Answer:
yes
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
I passed 7th grade with a B
16 divided by 5 as a decimal
Answer:
3.2 brainliets
Step-by-step explanation:
Today everything at a store is on sale the store offers a 20
% discount the regualr price of a t shirt is 18 what is the discount price
Answer:
$14.40 is the discount price.
Step-by-step explanation:
0.2 x 18 = 3.6
18 - 3.6 = 14.4
3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
A car travels at a constant speed of 56 mph for 2 hours. How far does the car travel in this
time?
A classroom has 12 girls for every 4 boys. What is the ratio of boys to total students?
Question 7 options:
4 : 16
12 : 4
4 : 12
12 : 16
Answer:
I don't understand please elaborate more your given question.
Step-by-step explanation:
Jonah earns $3 an hour working after school and $4 an hour working on Saturdays. Last week he earned $43, working a total of 13 hours. How many hours did he work on Saturday?
Answer:
9 hours worked after school and 4 hours worked on saturday
Step-by-step explanation:
x = amount of hours worked after school
y = amount of hours worked on saturday
x + y = 13 or x = 13 - y
and
3x + 4y = 43
plug:
3 · (13 - y) + 4y = 43
39 - 3y + 4y = 43
y = 4
plug:
x = 13 - y
x = 13 - 4 = 9
9 hours worked after school and 4 hours worked on saturday
Express the tan G as a fraction in simplest terms.
Answer:
[tex]\frac{\sqrt{70} }{5}[/tex]
fill in the blank with the letter of the description that best matches the term for the verb porter, match the subject pronoun with the correct form of the verb. i'll mark Brainliest if the answers are correct.
A. portons
B. porte
C. portez
D. portes
E. portent
FILL IN THE BLANK
je ____
tu ____
nous ____
vous ____
ils ____
Step-by-step explanation:
je........porte
tu.......portes
nous.......portons
vous........portez
ils......portent
HELP ME PLEASE RNNN FASTTT
Answer:
The first three are functions
Step-by-step explanation:
4th one fails the Vertical line test.
Please help ASAP !!!
THANKS!!
Answer:
rotation
Step-by-step explanation:
Answer:
Reflection
Step-by-step explanation:
I think its reflection because if you reflect them across the y axis then the x axis I believe they will be in those positions.
PLEASE HELP ME!!! jacky starts biking to meet up with her friend. she knows that if she bikes at a speed of 10 mph, she will be 3 minutes late. jacky also know that if she bikes at a speed of 12 mph, she will be there 2 minutes before they agree to meet. how much time does she have left before the appointed time?
Answer:
27s
Step-by-step explanation:
d = distance to rendezvous point in miles
t = time of arrival at 10mph, i.e. 3 mins later than appointed time
10 mph = 10 miles per hour = ¹/₆ miles per min
12 mph = ¹/₅ miles per min
t = d/(¹/₆)
t = 6d
5 min = ¹/₁₂ hr
t - ¹/₁₂ = d/(¹/₅)
t = 5d + ¹/₁₂
Elimination of t:
6d = 5d + ¹/₁₂
d = ¹/₁₂ mi
t = 6(¹/₁₂)
t = ¹/₂ min
Time left to appointed time = ¹/₂ - ³/₆₀
= ¹⁰/₂₀ - ¹/₂₀
= ⁹/₂₀.min → 27 seconds
Answer:
27 min
Step-by-step explanation:
rsm
x=5 and y=7
9y+x= ?
i need help );
Answer:
Step-by-step explanation:
All we need to do is substitute the y and x. This would then look like:
9y + x =
9 × 7 + x =
9 × 7 + 5.
Can you solve it from here?
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
Please I need help ASAP. Can someone help me?
Answer: The second bubble thing is correct you have picked the wrong one.
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
A delivery company's charge for an overnight package weighing in excess of one pound is given by the formula c= 2.53w + 15, 16
where w is the weight of package in pounds. Find the following.
Write down an example to show that each of the following two siatements is not correct
a) The factors of an even number are always even
Answer:
a) 2 * 3 = 6.
b) 123 is odd but contains an even digit (2).
