Deja is training for a race on Saturday. On Sunday, she runs 1/6 of a mile. On Monday she runs 1/5 of a mile. On Tuesday she runs 1/4 of a mile. On Wednesday she runs 1/3 of a mile. On Thursday she runs 1/2 of a mile. Finally, on Friday, the day before the race, she runs a whole mile. If the length of the race is the same as the total distance Deja ran in preparation, how many miles is the race?

Answer:

Step-by-step explanation:

Answer:

x=6

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

x = 6

Step-by-step explanation:

In this equation, we are told to solve for the value of x. Thus, we must isolate the variable x (poor x... we're always trying to isolate it).

3 - 2x = -1.5x

(I'm going to swap sides to make it easier for me to solve. This doesn't change anything mathematically due to the associative laws. It's purely cosmetic.)

-1.5x = 3 - 2x

First, we can add 2x to both sides of the equation to get all algebraic expressions containing the variable x on one side of the equation alone.

0.5x = 3

For our next part here, let's convert 0.5 to a fraction to make life easier for us.

[tex]\frac{1}{2}[/tex]x = 3

When isolating x in this, we are trying to get rid of 1/2. How can we do this? We can multiply is by 2!

[tex]\frac{1}{2}[/tex]x · [tex]\frac{2}{1}[/tex] = 1x (or simply x)

What we do to one side we must do to another.

x = 3 · 2

x = 6

Our answer is x = 6. Woo!

Answer:

Brainliest please

The  Volume is 125 times bigger.

Step-by-step explanation:

V = [tex]\frac{4}{3}*\pi *r^{3}\\[/tex] is the normal formula.

If you multiply the radius by 5 the it changes to

V = [tex]\frac{4}{3}*\pi *(5r)^{3}[/tex]

And when you simplify you get

V = [tex]\frac{4}{3} * \pi * 125r^3[/tex]

And the only difference between the inital equation and this one is *125 and so the volume is 125 bigger if the radius is multiplied by 5.

Answer:

This first expression is correct

V= 2/3*pi*r³

Step-by-step explanation:

This problem bothers on the volume of a cone

We know that the volume of a cone is expressed as

V= 1/3πr²h

Given that h= 2r

Let us substitute h=2r in the formula above

V= 1/3πr²*2r

V= 2/3πr³

The Answer Is:

2/3pix^3

Answer:

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

Please have a look at the attached photo.  

My answer:

1. Chuck wants to draw three-dimensional figures whose lateral faces are rectangles. He says he can draw prisms and pyramids. Do you agree

No, I do not agree because:

2. Part B. Chuck says that he can draw a cylinder on his polyhedron poster because it has a pair of bases that are congruent.

No, do not agree because:

A  cylinder has two congruent bases but it is not a  polyhedron while a cylinder has a curved surface when a polyheron has faces that are polygons

Hope it will find you well.

1x1x1.  That's pretty much the definition of

Answer: 1 cubic foot, last choice

Answer:

64 - 8 + 12 x (2 + 9) = 188

Step-by-step explanation:

64 - 8 + 12 x 2 + 9 = 188

Putting parentheses around two numbers and one operation:

64 - 8 + 12 x (2 + 9) = 188

Following the BODMAS principle

Solving the bracket or parentheses first

(2 + 9) = 11

64 - 8 + 12 × 11

Then multiplication:

12 × 11 = 132

64 - 8 + 132

Then addition:

-8 + 132 = 124

64 + 124 = 188

Hence the proof

Answer:

1. x=3, y=1

2. x=1, y= 1

3.( i dont know what the first expression means, are you multiplying 4x and 5y or adding it?)

4. x=1 , y=2

Step-by-step explanation:

This is simple simultaneous equations. You need to eliminate one element in each of the two equations, either y or x and the calculate for the other value.

Answer:

Step-by-step explanation:

There must be an attachment. I have no knowledge of what to solve for, unless you can tell or show me the missing pieces.

Answer: 1, 3 , 5, and 6

I took the test have a great day!

Answer:

[tex]73\%[/tex]

Step-by-step explanation:

Given: Present weight of Caleb’s puppy = 2,250 grams

Puppy weighed 600 grams at his last visit to the veterinarian’s office.

