Determine the Concentration of the Unknown Strong Acid
In this activity you will use the virtual lab to determine the concentration of a strong monoprotic acid. To do this, you can perform
a titration using NaOH and phenolphthalein found in the virtual lab. (Note: The concentration of the acid is between 0.025M and
2.5M so you will need to dilute the NaOH solution so that the volume to reach the endpoint is between 10 and 50 mL).
Once you have determined the concentration of the acid, please enter your answer into a form at the bottom of this page.
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Unknown Acid Problem
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Answers

Answer 1
Hey baby I know it’s late but I wanted to say how are u doing

Related Questions

In the presence of excess iodide ions, the iodine formed by reaction of iodide with NBS will react further to form triiodide ions. What does the triiodide combine with to form the blue color of the endpoint

Answers

Answer:

Starch.

Explanation:

When the triiodide combine with starch, it forms dark blue colour. Amylose in starch is responsible for the occurrence of a deep blue color when the iodine is combine with the starch. The iodine molecule goes inside of the amylose coil which makes a linear triiodide ion complex that goes into the coil of the starch that leads to an intense blue-black color in the end so we can say that starch turns the colour into blue.

For the reaction...
N2 + O2 <=> 2NO: AH = +182 kJ mol-1.
If the temperature is increased the equilibrium position will shift
Your answer:
a) to the left
b) to the right
c) to the left and right
d) neither left nor
right

Answers

Answer:

B

Explanation:

AH is positive so the forward reaction is endothermic. Thus, increasing temperature would cause equilibrium to shift to the right as endothermic reaction favors higher temperature. This increases the yield of NO.

Answer: B

Explanation:

How many carbon dioxide molecules react to form one glucose molecule during photosynthesis

Answers

Answer:

6 molecules

Explanation:

Only three elements are present in the products of photosynthesis: oxygen, carbon, and hydrogen. These same elements are present in the reactants of photosynthesis. Notice that it takes six molecules of water and six molecules of carbon dioxide to make one molecule of glucose

Answer:

6 molecules of carbone dioxide.

what's the ph of 0.0000067 m hcl solution

Answers

Answer:

[tex]pH = - log[H {}^{ + } ] \\ = - log(0.0000067) \\ pH = 5.17[/tex]

PLEASE is possible to calculate the theoretical yield without a balanced equation?

Answers

No, you absolutely need a balanced equation because you need the coefficients to figure out the molar ratios plus you need the amount of one reactant or product to determine the theoretical yield.

No, it's not possible to calculate the theoretical yield  without a balanced equation.

What is the theoretical yield?

Theoretical yield is the yield that is calculated by the complete reaction of the limiting reagent. This is called expected or calculated amount of product.

[tex]\rm percent\; yield = \dfrac{(actual\; yield)}{(theoretical\; yield)} \times 100\\\\[/tex]

Thus, No, it's not possible to calculate the theoretical yield  without a balanced equation.

Learn more about theoretical yield

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Name an alkene that would yield the alcohol above on hydration. (Submit a single name even if there is more than one correct answer. Ignore double bond stereochemistry.) Name: fill in the blank 75a878faaf91fe7_1 2,3-Dimethylpentane . Specify whether you would use hydroboration/oxidation or oxymercuration.

Answers

Answer:

Enzyme ? ...............

1) 7.269 moles of oxygen gas are used in combusting butane (C H..). How many moles of carbon dioxide
gas are produced? You must start with a balanced chemical equation. Start with a balanced equation

Answers

Explanation:

C4H10 + 13/2O2 ---------> 4CO2 + 5H2O

so u can work out the amount of moles by doing

moles=mass/mr

mr of C4H10 is 12 × 4 + 10 =58

=7.269/58

= 0.125moles

Then u can use the molar ratio which is

6.5:4

0.125 ÷6.5 × 4 = 0.0769moles

hope this helps:)

a sample of cobalt, A, with a mass of 5.00g, is initially at 25 C. When this sample gains 6.70 J of heat, the temperature rises to 27.9 C. Another sample of cobalt, B, with a mass of 7.00 g, iw initially at 25 C. If sample B gains 5.00 J of heat, what is the final temperature of sample B

Answers

Answer:

26.5°C

Explanation:

We can solve this question using the equation:

q = m*S*ΔT

Where Q is heat gained in joules, m is the mass of the sample, S is specific heat and ΔT change in temperature.

