Drag each label to the correct location on the figure. Not all labels will be used.
Find the missing angle measurements.
51°
54
47
75°
98°
82
?
105
28

Drag Each Label To The Correct Location On The Figure. Not All Labels Will Be Used.Find The Missing Angle

Answers

Answer 1
When referring to angles, I will use top, middle and bottom.

The middle angle is 180 - 28 - 105 = 37°

The top angle is 180 - 37 - 82 = 61°

The bottom angle is 180 - 28 - (180 - 82) = 54°
Answer 2

Answer:

The measure of angle B is 54°. The measure of angle A is 51°. The measure of angle AFE is 47°.


Related Questions

Olivia has 4 2/3 yards of fabric to make scarves. She needs 3/4 yards for one scarf. How many
scarves can she make?​

Answers

Answer:

6 scarves

Step-by-step explanation:

So we know that 3/4 yd. = 1 (scarf)

We have 4 2/3 material to make the scarves

=> convert to an improper fraction 4 2/3 = 14/3

=> Divide material by needed amt.

=> 14/3 / 3/4 = 14/3 x 4/3

=> 14/3 x 4/3 = 56/9

56/9 = 6 2/9

But 6 2/9 is not our answer. Since we need a full amt. of scraves, we round down to our final answer of 6 scarves.

Hope this helps!

solve for v. 27= -v/2

Answers

Answer:

v = -54

Step-by-step explanation:

27= -v/2

Multiply each side by -2

27 *-2= -v/2 *-2

-54 = v

Answer:

-54

Step-by-step explanation:

[tex]27=\frac{-v}{2}[/tex] .... Equation to start with

[tex]27 x 2= \frac{-v}{2} x2[/tex] ..... Cancelling out the denominator and multiplying on the other side

[tex]54 = -v[/tex] .... Multipling

[tex]-54 =v[/tex] ..... Solving for v, not -v, so bring the negative over to the other side

Hope you understood:)

solve 3(11)× =3,993 for x​

Answers

Hi there! :)

Answer:

[tex]\huge\boxed{x = 3}[/tex]

Given the equation:

[tex]3(11)^{x} = 3993[/tex]

Divide both sides by 3:

[tex](11)^{x} = 1331[/tex]

Rewrite both sides of the equation with a base of 11.

[tex]1331 = 11^{3}[/tex], therefore:

[tex](11)^{x} = 11^{3}[/tex]

x = 3.

Answer:

121

Step-by-step explanation:

121 x 33 = 3993

4x- 3y = -13 -x + 6y = -44

Answers

Answer:

3x and 9y and -31 is the correct answer if you are bloviating.

Step-by-step explanation:

bloviate the factors of x and y.

(x,y) =(-19/3 , 56/9)

Keenan currently does a total of 8 pushups each day. He plans to increase the number of pushups he does each day by 2 pushups until he is doing a total of 30 pushups each day. Which equation can we use to determine x, the number of days that it will take Keenan to reach his goal? In an expression

Answers

Answer:

Number of push up = 8 + 2x

Step-by-step explanation:

Keenan can do 8 push ups each day. He plans to do 2 extra day until he is doing 30 push ups. Each day he does an additional 2 push up, on the first day he does 8 + 2 = 10 push up, on the second day he does 10 + 2 = 12 push ups. This can be represented by the expression:

Number of push up = 8 + 2x

where x is the number of days.

To do 30 push ups, we can calculate the number of days needed:

30 = 8 + 2x

2x = 30 - 8

2x = 22

x = 11

Answer:

8+2x its from khan academy

Step-by-step explanation:

give person above brainliest :)

Find the vertex of the parabola.
f (x) = x squared minus 6 x + 13
a.
( 4, 0)
c.
( 3, 4)
b.
(0, 3)
d.
( 4, 3)

Answers

Answer:

The vertex is (3,4)

Step-by-step explanation:

f (x) = x^2 - 6 x + 13

Completing the square

-6/2 = -3 and squaring it = 9

    = x^2 -6x +9 +4

   = ( x-3) ^2 +4

The equation is now in vertex form

a( x-h) ^2 +k

where the vertex is ( h,k)

The vertex is (3,4)

Answer:

C on edge

Step-by-step explanation:

[tex]\frac{63,756×60}{70×5,280}[/tex]

Answers

Answer:

[tex]1035[/tex]

Step-by-step explanation:

(63756×60)/(70×5280)

=1035

A ship travels a distance of 700 km. On the return trip it averages 10km/hr faster and 8 hours less, tp travel the 700km back. Determine how long the original part of the trip took in hours

Answers

Answer:

The total duration of the trip is 48 hours.

