Answer:
The compression ratio is 10
Explanation:
Given
[tex]V_d = 450cm^3[/tex] --- swept volume
[tex]V_c = 50cm^3[/tex] --- compression volume
Required
Determine the compression ratio (CR)
This is calculated as:
[tex]CR = \frac{V_d + V_c}{V_c}[/tex]
[tex]CR = \frac{450+50}{50}[/tex]
[tex]CR = \frac{500}{50}[/tex]
[tex]CR = 10[/tex]
Answer:
10 is the compression ratio of an engine that has a swept volume of 450cm3 and a clearance volume of 50cm3.
Explanation:
determine the compression ratio using
[tex] \frac{vd + vc}{vc} = \frac{450 + 50}{50} [/tex]
A(n) 28.3 g bullet is shot into a(n) 5004 g wooden block standing on a frictionless surface. The block, with the bullet in it, acquires a speed of 1.7 m/s. Calculate the speed of the bullet before striking the block. Answer in units of m/s
Answer:
the speed of the bullet before striking the block is 302.3 m/s.
Explanation:
Given;
mass of the bullet, m₁ = 28.3 g = 0.0283 kg
mass of the wooden block, m₂ = 5004 g = 5.004 kg
initial velocity of the block, u₂ = 0
final velocity of the bullet-wood system, v = 1.7 m/s
let the initial velocity of the bullet before striking the block = u₁
Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
0.0283u₁ + 5.004 x 0 = 1.7(0.0283 + 5.004)
0.0283u₁ = 8.5549
u₁ = 8.5549 / 0.0283
u₁ = 302.3 m/s
Therefore, the speed of the bullet before striking the block is 302.3 m/s.
b) When the muscles connected to the crystalline lens contract fully, its focal length is 16.5000 cm. With this focal length, how far away must an object be to form sharply focused images on the retina? (Note: this distance is called the far point of vision.)
c) When the muscles connected to the crystalline lens relax, the focal length is 9.0000 cm. With this focal length, how close must an object be to form sharply focused images on the retina? (Note: this distance is called the near point of vision.)
d) As people age, the crystalline lens hardens (a condition called presbyopia or “old-age” eyes) and can only vary in focal length from 12 to 15.60 cm. Calculate range of vision (the new near point and far point) for this older eye.
e) Based on part d) why might an older person hold the newspaper at arm’s length to read it?
Answer:
I have to go to work and figure it out
An object travels 4 km from A to B towards north and then 3 km from B to C towards west. Find its displacement.
QUËSTIONS:-
An object travels 4 km from A to B towards north and then 3 km from B to C towards west. Find its displacement.
ANSWER:- displacement
[tex] {x}^{2} = {3 }^{2} + {4}^{2} \\ {x}^{2} = 9 + 16 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5[/tex]
displacement = 5 km
Explanation:
We nee to use triangle law
As displacement is the shortest path travelled, we take A-C
so, D=√4^2+3^2
D=5km
How many times will the temperature of oxygen with a mass of 1 kg increase if its volume is increased by 4 times, and the pressure is decreased by 2 times?
Round off the answer to the nearest whole number.
Answer:
9.2 Relating Pressure, Volume,
Figure 1. In 1783, the first (a) hydrogen-filled balloon flight, (b) manned hot air balloon flight, and (c) manned hydrogen-filled balloon flight occurred. When the hydrogen-filled balloon depicted in (a) landed, the frightened villagers of Gonesse reportedly destroyed it with pitchforks and knives. The launch of the latter was reportedly viewed by 400,000 people in Paris.
Explanation:
hope its help :)
nicsfrom #philippines
You wish to make a simple amusement park ride in which a steel-wheeled roller-coaster car travels down one long slope, where rolling friction is negligible, and later slows to a stop through kinetic friction between the roller coaster's locked wheels sliding along a horizontal plastic (polystyrene) track. Assume the roller-coaster car (filled with passengers) has a mass of 756.5 kg and starts 88.2 m above the ground. (a) Calculate how fast the car is going when it reaches the bottom of the hill.
