distribute and simplify these radicals 2^3 x (^2+^3)

Answer:

AE=4

EC=4

BF=2.24

FD=2.24

Step-by-step explanation:

here we go honey  

Answer:

0

Step-by-step explanation:

=>sec A cosec A - tan A - cot A

=>(1/sinAcosA)-(sinA/cosA)-(cosA/sinA)

You get the LCM as sinAcosA then it becomes

=>(1-sin^2(A)-cos^2(A)) /sinAcosA [1-sin^2(A)=cos^2(A)]

=>(cos^2(A)-cos^2(A))/sinAcosA

=>0/sinAcosA

=>0

Step-by-step explanation:

A line with the specific numbers plotted on it, numerical order

Answer:

1- Put the letter A on positive 7

2- Put the letter B on positive 5

3- Put the letter C on 0

4- Put the letter D on negative 4

5- Put the letter E on negative 9

Answer:

10.A

11.A

12.A

Step-by-step explanation:

thank me later

Answer:

7480 hours

Step-by-step explanation:

440 - 100 = 340

LCM of 440 and 340

440 = 2 × 2 × 2 × 5 × 11

340 = 2 × 2 × 5 × 17

LCM = 2 × 2 × 2 × 5 × 11 × 17

LCM = 7480

Answer:

1,260,000,000

Answer:

No

Step-by-step explanation:

The coefficents of x³ and x² are 1 and -6 respectively

neither has a factor of 4

Answer:

[tex]P(Yellow) = \frac{29}{147}[/tex]

Step-by-step explanation:

Given

[tex]Brown = 27\\Purple = 47\\Yellow = 29\\Green = 44[/tex]

Required

[tex]P(Yellow)[/tex] --- next roll to be yellow

This is calculated as:

[tex]P(Yellow) = \frac{Yellow}{Total}[/tex]

So, we have:

[tex]P(Yellow) = \frac{29}{27 + 47 + 29 + 44}[/tex]

[tex]P(Yellow) = \frac{29}{147}[/tex]

Answer:

The minimum percentage of stores that sell a gallon of milk for between $3.65 and $4.17 is of 75%.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

In this question:

We have a mean of $3.91 and a standard deviation of $0.13.

Using Chebyshev's Theorem, what is the minimum percentage of stores that sell a gallon of milk for between $3.65 and $4.17?

3.65 = 3.91 - 2*0.13

4.17 = 3.91 + 2*0.13

Within 2 standard deviations of the mean, so, by the Chebyshev's Theorem, the minimum percentage of stores that sell a gallon of milk for between $3.65 and $4.17 is of 75%.

Answer:

B

Step-by-step explanation:

If you do 640/75 that equals 8.5333 etc. That is between 8 and 9!

Hope that helps!

Answer:

Step-by-step explanation:

y = 3x³ -4

the inverse is found by changing x with y and y with x than solve for y

x = 3y³ -4

x+4 = 3y³-4+4; add 4 to both sides

x+4 = 3y³

(x+4)/3 =y³ ;divide both sides by 3

∛((x+4)/3) = y ;cube root both sides

the inverse function of f(x) =3x³-4 is

[tex]f(x)^{-1} =\sqrt[3]{\frac{x+4}{3} }[/tex]

Answer:

[tex]9x - 10y = - 34 - - - (a) \\ 3x - 4y = - 16 - - - (b) \\ (a) - 3 \times (b) : \\ 0x + 2y = 14 \\ y = 7 \\ 3x - (4 \times 7) = - 16 \\ 3x = 12 \\ x = 4[/tex]

answer: ( 4, 7 )

Hi there!  