Step-by-step explanation:

Let suppose that ship travels at constant speed during its travel. Each stage is represented by the following kinematic equation:

[tex]v =\frac{\Delta s}{\Delta t}[/tex]

Where:

[tex]\Delta s[/tex] - Travelled distance, measured in kilometers.

[tex]\Delta t[/tex] - Time, measured in hours.

[tex]v[/tex] - Speed, measured in kilometers per hour.

Now, each stage is represented by the following expressions:

Outbound trip

[tex]v = \frac{700\,km}{\Delta t}[/tex]

Return trip

[tex]v + 10\,\frac{km}{h} = \frac{700\,kh}{\Delta t - 8\,h}[/tex]

By eliminating [tex]v[/tex] and simplifying the resulting expression algebraically:

[tex]\frac{700\,km}{\Delta t} + 10\,\frac{km}{h} = \frac{700\,km}{\Delta t -8\,h}[/tex]

[tex](700\,km)\cdot \left(\frac{1}{\Delta t - 8\,h}-\frac{1}{\Delta t} \right) = 10\,\frac{km}{h}[/tex]

[tex]\frac{1}{\Delta t - 8\,h}-\frac{1}{\Delta t} = \frac{1}{70}\,\frac{1}{h}[/tex]

[tex]\frac{8\,h}{\Delta t \cdot (\Delta t-8\,h)} = \frac{1}{70}\,\frac{1}{h}[/tex]

[tex]560\,h^{2} = \Delta t\cdot (\Delta t - 8\,h)[/tex]

[tex](\Delta t )^{2}-8\cdot \Delta t - 560 = 0[/tex]

This equation can be solved by means of the Quadratic Formula, whose roots are presented below:

[tex]\Delta t_{1} = 28\,h[/tex] and [tex]\Delta t_{2} = -20\,h[/tex]

Only the first roots offers a physically resonable solution. Then, total duration of the trip is:

[tex]t_{T} = 28\,h +20\,h[/tex]

[tex]t_{T} = 48\,h[/tex]

The total duration of the trip is 48 hours.

Suppose triangle TIP and triangle TOP are isosceles triangles. Also suppose that TI=5, PI=7, and PO=11. What are all the possible lengths TO? Enter the possible values, separated by commas.

Answers

Three Answers:  5, 7, 11

===========================================

Explanation:

Refer to the diagram below.

In order for triangle TOP to be isosceles, the missing side x must be either 5 or 7. This way we have exactly two sides that are the same length.

--------

If TP = 5, then the value of y could be either 5 or 11 to ensure that triangle TIP has exactly two sides the same length.

If TP = 7, then y = 7 or y = 11 for similar reasons.

--------

Therefore, the possible lengths for segment TO are 5, 7, and 11.

Answer:

7, 11

Step-by-step explanation:

its right- trust me-

sandra is playing a trivia game.on her first turn she lost 75 points. on her second turn,she lost 35 points. on her third turn,she scored 100 points. What is sandras score after three turns?

Answers

Answer: -10 points

Step-by-step explanation:

She lost 110,so that loss -the gain(100) is the total score at the end of three games

if the morning temperature started at -7 celsius but warmed during the day to 24 celsius . What is the temperature change

Answers

Answer:

31° change

Step-by-step explanation:

If we want to find the change between two numbers, we need to imagine it like a number line.

<-------------0------------->

Let's plot -7 and 24 on this number line.

<----------[tex]-7[/tex]--0------------24>

If we want to get from -7 to 0, we increase by 7. To get from 0 to 24, we increase by 24.

So the total change is [tex]7 + 24 = 31[/tex].

Hope this helped!

this is progression
i need to know C plsssss
thankssssssssssßsssssss

Answers

Answer:

[tex]l = 28[/tex]

Step-by-step explanation:

Given

[tex]S = \sum (2k - 3); k = 4\ to\ l[/tex]

Required

What is l when S = 725

This can be solved using Sum of n terms of an AP;

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where

[tex]S_n = 725[/tex]

[tex]T_1 = first\ term[/tex]

To get T1; we substitute 4 for k in 2k - 3

[tex]T_1 = 2 * 4 - 3[/tex]

[tex]T_1 = 8 - 3[/tex]

[tex]T_1 = 5[/tex]

[tex]T_n = last\ term[/tex]

