does anyone know the values of x and y? my teacher didn’t go over this type of problem

Answer:

21 cups of sugar

Step-by-step explanation:

3/4 x 28 = 21

Answer:

I believe the answer is B

Answer:

(x-3)² + (y+5)² = 16

Step-by-step explanation:

Radius will be half of diameter means that radius = r = 8/2 = 4.

With Center (h,k) the equation of circle is

(x-h)² + (y-k)² = r²

so by putting values answer will be

(x-3)² + (y+5)² = 4²

(x-3)² + (y+5)² = 16

Answer:

Im lost to lol mark brainlest imagine

Step-by-step explanation:

Marked price (mp) =rs 1500

discount (d) = 20%

discount amount = d% of mp

=20/100 *1500

= Rs. 300

bill amount paid = mp -d

= 1500 - 300

= Rs. 1200

[tex]\huge\bf\underline{Answer}[/tex]

[tex]\boxed{\huge \sf{TSA = 6a²}}[/tex]

Let the Side of a cube be 'x'

[tex]\sf{:⇒6(x) ^{2} } = 1944cm^{2} [/tex]

[tex]\sf{:⇒ {x}^{2} = \dfrac{1944}{6} }[/tex]

[tex]\sf{:⇒ {x}^{2} = 324}[/tex]

[tex]\sf{:⇒x = \sqrt{324} }[/tex]

[tex]\sf{:⇒x = 18cm}[/tex]

Answer:

cost of slices=2x

cost=monthly fee+cost of slices

15x+2x

Step-by-step explanation:

Answer:

x = -3/2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

2x + 1 = -2

Step 2: Solve for x

Answer: 90 different meal packages.

Step-by-step explanation:

Given data:

Types of drinks available = 5

Types of sandwiches available = 6

Types of chips available = 3.

Solution:

No of meal packages possible for this combination

= 6*5*3

= 90

A total of 90 different meal packages would be gotten:

Answer:

24 bags can be made from three 5 pounds bags.

Step-by-step explanation:

Given that:

Three 5 pound bags are donated.

Total weight of bags = 3*5 = 15 pounds

We know that:

1 pound = 16 ounces

15 pounds = 16*15 = 240 ounces

A bag weighs 10 ounces.

Number of bags = [tex]\frac{240}{10}[/tex]

Number of bags = 24 bags

Hence,

24 bags can be made from three 5 pounds bags.

Answer:

X= -1

Step-by-step explanation:

Answer:

A shock absorber?

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hi,

1) Find z if the standard normal curve area between -z and z is 0.4530.

Y1 = normalcdf(-x,x,0,1) - .4530 and x = .60226

a. ± 0.118

b. ± 0.398

c. ± 0.602 <==ANSWER

d. ± 0.752

2) If a random variable has the normal distribution with μ = 104.3 and σ = 5.7, find the probability that the value will be greater than 112.3

normalcdf(112.3, 500, 104.3, 5.7) = .08023

a. 0.08 <==ANSWER

b. 0.09

c. 0.10

d. 0.11

3) Determine a 90% confidence interval for μ if σ = 5, \bar{x} = 70, and n = 82. Answer interval rounded to two decimal places.

70 ± 1.645 (5/√82) or 69.09 to 70.91 <==ANSWER

I hope that helps!! :-)

Answer:

(14 , -7)

Step-by-step explanation:

terminal points: A (-6,3)   B (4,-2)

u = x₁ + i y₁    u = -6 + i3

v =x₂ + iy₂ = 4 - i2       2v = 8 - i4

2v - u = (8 - i4) - (-6 + i3) = 14 -i7

Resulting terminal point: (14 , -7)

Position vectors u and v have terminal points of (-6, 3) and (4, -2), respectively. Find the resulting terminal point of 2v - u.

(2, 1)

(14, 1)

(2, -7)

Answer:

B) 5.7

Step-by-step explanation:

The area of a square is found by multiplying its sides. Since a square has perfectly equal side lengths, you know that the square root of the area is equal to the side lengths. The area is 33. The square root of 33 is roughly 5.7. Hope that helps!

For the probability of you or your friend add the probability of each together:

68% + 26% = 94%  (0.94 if you need it as a decimal)

Answer: there's an 42 percent chance that your friend might make a free throw.

Step-by-step explanation: if u subtract u will get your answer that's bow i got this answer.

