Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.
Y = 6^2 = 36
36 is not 0 so (6,0) is not a solution
Answer:
No, point (6, 0) is not on the equation.
Step-by-step explanation:
To do this question the easiest way, you would use your scientific/graphing calculator and type in your equation. But you can do this with your mind.
Since the equation y = x^2 does not have any number in it (such as m = slope) it does not start anywhere. You will put it in the origin which is (0, 0) from there, you can tell that the equation will not reach (6, 0), but only (1, 1).
Lesson 9.6: Steady-State Analysis.) Consider a particular data set of 100,000 stationary waiting times obtained from a large queueing system. Suppose your goal is to get a confidence interval for the unknown mean. Would you rather use (a) 50 batches of 2000 observations or (b) 10000 batches of 10 observations each?
Answer:
I would rather use:
(b) 10,000 batches of 10 observations each.
Step-by-step explanation:
It is easier to have 10,000 batches of 10 observations each than to have 50 batches of 2,000 observations. Human errors are reduced with fewer observations. For example, Hadoop, a framework used for storing and processing big data, relies on batch processing. Using batch processing that divides the 100,000 stationary waiting times into 10 observations with 10,000 batches each is more efficient than having 2,000 observations with 50 batches each.
A telephone call arrived at a switchboard at random within a one-minute interval. The switch board was fully busy for 10 seconds into this one-minute period. What is the probability that the call arrived when the switchboard was not fully busy
Answer:
50/60 = .8333= 83.33%
Step-by-step explanation:
The probability that the call arrived when the switchboard was not fully busy is 0.75.
What is Normal Distribution?A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean. The normal distribution appears as a "bell curve" on a graph.
Given:
Here X follows uniform distribution with parameter a and b.
Where,
a = 0 and b = 1.
Then,
The density function of Y is given by:
P( 15 < Y ≤ 60)
or, P( 0.25 < Y ≤ 1)
So, P( 0.25 < Y ≤ 1) = [tex]\int\limits^{1}_{0.25}{f(y) \, dy[/tex]
= [tex][y]^1 _ {0.25}[/tex]
= (1- 0.25)
= 0.75
Hence, The probability that the call arrived when the switchboard was not fully busy is 0.75.
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Express 18 hours to 2 days in its lowest term
Answer:
1 : 3
Step-by-step explanation:
We know that 1 days is 24 hours
2 days = 2*24 = 48 hours
16 hours : 48 hours
Divide each by 16
16/16 : 48/16
1 : 3
Answer:
[tex]3 : 8[/tex]
Step-by-step explanation:
[tex]18h : 2d \\ 18h : 2 \times 24h \\ 18 :48 \\ 3 : 8[/tex]
A data set includes data from student evaluations of courses. The summary statistics are n=89, x=3.44, s=0.67. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
What are the null and alternative hypotheses?
A.
H0: μ=3.50
H1: μ>3.50
B.
H0: μ=3.50
H1: μ<3.50
C.
H0: μ≠3.50
H1: μ=3.50
D.
H0: μ=3.50
H1: μ≠
(I also need the test statistic and p-value) thank you so much in advance :)
We're told that "the claim that the population of student course evaluations has a mean equal to 3.50". So this means μ=3.50 makes up the null H0
The alternative would be H1: μ ≠ 3.50 since it's the opposite of the claim made in the null.
We go with answer choice D to form the null and alternative hypotheses.
The sign ≠ in the alternative hypothesis tell us that we have a two tail test.
---------------------------------------
Let's compute the test statistic
z = (xbar - mu)/(s/sqrt(n))
z = (3.44 - 3.50)/(0.67/sqrt(89))
z = -0.84483413122896
z = -0.84
The test statistic is roughly -0.84
---------------------------------------
Despite not knowing what sigma is (aka the population standard deviation), we can see that n > 30 is the case. So we can use the Z distribution. This is the standard normal distribution. When n > 30, the T distribution is fairly approximately the same as the Z distribution.
