driver a had a speed of 145.155 and driver b had a speed of 145.827 and driver c had a speed of 1144.809.Driver d had a speed between driver a and driver c. Write a possible speed for driver d. ​

Answer:

a²+(b-c)²

hope it helps

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

[tex]m=\frac{2Ke}{v\\^{2} }[/tex]

Answer:

Step-by-step explanation:

Answer:

There would be a line going directly through the x-asis

Step-by-step explanation:

Answer:

Step-by-step explanation:

AC² = AD² + DB ²

25 = AD² + 9

AD²= 25 - 9

AD² = 16

AD = 4

Area = 4*3 /2

= 6cm

Answer:

sum of two terms. So, the verbal expression 15 plus r can be used to describe the algebraic expression 15 + r

Step-by-step explanation:

Answer:

Im pretty sure it would be C

Step-by-step explanation:

The location of R on the number line will be 15/7 so option (C) will be correct.

In mathematics, a number line is a straight line containing numbers arranged at equal segments or periods throughout its duration.

In another word, a number line is basically a line in which infinite numbers have been written in ascending order or increasing order.

A horizontal number line is the most common representation and can be extended infinitely in any direction.

Distance from S to T = 3 + 9 = 12

So,

SR + RT = 12

And given,

SR/RT = 3/4 ⇒ SR = (3/4)RT

By substitution,

(3/4)RT + RT = 12

RT ( 7/4) = 12

RT = 48/7

Now the location of point R ⇒

OT - RT = 9 - 48/7 = 15/7

Hence "The location of R on the number line will be 15/7".

To learn more about the number line,

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Answer:

[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]

Or:

[tex]pm = qn \text{ and } pn + qm \neq 0[/tex]

Step-by-step explanation:

We are given two complex numbers:

[tex]\displaystyle m + ni \text{ and } p + qi[/tex]

Where m, n, p, and q are real numbers.

And we want to determine the relationship among m, n, p, and q such that the product of the two complex numbers will only have an imaginary part.

Find the product:

[tex]\displaystyle \begin{aligned} (m+ni)(p+qi) &= p(m+ni) + qi(m+ni) \\ &= (pm + pni) + (qmi + qni^2) \\ &= (pm + pni) + (qmi - qn) \\ &= (pm - qn) + i(pn + qm) \end{aligned}[/tex]

Therefore, for the product to have only an imaginary part, the real part must be zero and the imaginary part must not be zero. That is:

[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]

In conclusion, the relationship between m, n, p, and q is:

[tex]\displaystyle pm - qn = 0\text{ and } pn + qm \neq 0[/tex]

Or:

[tex]pm = qn \text{ and } pn + qm \neq 0[/tex]

(Note: I couldn't understand the provided answer choices, but the above answer is indeed correct (and the second equation can be ignored).)

Answer:

this question doesn`t have much information but here`s my best guess

(2x-y)^2

[tex](2x - y)^2[/tex]. This expression represents the result of squaring the difference between 2x and y.

1. **Difference between 2x and y:** The difference between 2x and y is calculated by subtracting y from 2x. This gives us the expression "2x - y," which represents the numerical difference between these two quantities.

2. **Square of the Difference:** To square this difference, we simply multiply "2x - y" by itself. When you square something, you multiply it by itself. In mathematical notation, squaring is denoted using an exponent of 2, which is written as "^2."

So, combining the two steps, we have:

[tex](2x - y)^2[/tex]. This expression represents the result of squaring the difference between 2x and y. When you expand this expression, you get a quadratic expression, which may include terms like [tex]4x^2, y^2[/tex], and -2xy, among others, depending on the values of x and y.

To know more about difference :

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Step-by-step explanation:

n+4-9-5n

n-5n+4-9

-4n-5

It is composite because it can be divided by 2 and 4.

Answer:

18).

[tex]n + 4 - 9 - 5n \\ = (n - 5n) + (4 - 9) \\ = - 4n - 5 \\ = - (4n + 5)[/tex]

20).

It is a composite number, because it had more than two factors

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

6)b) Sin A - x Cos A = 0

Sin A = x Cos A

[tex]\dfrac{Sin \ A}{Cos \ A} = x[/tex]

[tex]\dfrac{1}{x}=\dfrac{1}{\dfrac{Sin \ A }{Cos \ A}}=1*\dfrac{Cos \ A}{Sin \ A}=\dfrac{Cos \ A}{Sin \ A}[/tex]

[tex]RHS = x +\dfrac{1}{x}\\\\\\[/tex]

