Answer:
lines are perpendicular
Step-by-step explanation:
• Parallel lines have equal slopes
• The product of the slopes of perpendicular lines = - 1
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange the given equations into this form and extract the slope
3x - 2y = - 6 ( subtract 3x from both sides )
- 2y = - 3x - 6 ( divide through by - 2 )
y = [tex]\frac{3}{2}[/tex] x + 3 ← in slope- intercept form
with slope m = [tex]\frac{3}{2}[/tex]
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4x + 6y = 2 ( subtract 4x from both sides )
6y = - 4x + 2 ( divide through by 6 )
y = - [tex]\frac{4}{6}[/tex] x + [tex]\frac{2}{6}[/tex] , that is
y = - [tex]\frac{2}{3}[/tex] x + [tex]\frac{1}{3}[/tex] ← in slope- intercept form
with slope m = - [tex]\frac{2}{3}[/tex]
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[tex]\frac{3}{2}[/tex] ≠ - [tex]\frac{2}{3}[/tex] , then lines are not parallel
[tex]\frac{3}{2}[/tex] × - [tex]\frac{2}{3}[/tex] = - 1
Thus the lines are perpendicular to each other