Does the graph below represent a proportional relationship?

———————————————

A. Yes, because the graph is a straight line

B. No, because it crosses the y -axis

C. Yes, because it crosses the y -axis

D. No, because the line doesn't pass through the origin, point (0,0)

Does The Graph Below Represent A Proportional Relationship? A. Yes, Because The Graph Is A Straight LineB.

Answers

Answer 1
The answer is A.
The reason being straight lines mean equal proportions, while curved lines are exponential or quadratic.
Answer 2

Answer:  D. No, because the line doesn't pass through the origin, point (0,0)

Explanation:

A direct proportional graph is always a straight line through the origin.

Algebraically, the form of any direct proportion equation is y = kx, where k is some constant. It plays the role as the slope.

We can rewrite y = kx as y = kx+0 to see that the y intercept is always 0 for these types of equations.

Unfortunately, this line shown has a y intercept of 2 instead of 0. So it's not a direct proportion.


Related Questions

At the end of 2 years, P dollars invested at an interest rater compounded annually increases to an amount, A dollars, given by the following formula.
A = P(1+r)?
Find the interest rate if $192 increased to $363 in 2 years. Write your answer as a percent..
-
Annual compound interest rate = % (Type an integer or a decimal.)

Answers

Answer:

37.5%

Step-by-step explanation:

A=P(1+r)^t

363=192*(1+r)^2

1.375=1+r, r=0.375=37.5%

write fifty and two hundreds eight thousandths as a mixed decimal

Answers

Answer:

Pretty sure it's 0.528

please help me with this on the image

Answers

Answer:

6ab

Step-by-step explanation:

Answer 6ab
Explanation 3xax2xb
3x2 =6
axb= ab
= 6ab

simplify 2√3 x 3√8
i’ll give u brainiest pls

Answers

Answer:

[tex]12 \sqrt{6} [/tex]

Step-by-step explanation:

[tex]2 \sqrt{3} \times 3 \sqrt{8} \\ (2 \times 3) \sqrt{(3 \times 8)} \\ 6 \sqrt{24} \\( 6 \times 2) \sqrt{6 } \\ 12 \sqrt{6} [/tex]

The lines shown below are parallel. If the green line has a slope of -2, what is
the slope of the red line?

Answers

Answer:

Hi! There's no picture, but we don't need that to find the answer. Parallel lines always have the same slope. I suppose you're saying that the green and red line are parallel -- so, the red line's slope is also -2.

-2 <--

Hope this helps!! Have a nice day & please mark brainliest if you don't mind!

Solve the following quadratic function
by utilizing the square root method.
y = 16 – x2

Answers

Answer:

The solutions are x = -4 and x = 4.

Step-by-step explanation:

Solving a quadratic equation:

We have to find x for which [tex]y = 0[/tex].

In this question:

[tex]y = 16 - x^2[/tex]

So

[tex]16 - x^2 = 0[/tex]

[tex]x^2 = 16[/tex]

[tex]x = \pm \sqrt{16}[/tex]

[tex]x = \pm 4[/tex]

The solutions are x = -4 and x = 4.

A runner increases his velocity from 0 m/s to 20 m/s in 2.0 s. What was his average acceleration?

Answers

Answer:

[tex]a = \frac{dv}{dt } = \frac{20 - 0}{2} = 10[/tex]

Mr. Thomas invested an amount of ₱13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be ₱3508, what was the amount invested in Scheme B?

Answers

9514 1404 393

Answer:

  ₱6400

Step-by-step explanation:

Let 'b' represent the amount invested in scheme B. Then 13900-b is the amount invested in scheme A. The total interest for 2 years is then ...

  14%(13900-b)(2) +11%(b)(2) = 3508

  1946 -0.03b = 1754 . . . . . . divide by 2, simplify

  -0.03b = -192 . . . . . . . . . subtract 1946

  b = 6400 . . . . . . . . . . . divide by -0.03

The amount invested in scheme B was ₱6400.

