Determine the mass of 2.86 mole Co(NH3)6Cl3

Answer:

765 g Co(NH₃)₆Cl₃

General Formulas and Concepts:

Explanation:

Step 1: Define

2.86 mol Co(NH₃)₆Cl₃

Step 2: Define conversions

Molar Mass of Co - 58.93 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Co(NH₃)₆Cl₃ - 58.93 + 6(14.01) + 18(1.01) + 3(35.45) = 267.52 g/mol

Step 3: Dimensional Analysis

[tex]2.86 \ mol \ Co(NH_3)_6Cl_3(\frac{267.52 \ g \ Co(NH_3)_6Cl_3}{1 \ mol \ Co(NH_3)_6Cl_3} )[/tex] = 765.107 g Co(NH₃)₆Cl₃

Step 4: Simplify

We are given 3 sig figs. Follow sig fig rules.

765.107 g Co(NH₃)₆Cl₃ ≈ 765 g Co(NH₃)₆Cl₃

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