Crystal left her running shoes at school yesterday. Today she walked 44 miles to school to get her shoes, she ran home along the same route, and the total time for both trips was 22 hours. Crystal walked and ran at constant speeds, and she ran 33 miles per hour faster than she walked.

What was Crystal’s walking speed in miles per hour?

Answers

Answer 1

Answer:

We can conclude that her walking speed is 2.1 miles per hour.

Step-by-step explanation:

We have the relation:

Speed = distance/time.

Here we know:

She walked for 44 miles.

And she ran along the same route, so she ran for 44 miles.

The total time of travel is 22 hours, so if she ran for a time T, and she walked for a time T', we must have:

T + T' = 22 hours.

If we define: S = speed runing

                     S' = speed walking

Then we know that:

"and she ran 33 miles per hour faster than she walked."

Then:

S = S' + 33mi/h

Then we have four equations:

S'*T' = 44 mi

S*T = 44 mi

S = S' + 33mi/h

T + T' = 22 h

We want to find the value of S', the speed walking.

To solve this we should start by isolating one of the variables in one of the equations.

We can see that S is already isoalted in the third equation, so we can replace that in the other equations where we have the variable S, so now we will get:

S'*T' = 44mi

(S' + 33mi/H)*T = 44mi

T + T' = 22h

Now let's isolate another variable in one of the equations, for example we can isolate T in the third equation to get:

T = 22h - T'

if we replace that in the other equations we get:

S'*T' = 44mi

(S' + 33mi/h)*(  22h - T') = 44 mi

Now we can isolate T' in the first equation to get:

T' = 44mi/S'

And replace that in the other equation so we get:

(S' + 33mi/h)*(  22h -44mi/S' ) = 44 mi

Now we can solve this for S'

22h*S' + (33mi/h)*22h + S'*(-44mi/S')  + 33mi/h*(-44mi/S') = 44mi

22h*S' + 726mi - 44mi - (1,452 mi^2/h)/S' = 44mi

If we multiply both sides by S' we get:

22h*S'^2 + (726mi - 44mi)*S' - (1,425 mi^2/h) = 44mi*S'

We can simplify this to get:

22h*S'^2 + (726mi - 44mi - 44mi)*S' - (1,425 mi^2/h) = 0

22h*S'^2 + (628mi)*S' - ( 1,425 mi^2/h) = 0

This is just a quadratic equation, the solutions for S' are given by the Bhaskara's equation:

[tex]S' = \frac{-628mi \pm \sqrt{(628mi)^2 - 4*(22h)*(1,425 mi^2/h)} }{2*22h} \\S' = \frac{-628mi \pm 721 mi }{44h}[/tex]

Then the two solutions are:

S' = (-628mi - 721mi)/44h = -30.66 mi/h

But this is a negative speed, so this has no real meaning, and we can discard this solution.

The other solution is:

S' = (-628mi + 721mi)/44h = 2.1 mi/h

We can conclude that her walking speed is 2.1 miles per hour.


Related Questions

If a product normal retails for $40, and a customer has a coupon for 15% off, what will the discounted price of the product be?

Answers

It will be 6 - hope it help

Answer:

$34

Step-by-step explanation:

price of the product = $40

coupon = 15% off

discount price = 15% of price of a product

=15/100 * $40

=$600/100

=$6

New price of the product = original price - discount

=$40 - $6

=$34

Question 11 of 40
Factor this polynomial completely.
x2 - 6x + 9
A. (x+3)(x+3)
B. Does not factor
C. (x-3)(x - 3)
D. (x+3)(x-3)

Answers

I don’t know the answer but I need points sorry

solve for x 6(x-3)=8(x-4)

Answers

Answer:

7=x

Step-by-step explanation:

6(x-3)=8(x-4)

Distribute

6x -18 = 8x-32

Subtract 6x from each side

6x-18 -6x = 8x-32-8x

-18 = 2x-32

Add 32 to each side

-18+32 = 2x-32+32

14 = 2x

Divide by 2

14/2 =2x/2

7=x

[tex]\sf\purple{x= 7}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

[tex]➺\:6(x - 3) = 8(x - 4)[/tex]

[tex]➺ \: 6x - 18 = 8x - 32[/tex]

[tex]➺ \: 6x - 8x = - 32 + 18[/tex]

[tex]➺ \: - 2x = - 14[/tex]

[tex]➺ \: x = \frac{ - 14}{ - 2} [/tex]

[tex]➺ \: x = 7[/tex]

Therefore, the value of [tex]x[/tex] is 7.

