Dos coches están separados por una distancia de 12000 m salen al encuentro uno del otro, el primero con una aceleración de 5,6 m/s2 el segundo con 10,4 m/s2 , calcula el tiempo y la distancia de encuentro.


Un bus parte del reposo con una aceleración de 3,2 m/s2 y en ese mismo momento a 2 km de distancia, sale otro en sentido opuesto, también partiendo del reposo pero con una aceleración de 6,5 m/s2. Calcular la distancia y el momento de encuentro.


Dos vehículos separados por 1300 m parten al encuentro en el instante t=0. El primero lo hace con una velocidad inicial constante de 15 km/h. El segundo parte desde el reposo y con una aceleración de 1,2 m/s2. ¿A qué distancia de la salida del primer vehículo se encuentran?


Un automóvil se desplaza por una carretera que es paralela a la vía de un metrotren. El automóvil se detiene ante un semáforo que está con luz roja en el mismo instante que pasa un metrotren con una rapidez constante de 14 [m/s]. El automóvil permanece detenido durante 8 s y luego parte con una aceleración constante de 2,5 [m/s2 ]. Determine:

a)El tiempo que emplea el automóvil en alcanzar al metrotren, medido desde el instante en que se detuvo ante el semáforo.

Un micro parte del reposo y acelera a razón de 1,4 m/s2 . En este instante un pasajero que desea abordarlo, se encuentra a 12 [m] por detrás de la puerta y corre con una velocidad constante de 5 m/s.

a) Determinar si el pasajero alcanza o no al micro


Salva mi trimestre

X <0 means x would be negative.

For x/y, a negative divided by a positive would give a negative answer.

A negative multiplied by a positive would result in a negative.

The answer would be B. Negative

Answer: 15 cups

Step-by-step explanation:

Answer:

Determination of type of error arising from the situations

Situation       Type of Error

1.                    Nonresponse

2.                   Bad sampling method

3.                   Question wording

4.                   Undercoverage

Step-by-step explanation:

Types of errors:

a. question wording means that the manner a question is worded elicits some particular responses, which may not accurately reflect reality.

b. undercoverage occurs when some elements of the target population is not represented on the survey frame.

c. processing error arises from data processing

d. bad sampling method is caused by the voluntariness of those who choose to respond.

e. response error is caused by a questionnaire that requires framing improvements, misinterpretation of questions by interviewers or respondents, and errors in respondents' statements.

f. nonresponse error arises as a result of incomplete information or partial response.

g. random sampling error arises from the limited sample size when compared with the population size.

Your answer is in the attachment.

Answer:

= 4

Step-by-step explanation:

first lets find the value of x in 3x+2=5/9

3x+2=5/9

3x = [tex]\frac{5}{9}[/tex] -2

3x = [tex]\frac{3}{9}[/tex]

3x = [tex]\frac{1}{2}[/tex]

x = [tex]\frac{1}{2 * 3\\ }[/tex]

x = [tex]\frac{1}{6}[/tex]

[tex]\frac{1}{6}[/tex] can also be written as [tex]6^{-1}[/tex]

−3x+8

-3 ([tex]\frac{1}{6}[/tex]) +8

[tex]\frac{-3}{6}[/tex] +8

= 4

Answer:

A

Step-by-step explanation:

I guess that is it may be

Answer:

C. 44.98

Step-by-step explanation:

Hi there!

We are given the right triangle ABC, m<B=12°, and CB =44

We want to find the length of AB

We can use trigonometry to do it

Let's find the ratio in reference to angle B, as that angle is given.

In reference to angle B the opposite angle is AC, the adjacent side is CB, and the hypotenuse is AB

Now let's recall the 3 most commonly used functions:

[tex]sine=\frac{opposite}{hypoptenuse}[/tex]

[tex]cosine=\frac{adjacent}{hypotenuse}[/tex]

[tex]tangent=\frac{opposite}{adjacent}[/tex]

Let's find the cosine of angle B, as it uses CB and AB, which are the given side and the side we need to find

In that case,

cos(12)=[tex]\frac{CB}{AB}[/tex]

cos(12)=[tex]\frac{44}{AB}[/tex]

Multiply both sides by AB

[tex]AB[/tex]*cos(12)=44

Divide both sides by cos(12)

AB=[tex]\frac{44}{cos(12)}[/tex]

Now plug [tex]\frac{44}{cos(12)}[/tex] into your calculator. Make sure your calculator is on degree mode

AB≈44.98

So the answer is C

Hope this helps!