$17,818 is invested, part at 11% and the rest at 6%. If the interest earned from the amount invested at 11% exceeds the interest earned from the amount invested at 6% by $490.33, how much is invested at each rate? (Round to two decimal places if necessary.)

Answers

Answer:We know the total amount of money invested. $17818

x+y=17818,

We know that the difference in interest earned by the two accounts is $490.33

0.11*x-0.06*y=490.33

x=17818-y

We substitute for x

0.11*(17818-y)-0.06*y=490.33

We multiply out

1959.98-0.11y-0.06*y=490.33

We combine like terms.

1469.65=0.17*y

Isolate y

y=1469.65/0.17

y=8645 at 6%

Calculate x

x=17818-8645

x=9173 at 11%

Check

0.11*9173-0.06*8645=490.33

interest earned at 11%=1009.03

interest earned at 6%=518.70

1009.03-518.7=490.33

490.33=490.33

Since this statement is TRUE and neither amount is negative then all is well.We know the total amount of money invested. $17818

x+y=17818,

We know that the difference in interest earned by the two accounts is $490.33

0.11*x-0.06*y=490.33

x=17818-y

We substitute for x

0.11*(17818-y)-0.06*y=490.33

We multiply out

1959.98-0.11y-0.06*y=490.33

We combine like terms.

1469.65=0.17*y

Isolate y

y=1469.65/0.17

y=8645 at 6%

Calculate x

x=17818-8645

x=9173 at 11%

Check

0.11*9173-0.06*8645=490.33

interest earned at 11%=1009.03

interest earned at 6%=518.70

1009.03-518.7=490.33

490.33=490.33

Since this statement is TRUE and neither amount is negative then all is well.

PAIesung
0 Weber
chool Careers
Reading list
- Blake bought a motorcycle for $550 last year and sold it for $330 this year. What is his sale
price as a percentage of his purchase price?

Answers

Answer:

The sale price was 60% of the purchase price.

Step-by-step explanation:

Given that Blake bought a motorcycle for $ 550 last year and sold it for $ 330 this year, to determine what is his sale price as a percentage of his purchase price, the following calculation must be performed:

550 = 100

330 = X

330 x 100/550 = X

33000/550 = X

60 = X

Therefore, the sale price was 60% of the purchase price.

5404 buttons are produced by a factory in Jebel Ali in a week. If the factory produced same number of buttons every day of the week, buttons produced in a day is _________________​

Answers

We need to find the number of buttons the company produced per day

The company produced 772 buttons per day

Total bottons produced in a week = 5404

There are 7 days in a week

If the factory produced same number of buttons every day of the week

Then,

Buttons produced per day = Total bottons produced in a week / Total number of days in a week

= 5404 / 7

= 772 buttons

The company produced 772 buttons per day

Read more: https://brainly.com/question/24368335

©/17
Correct
Question 1 of 17, Step 1 of 1
Write a mixed number to describe the length of the ribbon shown in the figure below.
Please enter your answer in the box below.
Inches
Answer
How to enter your answer
If your answer is a whole number, enter it in the left most box and leave the numerator and denominator boxes blank.

Answers

9514 1404 393

Answer:

  3 3/8 inches

Step-by-step explanation:

If you spend a little time looking at the marks on the ruler, you see that the smallest marks divide each inch into 8 parts. The ribbon comes to the 3rd small mark* after the 3-inch mark, so the length of the ribbon is 3 3/8 inches.

_____

* Technically, it is the second small mark, as the marks are small, medium, small. It marks the end of the third space, where each space is 1/8 inch.

Tìm GTLN và GTNN của
M=x+2y biết x^2 + 4y^2

Answers

Answer:

saya tidak tahu !)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!qjjjjbugg7yhhuhhhuhgy fundes per grallahegeuebevhehehnjķßùèò395oìùýþŕèwqàďhĺ

The room numbers of two adjacent classrooms are two consecutive odd numbers. If their sum is 860, find the classroom numbers

Answers

Answer:

429 & 431

Step-by-step explanation:

Consecutive numbers are numbers that come right after the other.