[tex]\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}[/tex]

[tex]➺ \: 6(x - 3) = 8(x - 4)[/tex]

[tex]➺ \: 6(7 - 3) = 8(7 - 4)[/tex]

[tex]➺ \: 6 \times 4 = 8 \times 3[/tex]

[tex]➺ \: 24 = 24[/tex]

➺ L. H. S. = R. H. S.

Hence verified.

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]

What is the smallest number you should subtract from 456 to make it divisible by 9?

Answers

Add up all the digits

4+5+6=15

The sum of the digits must be equal to 9 so,


15=9

15–9=0

So,it is equal to 6.If we subtract 6 from 456 i.e.,

=456–6

=450

Which is divisible by 9 so,the answer is 6.But if we subtract any digit less than 6 it will not be divisible by 9.






Solve for T: 10t-4x=3S Explanation plz

Answers

T=3s/10+2x/5 hope this helped <3

simplification please

Answers

Answer:

5

Step-by-step explanation:

WHen we raise a power to a power, we multiply them, in this case 5 is the base so we can just ignore it for now and replace it with x.

(X^1/3)^3

Multiply 1/3 by 3 and we get 1

So:

X^1

Which does nothing, so we can simplify to just:\

X

Remember x is 5 so the answer is:

5

Eric wants to buy a new hat
which costs $17. He made
$5 by raking leaves and
$8 by washing cars.
How much more money does he need?

Answers

Answer:

the answer is 4

Step-by-step explanation:

you subtract 13 from 17 =4

6
Which expression is equivalent

Answers

Answer:

I thimk it is B

Step-by-step explanation:

If a normal distribution has a mean of 154 and a standard deviation of 15,
what is the value that has a z-score of 1.6?

Answers

Answer:

The correct answer is - 178.

Step-by-step explanation:

The standard deviation is a measure of the amount of dispersion in a set of values.

Given:

Mean of a normal distribution (m) = 154

Standard deviation (s) = 15

z-score = 1.6

Solution:

To find: value (x) that has a z-score of 1.6

z-score is given by = x-u/15

1.6*15 = x-154

=> 154+24 = x

x = 178

brainliest answer po yung tama
nk tym for nega NEED HELP PK TALAG​

Answers

A

A

B

C

A

D

B

C

May choices po yan saamen

Step-by-step explanation:

Love you

25. Approximate the sample variance and standard deviation given the following frequency distribution: Class Frequency 0–9 13 10–19 7 20–29 10 30–39 9 40–49 11

Answers

Answer:

Sample variance = 228.408

Standard deviation = 15.113

Step-by-step explanation:

The well formatted frequency table has been attached to this response.

To calculate the sample variance and standard deviation of the given grouped data, follow these steps:

i. Find the midpoint (m) of the class interval.

This is done by adding the lower bounds and upper bounds of the class intervals and dividing the result by 2. i.e

For class 0 - 9, we have

m = (0 + 9) / 2 = 4.5

For class 10 - 19, we have

m = (10 + 19) / 2 = 14.5

For class 20 - 29, we have

m = (20 + 29) / 2 = 24.5

For class 30 - 39, we have

m = (30 + 39) / 2 = 34.5

For class 40 - 49, we have

m = (40 + 49) / 2 = 44.5

This is shown in the third column of the attached table.

ii. Find the product of each of the frequencies of the class intervals and their corresponding midpoints. i.e

For class 0 - 9, we have

frequency (f) = 13

midpoint (m) = 4.5

=> f x m = 13 x 4.5 = 58.5

For class 10 - 19, we have

frequency (f) = 7

midpoint (m) = 14.5

=> f x m = 7 x 14.5 = 101.5

For class 20 - 29, we have

frequency (f) = 10

midpoint (m) = 24.5

=> f x m = 10 x 24.5 = 245

For class 30 - 39, we have

frequency (f) = 9

midpoint (m) = 34.5

=> f x m = 9 x 34.5 = 310.5

For class 40 - 49, we have

frequency (f) = 11

midpoint (m) = 44.5

=> f x m = 11 x 44.5 = 489.5

This is shown in the fourth column of the attached table.

iii. Calculate the mean (x) of the distribution i.e

This is done by finding the sum of all the results in (ii) above and dividing the outcome by the sum of the frequencies. i.e

x = ∑(f x m) ÷ ∑f

Where;

∑(f x m) = 58.5 + 101.5 + 245 + 310.5 + 489.5 = 1205

∑f = 13 + 7 + 10 + 9 + 11 = 50

=> x = 1205 ÷ 50

=> x = 24.1

Therefore, the mean is 24.1

This is shown on the fifth column of the attached table.

iv. Calculate the deviation of the midpoints from the mean.