Answer:
The speed of roller coaster at the ground is 41.6 m/s.
Explanation:
mass of roller coaster, m = 756.5 kg
height, h = 88.2 m
(a) Let the speed of car at the ground is v.
Use conservation of energy
Potential energy at height = kinetic energy at bottom
[tex]m gh = \frac{1}{2}mv^2\\\\9.8\times 88.2= 0.5\times v^2\\\\v = 41.6 m/s[/tex]
What is the reason why many ships and plane ones traveled in this boundary got disappeared and no debris are found in the bermuda triangle?
Karl Kruszelnicki has insisted the reason why so many ships and planes vanish without trace in the area between Bermuda, Florida, Puerto Rico is nothing to do with aliens or fire-crystals from the lost city of Atlantis.
Instead, the Australian scientist ‘revealed’, the high number of disappearances is explained by nothing more supernatural than plain old human error plus bad weather and the fact that lots of planes and ships enter that area of the Atlantic Ocean in the first place.
Are you aware of human rights violation happening in the community and explain
Answer:
Individuals who commit serious violations of international human rights or humanitarian law, including crimes against humanity and war crimes, may be prosecuted by their own country or by other countries exercising what is known as “universal jurisdiction.”
The speed of a 2.0-kg object changes from 30 m/s to 40 m/s during a 5.0-second time interval.
During this same time interval, the velocity of the object changes its direction by 90°. What is the
magnitude of the average total force acting on the object during this time interval?
a. 30 N
b. 20 N
c. 15 N
d. 40 N
e. 10 N
Which is the correct answer?
Answer:
F = 2 * 30 / 5 = 12 N to stop forward motion
F = 2 * 40 / 5 = 16 N to accelerate to 90 degrees
(12^2 + 16^2)^1.2 = 20 N average force applied
The magnitude of the average total force acting on the object during this time interval is 20 N.
The given parameters:
Mass of the object, m = 2.0 kgInitial velocity, u = 30 m/sFinal velocity, v = 40 m/sTime of motion, t = 5.0 sThe magnitude of the average total force acting on the object during this time interval is calculated as follows;
[tex]F = \frac{mv }{t} \\\\F_1 = \frac{2(40)}{5} \\\\F_1 = 16\ N\\\\F_2= \frac{2(30)}{5} \\\\F_2 = 12 \ N\\\\F = \sqrt{F_1^2 + F_2^2} \\\\F = \sqrt{16^2 + 12^2} \\\\F = 20 \ N[/tex]
Learn more about resultant force here: https://brainly.com/question/25239010
Please help I need this done
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate would the car have to accelerate so that a quarter placed on the back wall would remain in place?
Answer:
25.59 m/s²
Explanation:
Using the formula for the force of static friction:
[tex]f_s = \mu_s N[/tex] --- (1)
where;
[tex]f_s =[/tex] static friction force
[tex]\mu_s =[/tex] coefficient of static friction
N = normal force
Also, recall that:
F = mass × acceleration
Similarly, N = mg
here, due to min. acceleration of the car;
[tex]N = ma_{min}[/tex]
From equation (1)
[tex]f_s = \mu_s ma_{min}[/tex]
However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.
Thus,
[tex]F = f_s[/tex]
[tex]mg = \mu_s ma_{min}[/tex]
[tex]a_{min} = \dfrac{mg }{ \mu_s m}[/tex]
[tex]a_{min} = \dfrac{g }{ \mu_s }[/tex]
where;
[tex]\mu_s = 0.383[/tex] and g = 9.8 m/s²
[tex]a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }[/tex]
[tex]\mathbf{a_{min}= 25.59 \ m/s^2}[/tex]
Define Kinetic Energy:
Begin by defining kinetic energy in your own words within one concise eight word sentence
Answer:
kinetic energy is the energy an object has beause of it's motion
Answer:
See explanation below
Explanation:
Kinetic energy is energy stored in a moving object.