Step-by-step explanation:
combine like the like terms
34w - 4g + 4g - 36w
the answer is -2w (i have the write at least 20 words to dont worry about this)
Answer:
-2w
Step-by-step explanation:
Like terms have same variable.
34w - 4g + 4g - 36w = 34w - 36w - 4g + 4g
= - 2w + 0 = -2w
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
Question 4 options:
y=47x−4
y=56x+1
y=−56x−4
y=−47x+1
Please help!
Answer: i think it is y=−56x−4
Step-by-step explanation:
The equation in the slope intercept form which passes through the points ( 0, -4 ) and ( 6 , 9 ) is y = (-5 / 6)x - 4.
The correct answer is Option C.
Given data:
To find the equation of a line in slope-intercept form (y = mx + b) that passes through the points (0, -4) and (6, -9), we need to determine the slope (m) and the y-intercept (b).
First, calculate the slope (m):
m = (change in y) / (change in x)
m = (-9 - (-4)) / (6 - 0)
m = (-9 + 4) / 6
m = -5 / 6
Now that we have the slope, we can use one of the given points (let's use (0, -4)) to solve for the y-intercept (b):
-4 = (-5 / 6) * 0 + b
-4 = b
So, the y-intercept (b) is -4.
Now, we can write the equation of the line in slope-intercept form:
y = (-5 / 6)x - 4
Hence, the equation of the line is y = (-5 / 6)x - 4.
To learn more about equation of line, refer:
https://brainly.com/question/14200719
#SPJ3
The complete question is attached below:
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
A) y = ( 4/7 )x - 4
B) y = ( 5/6 )x + 1
C) y = ( -5/6 )x - 4
D) y = ( -4/7 )x + 1
Answer all of the following questions. 3 Points a question. ALSO NO LINKS!
Is 2 a prime number?
Is 3 a prime number?
Is 11 a prime number?
Is 18 a prime number?
Is 20 a prime number?
Is 27 a prime number?
Answer:
no
yes
yes
no
no
yes
Step-by-step explanation:
a prime number cant be devided by any thing other than itself or one
Answer:
Step-by-step explanation:
Is 2 is 3 is 11 is 18 is 20 is 27
If the sum of a number and two is tripled, the result is one less than twice the number. Find the number.
Answer:
z
Step-by-step explanation:
hqvqhqvw karrar ras wallah a part
Can someone help me !!!
Answer:look close because that is the question
Step-by-step explanation:
i need help what is the answer
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
Use the information given to find the equation of the line using the point-slope formula (y-y_1)=m(x-x_1)). Then convert your answer to slope-intercept form (y=mx+b).
y-intercept of 2 and (4,-1)
If it's possible please a explanation on how you solved it.
Answer:
y=[tex]-\frac{3}{4}[/tex]x+2
Step-by-step explanation:
y=sx+2;
-1=4s+2;
s=-3/4;
y=[tex]-\frac{3}{4}[/tex]x+2
Which of the following is true?
|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5
Answer:
|-4| < |-5|
Step-by-step explanation:
because if modules is given sub sign will be deducate
how do you translate nine equals the quotient of a number and 54
Answer:
9 = [tex]\frac{n}{54}[/tex] or n ÷ 54
Step-by-step explanation:
nine equals the quotient of a number and 54
/\
9 = the quotient of a number and 54
/\
9 = will be division of a number and 54
/\
9 = [tex]\frac{n}{54}[/tex] or n ÷ 54
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
55.99 dollars gift with 18% coupon and 7.25% sales tax. What is the final cost?
Answer:
I think it is $91.89.
Step-by-step explanation:
1. Take the number and add sales tax by multiplying 0.0725 ( since that is what the percentage is in a decimal form). Then add that to the original and you have what it would be plus sales tax: $60.05.
2. Then you would need to multiply by 0.18. You would get 10.809
3. Next, subtract the 10.809 from $60.05 and the answer is $49.24.
I hope this helps! :)
(2x+y)2-y2 if x=-3 y=4 and z=-5