To get Tn; we substitute l for k in 2k - 3

[tex]T_n = 2 * l - 3[/tex]

[tex]T_n = 2l - 3[/tex]

n = the number of terms;

Since k = 4 to l, then

[tex]n = l - 4 +1[/tex]

[tex]n = l - 3[/tex]

Substitute these values in [tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]725 = \frac{l-3}{2}(5 + 2l - 3)[/tex]

Collect Like Terms

[tex]725 = \frac{l-3}{2}(2l + 5- 3)[/tex]

[tex]725 = \frac{l-3}{2}(2l + 2)[/tex]

Open the bracket

[tex]725 = \frac{l-3}{2} * 2l + \frac{l-3}{2} * 2[/tex]

[tex]725 = (l-3) * l + (l-3)[/tex]

[tex]725 = l^2-3l + l-3[/tex]

[tex]725 = l^2-2l -3[/tex]

Subtract 725 from both sides

[tex]725 - 725 = l^2-2l -3 - 725[/tex]

[tex]l^2-2l -3 - 725 = 0[/tex]

[tex]l^2-2l - 728 = 0[/tex]

[tex]l^2 + 26l - 28l - 728 = 0[/tex]

[tex]l(l + 26) - 28(l + 26) = 0[/tex]

[tex](l - 28)(l + 26) = 0[/tex]

[tex]l - 28 = 0[/tex] or [tex]l + 26 = 0[/tex]

[tex]l = 28[/tex] or [tex]l = -26[/tex]

But l must be positive;

Hence, [tex]l = 28[/tex]

Nala has 'n' marbles. Paul has three times as many marbles as Nala. Nala loses 5 marbles and Paul buys 10 marbles. Together they now have 105 marbles. Write down and solve an inequality in 'n'

Answers

Answer:

Step-by-step explanation:

Nala's marbles = n

Paul's marbles = 3n

nala loses 5 marbles

so nala's marbles = n - 5

paul buys 10 marbles

so paul's marbles = 3n + 10

Total marbles = 105

so,

n - 5 + 3n + 10 = 105

By transposing,

n + 3n = 105 - 10 + 5

4n = 100

n = 100 / 4

n = 25

Hope this helps

plz mark as brainliest!!!!!!!

a shop has a sale and reduces all the prices by 15k in naira.find the sale price of an article of an article marked at 750naira​

Answers

Answer:

Question (i):

Reduce = 15% of Rs 40 = 0.15 x 40 = Rs 6

Price after reduced = Rs 40 - Rs 6 = Rs 36

Answer: Rs 36

-

Question (ii):

Reduce = 15% x 20.40 = 0.15 x 20.40 = Rs 3.60

Price after reduced = Rs 20.40 - Rs 3.60 = Rs 17.34

Answer: Rs 17.34

-

Evaluate the following expression.
28 – 10 – 15 = 3 =
and this is the order of operations

Answers

Answer:

28 - 10 - 15 - 3

=> 18 - 15 - 3

=> 3 - 3

=> 0

Another way:

=> 28 - 10 - 15 - 3

=> 28 - 25 - 3

=> 28 - 28

=> 0

The time required to drive a fixed distance varies inversely as the speed. It takes 2 hr at a speed of 200 km/h to drive a fixed distance. How long will it take to drive the same distance at a speed of 80 km/h?

Answers

Answer:

5 hours

Step-by-step explanation:

From the question, we are told that:

Time required to drive a fixed distance varies inversely as the Speed

T ∝ 1/S

k = proportionality constant hence,

T =k × 1/S

T = k/S

Step 1

Find k

It takes 2 hr at a speed of 200 km/h to drive a fixed distance

T = 2 hours, S = 200km/h

T = k/S

2 = k / 200

k = 2 × 200

k = 400

Step 2

How long will it take to drive the same distance at a speed of 80 km/h?

S = 80km/h

T = k/S

k = 400

T = 400/80

T = 5

Therefore, it takes 5 hours to drive the same distance at a speed of 80km/hr

Simplify -1-7 +41. N

Answers

Answer:

-3

Step-by-step explanation:

-7+4=-3

The absolute value of -3 is 3

The negative sign in front of the absolute value bracket makes it -3

The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 0 and x = 3.

Answers

7/3 is the average rate of change.

Average rate of change of a function f(x) between any x values a and b = slope of the secant line connecting f(a) and f(b). This means (f(b)-f(a))/ (b-a). If a=0 and b=3, the average rate of change equals (f(3)-f(0))/(3-0).
f(3)=8+1=9, and f(0)= 1+1=2. So the average rate of change is (9-2)/3= 7/3.