A car is traveling at a constant velocity of 20 m/s for 45 seconds. How far does the car go?
Answer: My bad bro. Just tryna get me some points g
Explanation: tuff
Answer:
Explanation:
D=s*t
D=(20)(45)
D=900m.
hope it helps
Two circular, concentric and coplanar turns of
radii R1 = 30 cm and R2 = 20 cm are traversed by currents
i1 = 5 A and i2 = 2 A, indicated in the figure. being the constant of
magnetic permeability in vacuum μ0 = 4^.10-7 Tm/A,
characterize the magnetic induction vector originating at center O.
Answer:
(check the pic)
Explanation:
hope it helps
A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1177 g, and its velocity is +0.681 m/s after the bullet passes through it. The mass of the second block is 1626 g.
(a) What is the velocity of the second block after the bullet imbeds itself?
(b) Find the ratio of the total kinetic energy after the collision to that before the collision.
Answer:
(a)0.531m/s
(b)0.00169
Explanation:
We are given that
Mass of bullet, m=4.67 g=[tex]4.67\times 10^{-3} kg[/tex]
1 kg =1000 g
Speed of bullet, v=357m/s
Mass of block 1,[tex]m_1=1177g=1.177kg[/tex]
Mass of block 2,[tex]m_2=1626 g=1.626 kg[/tex]
Velocity of block 1,[tex]v_1=0.681m/s[/tex]
(a)
Let velocity of the second block after the bullet imbeds itself=v2
Using conservation of momentum
Initial momentum=Final momentum
[tex]mv=m_1v_1+(m+m_2)v_2[/tex]
[tex]4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2[/tex]
[tex]1.66719=0.801537+1.63067v_2[/tex]
[tex]1.66719-0.801537=1.63067v_2[/tex]
[tex]0.865653=1.63067v_2[/tex]
[tex]v_2=\frac{0.865653}{1.63067}[/tex]
[tex]v_2=0.531m/s[/tex]
Hence, the velocity of the second block after the bullet imbeds itself=0.531m/s
(b)Initial kinetic energy before collision
[tex]K_i=\frac{1}{2}mv^2[/tex]
[tex]k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)[/tex]
[tex]k_i=297.59 J[/tex]
Final kinetic energy after collision
[tex]K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2[/tex]
[tex]K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2[/tex]
[tex]K_f=0.5028 J[/tex]
Now, he ratio of the total kinetic energy after the collision to that before the collision
=[tex]\frac{k_f}{k_i}=\frac{0.5028}{297.59}[/tex]
=0.00169
Pete is investigating the solubility of salt (NaCl) in water. He begins to add 50 grams of salt to 100 grams of
room temperature tap water in a beaker. After adding all of the salt and stirring for several minutes, Pete
notices a solid substance in the bottom of the beaker. Which statement best explains why there is a solid
substance in the bottom of the beaker?
A. The salt he is using is not soluble in water.
B. The salt is changing into a new substance that is not soluble in water,
C. The dissolving salt is causing impurities in the water to precipitate to the bottom
D. The water is saturated and the remaining salt precipitates to the bottom
Answer:
would the answer be c
Explanation: that what i think in my opian
Answer:
A
Explanation:
The wave functions for states of the hydrogen atom with orbital quantum number l=0 are much simpler than for most other states, because the angular part of the wave.
a. True
b. False
Four identical masses m are evenly spaced on a frictionless 1D track. The first mass is sent at speed v toward the other three. As the masses collide they stick together. Mass 1 sticks to 2, then 1 2 sticks to 3, then 1 2 3 sticks to 4. When the combined 1 2 3 mass strikes mass 4, by what percentage does the speed decrease in %
Answer:
The speed decreases 75%.
