Determine whether each pair of segments is congruent.

Plz can someone help me

Step-by-step explanation:

for a=

[tex] \frac{s - n}{n} [/tex]

Answer:

Step-by-step explanation:

Given,

[tex] \frac{ \sqrt[4]{9} \sqrt{9} }{ \sqrt[4]{ {9}^{5} } } [/tex]

[tex] = \frac{ \sqrt[4]{9} \sqrt{9} }{ \sqrt[4]{9 \times 9 \times 9 \times 9 \times 9} } [/tex]

[tex] = \frac{ \sqrt[4]{9} \sqrt{9} }{9 \sqrt[4]{9} } [/tex]

[tex] = \frac{ \sqrt{9} }{9} [/tex]

[tex] = \frac{ {9}^{ \frac{1}{2} } }{ {9}^{1} } [/tex]

[tex] = {9}^{ \frac{1}{2} - 1} [/tex]

[tex] = {9}^{ - \frac{1}{2} } (ans)[/tex]

Answer:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

We have that the distance around the park to the nearest yard,QM to the nearest yard and the Time of travel for man's jog is given respectively as

From the Question we are told that

[tex]PQ=(50-10)=40\\\\QR=(80-10)70[/tex]

Generally the equation for the Resultant PR is mathematically given as

[tex]PR=\sqrt{PQ^2+QR^2}\\\\PR=\sqrt{70^2+40^2}\\\\PR=80yd[/tex]

a)

Generally the equation for the Distance around they park is mathematically given as

[tex]X=PQ+QR+PR\\\\X=80+70+40\\\\[/tex]

[tex]X=190yd[/tex]

b)

Generally the equation for the Path QM is mathematically given as

From the diagram we see that

[tex]QM=PM=MR\\\\QM=\frac{80}{2}\\\\[/tex]

[tex]QM=40yd[/tex]

c)

From the question we are told

Average speed of [tex]150yd/m[/tex]

Total distance traveled

[tex]D_t=40+40+40+70+40\\\\D_t=230yd[/tex]

Therefore

Time

[tex]T=\frac{D_t}{V}\\\\T=\frac{230}{150}[/tex]

[tex]T=1.5minutes.[/tex]

in conclusion

The distance around the park to the nearest yard,QM to the nearest yard and the Time of travel for man's jog is given respectively as

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Therefore, In the similarity transformation of ΔACB to ΔEFD, ΔACB was dilated by a scale factor of 2, reflected across the y-axis, and moved through the translation 2 units

What is graph transformation?

The technique of altering an existing graph or graphed equation to create a different version of the following graph is known as graph transformation. In particular, the change of algebraic equations, it is a typical kind of algebraic problem.

Graphs can be extended, rotated, inverted, or any combination of these transformations; they can also be translated or moved along the xyxy plane. The formulas "move the function f(x)f(x) by cc units in some direction," "stretch the function f(x)f(x) by cc units," and "rotate the function f(x)f(x) by xx units about the xx-, yy-, or zz-axis" are frequently used in mathematical issues. In every instance, the transformation has specific, calculable effects on the underlying function.

Since the triangle ABC and DEF is similar

So we can write,

DE/BC=EF/AB=FD/CA

scale factor =Length of CA/length of DF

                     =6/3

                      =2:1

Reflected at y axis i.e x=0

and raised by 2 units.

Therefore, In the similarity transformation of ΔACB to ΔEFD, ΔACB was dilated by a scale factor of 2, reflected across the y-axis, and moved through the translation 2 units

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Answer:

- 6[tex]x^{4}[/tex] + 14x³ + 8x² - 18x - 10

Step-by-step explanation:

Given

(3x² - 4x - 5)(- 2x² + 2x + 2)

Each term in the second factor is multiplied by each term in the first factor, that is

3x²(- 2x² + 2x + 2) - 4x(- 2x² + 2x + 2) - 5(- 2x² + 2x + 2) ← distribute parenthesis

= - 6[tex]x^{4}[/tex] + 6x³ + 6x² + 8x³ - 8x² - 8x + 10x² - 10x - 10 ← collect like terms

= - 6[tex]x^{4}[/tex] + 14x³ + 8x² - 18x - 10

Answer:

Step-by-step explanation:

