Answer:
a small medical thermometer with a short but finely calibrated range, for taking a person's temperature.
Answer:
Thermometer which are used in clinical to measure the temperature of human body is called clinical thermometer.
Answer these three please! Thank you <3333
(I will give brainliest)
Answer:
Explanation:
21:B 22:B
Explain in a short sentence how you can tell a reaction is a decomposition reaction.
Answer: A decomposition reaction occurs when one reactant breaks down into two or more products.
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What is the percent composition of Phosphorus in Li3PO3
Answer:
you will get 17.983 g of lithium for every 100 g of lithium phosphate.
Explanation:
69.7% is the percent by mass of Lithium in Li[tex]_3[/tex]PO[tex]_3[/tex]. A percent is obtained by multiplying the result by 100.
One approach to show the concentration for an element within a compound or component in a combination is as a mass percentage. The mass percentage is computed by dividing the total weight of the combination by the mass of each component and multiplying the result by 100%. The mass percent is calculated by dividing the mass that contains the compound and solute by the mass for the element or solute.
99.795g/mol = molar mass of Li[tex]_3[/tex]PO[tex]_3[/tex]
6.94g/mol = molar mass of Li
mass percentage of Li=(molar mass of Li/molar mass of Li[tex]_3[/tex]PO[tex]_3[/tex])× 100
=(6.94/99.7)× 100
=69.7%
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1. __N2 + __H2-> __NH3
2. __Fe + __HCl-> __H2 + __FeCl3
Answer:
N2+ 3H2-> 2NH3
2Fe + 6HCl -> 3H2 + 2FeCl3
Explain five physical and/or chemical properties that you need to consider for the substances before using them as construction materials for buildings
Answer: There are many properties of a metal which is taken into consideration when it is used for construction
Explanation:
The properties can be physical, chemical, et cetera. The physical properties that is considered are:
1. Durability: It can be defined as the property of the material to withstand the atmospheric pressure and other factors.
2. Density: The ratio of mass by volume of a material (homogeneous material) is called as density.
3. Fire resistance: The ability of the material to withstand in fire without changing its size or shape.
4. Weather resistance: The ability of the material to withstand the weather which could be variable round the year.
5.Water absorption: The ability of the material to absorb water and retain it.
5. CaCO, - CaO+CO,
Reaction Type
Answer:
(a) Decomposition: A substance breaks down to smaller species. [e.g. CaCO3(s) → CaO(s) + CO2(g) Decomposition of limestone to calcium oxide (quicklime) and carbon dioxide on heating.]
An object has a mass of 26.94 grams and a volume of 2.568 cubic centimeters. What material is it likely to be
made of?
Substance iron gold silver copper
Density (g/cm) 7.874 19.32 10.49 8.92
a. Silver
c. Iron
b. Gold
d. Copper
Answer:
a) silver
Explanation:
Given data:
Mass of object = 26.94 g
Volume of object = 2.568 cm³
Which subject is this = ?
Solution:
Formula:
d = m/v
by putting values
d = 26.94 g/ 2.568 cm³
d = 10.49 g/cm³
Densities of objects: g/cm³
iron = 7.874
gold = 19.32
silver = 10.49
copper = 8.92
Thus, given object is silver.
Which characteristic do euglenoids and algae share?
Both are fungus-like protists.
Both can be autotrophic.
Both have whip-like tails.
Both are decomposers.
To solve this we must be knowing each and every concept related to autotroph. Therefore, eugenides and algae, both can be autotrophic. The correct option is option B.
What is autotroph?An creature that can make its own sustenance out of inorganic materials is known as an autotroph. Contrarily, heterotrophs are species that can't make their own nutrition and must eat other organisms in order to survive.
In contrast to autotrophs, heterotrophs are unable to manufacture their own nourishment. Heterotrophs need to consume organic material in order to produce the nutrients needed for life, not inorganic. Eugenides and algae, both can be autotrophic.
Therefore, Eugenides and algae, both can be autotrophic. The correct option is option B among all the given options.