Explanation:
Since no friction present, assuming no external forces acting during the three collisions, total momentum must be conserved.For the first collission, only mass 1 is moving before it, so we can write the following equation:[tex]p_{i} = p_{f} = m*v_{o} (1)[/tex]
Since both masses are identical, and they stick together after the collision, we can express the final momentum as follows:[tex]p_{f1} = 2*m*v_{1} (2)[/tex]
From (1) and (2) we get:v₁ = v₀/2 (3)Since the masses are moving on a frictionless 1D track, the speed of the set of mass 1 and 2 combined together before colliding with mass 3 is just v₁, so the initial momentum prior the second collision (p₁) can be expressed as follows:[tex]p_{1} = 2*m*v_{1} = 2*m*\frac{v_{o} }{2} = m*v (4)[/tex]
Since after the collision the three masses stick together, we can express this final momentum (p₂) as follows:[tex]p_{2} = 3*m*v_{2} (5)[/tex]
From (4) and (5) we get:v₂ = v₀/3 (6)Since the masses are moving on a frictionless 1D track, the speed of the set of mass 1, 2 and 3 combined together before colliding with mass 4 is just v₂, so the initial momentum prior the third collision (p₂) can be expressed as follows:[tex]p_{2} = 3*m*v_{2} = 3*m*\frac{v_{o} }{3} = m*v (7)[/tex]
Since after the collision the four masses stick together, we can express this final momentum (p₃) as follows:[tex]p_{3} = 4*m*v_{3} (8)[/tex]
From (7) and (8) we get:v₃ = v₀/4This means that after the last collision, the speed will have been reduced to a 25% of the initial value, so it will have been reduced in a 75% regarding the initial value of v₀.please help me and i will mark u as brainlist
Answer:
a) 8 secs I think
b)2m/s^2
Consider the circuit shown in the figure to find the power delivered to 6 Ohm resistance (in W). Given that Vs= 30
V
66.7 Watts
Explanation:
Let [tex]R_{1}=1.0[/tex] ohms, [tex]R_{2}=3.0[/tex]ohms and [tex]R_{3}=6.0\:[/tex]ohms. Since [tex]R_{2}[/tex] and [tex]R_{3}[/tex] are in parallel, their combined resistance [tex]R_{23}[/tex] is given by
[tex]\dfrac{1}{R_{23}}=\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}[/tex]
or
[tex]R_{23}=\dfrac{R_{2}R_{3}}{R_{2}+ R_{3}}=2.0\:ohms[/tex]
The total current flowing through the circuit I is given
[tex]I=\dfrac{V_{s}}{R_{Total}}[/tex]
where
[tex]R_{Total}=R_{1}+R_{23}= 3.0\:ohms[/tex]
Therefore, the total current through the circuit is
[tex]I=\dfrac{30\:V}{3.0\:ohms}=10\:A[/tex]
In order to find the voltage drop across the 6-ohm resistor, we first need to find the voltage drop across the 1-ohm resistor [tex]V_{1}[/tex]:
[tex]V_{1}=(10\:A)(1.0\:ohms)=10\:V[/tex]
This means that voltage drop across the 6-ohm resistor [tex]V_{3}[/tex] is 20 V. The power dissipated P by the 6-ohm resitor is given by
[tex]P=I^{2}R_{3}= \dfrac{V^{2}}{R_{3}}=\dfrac{(20\:V)^{2}}{6\:ohms}= 66.7 W[/tex]
7. An electric train moving at 20km/hrs
. Accelerates to a speed of 30km/hrs. in
20 sec, find the distance travelled in meters during the period of
acceleration
Answer
NB:
- speed, U is measure in m/s
- acceleration, a is measured in m/s²
-time t in seconds , s
Therefore conversation must be made
Speed U = 20km/hrs
=20km÷1hr
But 20km= 20×1000=20000m
1hr= 1×60min×60sec=3600s
U=20000÷3600=5.56m/s
a=30km/hrs
=30km÷1hr
But 30km=30×1000=30000
1hr=3600s
a=30000÷3600=8.33m/s²
From the equation of motion
S=Ut + ½ at².