»»————-　★　————-««

I believe your answer is:  

(4,7)

»»————-　★　————-««  

Here’s why:  

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

A)

[tex]f(x)=x^(2)-2x+3[/tex]

Step-by-step explanation:

Answer:

option a

pls give brainliest

Step-by-step explanation:

Answer:

6 1/6

Step-by-step explanation:

Divide the numerator (19) by the denominator (6)

Write down the whole number result which in this case would be 3

Use the remainder as the new numerator over the denominator. This is the fraction part of the mixed number. which in this case is 1/6

therefore the answer is 6 1/6

Answer:

I think the answer is 200cm^2

Step-by-step explanation:

since the square is divided into eight equal parts

and one shaded part is =25cm^2

multiply the area of the shaded part by the number of equal parts

= 25cm^2 ×8

= 200cm^2

Answer:

length = 22

Width = 17

Step-by-step explanation:

78 = 2(w+5) + 2(w)

78 = 2w + 10 + 2w

78 = 4w + 10

68 = 4w

w = 17

l = 17 + 5 = 22

Answer:

286 mm ^2

Step-by-step explanation:

The figure is a trapezoid

The area of a trapezoid is given by

A = 1/2 ( b1+b2) *h where b1 and b2 are the lengths of the bases and h is the height

A = 1/2 ( 28+24) * 11

A = 1/2 (52)*11

A =286 mm ^2

Answer:

The area of this figure is 286

Step-by-step explanation:

The formula for the area of a trapezoid is A = (a+b/2)h, or the top line plus the bottom line divided by 2 times the height. a is given as 24 mm and b is given as 28 mm so 24 plus 28 is 52. 52 divided by 2 is 26. 26 times 11 is 286 therefore the answer and area is 286.

Answer:

1 torr = 760 atm

1 torr = 1 mmHg

Answer:

46-22= 24

Therefore, the answer is ;

A.24

Answer:

-3

Step-by-step explanation:

change in y over the change in x

pick to points and use slope formula

9-3

0-2

that's 6/-2 = -3

Given:

M is the midpoint of AB.

M(2,0) and A(-3, 3).

To find:

The coordinates of point B.

Solution:

Midpoint formula:

[tex]Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]

Let the coordinates of point B are (a,b). Then, using the midpoint formula, we get

[tex](2,0)=\left(\dfrac{-3+a}{2},\dfrac{3+b}{2}\right)[/tex]

On comparing both sides, we get

[tex]\dfrac{-3+a}{2}=2[/tex]

[tex]-3+a=2\times 2[/tex]

[tex]a=4+3[/tex]

[tex]a=7[/tex]

And,

[tex]\dfrac{3+b}{2}=0[/tex]

[tex]3+b=0[/tex]

[tex]3+b-3=0-3[/tex]

[tex]b=-3[/tex]

Therefore, the coordinates of point B are (7,-3).

Given:

Three coins are tossed.

Let the event H represents all Heads and the event K represents at least one Heads.

To find:

a. The probability that the outcome is all heads if at least one coin shows a heads.

b. P(K) = ?

c. P(H∩K) = ?

Solution:

If three coins are tossed, then the total possible outcomes are:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Total outcomes = 8

Possible outcomes for all Heads = 1

Possible outcomes for at least one Heads = 7

Let the following events:

H = all Heads

K = at least one Heads.

Then,

[tex]H=\{HHH\}[/tex]

[tex]K=\{HHH, HHT, HTH, HTT, THH, THT, TTH\}[/tex]

[tex]H\cap K=\{HHH\}[/tex]

Now,

[tex]P(K)=\dfrac{7}{8}[/tex]

[tex]P(H\cap K)=\dfrac{1}{8}[/tex]

a. The probability that the outcome is all heads if at least one coin shows a heads is:

[tex]P(H|K)=\dfrac{P(H\cap K)}{P(K)}[/tex]

[tex]P(H|K)=\dfrac{\dfrac{1}{8}}{\dfrac{7}{8}}[/tex]

[tex]P(H|K)=\dfrac{1}{7}[/tex]

Therefore, the probability that the outcome is all heads if at least one coin shows a heads is [tex]\dfrac{1}{7}[/tex].

b. [tex]P(K)=\dfrac{7}{8}[/tex]

c. [tex]P(H\cap K)=\dfrac{1}{8}[/tex]

9514 1404 393

Answer:

  x = {-0.6, 1.8}

Step-by-step explanation:

Adding 33 we have ...