Use a calculator or a Z table to determine that
P(Z < -0.84) = 0.2005
which is approximate
Because we're doing a two-tail test, this means we double that result to get 2*0.2005 = 0.401
The p-value is roughly 0.401
-----------------------------------------
Since the p-value is larger than alpha = 0.05, we don't have enough evidence to reject the null. So you can say that we fail to reject the null, or we accept the null.
The conclusion based on that means that μ=3.50 must be true (unless other evidence comes along to disprove this). In other words, the mean evaluation score from students appears to be 3.50
Mr. Howe ate 1/3 of a pizza and then Mr. Kurt ate 1/8 of the same pizza. How
much of the pizza has been eaten? *
12/24
Step One: We need to convert 1/3 and 1/8 so both have the same denominator, so we need to find the a number that is able to be multiply by 3 and 8 for the process.
Step Two: 1/3 x 8= 8/24 and 1/8x3= 3/24
Step Three: Add our new fractions: 3/24+8/24= 12/24
Step Four: Subtract 12 by 24: 24-12= 12; our answer is 12/24 or half the pizza was eaten
I hope I've help!
find the surface area of the prism
Answer:
Base area=5*12=60
Height is 4
Perimeter or the base is 2*(12+5)=34
Surface area is 2B+Ph=120+136=256
find the two intersection points
(x+1)^2 +(y+2)^2 = 16
3x+ 4y = 1
Show your steps please
Answer:
Our two intersection points are:
[tex]\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)[/tex]
Step-by-step explanation:
We want to find where the two graphs given by the equations:
[tex]\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1[/tex]
Intersect.
When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.
Since the linear equation is easier to solve, solve it for y:
[tex]\displaystyle y = -\frac{3}{4} x + \frac{1}{4}[/tex]
Substitute this into the first equation:
[tex]\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16[/tex]
Simplify:
[tex]\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16[/tex]
Square. We can use the perfect square trinomial pattern:
[tex]\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16[/tex]
Multiply both sides by 16:
[tex](16x^2+32x+16)+(9x^2-54x+81) = 256[/tex]
Combine like terms:
[tex]25x^2+-22x+97=256[/tex]
Isolate the equation:
[tex]\displaystyle 25x^2 - 22x -159=0[/tex]
We can use the quadratic formula:
[tex]\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
In this case, a = 25, b = -22, and c = -159. Substitute:
[tex]\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}[/tex]
Evaluate:
[tex]\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}[/tex]
Hence, our two solutions are:
[tex]\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}[/tex]
We have our two x-coordinates.
To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:
[tex]\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2[/tex]
And:
[tex]\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}[/tex]
Thus, our two intersection points are:
[tex]\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)[/tex]
How many real solutions does this system of equations have? x2 +3 = y
3х — у+1 = 0
Answer:
Step-by-step explanation:
y = x²+3
y = 3x+1
x² + 3 = 3x +1
x² - 3x + 2 = 0
(x-2)(x-1) = 0
x = 2, 1
Two solutions
(2,7) and (1,4)
What is the minimum perimeter of a rectangle with an area of 625 mm^2
PLEASE HELP ILL GIVE BRAINLIEST !!!!
Answer:
y=3x-2
Step-by-step explanation:
The slope of the equation is (-2-(-5))/(0-(-1))=3. The y intercept is - 2. So y=3x-2
3)
Write an inequality for the graph below. If necessary, use
<= for < or >= for.
Kinda stuck and running out of time
Answer:
Step-by-step explanation:
10 times as much as 9
Answer:
90
Step-by-step explanation:
10 x 9
=> 90
10 times 9 is 90.
A scientist is studying the growth and development of an epidemic virus with a growth rate of 9% per month that has infected 3,124 people. If this rate continues, what will be the number of infected people in another 9 months? Round your answer to the nearest whole number.
Answer:
About 6,785 people will be infected about nine months.
Step-by-step explanation:
We can write an exponential function to represent the situation. The standard exponential function is given by:
[tex]\displaystyle f(x) = a(r)^x[/tex]
Where a is the initial value, r is the rate, and x, in this case, is the time that has passed in months.
3,124 people have already been infected. Thus, our initial value a = 3124.