This is done by finding the difference between the midpoints and the mean. i.e m - x where x = mean = 24.1 and m = midpoint

For class 0 - 9, we have

midpoint (m) = 4.5

=> m - x = 4.5 - 24.1 = -19.6

For class 10 - 19, we have

midpoint (m) = 14.5

=> m - x = 14.5 - 24.1 = -9.6

For class 20 - 29, we have

midpoint (m) = 24.5

=> m - x = 24.5 - 24.1 = 0.4

For class 30 - 39, we have

midpoint (m) = 34.5

=> m - x = 34.5 - 24.1 = 10.4

For class 40 - 49, we have

midpoint (m) = 44.5

=> m - x = 44.5 - 24.1 = 20.4

This is shown on the sixth column of the attached table.

v. Find the square of each of the results in (iv) above.

This is done by finding (m-x)²

For class 0 - 9, we have

=> (m - x)² = (-19.6)² = 384.16

For class 10 - 19, we have

=> (m - x)² = (-9.6)² = 92.16

For class 20 - 29, we have

=> (m - x)² = (0.4)² = 0.16

For class 30 - 39, we have

=> (m - x)² = (10.4)² = 108.16

For class 40 - 49, we have

=> (m - x)² = (20.4)² = 416.16

This is shown on the seventh column of the attached table.

vi. Multiply each of the results in (v) above by their corresponding frequencies.

This is done by finding f(m-x)²

For class 0 - 9, we have

=> f(m - x)² = 13 x 384.16 =  4994.08

For class 10 - 19, we have

=> f(m - x)² = 7 x 92.16 = 645.12

For class 20 - 29, we have

=> f(m - x)² = 10 x 0.16 = 1.6

For class 30 - 39, we have

=> f(m - x)² = 9 x 108.16 = 973.44

For class 40 - 49, we have

=> f(m - x)² = 11 x 416.16 = 4577.76

This is shown on the eighth column of the attached table.

vi. Calculate the sample variance.

Variance σ², is calculated by using the following relation;

σ² = ∑f(m-x)² ÷ (∑f - 1)

This means the variance is found by finding the sum of the results in (vi) above and then dividing the result by one less than the sum of all the frequencies.

∑f(m-x)² = sum of the results in (vi)

∑f(m-x)² = 4994.08 + 645.12 + 1.6 + 973.44 + 4577.76 = 11192

∑f - 1 = 50 - 1 = 49         {Remember that ∑f was calculated in (iii) above}

∴ σ² = 11192 ÷ 49 = 228.408

Therefore, the variance is 228.408

vii. Calculate the standard deviation

Standard deviation σ, is calculated by using the following relation;

σ =√ [ ∑f(m-x)² ÷ (∑f - 1) ]

This is done by taking the square root of the variance calculated above.

σ = [tex]\sqrt{228.408}[/tex]

σ = 15.113

Therefore, the standard deviation is 15.113

Determine the value of x for which r is parallel to s if m angle 1 = 60-2x and m angle 2=70-4x

Answers

Answer:  r = 5

Step-by-step explanation:

Look at the illustration.
What is WX?

Answers

Answer:

O  0.5 units

Step-by-step explanation:

so the first thing we have to do is to calculate for the dilation factor. Taking point G as the reference point, we can see that the distance of point G from rectangle W'X'Y'Z is 1.5 while the distance from rectangle WXYZ is (1.5 + 7.5) = 1.5 / 9 = 1/6

Since WX has an initial measure of 3 units, therefore the measure of W'X' is:

W'X' = 3 units *(1/6) = 0.5 units

This is for my brother’s test
What are the measures of L1 and L2? Show your work or explain your answers.

Answers

Answer:

angle 2 is 75°

osjdiajsjoasnndosnsnd

Help me pls I don’t know how to do this

Answers

Answer:

[tex]radius=6.68cm[/tex]

Step-by-step explanation:

Formula to find radius:

[tex]r=\frac{C}{2\pi }[/tex]

[tex]r=42/2\pi[/tex]

[tex]r=42/2(3.14)[/tex]

[tex]r=6.68cm[/tex]

hope this helps......

what number must you add to complete the square? x^2+24x=50

Answers

Answer:

144

Step-by-step explanation:

Divide the b term which is 24 by 2

Gives you 12, then square it.

that's 144

formula for completing squares is [tex](b/2)^{2}[/tex]

WILL MARK YOU IF YOU ANSWER SO PLEASE HELP

Answers

Answer:

x= 83

first take vertical opposite angle then take corresponding angles then you're done

Answer:

x value is 83 degree

because they both are alternate exterior angle

Find the interest earned on $1,000 for 1 year at a 6% rate of interest when the interest is compounded quarterly.

