Answer:
Rise= y-axis
Run=x-axis
Slope=rate of change
Step-by-step explanation:
Think of run as you are running on the ground. The x-axis is positioned to look like you would be able to run on a flat horizontal line. When it is referring to run, it means the y-axis because when you run you go up in a way, just like the y-axis. Rise and Run is a phrase used to represent slope because it is indicating that to calculate slope, you take your "y" value over your "x" value as in a fraction. For example [tex]\frac{y}{x}[/tex]. Slope is just how fast a certain unit is changing at a consistent "speed".
Please help…
As soon as possible..
note: you may need to leave off the pi term if your teacher just wants to know what goes in the green box
======================================================
Work Shown:
C = 2*pi*r
C = 2*r*pi
C = 2*5*pi
C = 10pi
Two terms of a geometric sequence are given. Find the first five terms. Please help asap
Answer:
4, 8, 16, 32, 64
Step-by-step explanation:
The nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]
Given
a₇ = 256 and a₁₀ = 2048 , then
a₁ [tex]r^{6}[/tex] = 256 → (1)
a₁ [tex]r^{9}[/tex] = 2048 → (2)
Divide (2) by (1)
[tex]\frac{a_{1}r^{9} }{a_{1}r^{6} }[/tex] = [tex]\frac{2048}{256}[/tex]
r³ = 8 ( take the cube root of both sides )
r = [tex]\sqrt[3]{8}[/tex] = 2
Substitute r = 2 into (1)
a₁ × [tex]2^{6}[/tex] = 256
a₁ × 64 = 256 ( divide both sides by 64 )
a₁ = 4
Then
a₁ = 4
a₂ = 2a₁ = 2 × 4 = 8
a₃ = 2a₂ = 2 × 8 = 16
a₄ = 2a₃ = 2 × 16 = 32
a₅ = 2a₄ = 2 × 32 = 64
Given the arithmetic sequence 2, -7, -16, -25, ..., determine the
general term tn.
Answer:
Step-by-step explanation:
Common difference is -9.
t_1 = 2
t_n = t_1 - (n-1)9
= t_1 - (9n - 9)
= 2 - (9n - 9)
= 11 - 9n
Differentiate y= ln (6 – 3x)^4
Step-by-step explanation:
[tex] \frac{dy}{dx} = \frac{1}{ {(6 - 3x)}^{4} } \times {4(6 - 3x)}^{3} ( - 3) \\ = \frac{ - 12 {(6 - 3x)}^{3} }{ {(6 - 3x)}^{4} } \\ = - \frac{12}{6 - 3x} [/tex]
I hope I'm correct. I've never learnt differentiation for log and exponents before
Which is true about the solution to the system of inequalities shown?
y > 3x + 1
y < 3x – 3
they don't share any points
that's one thing, but I don't know what your options are of course.
see screenshot for illustration of the inequalities
what is the additive inverse of -61
Answer:
The additive inverse of -61 is 61. For additive inverse just reverse the sign.
In isoceles triangle the length of a leg is 17cm, and the base is 16cm. Find the length of the altitude to the base
This triangle has base 16 therefore the sides must be 17cm and 17 cm
When we make a altitude it divides it into two right triangles and there is a property in which the altitude of the isoceles triangle divides the base in 2 equal halves
So the side of the right triangle will be x , 8 , 17
Using pythgoreus theorem
x²+8²=17²
x = √225
x = 15
So the altitude is 15 cm
Must click thanks and mark brainliest
Can someone please help me I don’t know how to do this (Due today)
First go to the y intercept (or the b in y=mx+b) look for the slope and plot the points on the graph they're talking about e.g. #23 the y-intercept is 6 go to the 6 on the y axis, and then look at the slope (x), so it goes up and over to the right since it's positive by 1
Find a if ZB = 25°, ZC = 48°, AC = 5.
Answer:
11.3
Step-by-step explanation:
a = AC × sin(A)/sin(B)
Now <A =180-25-48 = 107
a = 5×sin(107)/sin(25)
a ≈ 11.3
Answered by GAUTHMATH
the cost of plastering a wall of a room having length 8m and heights 4m at Rs 15 per m² is Rs 1560 . find the cost of carpeting the room at rs 300 per m²
Step-by-step explanation:
here ,
length = 8m
height=4m
Rate of plastering 4 walls = 15/m^2
Cost of plastering 4 wall = Rs 1560
Area of floor = Cost of plastering / Rate of plastering
= 1560/15
= 104
again,
Area of four wall = 2h(l+b)
or, 104= 2×4(8+b)
or, 104 =8(8+b)
or, 104/8=8+ b
or,13 - 8= b
or, b= 5
again,
Area of floor= l×b
= 8×5
= 40
again,
Rate of carpeting the floor= 300/ m^2
Area of floor = 40 m^2
cost of carpeting=Rate × Area
= 300×40
= 12000
pls pls pls help meeeeee
Answer:
i think you just extend the coordinates to the side, except the right point, by 3, and then the bottom ones go down by 3, and the top one goes up by 3
Step-by-step explanation:
Problem 1 Find the mBC.
