Does the Sun actually turn dark during a total solar eclipse? Why or why not?

Answer:

the magnitude of the normal force on the book is 25.78N

Explanation:

The computation of the magnitude of the normal force on the book is shown below

Normal force = N is

= mgcosβ

= 2.70 × 9.8 × cos13°

= 25.78N

hence, the magnitude of the normal force on the book is 25.78N

The above formula should be applied

Answer:

Kinetic energy and potential energy.

Explanation:

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v^2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared. Kinetic energy is usually measured in units of Joules (J); one Joule is equal to 1 kg m^2 / s^2.

The formula for potential energy depends on the force acting on the two objects. For the gravitational force, the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m/s^2 at the surface of the earth) and h is the height in meters. Notice that gravitational potential energy has the same units as kinetic energy, kg m^2/s^2. In fact, all energy has the same units, kg m^2/s^2, and is measured using the unit Joule (J).

Work is also measured with the unit Joule (J).

[tex]\displaystyle U_s = 0.6 \ J[/tex]

Math

Pre-Algebra

Order of Operations: BPEMDAS

Physics

Energy

Elastic Potential Energy: [tex]\displaystyle U_s = \frac{1}{2} k \triangle x^2[/tex]

Step 1: Define

k  = 7.50 N/m

Δx = 0.40 m

Step 2: Find Potential Energy

Answer:

Newton's second law of motion

Answer:

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THE ANSWER IS FAILURE

Answer: Mohs Scale

Explanation: Mohs Scale of Hardness

hope this helped!!!!!!!!!!!

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

Answer:

c is the answer,................

16 years of education would the typical professional astronomer have today, at minimum

Minimum qualifications of Astronomer 4 year degree to get a postgraduate qualification like a master of physics.

2 or 3 A levels of math and physics; 5 GCSEs at grades 9 to 4 (A* to C), or equivalent; and a degree in a field that is useful for postgraduate are needed.

Math and physics expertise needed, analytical thinking abilities, science knowledge, great verbal communication skills, and the capacity to think coherently both logic and reasoning are all essential.

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Answer:

gravitational potential energy.

Explanation:

Gravitational potential energy (GPE) can be defined as an energy possessed by an object or body due to its position above the earth surface.

Mathematically, gravitational potential energy is given by the formula;

[tex] G.P.E = mgh[/tex]

Where,

G.P.E represents gravitational potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

This ultimately implies that, anytime there is height, the object must have gravitational potential energy.

Hence, an object possesses gravitational potential energy due to its height (position) and the earth's gravitational force.

Answer:

by potential difference and electron gun

Explanation:

a magnetic field is produced whenever an electrical charge is in motion. The spinning and orbiting of the nucleus of an atom produces a magnetic field as does electrical current flowing through a wire. The direction of the spin and orbit determine the direction of the magnetic field.

Answer:

Electromagnetic field can be produced by the superposition of electric field and magnetic field.

Explanation:

When two or waves propagate in a medium without affecting each other , then at any instant the displacement of a particle will be equal to the vectorial sum of the displacements due to the waves.

Hence Electromagnetic field can be produced by L-C CIRCUITS.

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Answer:

270 Kg e 130 kg

Explanation:

how many times is the number put together

Answer:

density is defined as the amount of mass contained in unit volume of a body .its si unit is kg/m*3

Answer:

Density is the amount of mass per unit volume of a substance.

Archimedes principle states that"When a body is totally or partially immersed in a liquid,it experience an upthrust which is equal to the weight of the liquid displaced"

Answer:

1. ELE to KE = Electrical energy conversion to kinetic energy.

2. KE to ELE = kinetic energy conversion to electrical energy.

3. CE to ELE = chemical energy conversion to electrical energy.

Explanation:

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

Some examples of energy are chemical energy, electrical energy, kinetic energy, sound energy, potential energy, light energy, etc.

The transformation of energy from one form to another are described below;

1. A hair dryer plugged into the wall: it involves the conversion of electrical energy to kinetic energy. The energy type present in the wall socket is electrical energy which powers the hair dryer to have kinetic energy i.e the energy possessed due to motion of hair dryer.

2. A hand crank generator emergency radio: it illustrates the conversion of kinetic energy to electrical energy. The hand crank generator possess kinetic energy as it is being wounded before it is then converted into electrical energy which powers the radio.

3. A battery operated fan: it illustrates the conversion of chemical energy to electrical energy. The cells present in battery possess chemical energy that is being converted into electrical energy to power the fan.

Answer:

they push off the wall with a force greater than the wall

Explanation:

The game of parkour involves moving from one point to another and performing several skills which includes flips, especially in a difficult environment.

To change directions, the person must exert a significant force on the wall.

When the person leaps on the wall, it means the person moves or jumps quickly on the wall.

While this is being carried out, the concept of force must be applied.

If the force that acts on a stationary object is smaller than the required force to move the object, the object's position remains unchanged.

