Answer: data warehouse
Explanation:
Data-mining agents work with a Data warehouse which helps in detecting trends and discovering new information.
A data warehouse refers to the large collection of business data that is used by organizations to make decisions. It has to do with the collection and the management of data from different sources which are used in providing meaningful business insights.
A process needs 103 KB of memory in order to run. If the system on which it is to run uses paging with 2 KB pages, how many frames in memory are needed
Answer: 52
Explanation:
Following the information given in the question, we are informed that a process needs 103 KB of memory in order to run and that the system on which it is to run uses paging with 2KB pages, then the number of frames in memory that are needed will be:
= 103/2
= 51.5
= 52 approximately
Therefore, 52 frames in memory are needed.
Create and configure databases in oracle database management system operation administration
Answer:
You typically create a database during Oracle Database software installation. However, you can also create a database after installation.
Reasons to create a database after installation are as follows:
You used Oracle Universal Installer (OUI) to install software only, and did not create a database. You want to create another database (and database instance) on the same host computer as an existing Oracle database. In this case, this chapter assumes that the new database uses the same Oracle home as the existing database. You can also create the database in a new Oracle home by running OUI again. You want to make a copy of (clone) a database.
SQLite is a database that comes with Android. Which statements is/are correct?
The content of an SQLite database is stored in XML formatted files because XML is the only file format supported by Android OS.
A SQLite database is just another name for a Content Provider. There is no difference as the SQLite implementation implements the Content Provider interface.
If an app creates an SQLite database and stores data in it, then all of the data in that particular database will be stored in one, single file.
A database query to an SQLite database usually returns a set of answers
To access individual entries, SQLite provides a so-called Cursor to enumerate all entries in the set.
This is yet another example of the Iterator pattern.
Answer:
1. Wrong as per my knowledge, SQLite may be an electronic database software that stores data in relations(tables).
2. Wrong. Content provider interface controls the flow of knowledge from your android application to an external data storage location. Data storage is often in any database or maybe it'll be possible to store the info in an SQLite database also.
3.Right. SQLite uses one file to store data. It also creates a rollback file to backup the stored data/logs the transactions.
4. Wrong. The queries are almost like a traditional electronic database system, the queries are going to be answered as per the conditions given and should return a group of answers or one answer depending upon the info and sort of query used.
5. Right. A cursor helps to point to one entry within the database table. this may be very helpful in manipulating the present row of the query easily.
Write a removeDuplicates() method for the LinkedList class we saw in lecture. The method will remove all duplicate elements from the LinkedList by removing the second and subsequent elements. If there is only one copy of an element, it is not removed. The list size should shrink accordingly based on the number of duplicates removed.
Answer:
removeDuplicates() function:-
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
Explanation:
Complete Code:-
//Create Linked List Class.
class LinkedList {
//Create head pointer.
static ListNode head;
//define structure of ListNode.
//it has int val(data) and pointer to ListNode i.e, next.
static class ListNode {
int val;
ListNode next;
//constructor to create and initialize a node.
ListNode(int d) {
val = d;
next = null;
}
}
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
//display() function prints linked list.
void display(ListNode node)
{
//run while loop till last node.
while (node != null)
{
//print node value of current node.
System.out.print(node.val + " ");
//move node pointer by one node.
node = node.next;
}
}
public static void main(String[] args) {
//Create object of Linked List class.
LinkedList list = new LinkedList();
//first we create nodes and connect them to form a linked list.
//Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.
//Create a Node having node data = 1 and assign head pointer to it.
//As head is listNode of static type. so, we call head pointer using class Name instead of object name.
LinkedList.head = new ListNode(1);
//Create a Node having node data = 2 and assign head.next to it.
LinkedList.head.next = new ListNode(2);
LinkedList.head.next.next = new ListNode(3);
LinkedList.head.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next = new ListNode(4);
LinkedList.head.next.next.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next.next.next = new ListNode(5);
LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);
//display linked list before Removing duplicates.
System.out.println("Linked List before removing duplicates : ");
list.display(head);
//call removeDuplicates() function to remove duplicates from linked list.
list.removeDuplicates();
System.out.println("")
//display linked list after Removing duplicates.
System.out.println("Linked List after removing duplicates : ");
list.display(head);
}
}
Output:-
What is the default return type of a method in Java language?
A.Void
B.Int
C.None
D.Short
Answer:
The default return data type in function is int
Answer: Option (b)
Explanation:
The default return data type in a function is int. In other words commonly if it is not explicitly mentioned the default return data type of a function by the compiler will be of an integer data type.
If the user does not mention a return data type or parameter type, then C programming language will inevitably make it an int.