And an additional 9% will be infected per month. Therefore, our rate r will be 1 + 9% or 1.09.
Hence, our function is:
[tex]\displaystyle f(x) = 3124(1.09)^x[/tex]
Then after nine months, the total amount of infected people will be f(9):
[tex]\displaystyle f(9) = 3124(1.09)^{(9)}[/tex]
Use a calculator:
[tex]\displaystyle f(9) \approx 6785[/tex]
About 6,785 people will be infected about nine months.
Answer:
7,022
Step-by-step explanation:
Find the approximate area of the shaded region below, consisting of a right triangle with a circle cut out of it. Use 3.14 as an
approximation for
90 m
40
2,794 square meters
1,256 square meters
974 square meters
O 6,844 square meters
The approximate area of the shaded region is 2794 m². The correct option is the first option 2794 square meters
From the question, we are to determine the approximate area of the shaded region
The area of the shaded region = Area of the triangle - Area of the circle
Area of triangle = 1/2 × base × height
Area of the triangle = 1/2 × 90 × 90
Area of the triangle = 4050 m²
Area of a circle = πr²
Where r is the radius
In the diagram,
Diameter = 40 m
∴ Radius = 40/2 = 20 m
Thus,
Area of the circle = π × 20²
Area of the circle = 3.14 × 400
Area of the circle = 1256 m²
Therefore,
The area of the shaded region = 4050 m² - 1256 m²
The area of the shaded region = 2794 m²
Hence,
The darkened area covers about 2794 m²
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Multiply:
2 × (–21) × 7
A)
294
B)
–273
C)
–7
D)
–294
Answer:
[tex]2\times \left(-21\right)\times \:7[/tex]
PEMDAS order of operations:
[tex]2\times \left(-21\right)=-2\times \:21=-42[/tex]
[tex]=-42\times \:7[/tex]
[tex]=-294[/tex]
D) -294 is your answer
OAmalOHopeO
How much state tax is withheld from $36,200 if the tax rate is 4%?
Answer:
$1448
Step-by-step explanation:
Tax=rate*amount=(4/100)*36200=1448
Hi I need help :( I can’t figure these out
Step-by-step explanation:
I do don't either ok wjshjddshsj
How far from "0 is the green rectangle?
What will be the reciprocal of 4/9 × 45/36
Answer:
[tex]\frac{9}{5}[/tex]
Step-by-step explanation:
[tex]\frac{4}{9}[/tex] × [tex]\frac{45}{36}[/tex]
= [tex]\frac{4}{9}[/tex] × [tex]\frac{5}{4}[/tex] ( cancel 4 on numerator/ denominator )
[tex]\frac{5}{9}[/tex]
Given a number n then its reciprocal is [tex]\frac{1}{n}[/tex]
Then the reciprocal of [tex]\frac{5}{9}[/tex] is
[tex]\frac{1}{\frac{5}{9} }[/tex] = [tex]\frac{9}{5}[/tex]
solve similar triangles (advanced)
solve for x
Answer:
27/2 =x
Step-by-step explanation:
We can write a ratio to solve
3 2
----- = ---------
3+x 11
Using cross products
3*11 = 2(3+x)
33 = 6+2x
Subtract 6 from each side
33-6 = 6+2x-6
27 = 2x
27/2 = 2x/2
27/2 =x
For an ordered pair left parenthesis x comma y right parenthesis in a relation, the x element represents the
Answer:
the x éléments représente the domain
x represents the value on the x-axis and the coordinate is also known as abscissa.
What is coordinate geometry?Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.
For an ordered pair left parenthesis x comma y right parenthesis in a relation that is (x, y).
Here x represents the value on the x-axis and the coordinate is also known as abscissa.
More about the coordinate geometry link is given below.
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Determine the dimension of the vector space. M4,2
STEP 1: Determine the number of linearly independent vectors needed to span M4,2. The basis for M4,2 has linearly independent vectors.
STEP 2: Using the result from Step 1, determine the dimension of M4,2.