  4x^2 -5x = 4

Dividing by 4, we get ...

  x^2 -5/4x = 1

We can complete the square by adding the square of half the x-coefficient:

  x^2 -5/4x +25/64 = 89/64

  (x -5/8)^2 = 89/64

  x = (5 ±√89)/8 = {-0.5542, 1.8042}

The solution rounded to the nearest tenth is ...

  x = {-0.6, 1.8}

Given equations;

y₁ = 3x - 8               -------------------(i)

y₂ = 0.5x + 7          --------------------(ii)

To fill the table, substitute the values of x into equations (i) and (ii)

=> At x = 0

y₁ = 3(0) - 8 = -8

y₂ = 0.5(0) + 7 = 7

=> At x = 1

y₁ = 3(1) - 8 = -5

y₂ = 0.5(1) + 7 = 7.5

=> At x = 2

y₁ = 3(2) - 8 = -2

y₂ = 0.5(2) + 7 = 8

=> At x = 3

y₁ = 3(3) - 8 = 1

y₂ = 0.5(3) + 7 = 8.5

=> At x = 4

y₁ = 3(4) - 8 = 4

y₂ = 0.5(4) + 7 = 9

=> At x = 5

y₁ = 3(5) - 8 = 7

y₂ = 0.5(5) + 7 = 9.5

=> At x = 6

y₁ = 3(6) - 8 = 10

y₂ = 0.5(6) + 7 = 10

=> At x = 7

y₁ = 3(7) - 8 = 13

y₂ = 0.5(7) + 7 = 10.5

=> At x = 8

y₁ = 3(8) - 8 = 16

y₂ = 0.5(8) + 7 = 11

=> At x = 9

y₁ = 3(9) - 8 = 19

y₂ = 0.5(9) + 7 = 11.5

=> At x = 10

y₁ = 3(10) - 8 = 22

y₂ = 0.5(10) + 7 = 12

The complete table is attached to this response.

(ii) To find the solution of the system of equations using the table, we find the value of x for which y₁ and y₂ are the same.

As shown in the table, that value of x = 6. At this value of x, the values of y₁ and y₂ are both 10.

Answer:

the answer is d trust me 0.22

Step-by-step explanation:

Answer:

c + (C+2) = 12

Step-by-step explanation:

Assume C is the no of dimes

So there are C+2 no of nickels

Guven that C + (C+ 2) = 12

Answer:

first and third option are correct.

Step-by-step explanation:

6(x+3)

=6*x + 6*3

=6x + 18

Answer:

[tex]\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & { 64.5} & {64-65} & {4} & {66.5 } & {66-67} & {4} & {68.5 } & {68-69} & {4} &{70.5 } & {70-71} & {5} & {72.5 } & {72-73} & {10} & {74.5 } & {74-75} & {4}\ \end{array}[/tex]

Using the frequency distribution, I found the mean height to be 70.1129 with a standard deviation of 3.2831

Step-by-step explanation:

Given

[tex]\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & { } & {64-65} & {4} & { } & {66-67} & {4} & { } & {68-69} & {4} &{ } & {70-71} & {5} & { } & {72-73} & {10} & { } & {74-75} & {4}\ \end{array}[/tex]

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

[tex]M = \frac{1}{2}(Lower + Upper)[/tex]

Where

[tex]Lower \to[/tex] Lower class interval

[tex]Upper \to[/tex] Upper class interval

So, we have:

Class 64-65:

[tex]M = \frac{1}{2}(64 + 65) = 64.5[/tex]

Class 66 - 67:

[tex]M = \frac{1}{2}(66 + 67) = 66.5[/tex]

When the computation is completed, the frequency distribution will be:

[tex]\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & { 64.5} & {64-65} & {4} & {66.5 } & {66-67} & {4} & {68.5 } & {68-69} & {4} &{70.5 } & {70-71} & {5} & {72.5 } & {72-73} & {10} & {74.5 } & {74-75} & {4}\ \end{array}[/tex]

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

[tex]\bar x = 70.1129[/tex]

[tex]\sigma = 3.2831[/tex]

See attachment for result of 1-VarStats

Solving (c): Compare the calculated mean to the actual mean

The actual mean is missing from the question, so I will make assumptions in this part

Assume they are close

This means that the selected sample is a reflection of the actual population where the samples are selected.

Assume they are not close

This means that the selected sample does not reflect the actual population where the samples are selected.