With the sample A we can find specific heat of cobalt in order to find, in sample B, the ΔT and the final temperature:

Sample A:

q = m*S*ΔT

6.70J = 5.00g*S*(27.9°C-25.0°C)

0.462J/g°C = Specific heat of cobalt

Sample B:

q = m*S*ΔT

5.00J = 7.00g*0.462J/g°C*ΔT

1.5°C = ΔT

As the initial temperature of sample B is 25°C, final temperature is:

25°C + 1.5°C = 26.5°C

Match the following parts of an atom to their description.
Neutron
?
Negatively charged
particle that moves
around the nucleus
Nucleus
?
Positively charged particle
in the nucleus
Electron
2
Noncharged particle in the
nucleus
Proton
?
Composed of protons and
neutrons

Answers

Answer:

Neutron - non charged particle in nucleus

nucleus - composed of proton and Neutron

electron - negatively charged particle that moves around the nucleus

proton - positively charged particle in the nucleus.

Explanation:

these the are definitions of the terms

Determine the mass in grams of hydrogen gas produced if 40.08 g of calcium react with excess aqueous hydrogen phosphate.

Answers

Answer:

[tex]2.02gH_2[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to to calculate the mass of hydrogen gas by firstly setting up the undergoing chemical reaction:

[tex]2H_3PO_4+3Ca\rightarrow Ca_3(PO_4)_2+3H_2[/tex]

Thus, we apply the following stoichiometric setup, whereas the atomic mass of calcium is 40.08 g/mol, that of hydrogen is 2.02 g/mol and the mole ratio of these two substances is 3:3:

[tex]40.08gCa*\frac{1molCa}{40.08gCa}*\frac{3molH_2}{3molCa}*\frac{2.02gH_2}{1molH_2} \\\\=2.02gH_2[/tex]

Regards!


The table below provides data about a gas sample.
Volume
1.0 L
Pressure
303.9 kPa
Temperature
323 K
Which of the following can be determined using the data?
A the chemical composition of the gas
B. the condensation temperature of the gas
C. the distance between gas molecules in the sample
D. the number of gas molecules in the sample

Answers

Answer:

the number of gas molecules in the sample

How many grams of carbon atoms are present in a sample of C3H8 if there are 4.70 moles of hydrogen atoms in the sample

Answers

Answer:

21.12 grams

Explanation:

Using the given number of hydrogen moles, we calculate the number of carbon atoms, keeping in mind that there are 3 carbon moles per hydrogen mol:

4.70 mol H * [tex]\frac{3molC}{8molH}[/tex] = 1.76 mol C

Finally we convert 1.76 moles of carbon into grams, using its molar mass:

1.76 mol * 12 g/mol = 21.12 g

38. Consider the following equilibrium:
2CO(g) + O2(g) =2CO2
Keg=4.0 x 10-10
What is the value of Key for 2CO2(g) + 2COR + O2g) ?​

Answers

Answer:

[tex]Key=2.5x10^{-9}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

[tex]2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)[/tex]

By knowing that the equilibrium expression is actually:

[tex]Key =\frac{[CO]^2[O_2]}{[CO_2]^2} =\frac{1}{Keg}[/tex]

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

[tex]Key =\frac{1}{4.0x10^{-10}}\\\\Key=2.5x10^{-9}[/tex]

Regards!

Calculate the volume of 0.320-M NaOH solution needed to completely neutralize 74.0 mL of a 0.230-M solution of the monoprotic acid HBr. mL NaOH.

Answers

Answer:

53.2 mL

Explanation:

As this problem deals with the neutralization of a strong monoprotic acid and a strong base, we can solve it by using the following formula:

Ca * Va = Cb * Vb

Where in this case:

Ca = 0.230 MVa = 74.0 mLCb = 0.320 MVb = ?

We input the data:

0.230 M * 74.0 mL = 0.320 M * Vb

And solve for Vb:

Vb = 53.2 mL

4. Cuanto electrones se necesitan para
pesarlo mismo que un proton?

Answers

Answer:

aproximadamente dos mil

Explanation:

masa_proton/masa_electron=

1.673e-24 / 9.11e-28 = 1836.443468715697

Which is an example of poor safety practices when working outdoors

Answers

Answer:

C

Explanation:

u can't touch a chemical with bare skin

Answer:

touching a chemical with his or her bare skin.

What's 2+7 hehdhenbeidbnejdbdbdbdi

Answers

Answer:

Answer

9......

Explanation:

Explaination:

Define pure substance. How is it classified on the basid of chemical properties?​

Answers

Answer:

if it is pure, the substances is either an element or a compound. if a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. if its composition is uniform throughout, it is a homogeneous.

How to change τhe color of silver mercury to red???

Answers

Answer: This is the hue of mercury if you're looking for it. Mercury reacts with sulphur to generate a crimson hue. In the past, they always used a thermometer.

Explanation:  However, due of its toxicity, individuals have switched to using alcohol in glass thermometers, which work similarly to mercury thermometers.

hope this helped best of luck mate! :) if this helped make sure to mark me Brainliest!

A student sets up the following equation to convert a measurement.
(The stands for a number the student is going to calculate.)

Fill in the missing part of this equation.