[tex]U=\{(x,y)\ \zeta\ y=|x+1| \ and\ x \in \{-2,-1,0,1,2\}\ \}\\\\\begin{array}{|c|c|}x&y\\---&---\\-2&2\\-1&0\\0&2\\1 & 4\\2&6\\---&---\\\end{array}\\\\U=\{(-2,2),(-1,0),(0,2),(1,4),(2,6)\}\\[/tex]

Answer:

2 / (-2,2)

Step-by-step explanation:

Answer:

The total cost was $52. Subtracting out the cost of the layer cake ($16) leaves us with $36 to pay for the 24 cupcakes. This means that each cupcake must have cost $1.50 ( = $36 / 24 cupcakes ).

Step-by-step explanation:

Answer:

Below

Step-by-step explanation:

First let us create an equation for this problem

     (24 cupcakes)( $ of each cupcake) + ( $16 layer cake ) = $52

Let's say that C will represent the $ of each cupcake to make it easier

Solving it....

     24C + 16 = 52

     24C = 36

Divide both sides by 24

          C = 1.5

Therefore, each cupcake cost $1.5

We can check to see if this works....

     24(1.5) + 16 = total cost

            36 + 16 = 52, so this is correct

Hope that helped! Best of luck <3

Answer:

[tex] \frac{1}{3} (2x - y) = z \\ \frac{2}{3} x - \frac{y}{3} = z \\ \frac{2}{3} x = z + \frac{y}{3} \\ \frac{2}{3} x = \frac{3z + y}{3} \\ x = \frac{3z + y}{3} \div \frac{2}{3} \\ x = \frac{3z + y}{3} \times \frac{3}{2} = \frac{3(3z + y)}{6} \\ \\ x = \frac{3z + y}{2} \\ \\ x = \frac{3z}{2} + \frac{y}{2} [/tex]

I hope I helped you^_^

Answer:

m = -18

Step-by-step explanation:

6 + m/2 = -3

Subtract 6 from each side

6 + m/2 -6 = -3-6

m/2 = -9

Multiply each side by 2

m/2 * 2 = -9*2

m = -18

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{6+ \dfrac{m}{2}=-3}}}\\\huge\boxed{\rightarrow\mathsf{6 + \dfrac{1}{2}m = -3}}[/tex]

[tex]\huge\boxed{\rightarrow \mathsf{\dfrac{1}{2}m+ 6 = -3}}\\\\\huge\boxed{\text{SUBTRACT 6 to BOTH SIDES}}\\\huge\boxed{\mathsf{\dfrac{1}{2}m + 6 - 6 = -3 + 3}}[/tex]

[tex]\huge\boxed{\mathsf{\dfrac{1}{2}m = -9}}[/tex]

[tex]\huge\boxed{\text{MULTIPLY 2 to BOTH SIDES}}[/tex]

[tex]\huge\boxed{\mathsf{\dfrac{1}{2}m \times 2 = 2 \times -9}}[/tex]

[tex]\huge\boxed{\mathsf{m = 2\times-9}}\\\huge\boxed{\mathsf{2\times-9 = m}}\\\huge\boxed{\mathsf{2\times-9 = \bf -18}}\\\\\huge\boxed{\textsf{Therefore, your answer: \bf -18}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

The cube root of 27 is 3!!

Answer:

that answer is (1)

hope that helps you

9514 1404 393

Answer:

  1

Step-by-step explanation:

You can put either number in the form of the other to see they are equal. A number divided by itself gives a quotient of 1.

  -1 1/10 = -(10·1 +1)/10 = -11/10 . . . . . matches the denominator

or

  -11/10 = -1 1/10 . . . . . matches the numerator

__

  (-11/10)/(-11/10) = 1 . . . . your quotient

_____

Additional comment

Here, we see that both numbers in the problem are negative, so we have an even number of minus signs. That means the quotient will be positive. Knowing this lets us eliminate the minus signs from the problem.

As you may know, there are a couple of (fully equivalent) ways to divide fractions.

1) "invert and multiply" or "dot swap"

  (11/10) ÷ (11/10) = (11/10) · (10/11) . . . . . . . the denominator has been inverted

  = (11·10)/(10·11) = 110/110 = 1

2) use the numerators when the denominators are equal.

  (11/10) / (11/10) = 11/11 = 1 . . . . denominators of the fractions are both 10

The median of that data set is 9.