Answers

Answer:

1060

Step-by-step explanation:

The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of the width? Write an inequality to represent this problem. Use w to represent the width of the parallelogram. [Hint: The formula for finding the perimeter of a parallelogram is P = 2 l + 2 w . What is the smallest possible measurement of the width? Justify your answer by showing all your work.

Answers

Answer: [tex]14\ ft[/tex]

Step-by-step explanation:

Given

Length of rectangle is [tex]6\ ft[/tex]

Perimeter must be greater than 40 ft

Suppose l and w be the length and width of the rectangle

[tex]\Rightarrow \text{Perimeter P=}2(l+w)\\\Rightarrow P\geq 40\\\Rightarrow 2(l+w)\geq40\\\Rightarrow l+w\geq20\\\Rightarrow w\geq20-6\\\Rightarrow w\geq14\ ft[/tex]

So, the smallest width can be [tex]14\ ft[/tex]

What is the period of the graph of y = 5 sin (πx) + 4?

Answers

Answer:

I think it’s 2 hope my answer was good have a nice day as well

Step-by-step explanation:

The period of the given function y = 5 sin (πx) + 4 is π.

We have given that,

y = 5 sin (πx) + 4

We have to determine the period

What is the period?

The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π.

Therefore the period of the given function is π.

To learn more about the period visit:

https://brainly.com/question/13753522

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Differentiate the function. y = (2x - 5)^2 (5 - x)?​

Answers

Answer:

[tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Distributive Property

Algebra I

Terms/CoefficientsFactoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                       [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

y = (2x - 5)²(5 - x)

Step 2: Differentiate

Derivative Rule [Product Rule]:                                                                        [tex]\displaystyle y' = \frac{d}{dx}[(2x - 5)^2](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Chain Rule [Basic Power Rule]:                                                                        [tex]\displaystyle y' = [2(2x - 5)^{2 - 1} \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Basic Power Rule:                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot 1 \cdot 2x^{1 - 1}](5 - x) + (2x - 5)^2(1 \cdot -x^{1 - 1})][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot 2](5 - x) + (2x - 5)^2(-1)[/tex]Multiply:                                                                                                             [tex]\displaystyle y' = 4(2x - 5)(5 - x) - (2x - 5)^2[/tex]Factor:                                                                                                               [tex]\displaystyle y' = (2x - 5)[4(5 - x) - (2x - 5)][/tex][Distributive Property] Distribute 4:                                                                 [tex]\displaystyle y' = (2x - 5)[20 - 4x - (2x - 5)][/tex][Distributive Property] Distribute negative:                                                    [tex]\displaystyle y' = (2x - 5)[20 - 4x - 2x + 5][/tex][Subtraction] Combine like terms (x):                                                              [tex]\displaystyle y' = (2x - 5)[20 - 6x + 5][/tex][Addition] Combine like terms:                                                                        [tex]\displaystyle y' = (2x - 5)(25 - 6x)[/tex]Factor:                                                                                                               [tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

f(x)=|x-6| written as piecewise function

Answers

I’m not sure if this was what you wanted but I used an app to calculate it.

A stamp collection is purchased for $1,000. Twenty years later, the owner is told that the collection is worth quite a bit of money! If the rate of return on the stamp collection is 4% per year, what is the current value of the stamp collection? In your final answer, include all of your calculations.

Answers

Answer:

The current value of the stamp collection is of $2,191.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

A stamp collection is purchased for $1,000.

This means that [tex]P = 1000[/tex]

The rate of return on the stamp collection is 4% per year

This means that [tex]n = 1, r = 0.04[/tex]

So

[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]

[tex]A(t) = 1000(1 + 0.04)^{t}[/tex]

[tex]A(t) = 1000(1.04)^{t}[/tex]

What is the current value of the stamp collection?

This is A(20). So

[tex]A(20) = 1000(1.04)^{20} = 2191[/tex]

The current value of the stamp collection is of $2,191.

Answer:

Step-by-step explanation:

y = 1000(1+0.04)^20

y = 1000(1.04)^20

Rounded to the nearest hundredth

y = 1000(2.19)

y = $2190

The manufacturer claims the mean bursting pressure for a certain type and size of PVC irrigation pipe to be at least 350 psi. A sample of 10 such pipes were experimentally determined to have the following bursting pressures: 401 359 383 427 414 415 389 463 394 428 State the null and alternative hypotheses:

Answers

Answer:

H0 : μ ≥ 350

H1 : μ < 350

Step-by-step explanation:

It is claimed that the mean is atleast 350 psi ;

10 such pipes were experimentally sampled ;

Here, the null hypothesis is the claim ; this means that the alternative hypothesis will be the opposite of the claim.