This means that for the person's direction to change, the person must exact a great force (or a significant force) enough to cause a change in direction.

Read more about force at:

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For the three-point charges fixed in a right triangle, we have:

1. The magnitude of the electric force on the +1.00 μC charge is 1.79 N.

2. The force does an angle of 21.68° with the x-axis.

First, let's denote the charges as is shown in the picture below:

The magnitude of the electric force on the charge 2 (+1.00 μC) is given by:  

[tex]|F_{net}| = \sqrt{(\Sigma\vec{F}_{x})^{2} + (\Sigma\vec{F}_{y})^{2}}[/tex]  (1)    

Where:  

We can calculate the electrical forces with Coulomb's law:

[tex]\vec{F} = \frac{Kq_{1}q_{2}}{d^{2}}[/tex]

Where:

Forces in the x-axis ([tex]\Sigma\vec{F}_{x}[/tex])

The forces in the x-component are given by:

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x} + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \vec{F}_{21}_{x}cos(\theta) + \vec{F}_{23}_{x}[/tex]

[tex]\Sigma\vec{F}_{x} = \frac{Kq_{1}q_{2}}{d_{12}^{2}}cos(\theta) + \frac{Kq_{2}q_{3}}{d_{23}^{2}}[/tex]   (2)

Where:              

We can calculate the angle θ with the following trigonometric function:

[tex]sin(\theta) = \frac{y}{z}[/tex]

[tex]\theta = sin^{-1}(\frac{y}{z}) = sin^{-1}(\frac{8.10 cm}{9.60 cm}) = 57.5 ^\circ[/tex]

To find the distance x (d₂₃), we need to use Pythagoras:

[tex]x = \sqrt{z^{2} - y^{2}} = \sqrt{(0.0960 m)^{2} - (0.0810 m)^{2}} = 0.051 m[/tex]

After entering θ and x (d₂₃) into equation 2, we have:

[tex]\Sigma\vec{F}_{x} = \frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}cos(57.5) + \frac{9.00 \cdot 10^{9}Nm^{2}C^{-2}(1.00 \cdot 10^{-6} C)(-0.600 \cdot 10^{-6} C)}{(0.051 m)^{2}}[/tex]

[tex]\Sigma\vec{F}_{x} = [0.78*cos(57.5) + (-2.08) N] = -1.66 N[/tex]

Hence, the x-component of the force is -1.66 N.

Forces in the y-axis ([tex]\Sigma\vec{F}_{y}[/tex])

The only force acting on the y-axis is the y-component of the force F₂₁, so:

[tex]\Sigma\vec{F}_{y} = -\vec{F}_{21}_{y} = -\vec{F}_{21}sin(\theta)[/tex]

The minus sign is because the vector is pointing in the negative y-direction (see the picture below).

[tex]\Sigma \vec{F}_{y} = -\frac{9.00\cdot 10^{9} Nm^{2}C^{-2}(0.800 \cdot 10^{-6} C)(1.00 \cdot 10^{-6} C)}{(0.0960 m)^{2}}sin(57.5) = -0.66 N[/tex]

Hence, the y-component of the force is -0.66 N.

Finally, the magnitude of the electric force on the charge +1.00 μC is (eq 1):  

[tex]|F_{net}| = \sqrt{(-1.66 N)^{2} + (-0.66 N)^{2}} = 1.79 N[/tex]                                  

Therefore, the magnitude of the electric force on the +1.00 μC charge is 1.79 N.

According to the picture below, the angle of the force with respect to the x-axis is given by:  

[tex]tan(\beta) = \frac{\Sigma\vec{F}_{y}}{\Sigma\vec{F}_{x}}[/tex]

[tex]\beta = tan^{-1}(\frac{-0.66 N}{-1.66 N}) = 21.68 ^\circ[/tex]

Therefore, the force does an angle of 21.68° with the x-axis.

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Answer:

Explanation:

Its Virtual, how would you describe the image formed by a convex mirrior? virtual upright, smaller

Answer:

Ti and O

Explanation:

It is what it is.

Answer:

B. Ti and O

Explanation:

A.P.E.X

Answer:

Sexual reproduction you need two organisms to reproduce.

Asexual is when you can multiply yourself and there is nothing different about the offspring and the parent.

Answer:

OK id k the names of everything but the quantity would be around 2.22222222222222222222222222222222222222222222222222222222222222222222222222222 ok?

Explanation:

Answer:

Gigantic towers, monuments and tall structures are always supported by a very thick layer of concrete that’s blended into their foundation. The purpose of this is quite straightforward: nothing provides greater support to a super heavy (and stationary) structure than a layer of concrete.  There may be other things that, in theory, could provide a stronger foundation, but they wouldn’t be nearly as cost effective as concrete.

Answer:

Because it has essentially zero strength in tension, it is almost always used as reinforced concrete, a composite material. It is a mixture of sand, aggregate, cement and water.