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In which highlighted section of the periodic table in the diagram provided above are the elements whose atoms have 1 valence electron located?
A) a
B) b
C) c
D) d
Answer:
B.
Explanation:
I don't really understand this worksheet question.
what type of heat transfer takes place when you come in contact with a snow flake on a cold day?
Answer:
Conduction
Explanation:
Conduction is how heat transfers through direct contact with objects that are touching. Any time that two objects or substances touch, the hotter object passes heat to the cooler object.
Answer:
Conduction
Explanation:
Conduction is how heat transfers through direct contact with objects that are touching. Any time that two objects or substances touch, the hotter object passes heat to the cooler object.
an object moving with a speed of 5m/s has a kinetic energy of 100J what is the mass of the object
Answer:
k. e. = 1/2 mv^2
100 = 1/2 * m * 5^2
100 = 1/2 * m * 25
m = 100 *2/25
m = 8 kg
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The general area of the atom (outside the nucleus) where the e- are located is the — and —
which are exmaples of chemical change?
•baking cookies
• The statue of liberty's metal tarnishes from copper to green
• cold butter melts into liquid when heated
•salt is dissolved into freshwater
•Food scraps decompose into fertilizer in a compost pile
• frying changes the color and texture of an egg
•ocean water evaporates to water vapor on a hot day
•lighting a match
Answer:
cold butter melted when heated, lighting a match, baking cookies,
Explanation:
What happens to valence electrons in ionic bonding?
Answer:
they are either donated to or taken by another atom to achieve octet arrangement
Explanation:
for example Na+ and Cl- .. they both have one extra and one less electron .
so they donate and receive one electron to/from each other to achieve the octet arrangement ..
If you find a chemical in the lab and are unsure of
its identity, what is the best way to find out what it
is?
Answer:
C. read the label on the container
Explanation:
What information is found in an SDS? Check all that apply.
A. the identification of the chemical
C. the chemical and physical properties of the substance
D. the first-aid measures to take if an accident occurs involving the chemical
Answer:
C
Explanation:
just did it
5. Describe the effects of photons of light on an electron of the hydrogen atom
Answer:
How do atoms give off light?
Atoms emit light when they are heated or excited at high energy levels. The color of light that is emitted by an atom depends on how much energy the electron releases as it moves down different energy levels. ... It shows the electron moving down energy levels.
Explanation:
determine the theoretical yield.
aluminum metal reacts with aqueous nickel II sulfate to produce aqueous aluminum sulfate and nickel as a precipitate. in this reaction 108 grams of aluminum were combined with 464 grams of nickel II sulfate to produce 274 grams of aluminum sulfate.
The question is incomplete, the complete question is;
In this stoichiometry problem, determine the percentage yield:
Excess aluminum metal reacts with aqueous nickel(II) sulfate to produce aqueous aluminum sulfate and nickel as a precipitate. In this reaction 108 g of aluminum were combined with 464 g of nickel(II) sulfate to produce 274 g of aluminum sulfate.
Answer:
80%
Explanation:
The correct equation for this reaction is;
2Al(s) + 3NiSO4(aq) --------> Al2(SO4)3 + 3Ni(s)
We already know that Al is in excess then NiSO4 is the limiting reactant.
Hence, Number of moles in 464 g of NiSO4 = mass/ molar mass
Molar mass of NiSO4 = 155 g/mol
Number of moles = 464g/155g/mol = 2.99 moles
Number of moles of Al2(SO4)3 = mass/molar mass
molar mass = 342 g/mol
So, Number of moles = 274g/342g/mol = 0.8 moles
Given the stoichiometric reaction equation;
3 moles of NiSO4 yields 1 mole of Al2(SO4)3
2.99 moles of NiSO4 yields 2.99 * 1/3 = 1 mole of Al2(SO4)3
percentage yield is given by; actual yield/ theoretical yield * 100/1
actual yield = 0.8 moles of Al2(SO4)3
Theoretical yield = 1 mole of Al2(SO4)3
Hence;
% yield = 0.8/1 * 100 = 80%
Structural formula of 2 ethyl, 4 methyl-Heptane