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In the forward chaining technique, used by the inference engine component of an expert system, the _____ condition is evaluated first.
Answer:
"if" is the right response.
Explanation:
Forward chaining is being utilized just to split the logical sequential order down as well as operate throughout every component once the preceding one is accomplished, from start to finish.Its whole algorithm begins with proven information that activates all the rules, which are fulfilled as well as makes established realities even more complete.When rating ads, I should only consider my personal feelings on the ad.
Answer:
yes when rating ads you should only consider your personal feelings on the ad
Indicate whether the following actions are the actions of a person who will be a victim, or will not be a victim, of phishing attacks.
Replying to an e-mail requesting your user ID and password Phishing victim Not a phishing victim
Answer:
Phishing Victim
Explanation:
Replying to this email could make you a victim of a phishing scam. Phishing attacks are common challenges on security that internet users are faced with. It could lead to others getting hold of sensitive information like your password or bank details. email is one way the hackers used to get this information. replying to such an email could lead one to an unsecure website where information could be extracted
Write a programmer defined function that compares the ASCII sum of two strings. To compute the ASCII sum, you need to compute the ASCII value of each character of the string and sum them up. You will thus need to calculate two sums, one for each string. Then, return true if the first string has a larger ASCII sum compared to the second string, otherwise return false. In your main function, prompt the user to enter two strings with a suitable message and provide the strings to the function during function call. The user may enter multiple words for either string. Then, use the Boolean data returned by the function to inform which string has the higher ASCII sum.
Answer:
The program in Python is as follows:
def ASCIIsum(str1,str2):
asciisum1 = 0; asciisum2 = 0
for chr in str1:
asciisum1 += (ord(chr) - 96)
for chr in str2:
asciisum2 += (ord(chr) - 96)
if asciisum1 > asciisum2:
return True
else:
return False
str1 = input("Enter first string: ")
str2 = input("Enter second string: ")
if ASCIIsum(str1,str2) == True:
print(str1,"has a higher ASCII value")
else:
print(str2,"has a higher ASCII value")
Explanation:
This defines the function
def ASCIIsum(str1,str2):
This initializes the ascii sum of both strings to 0
asciisum1 = 0; asciisum2 = 0
This iterates through the characters of str1 and add up the ascii values of each character
for chr in str1:
asciisum1 += (ord(chr) - 96)
This iterates through the characters of str2 and add up the ascii values of each character
for chr in str2:
asciisum2 += (ord(chr) - 96)
This returns true if the first string has a greater ascii value
if asciisum1 > asciisum2:
return True
This returns false if the second string has a greater ascii value
else:
return False
The main begins here
This gets input for first string
str1 = input("Enter first string: ")
This gets input for second string
str2 = input("Enter second string: ")
If the returned value is True
if ASCIIsum(str1,str2) == True:
Then str1 has a greater ascii value
print(str1,"has a higher ASCII value")
If otherwise
else:
Then str2 has a greater ascii value
print(str2,"has a higher ASCII value")
how to identify mistakes in a html code??
A cashier distributes change using the maximum number of five-dollar bills, followed by one-dollar bills. Write a single statement that assigns num_ones with the number of distributed one-dollar bills given amount_to_change. Hint: Use %.
Sample output with input: 19
Change for $ 19
3 five dollar bill(s) and 4 one dollar bill(s)
1 amount_to_change = int(input())
2
3 num_fives amount_to_change // 5
4
5 Your solution goes here
6 I
7 print('Change for $, amount_to_change)
8 print(num_fives, 'five dollar bill(s) and', num_ones, 'one dollar bill (s)')
Answer:
Explanation:
The code that was provided in the question contained a couple of bugs. These bugs were fixed and the new code can be seen below as well as with the solution for the number of one-dollar bills included. The program was tested and the output can be seen in the attached image below highlighted in red.
amount_to_change = int(input())
num_fives = amount_to_change // 5
#Your solution goes here
num_ones = amount_to_change % 5
print('Change for $' + str(amount_to_change))
print(num_fives, 'five dollar bill(s) and', num_ones, 'one dollar bill (s)')
Gray London is a retired race car driver who helped Dale Earnhardt, Jr. get his start. He is writing a book and making a video about the early days or Dale Earnhardt. He is trying to decide whether to market these items directly over the Internet or to use intermediaries. To make this decision, he needs to know the pros and cons of each route. Provide that information and make a recommendation to him.
Answer:
Explanation:
Marketing your product directly over the internet can lead to much greater profits and there are many options that you can choose from in order to target the correct audience. Unfortunately, doing so does require marketing knowledge and is basically like growing a business. If you were to use intermediaries they already have the knowledge necessary to market your product but will take a percentage of the profits, which will ultimately limit your gains. Since Gray London is a race car driver, I am assumming that he does not have any prior technological expertise or marketing expertise, therefore I would recommend using intermediaries.