Where s= distance
S = 5.56m/s × 20s + ½(8.33m/s²)(20s)²
S = 1777.3m
What type of lens is this?
Tip: A convex lens is thicker at the centre than at the edges.
When light goes through a concave lens, the light that goes through that lens spreads out more due to the structure of the surface of the lens. A concave lens does not form a focal point at the opposing side of the lens. Instead, it spreads out, doing the exact opposite of what a convex lens does. In the picture, we see a lens where the light goes through and unifies at the opposing side, which is what a convex lens does. So, the lens in that image is a convex lens.
3. What type of lens is this?
Answer: Convex
Wrong Answer: Concave
The weather map below shows air pressure reading given in millibars. Points A,B,C and D are locations of earths surface at which location is surface wind speed the lowest
Answer:
c
Explanation:
An amusement park ride whisks you vertically upward. You travel at a constant speed of 15 m/s during the entire ascent. You drop your phone 4.0 s after you (and your phone) begin your ascent from ground level.
a. How high above the ground is your phone when you drop it?
b. Find the maximum height above the ground reached by your phone.
Answer:
a. 60 m
b. 71.48 m
Explanation:
Below are the calculations:
a. The phone's height above the ground = Speed x Time
The phone's height above the ground = 15 x 4 = 60 m
b. Speed when phone drops, u = 15 m/s
At maximum height, v = 0
Use below formula:
v² = u² -2gh
0 = 15² + 2 × 9.8 × h
h = 11.48 m
Total height = 60 + 11.48 = 71.48 m
In a circuit, a source of voltage...
A
converts electrical energy to heat.
B
impedes the flow of electricity through the circuit.
C
leaves the circuit open so that current does not flow.
D
provides the power to move charge through the circuit.
Answer:
yes provides the power to move through the circuit
Explanation:
Which of the following would produce a star with the longest lifespan
1) a star with no mass
2)a star with low mass
3) a star with medium mass 4) a star with high mass 5)these options would not all be the same
Answer:
1
Explanation:
because stars with the lowest Mass live longer because they burn out slower than a star with high mass
Transfer of thermal energy between air molecules in closed room is an example of
conduction
convection
radiation
Answer and I will give you brainiliest
Answer: Conduction
Explanation: Conduction is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules. Conduction occurs more readily in solids and liquids, where the particles are closer to together, than in gases, where particles are further apart.
If you drive first at 40 km/h west and later at 60 km/h west, your average velocity is 50 km/h west.
and what else? is that all?
5. Tests performed on a 16.0 cm strip of the donated aorta reveal that it stretches 3.37 cm when a 1.80 N pull is exerted on it. (a) What is the force constant of this strip of aortal material
Answer:
53.41 N/m
Explanation:
From Hooke's law,
Applying,
F = ke............. Equation 1
Where F = Force, e = extension, k = force constant of the aortal material
Make k the subject of the equation
k = F/e............. Equation 2
From the question,
Given: F = 1.8 N, e = 3.37 cm = 0.0337 m
Substitute these values into equation 2
k = 1.8/(0.0337)
k = 53.41 N/m
Hence the force constant of the aortal material is 53.41 N/m
Which series represents the flow of thermal energy in a heat engine?
Fuel → air inside piston chamber → air outside piston chamber
Fuel → air inside piston chamber → piston movement
Fuel → piston movement
Fuel → air outside piston chamber
Answer:
B - Fuel → air inside piston chamber → piston movement
Explanation:
1 airplane
travel due north at 300 km while another airplane travels Due South and 300 km are there speed the same or their velocities the same
Answer:
Explanation:
Speed is scalar and velocity is vector. Vector values imply direction as well as magnitude. Therefore, speed and velocity are not the same. The speeds of these 2 planes are the same at 300km/hr, but the velocity of the plane traveling north is +300km/hr while the velocity of the plane traveling south is -300km/hr if we define north as positive and south as negative.
