Determine the number of subatomic particles in bromine-35.

Answers

Answer 1

Number of subatomic particles=35+36+35=106

Explanation:

Atomic number=35

Mass number=71

No. of proton p=35

No. of neutron n=71−35=36

No. of electron e=35


Related Questions

Por qué razón se fomenta la inmigración Europea?​

Answers

Hola aquí va la respuesta!

Se fomentó la inmigración europea porque la economía no era buena y vinieron a Paraguay para mejorar su situación.

Hola aquí va la respuesta!

Se fomentó la inmigración europea porque la economía no era buena y vinieron a Paraguay para mejorar su situación.

Use mathematics to prove that the 5.50 grams of salicylic acid (C7H6O3) used in this experiment is equal to 0.04 mol.

Answers

Answer:

Please find the answer to the question below

Explanation:

In chemistry, the following mathematical formula is used to calculate the number of moles contained by a substance:

mole = mass of substance (g)/molar mass of substance (g/mol)

Molar mass of salicylic acid (C7H6O3) = 12(7) + 1(6) + 16(3)

= 84 + 6 + 48

= 138g/mol

Mass = 5.50grams

mole = 5.5/138

mole = 0.039

Approximately, the number of moles of 5.5grams of salicylic acid is 0.04moles. This is in accordance with the mole value (0.04) given in this question.

What is the delta H when 72.0 grams H2O condenses at 100.00C?

Here are some constants that you MAY need.

specific heats heat of fusion heat of vaporization

H2O(s) = 2.1 J/g0C 6.01 kJ/mole 40.7 kJ/mole

H2O(L) = 4.18 J/g0C

H2O(g) = 1.7 J/g0C



2930 kJ


163 kJ


-163 kJ


-2930 kJ

Answers

Answer: The value of [tex]\Delta H[/tex] is -163 kJZ

Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

We are given:

Given mass of water = 72.0 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

[tex]\text{Moles of water}=\frac{72.0g}{18g/mol}\\\\\text{Moles of water}=4mol[/tex]

Calculating the heat released for the condensation process:

[tex]\Delta H=n\times \Delta H_{(vap)}[/tex] ......(2)

where,

[tex]\Delta H[/tex] = amount of heat released

n = number of moles of water = 4 moles

[tex]\Delta H_{(vap)}[/tex] = specific heat of vaporization = -40.7 kJ/mol

Negative sign represents the amount of heat released.

Putting values in equation 2:

[tex]\Delta H=4mol\times (-40.7kJ/mol)=-163kJ[/tex]

Hence, the value of [tex]\Delta H[/tex] is -163 kJ

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