Answer:
m BC = 100
Step-by-step explanation:
Since the angle is at the center, the arc has the same measurement as the angle
m BC = 100
Diagnostic
Analytics
When completing an online shopping transaction, a typical shopper takes 7 seconds to
select each product and another 9 seconds to complete the check-out process. If it takes 37
seconds to complete a transaction, how many products are being purchased?
products
Submit
Answer:
In 26 seconds to complete a transaction, 2 products are being purchased.
Step-by-step explanation:
1 item = 9 seconds
Time taken in all to check out = 8 seconds
Time taken to shop = 26 seconds
Now as check out process takes 8 seconds, so the
Time left to ACTUALLY SHOP = Total Time - Time Used to check out
= 26 seconds = 8 seconds = 18 seconds
Shopping of 1 item = 8 seconds
Shopping of 2 items = 2 x ( Time taken in 1 item) = 2 x 9 = 18 seconds
So, in 18 seconds, 2 clothing item can be selected.
Hence,in 26 seconds to complete a transaction, 2 products are being purchased.
What is the solution set to this equation?
log_4(x + 3) + log_4x = 1
Answer:
x=1
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
We know that loga(b) + loga(c) = loga(bc)
log_4(x + 3)x = 1
Raise each side to the base of 4
4^log_4(x + 3)x = 4^1
(x+3)x = 4
x^2 +3x = 4
Subtract 4 from each side
x^2 +3x -4 = 0
Factor
(x+4) (x-1) =0
Using the zero product property
x= -4 x=1
But x cannot be negative since logs cannot be negative
x=1
Answer:
A.. x = 1.
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
log_4 x(x + 3) = log_4 4
Removing the logs:
x(x + 3) = 4
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x = 1, -4.
We can ignore the -4 as there is no log of a negative.
Combine these radicals.
Anyone pls I need
Answer:
-26 sqrt(3)
Step-by-step explanation:
-12 sqrt(12) - 2 sqrt(3)
Rewriting
-12 sqrt(4*3) - 2 sqrt(3)
We know sqrt(ab) = sqrt(a)sqrt(b)
-12 sqrt(4)sqrt(3) - 2 sqrt(3)
-12 (2) sqrt(3) - 2 sqrt(3)
-24 sqrt(3) - 2 sqrt(3)
-26 sqrt(3)
Can anyone pls help me with this I'll mark as brainlist for correct answer please do explain in detail each answers Ty! (I'm preparing for my maths exam tmr)
Question 8
a^2 + 7a + 12
= (a+3)(a+4)
When factorising a quadratic, the product of the two factors should equal the constant term (12), and the sum of the two factors should equal the linear term (7). To find the two factors, list out the factors of 12 (1x12, 2x6, 3x4) and identify the pair that adds up to 7 (3+4).
An alternative method if you get stuck during your exam would be to solve it algebraically using the quadratic formula and then write it in the factorised form.
a = (-7 +or- sqrt(7^2 - 4(1)(12)) / 2(1)
= (-7 +or- sqrt(1))/2
= -3 or -4
These factors are the negative of the values that would go in the brackets when written in factorised form, as when a = -3 the factor (a+3) would equal 0. (If it were positive 3 instead, then in the factorised form it would be a-3).
Question 10
-3(x - y)/9 + (4x - 7y)/2 - (x + y)/18
Rewrite each fraction with a common denominator so you can combine the fractions into one.
= -6(x - y)/18 + 9(4x - 7y)/18 - (x + y)/18
= (-6(x - y) + 9(4x - 7y) - (x + y)) /18
Expand the brackets and collect like terms.
= (-6x + 6y + 36x - 63y - x - y)/18
= (29x - 58y)/18
= 29/18 x - 29/9 y
find the angle measures given the figure is a rhombus.
