, the water going from liquid to gas is a phase change and therefore physical. (It's still water, just in a different form). Im not sure about the second piece of evidence though. Unless you are talking about the Mac and Cheese which in that case is also a physical change as the two ingredients cheese and macaroni stay the same when cooked just become softer and edible.
atom ,molecule, proton neutron electron, elements/compounds from SMALLEST to the BIGGEST.
Answer:
Electron,Protons/Neutrons,Atom,Molecule
Explanation:
How many grams are in 4.58x1023 atoms of oxygen?
How many sulfur atoms are in 5 SF6 ?
Answer:
The molecular formula for sulfur hexafluoride is SF6 S F 6 , in which there is 1 sulfur atom and 6 fluorine atoms.
Explanation:
hope this helps
aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Supposed 6.93 g of hydrochloric acid is mixed with 2.4 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits. g
Answer:
Explanation:
HCl + NaOH = NaCl + H₂O.
1 mole 1 mole 1 mole 1 mole
6.93 g of hydrochloric acid = 6.93 / 36.5 = .189 mole of HCl
2.4 g of NaOH = 2.4 / 40 = .06 mole of NaOH
NaOH is in short supply so it is the limiting reagent .
1 mole of NaOH reacts with 1 mole of HCl to give 1 mole of Water
.06 mole of NaOH will react with .06 mole of HCl to give .06 mole of water
Water formed = .06 mole
= .06 x 18 = 1.08 g
= 1.1 g
Which of the statements about liquids and gases are true?
Both liquids and gases have a definite volume.
O The particles in liquids and gases can move past one another
freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.
Which of the statements about liquids and gases are true?
Answer:The particles in liquids and gases can move past one another freely.
#CARRYONLEARNING #STUDYWELLWhich of the statements about liquids and gases are true?
Choosing:Both liquids and gases have a definite volume.
The particles in liquids and gases can move past one another freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.
Answer:The particles in liquids and gases can move past one another freely.
#READINGHELPSWITHLEARNING #CARRYONLEARNING #STUDYWELLWhat is CaF2(aq) + Rb
Answer:
RbF2 + Ca
Explanation:
Since Rb is located in IIA as well as Ca, Rb has ion form Rb2+
Hence CaF2 + Rb → RbF2 +Ca
Please be reminded, this answer may not be 100% correct
6- A favorable condition for two elements to form an ionic bond is?
a- both should be electronegative
b- one should have low electron affinity and the other low ionization energy.
C- one should have high electron affinity and the other low ionization energy.
d- both should be highly electronegative
Answer: C- one should have high electron affinity and the other low ionization energy.
Explanation:
Ionization energy is the energy required to remove the electron from an isolated gaseous atom.
Electron affinity is the tendency of an isolated atom to attrcat the electrons towards itsellf.
An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and it can donate electron easily if it has low ionization energy.
The element which accepts the electrons is known as electronegative element or non metal and it can easily accept the electron if it has high electron affinity.
What is the formula for the ionic compound formed between sodium and oxygen?
Answer:
Na2O (the 2 is small the o is not a 0 but and OOh)
Explanation:
Hey there, The formula for the compound formed between sodium and oxygen will be Na2O
Though since sodium is a metal and oxygen is a nonmetal, Na2O is expected to be ionic.
What is an ionic compound?An ionic compound is a chemical compound made up of ions held together by electrostatic forces known as ionic bonding.
To determine an ionic compound's formula, first identify the cation and record its symbol and charge.
After that, identify the anion and record its symbol and charge. Finally, mix the two ions together to make an electrically neutral compound.
After two or more atoms lose or gain electrons to form an ion, an ionic bond can form.
Ionic bonds form when metals lose electrons and nonmetals gain electrons. Ions with opposite charges attract each other, forming an ionic bond.
The symbol for sodium is Na+, and the symbol for oxygen is O2. The resulting compound here in the given condition is Na2O.
Thus, this is the formula for the ionic compound formed between sodium and oxygen.
For more details regarding ionic compounds, visit:
https://brainly.com/question/9167977
#SPJ2
A student collected a 1.28 g sample of Magnesium. How many atoms of Mg are in his sample?
A student did an experiment that called for 1.24 x 1024 molecules of CaO. What is the mass of her reactant?
A student reacted 0.0405 g of glucose (C6H12O6). How many molecules of glucose did he react?
What is ATP? How does it provide energy
According to Image 2, which tectonic plate is composed of the largest percentage of oceanic lithosphere?
A. African Plate
B. Eurasian Plate
C. Indian Plate
D. Nazca Plate
Answer:
I think the answer is A the Afracan plate
Explanation:
hope this helps:)
(9) How many moles of oleum in 1780. g of oleum? - Write an equation to summarize the process.
Answer:
1. 10moles
2. Find the summarized equation below
Explanation:
Mole = mass ÷ molar mass
Molar mass of oleum (H2S2O7) = 1(2) + 32(2) + 16(7)
= 2 + 64 + 112
= 178g/mol
According to the information provided, the mass of oleum is 1780g, hence, the number of moles in it is:
Mole = 1780/178
Mole = 10moles
2. The summarized equation of the contact process is:
1) S + O2 → SO2
2) 2SO2 + O2 → 2SO3
3) SO3 + H2SO4 (conc. sulfuric acid) → H2S2O7
4) H2S2O7 + H2O → 2H2SO4 (dilute sulfuric acid)
Marine chemist exam in the mass percent composition of manganese sulfide compound from ocean floor he determined that 60.2% of this compound is sulfur determine the mole ratio between manganese and sulfur
Explanation:
Let the mass of the compound be 100g.
There are 60.2g of sulfur.
Moles of sulfur
= 60.2g / (32.07g/mol) = 1.877mol
There are 100g - 60.2g
= 39.8g of manganese.
Moles of manganese
= 39.8g / (54.94g/mol) = 0.724mol
Mole ratio of manganese to sulfur
= 0.724mol : 1.877mol = 1 : 2.5.
What is the molar mass of Mg(CIO3)2