Given an array of n distinct integers sorted in ascending order, write a function that returns a Fixed Point in the array, if there is any Fixed Point present in array, else returns -1. Fixed Point in an array is an index i such that arr[i] is equal to i. Note that integers in array can be negative. Examples: #include using namespace std; void removeDivByFive(int *arr,int& size) { int index=0; for(int i=0;i
Answer:
The function is as follows:
int returnsFixed(int arr [],int n){
int retVal = -1;
for(int i = 0; i<n;i++){
if(i == arr[i]){
retVal = i;
break;
}
}
return retVal;
}
Explanation:
This defines the functionl it receives the array and the length of the array
int returnsFixed(int arr [],int n){
This initializes the return value to -1
int retVal = -1;
This iterates through the array
for(int i = 0; i<n;i++){
This checks if i equals arr[i]
if(i == arr[i]){
If yes, the return value (i.e. the fixed point) is set to i
retVal = i;
And the code is exited
break;
} This ends the if condition
} This ends the iteration
This returns the calculated fixed point
return retVal;
}
A blogger writes that the new "U-Phone" is superior to any other on the market. Before buying the U-Phone based on this review, a savvy consumer should (5 points)
consider if the blogger has been paid by U-Phone
assume the blogger probably knows a lot about U-Phones
examine multiple U-Phone advertisements
speak to a U-Phone representative for an unbiased opinion
Answer:
Speak to a U-Phone representative.
Explanation:
A representative will tell you the necessary details about the U-phone without any biases whatsoever, as they´re the closest to the company when it comes to detail about their products.
Which of the following restricts the ability for individuals to reveal information present in some part of the database?
a. Access Control
b. Inference Control
c. Flow Control
d. Encyption
Answer:
it would have to be flow control which would be C.
Explanation:
Flow Control is restricts the ability for individuals to reveal information present in some part of the database. Hence, option C is correct.
What is Flow Control?The management of data flow between computers, devices, or network nodes is known as flow control. This allows the data to be processed at an effective rate. Data overflow, which occurs when a device receives too much data before it can handle it, results in data loss or retransmission.
A design concern at the data link layer is flow control. It is a method that typically monitors the correct data flow from sender to recipient. It is very important because it allows the transmitter to convey data or information at a very quick rate, which allows the receiver to receive it and process it.
The amount of data transmitted to the receiver side without any acknowledgement is dealt with by flow control.
Thus, option C is correct.
For more information about Flow Control, click here:
https://brainly.com/question/28271160
#SPJ5
Write a program in Cto define a structure Patient that has the following members
Answer:
Explanation:
The answer should be 1.16 or 61.1
If the signal is going through a 2 MHz Bandwidth Channel, what will be the maximum bit rate that can be achieved in this channel? What will be the appropriate signal level?
Answer:
caca
Explanation:
Cardinality ratios often dictate the detailed design of a database. The cardinality ratio depends on the real-world meaning of the entity types involved and is defined by the specific application. For the binary relationships below, suggest cardinality ratios based on the common-sense meaning of the entity types. Clearly state any assumptions you make.
Entity 1 Cardinality Ratio Entity 2
1. Student SocialSecurityCard
2. Student Teacher
3. ClassRoom Wall
4. Country CurrentPresident
5. Course TextBook
6. Item (that can
be found in an
order) Order
7. Student Class
8. Class Instructor
9. Instructor Office
10. E-bay Auction item E-bay bid
Solution :
ENTITY 1 CARDINALITY RATIO ENTITY 2
1. Student 1 to many Social security card
A student may have more than one
social security card (legally with the
same unique social security number),
and every social security number belongs
to a unique.
2. Student Many to Many Teacher
Generally students are taught by many
teachers and a teacher teaches many students.
3.ClassRoom Many to Many Wall
Do not forget that the wall is usually
shared by adjacent rooms.
4. Country 1 to 1 Current President
Assuming a normal country under normal
circumstances having one president at a
time.
5. Course Many to Many TextBook
A course may have many textbooks and
text book may be prescribed for different
courses.
6. Item Many to Many Order
Assuming the same item can appear
in different orders.
7. Student Many to Many Class
One student may take several classes.
Every class usually has several students.
8. Class Many to 1 Instructor
Assuming that every class has a unique
instructor. In case instructors were allowed
to team teach, this will be many-many.