Let x = first room number

[tex]x+x+2=860\\2x+2=860\\2x=858\\x=429\\\\(429) + 2 = 431[/tex]

Therefore, the two room numbers are 429 and 431.

I know that there are two room numbers, and they are both odd numbers. They both add up to 860. Therefore, I decided to subtract 860 by 2. This will give me an even number. 430 is the even number. I decided to add 1 to 430 to give me an odd number. Then, I subtracted 431 from 860 to give me 429. Therefore, the two numbers are 429 and 431.

PLEASE HELP ASAP !!!! THANKS

Answers

Answer:

Its the first one

Can I please get help it’s urgent . Find the lateral surface area and volume of the solid object.

Answers

surface area = 1282.98
volume = 2677.48

Hi- how do we calculate the distance from C to D? Thanks so much!

Answers

Answer:

CD=20

Step-by-step explanation:

Use the pythagorean theorem: a²+b²=c²

(20√2)²-20²=a²

400(2)-400

800-400=400

√400=20

Simplify: (-2)^-3

a) 8
b) 1/8
c) -8
d) -1/8

Answers

Answer:

-1/8

Step-by-step explanation:

(-2)^-3

We know that a^-b = 1/a^b

1/(-2)^3

We know (-2)^3 = -8

1/(-8)

-1/8

how old is sherif now ? ahmed is eight years younger than sherif in seven years, the sum of their ages will be 7/10 th of 100​

Answers

Answer:

32year

Step-by-step explanation:

let Ahmed be x years then sheriff will be x+8

in 7years time

sheriff will be x+8+7=x+15

Then Ahmed will be x+7

sum of their ages will be 7\10×100=70years

x+15+x+7=70

collect like terms

2x+22=70

2x=70-22

2x/2=48/2

x=24years

Sheriff=24+8

32years

Evaluate 3x ^ 2 + 3x - 9 , when x = 2

A=-3
B=3
C=9
D=27

Answers

Answer:

C. 9

Step-by-step explanation:

Start plugging in the number 2

3(2)^2+3(2)-9

6^2+6-9

12+6-9

18-9

9

:
The width of a rectangle is 5 cm more than triple its length. The perimeter of the
rectangle is 240 cm. What is the length and width of the rectangle?

Answers

9514 1404 393

Answer:

length: 28.75 cmwidth: 91.25 cm

Step-by-step explanation:

Let L represent the length of the rectangle. Then the width is W=5+3L, and the perimeter is ...

  P = 2(L+W)

  240 = 2(L +(5 +3L))

  120 = 5 +4L

  115 = 4L

  115/4 = L = 28.75 . . . . cm

  W = 5+3L = 5 +3(28.75) = 91.25 . . . . cm

The length and width of the rectangle are 28.75 cm and 91.25 cm.

write your answer in simplest radical form​

Answers

Answer:

[tex]5 \sqrt{2 } [/tex]

Step-by-step explanation:

In a 45 45 90 triangle, the hypotenuse is equal to

[tex]x \sqrt{2} [/tex]

where x is the length of a leg of the triangle

what shape is the 1st one? I already know the second one

Answers

the first one is a quadrilateral

Step-by-step explanation:

a quadrilateral have four side

Can’t find answers online to check mine.

Answers

Answer:

3. 100% = 1

3/4 = 0.75

Now, 0.75 is halfway between 0.5 and 1, so Chris is correct.

4. 10% = 10/100 = 0.1

3/5 = 0.6

Now, 0.2 is not halfway between 0.1 and 0.6, so Emily is wrong.

Answer:

3 đúng 4 wrong

Step-by-step explanation:

100%=1

giữa 0, 5 và 1 =(0,5+1)/2=3/4

10%= 0,1

giữa  0,1 và  3/5 =(0,1+3/5)/2=  0,35  #0,2

What is AE?