Sort the numbers from least to greatest and find the middle number (that should be your median)

If there are 2 numbers in the middle of the set, then you take the average and that would be your median.

Answer:

The selling price of 21 articles is equal to the cost price of 18 articles. Find the loss percent. Answer: answer is 100/7 %

Step-by-step explanation:

[tex]thank \: you[/tex]

Answer:

y=5-2x

2 5-2(2)=5-4=1

0 5-2(0)=5

4 5-2(4)=5-8=-3

Answer:

ball$

Step-by-step explanation:

<3

Answer:

13

Step-by-step explanation:

3x13-4=35 Hope this helps

Step-by-step explanation:

Hope it helps.

Thank you

interval notation of x<2

x=1

Answer:

33

Step-by-step explanation:

608pages/16h = 33pages/h

Answer:

a= 1 , b= 3 , c= –3

[tex]x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{ - 3 \frac{ + }{} {} \sqrt{ {3}^{2} - 4(1)( - 3)} }{2(1)} \\ = \frac{ - 3 \frac{ + }{} \sqrt{9 + 12} }{2} = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = \frac{ - 3 \frac{ + }{} \sqrt{21} }{2} \\ \\ x = 0.79 \\ x = - 3.79[/tex]

I hope I helped you^_^

Answer:

97

Step-by-step explanation:

388 (number of tickets) / 4 (number of groups (adults, and the 3 times as many kids))

If the number of student tickets sold was three times the number of adult tickets sold, 97 adult tickets were sold.

Let's assume the number of adult tickets sold is 'x.'

According to the information given, the number of student tickets sold was three times the number of adult tickets sold. So, the number of student tickets sold is 3x.

The total number of tickets sold is the sum of the adult and student tickets, which is 388:

x + 3x = 388

Now, combine like terms:

4x = 388

To find the value of 'x,' divide both sides of the equation by 4:

x = 388 / 4

x = 97

To verify the result, let's find the number of student tickets:

Number of student tickets = 3 * 97 = 291

Now, let's add the adult and student tickets:

97 (adult) + 291 (student) = 388

The result checks out, and we have 97 adult tickets and 291 student tickets, which together sum up to the total of 388 tickets sold for the school play.

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Answer:

False.

Step-by-step explanation:

.

17+1= 18

12= -6

12-17= -5 + 1 =-4.

Answer:

False

Step-by-step explanation:

12- (17 + 1) = (12 - 17) + 1

PEMDAS says parentheses first

12- (18) = (-5) + 1

Then add and subtract

-6 = -4

They are not equal

Step-by-step explanation:

In triangle ADE:

sum of all angles is 180.

3x-10+58+42=180

3x+90=180

3x=180-90

3x=90

x=90/3

x=30

As line DA and CB are parallel:

angle D=angle C

angle y=58

In angle BCE, sum of angles is 180.

z+58+42=180

z+100=180

z=180-100

z=80

Answer:

I have ans in the picture form.

Step-by-step explanation:

Take it

Answer:

Each of the domain values, x, should only output a single unique range value, y.

This example is a relation and not a function because the the domain value of -1 output 2 distinct range values.

-1 outputs a 3

and

-1 outputs a 5

If I were to draw a vertical line at the domain value of -1 that vertical line would intersect the points (-1,3) and (-1,5). Which indicates that the relation is not a function.

Answer:

None of the following set of points represents a function .

Answer:

27 square are there in the given figure

Answer:

<ALS - <2 = <1

< LDA + <ADE = 180  degrees

Step-by-step explanation:

<ALS = <1+<2

<ALS - <2 = <1

< LDA + <ADE = 180  degrees since it forms a straight line

Answer:

False, assuming "combined" means "added or subtracted and would simplify."

[tex]x^2[/tex] and [tex]x[/tex] cannot be combined with addition or subtraction.  They are not like terms.

Step-by-step explanation:

Combining like terms only works if the variables and the powers on the variables match perfectly.  

Examples:

[tex]x^2[/tex] and [tex]x[/tex] don't have matching powers, so they're not like terms.

[tex]x^2[/tex] and [tex]y^2[/tex] have the same powers, but the variables don't match, so they're not like terms.

Anything can be multiplied together though.  So that's a different situation.