Answer:

3(x + 8)

Step-by-step explanation:

"The product of three and the sum of a number and eight".

First, note that:

1) Product means multiply.

2) Sum means addition.

With that in mind, also note the order of operations. The order of operations is defined as PEMDAS, or:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

Also, let "a number" be denoted as the variable, x.

~

Firstly, "the sum of a number and eight": x + 8

Next, "The product of...": 3 *

Putting the two parts together will generate: 3(x + 8)

3(x + 8) is your answer.

~

Answer:

33%

Step-by-step explanation:

$16,500-$11,055= $5,445

$5,445÷$16,500= 0.33 which in percentage format is 33%

HOPE THIS HELPS! MARK BRAINLIEST PLEASE!!!!!

Answer:

Step-by-step explanation:

400*e^(.09*3)

$523.97

answer is b

Answer: Option B

$523.97

Explanation:

= 400×e^(0.09×3)

= $523.97

Must click thanks and mark brainliest

Answer:

x=4

y=7

Step-by-step explanation:

12=3x

x=4

6=y-1

y=6+1

y=7

Answer:

x=4

Step-by-step explanation:

Answer:

3rd option

Step-by-step explanation:

(1/2)^-2t

= (2^-1)^-2t

= 2^2t

= (2^2)^t

Answered by GAUTHMATH

Answer:

25

Step-by-step explanation:

F(x) = 2x^2- 5x-8

Let x=-3

f(-3) = 2 (-3)^2 -5(-3) -8

          =2(9) +15 -8

          =18+15-8

          =25

Answer:

x > 8

Step-by-step explanation:

You can start y multiplying both sides by 4 to cancel out the division by 4:

x/4 > 2

*4      *4

x > 8

Answer:

x > 8

Step-by-step explanation:

x/4 > 2

=> x > 2 × 4

=> x > 8

Answer:

Step-by-step explanation:

A right triangle has one right angle and two acute angles.

A and B are the acute angles.

A+B =  90°

One acute angle is 45 less than twice the other acute angle.

A = 2B-45°

(2B-45°) + B = 90°

3B = 135°

B = 45°

A = 45°

..... Here

This is the answer

If they run 3 miles west then 8 miles north, it forms a right triangle. So just use the Pythagorean Theorum.

A^2+B^=C^2

3^2+8^3=C^2

9+64=C^2

Square root 73=C or 8.54=C (Miles)

The runner is 8.54 miles from her starting point if she plans to run straight back.

From the question, a runner jogs 3 miles west and then jogs 8 miles north.

An illustrative diagram for the journey is shown in the attachment below.

In the diagram, S is the starting point. That is, the runner jogs 3 miles west to a place R and then 8 miles north to a place E.

The cardinal points (North, East, West and South) are indicated beside the diagram.

Now, to calculate how far she is from her starting point if she plans to run straight back, we will determine the length of /ES/ in the diagram.

The diagram is a right-angled triangle and /ES/ can be determined using the Pythagorean theorem.

The Pythagorean theorem states that, in a right-angled triangle, the square of the longest side ( that is hypotenuse) equals sum of the squares of the other two sides.

In the diagram, hypotenuse = /ES/

∴ /ES/² = /SR/² + /RE/²

/SR/ = 3 miles

/RE/ =8 miles

/ES/² = 3² + 8²

/ES/² = 9 + 64

/ES/² = 73

/ES/ = [tex]\sqrt{73}[/tex]

/ES/ = 8.54 miles

Hence, the runner is 8.54 miles from her starting point if she plans to run straight back.

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Answer:

Step-by-step explanation:

The question has an error. Volume is expressed in cubic units. You probably mean cm³ .

Volume = 8 cm³

Length of each edge = ∛8 = 2 cm

Answer:

2cm

Step-by-step explanation:

Volume of cube=a^3 cubic units

8=a^3

a=cuberoot of 8

which is 2

Answer:

Step-by-step explanation:

Garden is two times as long as it is wide.