Answer:

637.5 I think it's right

Step-by-step explanation:

2,500x.04=100x3=300

2,500x.045=112.5x3=337.5

300+337.5=637.5 interest

2,500x2+637.5=5,637.5

Answer:

$5,612.16

Step-by-step explanation:

Part 1) Account I earns 4% annual simple interest.

we know that

The simple interest formula is equal to A = P (1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have:

t = 3 years

P = $2,500

r = 4% = 4/100 = 0.04

substitute in the formula above

A = 2,500 (1 + 0.04 * 3)

A = 2,500 (1.12)

A = $2,800

Part 2) Account II earns 4% interest compounded annually.

we know that    

The compound interest formula is equal to: A = P (1 + r/n)nt

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t = 3 years

P = $2,500

r = 4% = 4/100 = 0.04

n = 1

substitute in the formula above  

A = 2,500 * (1 + 0.04/1)3

A = 2,500 * (1.04)3

A = $2,812.16

Part 3) What is the sum of the balances of Account I and Account II at the end of 3 years?

Sum the two final investment:

$2,800 + $2,812.16 = $5,612.16

Answer:

wish i could herlp sorry have a great day

Step-by-step explanation:

Answer:

x > -2

Step-by-step explanation:

Answer:

x=30

Step-by-step explanation:

-8/5 - 6 = -54

-8x/5 - 6 = -54

-8x/5 −  6 +6 = -54 plus 6

Then Add the numbers and simplify

so then the answer would be x=30

Answer: x=30

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Multiply:

[tex](\frac{5}{5+\sqrt{10x} } )(\frac{5+\sqrt{10x} }{5+\sqrt{10x} } )[/tex]

Simplify:

[tex]\frac{5(5-\sqrt{10x}) }{(5+\sqrt{10x})(5-\sqrt{10x} ) }[/tex]

Factor:

[tex]\frac{5(5-\sqrt{10x}) }{25-10x}[/tex]

Reduce:

[tex]\frac{5(5-\sqrt{10x}) }{5(5-2x)}[/tex]

Solution:

[tex]\frac{5-\sqrt{10x} }{5-2x}[/tex]

The function f(x) for the input values are f(-2) = 2, f(0) = 3 and f(4) = -1

From the question, we have the following parameters that can be used in our computation:

The graph of a function and a set of input values

The input values are given as

–2, 0, and 4

Next, we read the above input values from the graph

Using the above as a guide, we have the following:

f(-2) = 2

f(0) = 3

f(4) = -1

Hence, the values are f(-2) = 2, f(0) = 3 and f(4) = -1

Read more about functions at

brainly.com/question/28277110

#SPJ1

Answer:

[tex] \huge \boxed{x = \frac{2}{3} y}[/tex]

Answer:

x=12

Step-by-step explanation:

First you make sure x is on both sides of the equation. So you do 0.7x-5-0.2x=0.2x+1-0.2x. Which just simplifies to 0.5x-5=1. You make sure x is the only thing on that side of the equation so you do 0.5x-5+5=1+5 which simplifies to 0.5x=6. Multiply the equation times 2 to just have x. x=12. The value that makes true of x is 12.

Answer:

umumumuykik.iu.fg

Step-by-step explanation:

lui;iou;uyfluylfuy;lui;uy;

Answer:

x = −37/16

This is the value of x which completes the equation properly, unless you mean x^2 instead of x2.

Answer:

B

Step-by-step explanation:

We are given that the position of a particle is modeled by the function:

[tex]s(t)=2t^3-24t^2+90t+7[/tex]

And we want to find the times for which the speed of our particle is increasing.

In other words, we want to find the times for which our acceleration is positive (a(t)>0).

So first, we will find our acceleration function. We can differentiate twice.

By taking the derivative of both sides with respect to t, we acquire:

[tex]\displaystyle s^\prime(t)=v(t)=\frac{d}{dt}\big[2t^3-24t^2+90t+7\big][/tex]

Differentiate:

[tex]v(t)=6t^2-48t+90[/tex]

This is our velocity function. We can differentiate once more to acquire the acceleration function. Therefore:

[tex]\displaystyle v^\prime(t)=a(t)=\frac{d}{dt}\big[6t^2-48t+90\big][/tex]

Differentiate:

[tex]a(t)=12t-48[/tex]

If our speed is increasing, our acceleration must be positive. So:

[tex]a(t)>0[/tex]

By substitution:

[tex]12t-48>0[/tex]

Now, we can solve for t:

[tex]12t>48\Rightarrow t>4[/tex]

Therefore, the only interval for which the speed of the particle is increasing (i.e. the acceleration is positive) is for all times t>4.

So, our answer is B.

Answer:

10.25 which is equal to letter c

Step-by-step explanation:

I used a calculator and figured out which equals it