The slope of the line whose equation is x + y = 6 is: -1 1 6

Answers

Answer:

the slope of the line x+y = 6 is -1.

Step-by-step explanation:

slope = - coefficient of x

----------------------

coefficient of y

slope = -1 /1

slope = -1

Answer:

A: -1

Step-by-step explanation:

2x-15=3(2x+3)
It’s multi step equations

Answers

x=−6 quick maths xd xd xd

Answer:

x = -6

Step-by-step explanation:

Hello!

2x - 15 = 3(2x + 3)

Distribute the 3

3 * 2x = 6x

3 * 3 = 9

2x - 15 = 6x + 9

Subtract 2x from both sides

-15 = 4x + 9

Subtract 9 from both sides

-24 = 4x

Divide both sides by 4

-6 = x

Hope this helps!

A man drove 16 mi directly east from his home, made a left turn at an intersection, and then traveled 2 mi north to his place of work. If a road was made directly from his home to his place of work, what would its distance be to the nearest tenth of a mile?

Answers

Answer:

16. 1 miles

Step-by-step explanation:

Using Pythagorean Theorem,

a^2 + b^2 = c^2

Since the road that goes from his home to work directly is c^2...

Plug in the rest of the numbers

16^2 + 2^2 = c^2

256 + 4 = c^2

260 = c^2

The reverse square of 260 is

16. 1 miles

How would I solve this? (y-z) ÷ z y=-2 and z=4/5

Answers

Answer:

-3.5

Step-by-step explanation:

The problem you have stated is (y-z)/z where y=-2 and z = 4/5. To solve, substitute the values of y and z into the problem. Then, you have (-2-4/5)/4/5. (-2-4/5) simplifies to -14/5 so then you have (-14/5)/4/5. To divide, multiply -14/5 by 5/4 {multiplying by the reciprocal}. That equals -70/20 which is equal to -3.5

Answer:

[tex]\large\boxed{-3.5}[/tex]

Step-by-step explanation:

(y - z) ÷ z          y = -2 and z = 4/5

Substitute in the given values for y and z into the equation

(y - z) ÷ z  

(-2 - 4/5) ÷ 4/5

Subtract inside the parenthesis (-2 - 4/5)

-2.8 ÷ 4/5

Convert 4/5 into a decimal (in this case that can be done by multiplying both the numerator and denominator by 20)

4/5 = (4 * 20) / (5 * 20) = 80 / 100

80 / 100

Divide numerator and denominator by 10

8/10 = 0.8

Substitute into previous equation

-2.8 ÷ 4/5 = -2.8 ÷ 0.8

Divide

[tex]\large\boxed{-3.5}[/tex]

Hope this helps :)

Using the Distributive Property to factorize the equation 3x2 + 24x = 0, you get

Answers

Answer:

3x(x+8)=0

x=0,-8

This is how to solve for x.

I REALLY need help with these 3 questions plz!!!!

Answers

Answer:

6. No. See explanation below.

7. 18 months

8. 16

Step-by-step explanation:

6. To rewrite a sum of two numbers using the distributive property, the two numbers must have a common factor greater than 1.

Let's find the GCF of 85 and 99:

85 = 5 * 17

99 = 3^2 + 11

5, 3, 11, and 17 are prime numbers. 85 and 99 have no prime factors in common. The GCF of 85 and 99 is 1, so the distributive property cannot be used on the sum 85 + 99.

Answer: No because the GCF of 85 and 99 is 1.

7.

We can solve this problem with the lest common multiple. We need to find a number of a month that is a multiple of both 6 and 9.

6 = 2 * 3

9 = 3^2

LCM = 2 * 3^2 = 2 * 9 = 18

Answer: 18 months

We can also answer this problem with a chart. We write the month number and whether they are home or on a trip. Then we look for the first month in which both are on a trip.

Month                Charlie          Dasha

1                          home             home

2                          home             home

3                          home             home

4                          home             home

5                          home             home

6                         trip                home

7                          home             home

8                          home             home

9                          home             trip

10                         home             home

11                         home             home

12                         trip               home

13                         home             home

14                         home             home

15                         home             home

16                         home             home

17                         home             home

18                         trip                 trip

Answer: 18 months

8.

First, we find the prime factorizations of 96 an 80.