Answers

Answer:

–0.13 Pa.m²

Explanation:

From the question given above, the following data were obtained:

Measurement (Pa.mm²) = –1.3×10⁵ Pa.mm²

Measurement (Pa.m²) =?

We can convert from Pa.mm² to Pa.m² by doing the following:

1 Pa.mm² = 1×10¯⁶ Pa.m²

Therefore,

–1.3×10⁵ Pa.mm² = –1.3×10⁵ Pa.mm² × 1×10¯⁶ Pa.m² / 1 Pa.mm²

–1.3×10⁵ Pa.mm² = –0.13 Pa.m²

Thus, –1.3×10⁵ Pa.mm² is equivalent to –0.13 Pa.m².

The complete equation will be:

[tex](-1.3\times 10^5 Pa.mm^2)\times 10^{-6}=(-0.13) Pa.m^2[/tex]

Explanation:

Given:

The equation to convert a measurement:

[tex](-1.3\times 10^5 Pa.mm^2)\times ? = ? Pa.m^2[/tex]

To find:

The missing part of the equation.

Solution:

[tex](-1.3\times 10^5 Pa.mm^2)\times ? = ? Pa.m^2[/tex]

On LHS the unit is in [tex]Pa. mm^2[/tex] and RHS the unit is in [tex]Pa.m^2[/tex] which means that we have to convert [tex]mm^2[/tex] to [tex]m^2[/tex]

In 1 millimeter there are 0.001 meters.

[tex]1 mm = 0.001 m\\1 mm^2=0.000001 m^2=10^{-6} m^2[/tex]

So, the complete equation will be:

[tex](-1.3\times 10^5 Pa.mm^2)\times 10^{-6}=(-0.13) Pa.m^2[/tex]

Learn more about conversions here:

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Which expression gives the standard enthalpy
change of formation for methanol?

Answers

Answer:

25

Explanation:

bec

Read the given equation:
NH + HCI - NH4ACI
Which of the following is true about the equation?
NH3 is the acid and NH4Cl is the salt.
NH3 is the base and NH4Cl is the salt.
HCI is the acid and NH3 is the salt.
HCl is the base and NH3 is the salt.

Answers

Answer:

NH3 is the base and NH4Cl is the salt.

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to rewrite the chemical equation and thus obtain:

[tex]NH_3+HCl\rightarrow NH_4Cl[/tex]

Whereas it is possible to notice that ammonia, NH3, received the hydrogen ions from HCl to form NH4 ions and Cl ions; in such a way, we infer that NH3 is the base and NH4Cl is the salt.

Regards!

Answer:

NH3 is the base and NH4Cl is the salt

Explanation:

What is the Kc expression for this reaction?
2 NO(g) + O2(g) ⇌ 2 NO2(g)

a)Kc = [NO2]2 / [NO]2 [O2]
b)Kc = [NO]2 [O2] / [NO2]2
c)Kc = [NO]2 [O2] [NO2]2
d)Kc = [NO2]2 / [NO]2 + [O2]

Answers

Answer:

D

Explanation:

because product are at the top and reactant are at the bottom also it to the power of the moles in front e.g 2NO it will be to the power of 2 in this case.

hope it make sense :)

molar mass of Beryllium

Answers

Answer:

The molar mass of Beryllium is 9.012182 u

How is the enthalpy of reaction shown in this potential energy diagram

Answers

Answer:

In the given potential energy diagram, the energy of product at higher level and energy of reactant at lower level. The for this reaction will be positive. So, the enthalpy of reaction is defined as the difference of the energy of the reactants and the energy of the products.

Hope this is fine for you,,!

select the two atomic models that belong to the same element !

Answers

Answer:

The second and the third atomic model.

Explanation:

An element is identified by the no. of protons in the said element. Proton number cannot be changed. Both second and third atomic model have 5 protons, so they are of the same element.

Star
Planet
*
As the planet makes one completer revolution around the star, starting at the position shown the gravitational attraction between the star
and the planet will
A Continually decrease
3 Decrease, then increase
increase then decrease
Romain the same
RI
12.20 AM
618/2001

Answers

Answer:

according to the path shown in the figure it will start decreasing then again it will start increasing when the path will be nearer to the star.

Reason is gravitation force is indirectly proportional to the distance.

So, option B. decrease then increase is correct

what will happen if atom hit earth with speed of light?​

Answers

Answer:

A little atom will leave a big hole and a big atom cant travel that fast

Explanation:

I need the answer please

Answers

Answer:

the answer is the first one

Na+

HELP!!! i will give brainliest!!

Different chemical elements have different chemical symbols, and this is determined by their atomic structure. Look at the two chemical symbols in the image. Compare and contrast the atomic symbols and the atomic structure of fluorine and oxygen.

Answers

Answer:

Explanation:

fluorine have gained one electron that is why the sign is -1. they both have different number of protons. They have different neutron numbers. F have 10 and O have 8.

hope this helps :)

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