Answer:
STEP 1
M_{4,2} is set of 4x2 matrices hence each matrix has 4*2=8 entries. Each entry can be filled independently.
Hence its basis has 8 linearly independent vectors.
STEP 2
Dimension= cardinality of basis = 8.
If f(x)=x-2 and g(x)=2x-6, then g(4)/f(3)
Answer:
2
Step-by-step explanation:
g(x) = 2x - 6
g(4) = 2*4 - 6
g(4) = 2
f(x) = x - 2
f(3) = 3 - 2
f(3) = 1
Thus g (4) / f (3) = 2 / 1 = 2
The value of the function g (4) / f (3) is 2.
What is a function?Function is a type of relation, or rule, that maps one input to specific single output.
We are given the function as;
f(x)=x-2 and g(x)=2x-6, then we need to find g(4)/f(3)
Therefore, g(x) = 2x - 6
g(4) = 2*4 - 6
g(4) = 2
Similalry,
f(x) = x - 2
f(3) = 3 - 2
f(3) = 1
Thus we have the value of function as
g (4) / f (3) = 2 / 1
g (4) / f (3) = 2
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A hot air balloon descends 200 feet per
minute from an altitude of 1000 feet. Write a expression
Suppose that appearances of a foe to battle (that is, a random encounter) in a role-playing game occur according to a Poisson process, and the average rate equals one appearance per two minutes. Measured in minutes, the time T until the next encounter is Exponential with what rate parameter?
Answer:
Rate parameter of [tex]\mu = 0.5[/tex]
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
One appearance per two minutes.
This means that [tex]m = 2[/tex]
Measured in minutes, the time T until the next encounter is Exponential with what rate parameter?
[tex]\mu = \frac{1}{m} = \frac{1}{2} = 0.5[/tex]
So
Rate parameter of [tex]\mu = 0.5[/tex]
Which polynomial function is best represented by the graph?
ƒ(x) = –x(x – 1)4
ƒ(x) = x2(x + 1)3
ƒ(x) = x2(x – 1)3
ƒ(x) = x(x – 1)4
Answer: ƒ(x) = x2(x – 1)3
Will give brainliest answer
Answer:
Step-by-step explanation:
A(1) is the amount after 1 decade.
A(0.1) is the amount after 1 year.
Every year, the amount of CO₂ increases by a factor of 1.06^(0.1) ≅ 1.0058
Which expression is equivalent to sqrt of (6x^5 z)^3/ 4x^4 z^2
Answer:
[tex]\frac{(6x^{5}z) ^{3} }{4x^{4} {z}^{2} } = \frac{216 {x}^{15}z^{3} }{4 {x}^{4} {z}^{2} } = \frac{4x ^{4} {z}^{2} (54x ^{11}z) }{4 {x}^{4} {z}^{2} } = 54 {x}^{11} z[/tex]
I hope I helped you^_^
In a certain year Congress debated a bill. A poll of 1000 Americans indicated 401 opposed 293 favored 306 not sure. What is the probability that random person was in favor
Refer to this design web of a car manufacturer’s experiment. Which of the following statements are true? Check all that apply.
A confounding variable is the use of cruise control.
A confounding variable is the weather conditions.
A confounding variable is the participants’ reporting on their fuel efficiency.
There are no confounding variables in this experiment.
A confounding variable is the speed at which the participants drive on the course.
Answer:
2.3,5
Step-by-step explanation:
Both the 2nd and 3rd statement is true. Because of both statement is closely analyzed up during design process of automobile.
How do car manufacturers design cars?The process of creating the outside (and, to some degree, interior) of motor vehicles, such as cars, motorbikes, trucks, buses, coaches, and vans, is known as automotive design.Although a big team from many various disciplines, including automotive engineering, normally works on the functional design and development of a contemporary motor vehicle, design jobs are not always linked to educational requirements for professional- or chartered-engineer status. In this context, automotive design primarily focuses on improving the visual appeal or aesthetics of vehicles while also getting involved in the development of product concepts. Designers with degrees in industrial design or transportation design who have an artistic background often work in the field of automotive design professionally.Learn more about Automobile design refer :
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