L = 2W

Perimeter is 120 feet

2L + 2W = 120

L +W = 60

(2W) + W = 60

3W = 60

W = 20 feet

L = 2W = 40 feet

==========================================================

Explanation:

area of rectangle = L*W = 129

L*W = 129

x*(2x-9) = 129

2x^2-9x = 129

2x^2-9x-129 = 0

Apply the quadratic formula. We'll use a = 2, b = -9, c = -129.

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-9)\pm\sqrt{(-9)^2-4(2)(-129)}}{2(2)}\\\\x = \frac{9\pm\sqrt{1113}}{4}\\\\x \approx \frac{9\pm33.36165464}{4}\\\\x \approx \frac{9+33.36165464}{4}\ \text{ or } \ x \approx \frac{9-33.36165464}{4}\\\\x \approx \frac{42.36165464}{4}\ \text{ or } \ x \approx \frac{-24.36165462}{4}\\\\x \approx 10.59041366\ \text{ or } \ x \approx -6.09041364\\\\[/tex]

We ignore the negative solution because a negative length makes no sense.

The length is approximately L = 10.5904 cm.

The width is 2L-9 = 2*10.5904-9 = 12.1808 cm approximately.

As a quick check,

L*W = 10.5904*12.1808 = 128.99954432

which isn't too far off from 129. We have rounding error which is why we don't perfectly land on the target area value. If you wanted to get closer to the value 129, then use more decimal digits in the approximations of L and W.

----------------------------

If you draw a diagonal in the rectangle, then you form two identical or congruent right triangles.

Focusing on one of those triangles, we have

Apply the pythagorean theorem

a^2+b^2 = c^2

c = sqrt( a^2 + b^2 )

c = sqrt( (10.5904)^2 + (12.1808)^2 )

c = 16.1408940520653

c = 16.14

The diagonal is roughly 16.14 cm long.

Answer:

5 %

Step-by-step explanation:

1000 g = 1 kg

50 kg = 0.05 kg

0.05 = 5%

Therefore, 50 g as a percentage of 1kg is 5%.

Answer:

7

Step-by-step explanation:

Answer:

it is 1/4

Step-by-step explanation:

20/60=10/30=1/3

Answer:

20/60=1/3

Step-by-step explanation:

20/60

HCF=20,

20*1=20, 20*3=60

1/3

or,

Remove the zeros,

2/6

Divide by 2 on both,

1/3

or divide by any common factor on both and keep dividing until u cant no more

20/60=1/3

Answer:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}[/tex]

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:                                                                     [tex]\displaystyle \lim_{x \to c} x = c[/tex]

L'Hopital's Rule

Differentiation

Basic Power Rule:

Derivative Rule [Chain Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

We are given the limit:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}[/tex]

When we directly plug in x = 0, we see that we would have an indeterminate form:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}[/tex]

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}[/tex]

Plugging in x = 0 again, we would get:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}[/tex]

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}[/tex]

Substitute in x = 0 once more:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}[/tex]

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

The identity as been verified/proved as:

[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]

Given that:

[tex]\frac{\cos(a + b)}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

Apply cosine identity to the numerator

[tex]\frac{\cos\ a\ cos\ b - \sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

Split the fraction:

[tex]\frac{\cos\ a\ cos\ b}{\cos\ a\cos b} - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

Cancel out common terms

[tex]1 - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

In trigonometry, we have:

[tex]\frac{\sin \theta}{\cos \theta} = \tan \theta[/tex]

So, the equation becomes:

[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]

Hence, the identity has been verified

Read more about trigonometry identities at:

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Answer:

15

Step-by-step explanation:

The figure has total 15 faces, the correct option is A.

A hexagon is a polygon with six sides.

A hexagonal pyramid has 8 faces

From (2 hexagonal base + 6 lateral surfaces)

A hexagonal prism has 7 faces

From ( A hexagonal base + 6 lateral faces)

Total faces the figure has is 8 +7 = 15

To know more about Hexagon

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Answer:

H0 : The variables are independent

H1 : The variables are not independent

Step-by-step explanation:

In a Chisquare test ; The null hypothesis is used to lay claim that the variables are independent, that is no relationship exists between the categorical variables in the population while the alternative hypothesis negates the null thus claiming that the variables aren't independent.

The null hypothesis, H0 : The variables are independent, A = B = C

The alternative hypothesis ; H1 : The variables are not independent, A ≠ B ≠ C

The centroid and center of mass need not be the same point. They are the same only when a body's mass is uniformly distributed.