Draw the structural formula for both of these alcohols:
2,3, 4-trimethyl, 3-heptanol
4-ethyl, 4-octanol

Answer:

A mixture is matter that can vary in composition. ... A heterogeneous mixture is a type of mixture in which the individual substances are not evenly mixed. Because the substances in a heterogeneous mixture are not evenly mixed, two samples of the same mixture can have different amounts of the substance.

Explanation:

Answer:

[tex]pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12[/tex]

answer is 2546 h

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Answer:

Mass of the ball is . 42 kg. The density of air is 1.2 kg/m3.

Explanation:

Answer:

[tex]^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He[/tex]

Explanation:

Hello there!

In this case, since the radioactive reaction for the alpha emission of astatine-218 to bismith-214 involve the release of a helium atom as shown below:

[tex]^{218}_{85}At\rightarrow ^{214}_{83}Bi+^{4}_{2}He[/tex]

Whereas the atomic number decreases by 2 and the mass number by 4 in agreement to the release of the Helium atom.

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Answer:

See explanation

Explanation:

Let us look at the reaction again;

Cr2O7 2- (aq) + H2O(l)⇄ 2CrO4 2-(aq) + 2H^+(aq)

When we add sodium hydroxide to the system as shown, the hydroxide ion removes the hydrogen ion thereby leaving a large concentration CrO4^2-(aq) in the system this causes the solution to turn green(equilibrium position shifts to the right).

The net ionic equation is;

OH^-(aq) + H^+(aq) ----> H2O(l)

The reaction;

OH^-(aq) + H^+(aq) ----> H2O(l) is exothermic hence, if the temperature of the system is increased, the equilibrium position will shift towards the left hand side and the solution turns orange.

Answer:

True

Explanation:

hope this helps mate

Answer:

cornea,Jens and pupil

tma Po yan

Answer:

the 2nd and 5th

Explanation:

they are both correct

Answer:

b and d | Glucose is a reactant in both photosynthesis and cellular respiration. | Carbon dioxide is a product of both photosynthesis and cellular respiration.

Explanation:

hope this helps.

Answer:

-713 kJ

Explanation:

Step 1: Write the balaned thermochemical equation

4 NH₃(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(g)  ΔΗ = -1267 kJ

Step 2: Calculate the moles corresponding to 38.4 g of NH₃

The molar mass of NH₃ is 17.03 g/mol.

38.4 g × 1 mol/17.03 g = 2.25 mol

Step 3: Calculate the  enthalpy change to burn 2.25 mol of ammonia

According to the thermochemical equation, 1267 kJ are released per 4 moles of ammonia that react.

2.25 mol × (-1267 kJ/4 mol) = -713 kJ

Answer:

Research that releases a poisonous gas into the air.

Explanation:

Since I don't know the options I will guess it is ^

Answer:

1

Explanation:

hhihh2

Answer:

The Cell Wall

Explanation:

Answer:

C. It was based on the thoughts of an early philosopher.

The symbol of the element in which it's ion has 38 protons, 36 electrons, and 40 neutrons is ⁷⁸₃₈Sr

To obtain the symbol of the element, we shall obtain the mass number of the element. This is shown below:

Mass number = Proton + Neutron

Mass number = 38 + 40

Mass number = 78

Finally, we shall determine the symbol of the element. Details below:

From the periodic table, the element with atomic number of 38 is Strontium.

Thus, the symbol of the element will be ⁷⁸₃₈Sr

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Answer:

59.3g

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (8.12×10^23)/(6.02×10^23)

Mole = 1.35mole

Molar mass of CO2 = 12+ 2(16)

Molar mass= 12 + 32= 44g/mol

Mole = mass/molar mass

Mass = Mole × molar mass

Mass = 1.35× 44

Mass= 59.35g

Answer:

ee = 96%

Explanation:

Enantiomeric excess, ee, is a way to express a mixture that is not enantiomerically pure. It is defined as 100 times the ratio between the  differences of amounts of enantiomers and the total amunt. that is:

ee = |A-B|/ A+B * 100

ee = |98%-2%| / 98+2 * 100

Helium atom would have the highest kinetic energy.

Kinetic energy is a form of energy that a gas has by reason of its motion.