To find: percent increase in the puppy’s weight rounded to the nearest whole number

Solution:

Increase in puppy's weight = 2250 - 600 = 1650 grams

Percent increase in the puppy’s weight =( Increase in puppy's weight/Present weight of Caleb’s puppy) × 100 = [tex]\frac{1650}{2250}(100)=73.33 \%[/tex]

[tex]73.33\%[/tex] is rounded to [tex]73\%[/tex]

Answer:

1 hour and 20 minutes

Step-by-step explanation:

Answer:

Total time taken by Natalie to reach the airport is 1 hour and 20 minutes

the correct answer is -4π/3.

Answer:

$39

Step-by-step explanation:

Using the given formula :

I = P × R × T

I = 30 × 10/100 × 3

I = $9

She have = 30 + 9 = $39

Answer:

Step-by-step explanation:

43feet

Answer:

-1

Step-by-step explanation:

Take the two points

(-2,4) and (4,-2)

And we can find the  slope

m = (y2-y1)/(x2-x1)

   = (-2-4)/( 4 - -2)

   =(-2-4)/(4+2)

   = -6/6

   = -1

Answer:

300 Backpacks each week]

Step-by-step explanation:

dont have an explanation srry but the answer is totally 300 backpacks a week

Answer:

30

Step-by-step explanation:

Answer:

You'll find the answer below each.

Step-by-step explanation:

1-4 you can use this formula: [tex]V=l*h*w[/tex]

1.

[tex]V=l*w*h\\V=(6ft)(4ft)(1ft)\\V=24ft^3[/tex]

2.

[tex]V=l*h*w\\V=(2yd)(\frac{1}{2}yd )(2yd)\\V=2yd^3[/tex]

3.

[tex]V=l*h*w\\V=(12\frac{1}{2}mm)(3mm)(4mm)\\V=150mm^3[/tex]

4.

[tex]V=l*h*w\\V=(2cm)(8.5cm)(2cm)\\V=34cm^3[/tex]

5-7 you need these 2 formulas: [tex]A=\frac{bh}{2}[/tex] and [tex]V=Bh[/tex] or you can use one formula which is: [tex]V=\frac{bh}{2}*h[/tex]

Let me explain. The first formula is for finding the area of the base of the triangle and the second formula is for finding the volume of the prism using the area previously mentioned. The first h is with respect to the triangle and the second h is with respect to the prism.

5.

[tex]V=\frac{bh}{2}*h\\V=\frac{(8in)(6in)}{2}* 18in\\V=\frac{48in^2}{2}*18in\\ V=48in^2*9in\\V=432in^3[/tex]

6.

[tex]V=\frac{bh}{2}*h \\V=\frac{(11m)(5m)}{2}*35m \\V=\frac{55m^2}{2}*35m\\ V=\frac{1925m^3}{2}\\ V=962.50m^3[/tex]

7.

[tex]V=\frac{bh}{2}*h \\V=\frac{(5mm)(8mm)}{2}*12mm\\V=\frac{40mm^2}{2}*12mm\\ V=40mm^2*6mm\\V=240mm^3[/tex]

For the last one, we have a special case.

This formula is a bit odd and long.

[tex]V=\frac{1}{4}h(\sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4}[/tex]

a=8yd

b=15yd

c=17yd

h=11yd

[tex]V=\frac{1}{4}(11yd)(\sqrt{-(8yd)^4+2[(8yd)(15yd))]^2+2[(8yd)(17yd)]^2-(15yd)^4+2[(15yd)(17yd)]^2}[/tex][tex]-(17)^4[/tex]

As you can see this is long. I'll just jump to the answer.

Answer: [tex]660yd^3[/tex]

Answer:

He is correct

Step-by-step explanation:

Answer

7.85

but I not sure JutMon21 know the problem

Answer:

I got 7.85

Step-by-step explanation:

First, I took the center angle which is 90 degrees in this case and divided by 360 and I got 0.25 Then, I multiplied that number by the radius which is 5 and I got 1.25. After that I multiplied 1.25 with 2π and the final answer that I got is 7.85

Answer:

B = 41.81

Step-by-step explanation:

sin B = opposite/ hyp

sin B = 2/3

Take the inverse sin of each side

sin ^-1 sin (B) =sin ^-1 (2/3)