9. Instructor 1 to 1 Office
Assuming every instructor has only one
office and it is not shared. In case of offices
shared by 2 instructors, the relationship
will be 2-1. Conversely, if any instructor has a joint
appointment and offices in both departments,
then the relationship will be 1-2. In a very general
case, it may be many-many.
10. E-bay Auction item 1-Many E-bay bid
1 item has many bids and a bid is unique
to an item.
Functions IN C LANGUAGE
Problem 1
Function floor may be used to round a number to a specific decimal place. The statement
y = floor( x * 10 + .5 ) / 10;
rounds x to the tenths position (the first position to the right of the decimal point). The
statement
y = floor( x * 100 + .5 ) / 100;
rounds x to the hundredths position (the second position to the right of the decimal
point).
Write a program that defines four functions to round a number x in various ways
a. roundToInteger( number )
b. roundToTenths( number )
c. roundToHundreths( number )
d. roundToThousandths( number )
For each value read, your program should print the original value, the number rounded to
the nearest integer, the number rounded to the nearest tenth, the number rounded to
the nearest hundredth, and the number rounded to the nearest thousandth.
Input Format
Input line contain a float number.
Output Format
Print the original value, the number rounded to the nearest integer, the number rounded
to the nearest tenth, the number rounded to the nearest hundredth, and the number
rounded to the nearest thousandth
Examples
Example 1
Input 1
24567.8
Output 1
24567.8 24568 24570 24600
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have methods that return the following: the total rainfall for the year the average monthly rainfall the month with the most rain the month with the least rain Demonstrate the class in a complete program and use java 8 examples to do so. Input Validation: Do not accept negative numbers for monthly rainfall figures.
Answer:
Explanation:
The following code is written in Java. It creates the Rainfall class with two constructors, one that passes the entire array of rainfall and another that initializes an array with 0.0 for all the months. Then the class contains a method to add rain to a specific month, as well as the three methods requested in the question. The method to add rain validates to make sure that no negative value was added. 8 Test cases were provided, and any methods can be called on any of the 8 objects.
class Brainly {
public static void main(String[] args) {
Rainfall rain1 = new Rainfall();
Rainfall rain2 = new Rainfall();
Rainfall rain3 = new Rainfall();
Rainfall rain4 = new Rainfall();
Rainfall rain5 = new Rainfall();
Rainfall rain6 = new Rainfall();
Rainfall rain7 = new Rainfall();
Rainfall rain8 = new Rainfall();
}
}
class Rainfall {
double[] rainfall = {0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0};
public Rainfall(double[] rainfall) {
this.rainfall = rainfall;
}
public Rainfall() {
}
public void addMonthRain(double rain, int month) {
if (rain > 0) {
rainfall[month-1] = rain;
}
}
public double totalRainfall() {
double total = 0;
for (double rain: rainfall) {
total += rain;
}
return total;
}
public double averageRainfall() {
double average = totalRainfall() / 12;
return average;
}
public double rainiestMonth() {
double max = 0;
for (double rain : rainfall) {
if (rain > max) {
max = rain;
}
}
return max;
}
}
How can COUNTIF, COUNTIFS, COUNT, COUNTA, and COUNTBLANK functions aide a company to support its mission or goals
Answer:
Following are the responses to these questions:
Explanation:
It employs keywords to autonomously do work tasks. Users can type numbers directly into the formulas or use the following formulae, so any data the cells referenced provide would be used in the form.
For instance, this leadership involves accounting, and Excel is concerned with organizing and organizing numerical data. In this Equation, I can discover all its information in the data. This idea is simple me count the number many cells containing a number, and also the number of integers. It counts integers in any sorted number as well. As both financial analysts, it is helpful for the analysis of the data if we want to maintain the same number of neurons.
Explain the following terms.
a) Explain Final keyword with example. b) Define Static and Instance variables
Answer:
A.
the final keyword is used to denote constants. It can be used with variables, methods, and classes. Once any entity (variable, method or class) is declared final , it can be assigned only once.
B.
Static variables are declared in the same place as instance variables, but with the keyword 'static' before the data type. While instance variables hold values that are associated with an individual object, static variables' values are associated with the class as a whole.
You know different types of networks. If two computing station high speed network link for proper operation which of the following network type should be considered as a first priority?
MAN
WAN
WLAN
LAN
All of these
Answer:
All of these.
PLZ MARK ME BRAINLIEST.
3. Most widely used structure for recording database modifications is called
A. Scheduling
B. Buffering
C. Log
D. Blocking
Answer:
C. log
Explanation:
The log is a sequence of log records, recording all the update activities in the database
hope this helps
Answer:
C. Log is the
answer
Explanation:
a sequence of log records recording all update activity in database
????????????????????????????????
