Draw a rough sketch of a quadrilateral KLMN. State, (a) two pairs of opposite sides, (b) two pairs of opposite angles, (c) two pairs of adjacent sides, (d) two pairs of adjacent angles. please draw the answer

Explanation:

Like with the previous problems, the answer comes fairly straight forward from the values of c and d.

c = 4 tells us we have a shift of 4 units to the left

d = 3 indicates we're shifting 3 units up.

Note: we shift left instead of right because x+c = x+4 means the xy axis has been shifted 4 units to the right, giving the illusion the cosine curve is shifted 4 units to the left.

Answer:

Following are the responses to the given question:

Step-by-step explanation:

[tex]\to y=(\frac{1}{2})(x-4)(x+4)\\\\\to y=(\frac{1}{2}) (x^2-16)\\\\\to y=(\frac{1}{2})(x-0)^2-8\\\\vertex \to (0,-8)[/tex]

The general x-intercept parabola equation [tex]y=k(x-4)(x+4)[/tex]

Parabola crosses the dot (2,-12)

[tex]\to k(2-4)(2+4)=-12\\\\\to k(-2)(6)=-12\\\\\to -12k=-12\\\\\to k=\frac{-12}{-12}\\\\\to k=1[/tex]

The parabolic equation which crosses the position [tex](2,-12)[/tex] is[tex]y=(x-4)(x+4)[/tex]

[tex]\to y=(x-4)(x+4)\\\\\to y=x^2-16\\\\\to y=(x-0)^2-16\\\\vertex \to (0,-16)[/tex]

The distance among the vertices of the two parabolas:

[tex]= \sqrt{(0 - 0)^2+(-8-(-16))^2}\\\\ = \sqrt{0+(-8+16))^2}\\\\ =\sqrt{0+(8)^2}\\\\=\sqrt{(8)^2}\\\\= 8\\\\[/tex]

Answer:

Question 10:

Answer: b.

[tex]{ \tt{f(x) = 5 {x}^{2} + 9x - 4}} \\ { \tt{g(x) = - {8x}^{2} - 3x - 4 }}[/tex]

(f + g)x, add f(x) and g(x):

[tex]{ \tt{(f + g)x = (5 - 8) {x}^{2} + (9 - 3)x - 4 - 4}} \\ { \tt{(f + g)x = - 3 {x}^{2} + 6x - 8}}[/tex]

Question 11:

Answer: a.

In relation with solution of question 10, same procedure:

[tex]{ \tt{(f - g)x = - 3 {x}^{3} + (1 - 2) {x}^{2} + ( - 3 - 4)x + 9 - ( - 9)}} \\ { \tt{(f - g)x = - 3 {x}^{3} - {x}^{2} - 7x + 18 }}[/tex]

Answer:

y>1

Step-by-step explanation:

Step-by-step explanation:

9 x 4=36 is the answer

hope this helps you

have a nice day:)

Answer:the answer is 10 because if u subctract it will work

Step-by-step explanation:

Answer:

D.

a1=7an=−3 · an−1a subscript 1 baseline equals 7 line break a subscript n baseline equals negative 3 times a subscript n minus 1 baseline

Step-by-step explanation:

Answer:

i think 5 is the answer not sure check with other helpers or brainer

Step-by-step explanation:

Answer:

Put both of those equations into slope-intercept form (in order to be typed into the graphing calculator).  

2x + 3y = 16.9

3y = -2x + 16.9

y = (-2/3)x + 16.9/3  

5x = y + 7.4

5x - 7.4 = y  

So in the graphing calculator,

Y1 = (-2/3)x + 16.9/3

Y2 = 5x - 7.4  

Then find the point of intersection and the x value of that would be the solution.

You get the coordinate (2.3, 4.1). So x = 2.3, y = 4.1

Step-by-step explanation:

Answer:

1 Cups (US) = 0.24992635042 Quarts

either divide or multiply by 0.24992635042

52* 0.24992635042 = 13

13 /  0.24992635042 = 52

Step-by-step explanation:

Answer:

I believe it is 3/4

Step-by-step explanation:

Answer:

hjjjnnnhjjjjj

Step-by-step explanation:

answer is d

1)

[tex]\sf {x}^{2} - 4 \\ \sf \: Use \: the \: sum \: product \: method[/tex]

[tex]\sf {x}^{2} - 4 \\ = \sf{x}^{2} + 2x - 2x - 4[/tex]

[tex]\sf \: Now \: take \: the \: common \: factor \: out \\ \sf{x}^{2} + 2x - 2x - 4 \\\sf = x(x + 2) - 2(x + 2)[/tex]

[tex]\sf \: Factorize \: it \\ \sf \: x(x + 2) - 2(x + 2) \\ = \sf(x - 2)(x + 2)[/tex]

Answer ⟶ [tex]\boxed{\bf{(x-2)(x+2)}}[/tex]

_________________________

2)

[tex]\sf {x}^{3} - 27[/tex]

[tex]\sf {x}^{3} \: and \: 27 \: ( {3}^{3} ) \: are \: perfect \: real \: cubes.[/tex]