B =41.8103149

To the nearest hundredth

B = 41.81

Answer:

v= 904.78

Step-by-step explanation:

Answer:

904.77868423386 feet^3

Step-by-step explanation:

Step one the formula is 4/3 Pie R ^3

Step two you do 4/3 x PI x 6^3

Step three do exponents first so 6x6x6=216

Step four multiply 4/3 x 3.14 which equals 4.187

Step four finally you are going to multiply 216 by 4.187 to get   904.77868423386 feet^3

Answer:

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is expressed as shown;

[tex]Tn = a+(n-1)d[/tex]

a is the first term of the sequence

n is the number of terms

d is the common difference

If T₁₂ = 70 and T₃₀ = 124

T₁₂  = a+(12-1)d = 70

T₁₂  = a+11d = 70... (1)

Similarly;

T₃₀ = a + (30-1)d = 124

T₃₀ = a +29d = 124...(2)

Solving equation 1 and 2 simultaneously to get a and d.

Subtracting 2 from 1 we have;

29d - 11d = 124-70

18d = 54

d = 54/18

d = 3

Substituting d = 3 into equation 1 to get a we have;

a + 11(3) = 70

a + 33 = 70

a = 70-33

a = 37

The explicit rule for the nth term of the sequence can be gotten by substituting the value of a and d into the formula Tn = a+(n-1)d

Tn = 37+(n-1)*3

Tn = 37+3n-3

Tn = 34+3n

Answer:

The correct answer is B.

Step by step explanation:

Domain of [tex]x^2-4 : \left [ {{Solution : - \infty} <x<\infty}} \atop {Interval Notation: (-\infty, \infty})}} \right][/tex]

Range of [tex]x^2-4:[/tex][tex]x^2-4 : \left [ {{Solution : f(x)\geq -4}} \atop {Interval Notation: [-4, \infty})}} \right][/tex]

Axis interception points of [tex]x^2-4 :[/tex] X Intercepts: [tex](2,0), (-2,0)[/tex], Y Intercepts: [tex](0,-4)[/tex]

Vertex of [tex]x^2-4:[/tex] Minimum [tex](0,-4)[/tex]

Hope this helps. If so, may I get brainliest and a thanks?

Thank you, Have a good day!

Answer:

{FL1, FL2, IT1, IT2, ME1, ME2, EN1, EN2}

Step-by-step explanation:

This is each location paired with one week, and each location paired with two weeks.

Answer:

c

Step-by-step explanation:

Answer:

1. 48 + 86 + + Q = 180

2. 46 degrees

3. They are congruent

Step-by-step explanation:

I just got them right on edg

Angle sum property (In ΔPQR, ∠P + ∠Q + ∠R = 180°) can be used to determine the measure of angle Q.

Using angle sum property, ∠Y = 46°.

It can be concluded that ∠Y = ∠Q.

The angle sum property of a triangle states that the sum of the angles of a triangle is equal to 180º.

In ΔPQR,

∠P + ∠Q + ∠R = 180° (angle sum property)

86 + ∠Q + 48 = 180

∠Q = 180 - 86 - 48 = 46°

In ΔXYZ,

∠X + ∠Y + ∠Z = 180° (angle sum property)

86 + ∠Y + 48 = 180

∠Y = 180 - 86 - 48 = 46°

As visible, ∠Q = ∠Y.

Learn more about angle sum property here

https://brainly.com/question/4316040

#SPJ3

Answer:

a) 60 times

b) 0.24

c) 150 times

Step-by-step explanation:

Two rectangles can be similar, but that's not always guaranteed.

In fact, similar shapes have the same angles and correspondant sides in proportion.

All rectangles will always have four right angles, so we only have to worry about the sides.

Let [tex]a,b[/tex] be the sides of a rectangle, with [tex]a\leq b[/tex]. Let [tex]c,d[/tex] be the sides of a rectangle, with [tex]c\leq d[/tex].

Then, the two rectangles are similar if and only if

[tex]a\div c=b\div d[/tex]

So, for examples, a rectangle with dimensions 3 and 7 is similar to a rectangle with sides 6 and 14 (both sides have been doubled), but it's not similar to a rectangle with sides 6 and 21 (one side has been doubled, the other has been tripled).