The hypothesis

H0 : μ ≥ 350

H1 : μ < 350

Jill calls a plumber to her house to fix the leaking faucets . The plumber charges a one-time fee of $50 plus an additional $35 per hour of labor. What are the independent and dependent variables

Answers

Answer:

independent=$50

dependent=$35X

Step-by-step explanation:

50 is the independent variable because it doesn't change.

35X is the dependent variable because it does change.

In this scenario, the independent variable is the number of hours of labor and dependent variable is the total cost.

The independent variable is the number of hours. It is the variable that we can control or change.

The dependent variable is the total cost charged by the plumber.

It depends on the number of hours of labor and is determined by the plumber's fee structure, which includes a one-time fee of $50 plus $35 per hour of labor.

The total cost is calculated based on the number of hours of labor, making it the dependent variable in this situation.

Learn more about Independent variable here:

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what is 72 Times 27 equal

Answers

Answer:

1,944

Step-by-step explanation:

72x27=1,944

Have a wonderful day or night

Answer

1944

Step-by-step explanation:

72*27 = 1944

the image above should clarify how you're actually supposed to do it! couldn't submit this without 20 characters :,)

Joseph borrows $10000 from his sister Katie at an annual interest rate of 10%. If the
interest is compounded twice a year, how much does he owe after 12 months? Give your answer in dollars.

Answers

Answer:

A  =  P  ( 1  + r / n)  ^( t * n)

where

A  =  the amt  owed

P  = amt borrowed

r  = the  interest  rate  as a decimal

n =  the  number of compoundings  per year

t  = the  number of years

A  =    10000  (  1  + .10  / 2)^(2 *1)    =   10000  ( 1.05)^2    =  $11025

Step-by-step explanation:

Solve for x round to the nearest tenth if necessary

Answers

Answer:

x = 2.8

Step-by-step explanation:

sin = opp/hyp

hyp = opp/sin

x = 2.4/sin60

x = 2.771281292110204

rounded

x = 2.8

100° - y А (x+2) units Match the values based on parallelogram ABCD, shown in the figure. length of BC value of y mZDAB value of I 56 4 44 2​

Answers

Answer:

BC = 4 units

Value fo y = 44

∠DAB = 56°

Value of x = 2

Step-by-step explanation:

100 - y = 12 + y  (opposite angles of parallelogram are equal)

2y = 88

y = 44

Similarly,

6-x = x+2   (opposite sides of parallelogram are equal)

2x = 4

x = 2

PLEASE HELP ME WILL MARK YOU JF YOU HELP ME PLEASE!!!

Answers

Answer:

2, 3, 4, 7, 8, 10 I hope

Answers

Congruent by AAS (shown in the example)Congruent by SASCongruent by SSSCongruent by ASANot enough info  (shown in the second example)Congruent by AASCongruent by SASCongruent by SSSCongruent by AASNot congruent

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Explanations:

As the example shows, we have two pairs of congruent angles and a pair of congruent sides. The side are not between the angles in question. So AAS is slightly different from ASA.We have two pairs of congruent sides, and a pair of congruent angles. The angles are between the sides. So we use SAS which is a valid congruence theorem. Recall that SSA is not a valid theorem, so the order matters.We have three pairs of congruent sides, so we go with SSS. The order doesn't matter here.Similar to problem 1, but now the sides are between the angles. So we go with ASA this time instead of AAS.We unfortunately don't have enough info to determine if the triangles are congruent or not. We need to know something about the side lengths to determine congruency.As the hint suggests, marking the vertical angles will produce the other pair of congruent angles. So that's why we go for AAS (the side is not between the angles).This is similar to problem 2, as both use SAS. Note the unmarked vertical angles which are congruent.This is similar to problem 3. We use SSS here because we have 3 pairs of congruent sides as indicated by the tickmarks.The unmarked vertical angles can get double arcs to show they are congruent. We have a pair of congruent sides that are not between the two pairs of congruent angles, so we go for AAS (problems 1 and 6 also use AAS).For the triangle on the left, the arc is between the tickmarked sides. The triangle on the right has the arc not between the tickmarked sides. So there's no way the triangles are the same. The arc needs to be between the marked sides for each triangle, if we wanted them to be congruent (using SAS).

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Acronyms

SSS = side side side

SAS = side angle side

ASA = angle side angle

AAS = angle angle side

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