(c) 4
Explanation:The function strpos() is a function in php that returns the position of the first occurrence of a particular substring in a string. Positions are counted from 0. The function receives two arguments. The first argument is the string from which the occurrence is to be checked. The second argument is the substring to be checked.
In this case, the string is "Get Well Soon!" while the substring is "Well"
Starting from 0, the substring "Well" can be found to begin at position 4 of the string "Get Well Soon!".
Therefore, the function strpos("Get Well Soon!", "Well") will return 4.
Then, with the echo statement, which is used for printing, value 4 will be printed as output of the code.
write an algorithm for finding the perimeter of a rectangle
Assign courseStudent's name with Smith, age with 20, and ID with 9999. Use the print member function and a separate cout statement to output courseStudents's data. End with a newline. Sample output from the given program:
#include
#include
using namespace std;
class PersonData {
public:
void SetName(string userName) {
lastName = userName;
};
void SetAge(int numYears) {
ageYears = numYears;
};
// Other parts omitted
void PrintAll() {
cout << "Name: " << lastName;
cout << ", Age: " << ageYears;
};
private:
int ageYears;
string lastName;
};
class StudentData: public PersonData {
public:
void SetID(int studentId) {
idNum = studentId;
};
int GetID() {
return idNum;
};
private:
int idNum;
};
int main() {
StudentData courseStudent;
/* Your solution goes here */
return 0;
}
Answer:
Replace /* Your solution goes here */
with the following:
courseStudent.SetName("Smith");
courseStudent.SetAge(20);
courseStudent.SetID(9999);
courseStudent.PrintAll();
cout <<courseStudent.GetID();
Explanation:
From the given code segment, we have the following methods defined under the StudentData class;
SetName -> It receives name from the main
SetAge -> It receives age from the main
SetID --> It receives ID from the main and passes it to GetID method
printID --> Prints all the required output.
So, we have:
Pass name to setName
courseStudent.SetName("Smith");
Pass age to setAge
courseStudent.SetAge(20);
Pass ID to setID
courseStudent.SetID(9999);
Print all necessary outputs
courseStudent.PrintAll();
Manually print the student ID
cout <<courseStudent.GetID();
A recursive method may call other methods, including calling itself. A recursive method has:
1. a base case -- a case that returns a value or exits from a method without performing a recursive call.
2. a recursive case -- calling the method again with a smaller case..
Study the recursive method given below.
For example, this call recursiveMethod (5); returns 15:
public static int recursiveMethod (int num) (
if (num == 0)
return 1;
else {
if (numX2!=0)
return num * recursiveMethod (num -1);
else
return recursiveMethod (num-1);
}
}
1 What is the base case?
2. What does the following statement check?
3. What does the method do?
Answer:
Hence the answer is given as follows,
Explanation:
Base Case:-
If (num == 0) //This is the base case for the given recursive method
return 1;
If(num % 2!=0) checks whether num is odd.
The above condition is true for all odd numbers and false for even numbers.
if the remainder is not equal to zero when we divide the number with 2 then it is odd.
The method:-
The above recursive method calculates the product of odd numbers up to the given range(that is num)
For num=5 => 15(5*3*1).
For num=7 => 105(7*5*3*1).
For num=10 => 945(9*7*5*3*1).
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have methods that return the following:
the total rainfall for the year
the average monthly rainfall
the month with the most rain
the month with the least rain
Demonstrate the class in a complete program.
Input Validation: Do not accept negative numbers for monthly rainfall figures.
import java.io.*;
import java.util.*;
public class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
months[n-1] = in.nextInt();
}
}
public double getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is" + total);
return total;
}
public double getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is" + average);
return average;
}
public double getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amout of rainfall was" + largest +
"inches in month" + (largeind + 1));
return largest;
}
public double getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amout of rainfall was" + smallest +
"inches in month " + (smallind + 1));
return smallest;
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
System.out.println("Total" + r.getTotal());
System.out.println("Smallest" + r.getSmallest());
System.out.println("Largest" + r.getLargest());
System.out.println("Average" + r.getAverage());
}
}
Answer:
Explanation:
The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.
import java.io.*;
import java.util.*;
class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
int answer = 0;
while (true) {
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
answer = in.nextInt();
if (answer > 0) {
months[n-1] = answer;
break;
}
}
}
}
public void getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is " + total);
}
public void getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is " + average);
}
public void getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amount of rainfall was " + largest +
" inches in month " + (largeind + 1));
}
public void getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amount of rainfall was " + smallest +
" inches in month " + (smallind + 1));
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
r.getTotal();
r.getSmallest();
r.getLargest();
r.getAverage();
}
}
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