[tex] \large \tt{{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]
A rhombus is a parallelogram in which all sides are equal i.e AB = BC = CD = CA Let ∠ A be x. In the ∆ ABC , AB = AC which means they are isosceles triangle and we know the opposite angles of isosceles triangle are equal i.e ∠ A = ∠ C = x. The sum of angles of a triangle is always 180°. Now , Find out the value of x :[tex] \large{ \tt{❁ \:x + x + 98 = 180 \degree \: [ Sum\: of \: angle \: of \: a \: triangle ]}}[/tex]
[tex] \large{ \tt{⟶2x + 98 \degree= 180 \degree}}[/tex]
[tex] \large{ \tt{⟶ \: 2x = 180 \degree - 98 \degree}}[/tex]
[tex] \large{ \tt{⟶ \: 2x = 82 \degree}}[/tex]
[tex] \large{ \tt{ ⟶x = \frac{82 \degree}{2} }}[/tex]
[tex] \large{ \tt{⟶ \: x = 41 \degree}}[/tex]
The value of x is 41°. Now , Find the measure of ∠ 1 :[tex] \large{ \tt{ ↔\angle \: 1 = x \degree = \boxed{41 \degree}}}[/tex] [ Being alternate angles ]
Hence , Our final answer is 41° .- Alternate angles are the non-adjacent interiors pair of angles lying to the opposite side of a transversal when it intersects two straight line segments. Alternate angles form ' Z ' shape.
Hope I helped! Let me know if you have any questions regarding my answer. :)Economy Hardware Store ordered items retailing for $2,500. They received a chain discount of 20/5/2. Find the net cost.
The net cost after discounts will be $ 2,450.
Given that Economy Hardware Store ordered items retailing for $ 2,500, and they received a chain discount of 5/20/2, the following calculation must be performed to find the net cost, knowing that the net cost is equal to the initial cost minus the discounts made about it:
First, the discount percentage must be calculated.
5/20/2 = X
4/2 = X
2 = X
Then, this percentage must be subtracted from the initial value.
2500 x (1-0.02) = X
2500 x 0.98 = X
2450 = X
Therefore, the net cost after discounts will be $ 2,450.
Learn more in https://brainly.com/question/17003148.
Angles 1 and 2 are supplementary. 2 lines intersect to form angles 1 and 2. Which equation represents the relationship between their measures?
Answer:
[tex]\angle 1 + \angle 2 = 180^o[/tex]
Step-by-step explanation:
Given
[tex]\angle 1[/tex] and [tex]\angle 2[/tex]
Required
The relationship between them [tex]\angle 1[/tex] and [tex]\angle 2[/tex]
From the question, we understand that [tex]\angle 1[/tex] and [tex]\angle 2[/tex] are supplementary
Supplementary angles add up to 180.
So, the relationship between [tex]\angle 1[/tex] and [tex]\angle 2[/tex] is:
[tex]\angle 1 + \angle 2 = 180^o[/tex]
FIND the product
(5a³-3a²+8)(3a-4)
The cube with side 2 is cut from the corner of rectangular prism with dimensions 4×3×5. Find the volume and total surface area of the new object.
Answer:
Volume: 52 Units Squared
Surface Area: 94 units.
Step-by-step explanation:
The volume is relatively simple to find. Just subtract the original volume by the 2x2x2 cube's volume. The original volume is 60. The cube's volume is 2x2x2 which is 8. 60-8=52.
The surface area is harder to find. Try to envision the corner of the rectangle being cut out. We see that each side of the cube has a surface area of 2x2 which is 4. In the picture, we see that three sides of the rectangle has been partially removed. But since each side of the cube has an equal surface area, it is safe to minus 3 of the sides that has been partially removed by 3. However, since that it is the corner, the "dent" that the cube made in the rectangle also needed to be counted. As we said, each of the sides of a cube has a surface area of 4, so since that the dent has 3 sides, we see that the surface area of the dent is 4x3 which is 12. Now we need to count the unaffected sides of the rectangle. There are three of them. Just multiply the edges to find the surface area of each side. Add all of the values up: 11+16+12+8+15+12+20=94 units.