96 = 2^5 * 3

80 = 2^4 *5

GCF = 2^4 = 16

Answer: 16

What is the formula for finding mean or average?​

Answers

Answer:

LOOK BELOW

Step-by-step explanation:

I would not call the explanation a formula

All you have to do to solve mean or average is add all of the numbers up and divide by the total amount of numbers

so for example

0,2,4,0,2,3,2,8,6  <-------- lets find the mean/average

0+2+4+2+3+2+8+6= 27/amount of numbers

amount of numbers=9

(count the zeros too!)

27/9=3

3 is the mean or average!!!

a 6 foot tall man casts a shadow that is 9 ft long. At the same time, a tree nearby casts a 48 ft shadow. how tall is the tree

Answers

Answer:

32 ft tall

Step-by-step explanation:

Since a 6 ft man casts a shadow 9 ft long, the shadow is 3/2 of the actual object/person.

SINCE THE TREE'S SHADOW IS AT THE SAME TIME, THE HEIGHT IS THE SAME RULE.

We know the tree's shadow is 48 ft.

--> 48/3 = 16

16 x 2 = 32

32 ft tall

Hope this helps!

Answer: 32ft tall

Step-by-step explanation:

2x/9 +x/3 = 13/6, solve for x

Answers

Answer:

x = 3 9/10

Step-by-step explanation:

2x/9 +x/3 = 13/6

Get a common denominator on the left side

2x/9 + x/3 *3/3 = 13/6

2x/9 + 3x/9 = 13/6

5x/9 = 13/6

Multiply each side by 9/5 to isolate x

5x/9 *9/5 = 13/6 * 9/5

x = 117/30

Divide the top and bottom by 3

x = 39/10

x = 3 9/10

Answer:

[tex]\bold{\red{\boxed{\blue{ x = 3.9}}}}[/tex]

Step-by-step explanation:

[tex] \frac{2x}{9} + \frac{x}{3} = \frac{13}{6} \\ \frac{2x + 3x}{9} = \frac{13}{6} \\ \frac{5x}{9} = \frac{13}{6} \\ use \: \: cross \: \: multipication \\ 5x \times 6 = 9 \times 13 \\ 30x =11 7 \\ \frac{30x}{30} = \frac{117}{30} \\ x = 3.9[/tex]

Ali was supposed to meet his friend in th evening every sunday. The first time he came at 4.30,the next time at5. 20,then at 6.30.Then at8. 00.When did he turn up the last time after that?

Answers

Answer:

9:50

Step-by-step explanation:

Given the following information :

First meeting = 4:30

Second meeting = 5:20

Third meeting = 6:30

Fourth meeting = 8:00

Frim careful observation of the meeting times :

Difference between the ;

Second and first meeting:

5:20 - 4:30 = 50 minutes

After that 20 minutes is added to the subsequent meetings as observed from the third and fourth meetings

6:30 - 5:20 = 70 minutes

8:00 - 6:30 = 90 minutes

Therefore, next meeting time :

(90 + 20) minutes = 110 minutes

8:00 + 110 minutes = 9:50

A 10 gram sample of a substance that’s used to detect explosives has a k-value of 0.1356.Find the substances half life in days.Round your answer to the nearest tenth.

Answers

Answer:

t ≈ 5.1 days

Step-by-step explanation:

A 10 gram sample of a substance thats used to detect explosives has a k-value of 0.1356. Find the substances half-life in days. round your answer to the nearest tenth. N=N₀ e^-kt N₀= initial mass (at time t = 0) N = mass at time t k= a positive constant that depends on the substance itself and on the units used to measure time t=time in days

The initial condition is that, at time t = 0, the amount of substance contains originally 10 grams

Find the value of N₀

N=N₀ e^-kt

We substitute:

10 = N₀ {e^(-0.1356)*0}

10 = N₀ (e^0)

10=N₀(1)

10=N₀

N₀ = 10

When the substance is in half-life

That is, half of the original substance (5 grams)

Find t

N=N₀ e^-kt

5 = 10 e^(-0.1356*t)

0.5 = e^(-0.1356*t)

Bring down t by multiplying natural log on both sides

ln(0.5) = -0.1356*t

Divide both sides by -0.1356

t = -(ln(0.5) / 0.1356

t ≈ 5.11 days

To the nearest tenth

t ≈ 5.1 days

Answer:

5.1 days in Plato

Step-by-step explanation:

evaluate 5!+2!. Thank you!

Answers

Answer:

122

Step-by-step explanation:

5!=5 x 4 x 3 x 2 x 1 = 120

2!=2 x 1 = 2

120+2=122

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