[tex]\sf \: So \: use \: the \: algebraic \: identity \: \\ \sf {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )[/tex]

[tex]\sf \: a = \sqrt[3]{x^{3}} = x \\ \sf \: b = \sqrt[3]{27} = 3[/tex]

[tex] \sf \: {x}^{3} - {3}^{3} \\ \sf= (x - 3)( {x}^{2} + 3x + {3}^{2} ) \\ = \sf \: (x - 3)( {x}^{2} + 3x + 9)[/tex]

Answer ⟶ [tex]\boxed{\bf{(x-3)(x^{2}+3x+9)}}[/tex]

Answer:

y=-2x+2

Step-by-step explanation:

substitute either the x or y value into the equations, if you substitute x=3 and get back y=-4, the equation is correct

Answer: What's the question? I'll edit my answer to the question if you would give me the actual problem

Step-by-step explanation:

9514 1404 393

Answer:

  invalid

Step-by-step explanation:

There is more than one set of dimensions that will give a triangle with an area of 6. The fact that the area is 6 implies nothing about the dimensions (except that their product is 12).

The converse is invalid.

Answer:

The first sentence is valid but the second one is invalid.

Step-by-step explanation:

You can't say just because the area of the triangle is 6, its base is 3 and its height is 4, it might have a base of 1 and a hight of 12 so there are more than one answers for the second one.

Feel free to message me if you still have questions :)

Answer:

-2 3/20 or -2.15

Step-by-step explanation:

There is an app you can get on your phone called fraction calculator, its an app for mulitplying, dividing, adding, and subtracting any number with a fraction:)

Answer:

Population of town in 2020 = 4626 (Approx.)

Step-by-step explanation:

Given:

Population of town in 2000 = 12,910

Decrease rate = 5% = 0.05 yearly

Find:

Population of town in 2020

Computation:

Number of year = 20 years

Population of town in 2020 = Population of town in 2000[1-r]ⁿ

Population of town in 2020 = 12,910[1-0.05]²⁰

Population of town in 2020 = 12,910[0.95]²⁰

Population of town in 2020 = 12,910[0.3584]

Population of town in 2020 = 4625.944

Population of town in 2020 = 4626 (Approx.)

Answer:

The population is 4628.

Step-by-step explanation:

Population in 2000 = 12910

Rate of decrease = 5 %

Time, t = 2020 - 2000 = 20 years

Let the population is P.

Use the formula

[tex]P = Po\left ( 1-\frac{r}{100} \right )^t\\\\P = 12910\left ( 1-0.05 \right )^2\\\\P = 4628[/tex]

Answer:

Step-by-step explanation:

With some research I found that the medians (QK, RJ, and SI) are broken into 2:1 ratios.

So what this means is that QD is twice as long as DK.

QD = 2DK

QD = 2 * 6.5

QD = 13

hope so this might help

ans is above in the pic

Recall that 2⁴ = 16. So you have

2⁶⁰ = 2⁴ˣ¹⁵ = (2⁴)¹⁵ = 16¹⁵

Answer:

3/4

Step-by-step explanation:

Fraction of names called last week = 1/4 of a page

Fraction called this week = 1/2 of a page

The number of pages worth of people called ;

This is an addition problem, as the total will be the sum. Of the fractions called this week and last week

Hence,

Total page worth of names called :

(1/4 + 1/2) = (1 + 2) / 4 = 3/4

Answer:

96 in²

36 in²

60 in²

6.51 in

Step-by-step explanation:

Given that :

Dimension of paper = 12 in by 8 in

Dimension of right triangles :

2 in by 9 in ; 3 in by 6 in

Area of sheet of paper = 12 in * 8 in = 96 in²

Area of triangle = 1/2 base * height

Therefore, area of remnant right triangle :

2 * 1/2 * 2 * 9 = 18 in²

2 * 1/2 * 3 * 6 = 18 in²

Combined area of triangle left = 18in + 18in = 36 in²

Area of parallelogram = Area of sheet - Area of triangles left

Area of parallelogram = 96in² - 36in² = 60 in²

Base, b of parallelogram = 9.22 in

Area of parallelogram = base * altitude,h

60in² = 9.22h

h = 60 / 9.22 = 6.51 in

Answer:

good evening good evening good evening good evening

Answer:

Step-by-step explanation:

I'm not sure if I am too late to answer this but the trick to this is to reflect the function over the line y = x.

Basically, if you have the point (-2, 3)

you turn in into (2, -3) and you'll be good. (switch the two coordinates and take the negative for both.)

Answer:

It decreased

Step-by-step explanation:

It decreased. Assuming that the temperature is 100 and it is now reduced by 60% then the temperature will be at 40 and if it increased by 80% then the final temp is 72. So it is 48% of the original temp.

Answer:

Solution given:

Relationship between base and hypotenuse is given by Cos angle

Cos Angle(?)=base/hypotenuse

Angle{?}=Cos-¹(40/58)

Angle{?}=46°

The indicated angle is 46°

Answer:

19 + 1 + 9 + 1

put any of those in the slots

Answer:

19 + 1 + 9 + 1

peace