3(-4x - 3) + 50 - 5= 0
Answer:
-12x-9+50-5=0
-12x+41-5=0
-12x+36=0
-12x=0-36
x= -36/-12
x = 3 Answer...
hope it helps
Answer:
[tex]x=3[/tex]
Step-by-step explanation:
[tex]3(-4x - 3) + 50 - 5= 0[/tex]
⇒ Subtract 50- 5 from both sides:-
[tex]3\left(-4x-3\right)+50-5-\left(50-5\right)=0-\left(50-5\right)[/tex]
[tex]3\left(-4x-3\right)=-45[/tex]
⇒ Divide both sides by 3:-
[tex]\frac{3\left(-4x-3\right)}{3}=\frac{-45}{3}[/tex]
[tex]-4x-3=-15[/tex]
⇒ Add 3 to both sides:-
[tex]-4x-3+3=-15+3[/tex]
[tex]-4x=-12[/tex]
⇒ Divide both sides by -4:-
[tex]\frac{-4x}{-4}=\frac{-12}{-4}[/tex]
[tex]x=3[/tex]
OAmalOHopeO
Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?
Answer:
Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:
1) [tex]\frac{a + i\,b}{c + i\,d}[/tex] Given.
2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.
3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex] Existence of additive inverse/Definition of division.
4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex] [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]
5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex] Distributive and commutative properties.
6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.
7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.
8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.
Step-by-step explanation:
Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:
1) [tex]\frac{a + i\,b}{c + i\,d}[/tex] Given.
2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.
3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex] Existence of additive inverse/Definition of division.
4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex] [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]
5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex] Distributive and commutative properties.
6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.
7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.
8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.
Which angle number represents an angle adjacent to /EHD?
In the diagram, ∠5 is adjacent to ∠EHD.
Angle
Angles are formed when two rays intersect at a point. An angle is also formed when to lines intersect each other, thereby the two lines share a common endpoint.
Adjacent angles are two angles that have a common side and a common vertex (corner point). They are placed side by side to each other.
In the diagram, ∠5 is adjacent to ∠EHD.
Find out more on Angle at: https://brainly.com/question/25770607
The quantity of milk consumed in five households in a week is 10L.12.13 L. 11 L and
14 L Find the mean weekly consumption of milk by these bouseholds. Also find the number
of households whose consumption is more than the mean weekly consumption
Answer:
12
Step-by-step explanation:
Add 10l to 12l to13l to11l to 14l=60l the divide 60l by the number of houses which will be 12 and there is your correct answer
A man invested a certain amount of money in a bank at a simple interest rate of 5percent per annum. At the end of the year, his total amount un the bank was GHC 840,000.00. How much sid he invest in the bank.
Answer: He invested 8,00,000.
Step-by-step explanation:
R = 5%
A = 840,000
T = 1 year
so
so
I = A-P
so
I = PTR/100
or, A-P = (p*1*5)/100
or, 840,000-P = 5p/100
or, 8,40,00,000-100P = 5p
or, 8,40,00,000 = 105P
so, p = 8,40,8,40,00,000
so, P = 8,00,000
How would I do this??
Part 1
[tex]\left(\frac{g}{h}\right)(x) = \frac{g(x)}{h(x)}\\\\\left(\frac{g}{h}\right)(x) = \frac{3x-5}{-2x^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{3(3)-5}{-2(3)^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{4}{-11}\\\\\left(\frac{g}{h}\right)(3) = -\frac{4}{11}\\\\[/tex]
Answer: -4/11
====================================================
Part 2
Set the denominator function equal to zero and solve for x to find which values to kick out of the domain.
[tex]h(x) = 0\\\\-2x^2+7 = 0\\\\7 = 2x^2\\\\2x^2 = 7\\\\x^2 = 7/2\\\\x^2 = 3.5\\\\x = \sqrt{3.5} \ \text{ or } x = -\sqrt{3.5}\\\\[/tex]
This shows that if x is equal to either of those values, then the denominator h(x) will be zero. These are the values to kick out of the domain to prevent a division by zero error. Any other value of x is valid in the domain.
Answer: [tex]x = \sqrt{3.5} \text{ and } x = -\sqrt{3.5}\\\\[/tex]
If 4 tickets to a show cost $17.60, what is the cost of 7 such tickets.
Answer:
30.80
Step-by-step explanation:
We can use a ratio to solve
4 tickets 7 tickets
------------------- = ----------------
17.60 dollars x dollars
Using cross products
4x = 17.60 * 7
4x =123.2
Divide each side by 4
4x/4 = 123.2/4
x=30.8
Help anyone can help me do this question,I will mark brainlest.
Answer:
Step-by-step explanation:
Find the value of x for which l||m
Answer:
30 =x
Step-by-step explanation:
The angles are correcting angle and corresponding angles are equal when the lines are parallel
55 = x+25
Subtract 25 from each side
55-25 = x+25
30 =x