         [tex]= \dfrac{Sin \ A}{Cos \ A}+\dfrac{Cos \ A}{Sin \ A}\\\\\\=\dfrac{Sin \ A*Sin \ A}{Cos \ A*Sin \ A}+\dfrac{Cos \ A * Cos \ A}{Sin \ A* Cos \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Cos \ A*Sin \ A}+\dfrac{Cos^{2} \ A}{Cos \ A* Sin \ A}\\\\= \dfrac{Sin^{2} \ A+Cos^{2} \ A}{Cos \ A*Sin \ A}\\\\=\dfrac{1}{Cos \A*Sin \ A}\\\\= \dfrac{1}{Cos \ A}*\dfrac{1}{Sin \ A}\\\\=Sec \ A * Cosec \ A[/tex]

          = LHS

7a) 1 - Sin A = 1/2

     [tex]1 = \dfrac{1}{2}+ Sin \ A\\\\1-\dfrac{1}{2}=Sin \ A\\\\\dfrac{1}{2}=Sin \ A\\[/tex]

⇒ A = 30°

Sec² A = Sec² 30° = [tex](\frac{2}{\sqrt{3}})^{2}=\frac{2^{2}}{(\sqrt{3)^{2}}}=\frac{4}{3}[/tex]

[tex]tan^{2} \ A = tan^{2} 30 = (\dfrac{1}{\sqrt{3}})^{2} = \dfrac{1}{3}[/tex]

LHS = 6 Sec² A + 9 tan² A

       [tex]= 6*\dfrac{4}{3}+9*\dfrac{1}{3}\\\\\\=2*4 + 3*1\\\\\\= 8 + 3\\\\= 11 = RHS[/tex]

Answer:

x + 2 + 3x = 30

Step-by-step explanation:

Both lengths are unknown, but Ginny's car length is described in terms of Zach's car length, so we choose a variable for Zach's car length.

Let x = Zach's car length.

Zach's car length is x.

"Ginny's car is 2 more than 3 times the length of Zach's car."

Ginny's car length is 2 + 3x.

Add the lengths:

x + 2 + 3x

"The sum of the lengths of both cars is 30 inches."

x + 2 + 3x = 30

Answer: x + 2 + 3x = 30

Answer:

64w^2

Step-by-step explanation:

Because 8w is in parentheses, you must apply the exponent to both the 8 and w.

So, it becomes (8*8)(x*x) which equals (64)(x^2).

Which then gives you your final answer, 64x^2.

Answer:

The balance would be $160 from whatever it was before the 4 months.

Step-by-step explanation:

Since the bank balance is being added by 40 for each month for 4 months, 4 * 40 is just 4*4 with an extra zero on the end. so that would be $160.

So if the balance before was $40, then the new balance after 4 months would be $200.

If there's no money previously, then there is now $160 after 4 months.

If there's a value before the $40 for 4 months, let me know and I will explain and tell you what it is.

Answer:

Step-by-step explanation:

The solution of a linear system is the intersection of the lines.

We can see the lines A and B intersect at the point (7.5, 12) which is the solution.

See attached for better visualization.

Answer:

(7.5,12.5)

Step-by-step explanation:

Answer:

a = 9

b = 2

Step-by-step explanation:

Given : a = 9

a = b + 7

9 = b + 7

b = 9 - 7 = 2

Answer:

According to my equation it's 20°

Answer:

[4,infinity] for DECREASING

[negative infinity, 4] for INCREASING

Step-by-step explanation:

Answer:

x=1

Step-by-step explanation:

x = -4 + 6 + (11 + 4(-3)).

First get the numbers in the parentheses

x = -4 + 6 + (11 - 12)

Since 11 - 12 = -1. We can replace (11-12) with -1

x = -4 + 6 -1

Now add and subtract

x = 1

Answer: I think Plan A is the cheapest

Step-by-step explanation:

I would say this because all it is is a 10 cent incline and 30 dollars cheaper, meaning it would take almost 15 weeks to earn 30 dollars on the plan a, while plan b will already be at like 100 Dollars.

I am sorry if I didn't completely answer your question but I did the best to my ability

Thanks!

Answer: 468 sandwiches

Step-by-step explanation:

subtract 812 from 2450. you're left with 1,638 dollars left.

divide 1638 by 3.5 and you get 468

Answer:

3

Step-by-step explanation:

Answer:

it would be false

Step-by-step explanation:

Answer: a = 300, b = b = 50.24

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

let x represent the equally priced bracelets of which there are 4 , so 4x

We know she spent $64 on rings and a total of $200 was spent , then

64 + 4x = 200 ← represents the situation

x represents the cost of a bracelet

Answer:

c

Step-by-step explanation:

the total amount paid at the jewelry is 200

64 was spent on rings

the rest amount of money was spent on 4 bracelets

let the price of one bracelet be x

200=4(x)+64

200=4x+64