Enter your answer in the box.


units

Answers

Answer:

AE = 18

Step-by-step explanation:

The triangles must be similar so we can use ratios

2x+4         12

--------  = ---------

x+8          10

Using cross products

(2x+4)10 = 12 (x+8)

20x +40 = 12x+96

Subtract 12x from each side

20x-12x +40 = 12x-12x +96

8x +40 = 96

Subtract 40 from each side

8x = 96-40

8x = 56

Divide by 8

x = 56/8

x = 7

AE = 2x+4 = 2(7) +4 = 14+4 = 18

The measurement of the radius of the end of a log is found to be 9 inches, with a possible error of 1/2 inch. Use differentials to approximate the possible propagated error in computing the area of the end of the log.

Answers

Answer:

[tex]\pm 9in^2[/tex]

Step-by-step explanation:

We are given that

Radius of end of a log, r= 9 in

Error, [tex]\Delta r=\pm 1/2[/tex]in

We have to find the error in computing the area of the end of the log by using differential.

Area of end of the log, A=[tex]pi r^2[/tex]

[tex]\frac{dA}{dr}=2\pi r[/tex]

[tex]\frac{dA}{dr}=2\pi (9)=18\pi in^2[/tex]

Now,

Approximate error in area

[tex]dA=\frac{dA}{dr}(\Delta r)[/tex]

Using the values

[tex]dA=18\pi (\pm 1/2)[/tex]

[tex]\Delta A\approx dA=\pm 9in^2[/tex]

Hence, the possible propagated error in computing the area of the end of the log[tex]=\pm 9in^2[/tex]

Answer:

[tex]A = (254.34 \pm 28.26) in^2[/tex]

Step-by-step explanation:

radius, r = 9 inches

error = 0.5 inch

The area of the end is

A = 3.14 x r x r = 3.14 x 9 x 9 = 254.34 in^2

[tex]A = \pi r^2\\\\\frac{dA}{dr}=2\pi r\\dA = 2 pi r dr \\\\dA = 2 \times 3.14\times 9\times 0.5 = 28.26[/tex]

So, the area is given by

[tex]A = (254.34 \pm 28.26) in^2[/tex]

Help with question b please​

Answers

9514 1404 393

Answer:

  (a) 5.82 cm (correctly shown)

  (b) 10.53 cm

Step-by-step explanation:

a) The length BC can be found from the law of sines:

  BD/sin(C) = BC/sin(D)

  BC = BC·sin(C)/sin(D) = (6 cm)sin(48°)/sin(50°) ≈ 5.82 cm

__

b) The angle ABD is the sum of the angles shown:

  angle ABD = 50° +48° = 98°

We know the lengths BA and BD and the included angle ABD, so we can use the law of cosines to find AD.

  AD² = BA² +BD² -2·BA·BD·cos(98°)

  AD² ≈ 8² +5.82² -2(8)(5.82)(-0.139173) ≈ 110.8411

  AD ≈ √110.8411 ≈ 10.53 . . . . cm

Plz show steps for this

Answers

Answer: Choice D. 3 : r=3

Step-by-step explanation:

Easiest method and probably only method given the graph without knowing exact points besides an asymptote at x=-3.

Since we know there is an asymptote at x=-3, we just solve for the denominator and find r, when x=-3.

We are setting equation equal to 0, because when the denominator is 0, the graph has an asymptote at that point.

x+r=0

-3+r=0

r=3

Answer:

r=3

Step-by-step explanation:

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective.

a. Suppose a sample of 865 floppy disks is drawn. Of these disks, 112 were defective. Using the data, estimate the proportion of disks which are defective.
b. Suppose a sample of 865 floppy disks is drawn. Of these disks, 112 were defective. Using the data, construct the 95% confidence interval for the population proportion of disks which are defective.

Answers

Answer:

a) 0.1295

b) The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).

Step-by-step explanation:

Question a:

112 out of 865, so:

[tex]\pi = \frac{112}{865} = 0.1295[/tex]

Question b:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 865, \pi = 0.1295[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].  

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 - 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1071[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1295 + 1.96\sqrt{\frac{0.1295*0.8705}{865}} = 0.1519[/tex]

The 95% confidence interval for the population proportion of disks which are defective is (0.1071, 0.1519).

Find m/c.
A
18 in
12 in
C
B
28 in

Answers

be A because it explains very well
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