If work, which transfers energy, is done on a gas by applying a net force, the gas speeds up and thereby gains kinetic energy

Different gas particles move at different speeds with there definite kinetic energy—gases with smaller particles tend to be moving faster at the same temperature, which means they have a higher speed.

Helium is the smallest particles and thus, it will be the gas with the highest speed.

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Answer:

CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl

Explanation:

Alkanes react with halogens in the presence of light to yield alkyl halides. The degree of substitution increases as the reaction progresses. The reaction occurs by free radical mechanism.

The reaction between butane and chlorine molecule to yields a monosubstitution product occurs as follows;

CH3CH2CH2CH3 + Cl2 --------> CH3CH2CH2CH2Cl + HCl

Answer:

128.4 g

Explanation:

Step 1: Given data

Step 2: Determine the total mass of the sample

The mass percent of element X in X(NO₃)₂ is 52.55%, that is, there are 52.55 g of X every 100 g of X(NO₃)₂. Then, the mass of X(NO₃)₂ that contains 67.50 g of X is:

67.50 g X × 100 g X(NO₃)₂/52.55 g X = 128.4 g X(NO₃)₂

Answer:

What's the equation?

Answer:

14.5 g

Explanation:

its true

Answer:

Explanation:

25.71 × 10²³ molecules are there in 4.27 mol of tungsten (VI) oxide, [tex]WO_3[/tex].

To find the Number of molecules of substance multiply the number of moles of given substance by Avogadro number

Number of molecules = Number of moles × Avogadro's Number

Avogadro's number [tex](N_{A})[/tex] is the number of particles in one mole of substance. 6.023 × 10²³ is known as Avogadro's constant / Avogadro's number.

Avogadro's number = 6.023 × 10²³ [tex]mol^{-}[/tex]

Now,

Number of molecules in 4.27 moles of [tex]WO_{3}[/tex]

= Number of moles of [tex]WO_{3}[/tex] × Avogadro's Number

= 4.27 × 6.023 × 10²³

= 25.71 × 10²³ molecules

Thus, we can say that 25.71 × 10²³ molecules are there in 4.27 moles of tungsten (VI) oxide, [tex]WO_3[/tex].

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Vascular tissue

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Cross section of celery stalk, showing vascular bundles, which include both phloem and xylem.

Detail of the vasculature of a bramble leaf.

Translocation in vascular plants

This article is about vascular tissue in plants. For transportation in animals, see Circulatory system.

Vascular tissue is a complex conducting tissue, formed of more than one cell type, found in vascular plants. The primary components of vascular tissue are the xylem and phloem. These two tissues transport fluid and nutrients internally. There are also two meristems associated with vascular tissue: the vascular cambium and the cork cambium. All the vascular tissues within a particular plant together constitute the vascular tissue system of that plant.

The cells in vascular tissue are typically long and slender. Since the xylem and phloem function in the conduction of water, minerals, and nutrients throughout the plant, it is not surprising that their form should be similar to pipes. The individual cells of phloem are connected end-to-end, just as the sections of a pipe might be. As the plant grows, new vascular tissue differentiates in the growing tips of the plant. The new tissue is aligned with existing vascular tissue, maintaining its connection throughout the plant. The vascular tissue in plants is arranged in long, discrete strands called vascular bundles. These bundles include both xylem and phloem, as well as supporting and protective cells. In stems and roots, the xylem typically lies closer to the interior of the stem with phloem towards the exterior of the stem. In the stems of some Asterales dicots, there may be phloem located inwardly from the xylem as well.

Between the xylem and phloem is a meristem called the vascular cambium. This tissue divides off cells that will become additional xylem and phloem. This growth increases the girth of the plant, rather than it

Answer:

V1 = 8.3 mL

Explanation:

Step 1: Given data

Initial volume (V1): ?

Initial concentration (M1): 6.0 M

Final volume (V2): 50.0 mL

Final concentration (M2): 1.0 M

Step 2: Calculate the volume of the initial solution

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the initial solution using the dilution rule.

M1 × V1 = M2 × V2

V1 = M2 × V2 / M1

V1 = 1.0 M × 50.0 mL / 6.0 M = 8.3 mL

We will take 8.3 mL of the 6.0 M solution and add water until we have 50.0 mL.