Due to the heavy rains, all pallets of blocks have become wet and the weight of each block has altered. It is desired to estimate the average weight of the blocks thus wet. For this, a sample of 15 blocks is selected and the following weights are recorded in kilograms: 45.8, 43.9, 46.2, 48.5, 47.2, 45.8, 49.1, 43.9, 47.6, 42.8, 46.5, 44.9, 46.8, 45.8 and 44.6; Estimate µ, the average weight of all pallets of blocks, and determine a bound for the estimation error.

Answers

Answer 1

Answer:

To find the estimated value we add all of them together then divide it by the amount of them

45.8+43.9+46.2+48.5+47.2+45.8+49.1+43.9+47.6+42.8+46.5+44.9+46.8+45.8 +44.6=689.4

now we divide it by 15 since there is 15 blocks so

689.4 divided by 15=45.96

so the average weight is 45.96


Related Questions

Can I get some help with this question? I have attempted several times and failed.

Answers

9514 1404 393

Answer:

  B.  relative maximum of 8.25 at x=2.5

Step-by-step explanation:

A quadratic of the form ax²+bx+c has an absolute extreme at x=-b/(2a). For your quadratic, that is ...

  x = -5/(2(-1)) = 5/2

The value of the extreme is ...

  f(5/2) = (-5/2 +5)(5/2) +2 = 25/4 +2 = 33/4 = 8.25

The negative leading coefficient tells you the graph opens downward, so the extreme is a maximum.

The function has a relative maximum of 8.25 at x = 2.5.

__

A graphing calculator can show this easily.

giải phương trình vi phân: y" - 5y' + 6y = 6x + 7

Answers

Неоднородное ДУ второго порядка. Детали в аттаче.

Choose the correct vertex of the function f(x) = x2 - X + 2.

Answers

Answer:

The vertex of the function is [tex](\frac{1}{2}, \frac{7}{4})[/tex]

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

[tex]f(x) = ax^{2} + bx + c[/tex]

It's vertex is the point [tex](x_{v}, y_{v})[/tex]

In which

[tex]x_{v} = -\frac{b}{2a}[/tex]

[tex]y_{v} = -\frac{\Delta}{4a}[/tex]

Where

[tex]\Delta = b^2-4ac[/tex]

If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]y_{v}[/tex].

f(x) = x² - X + 2.

Quadratic equation with [tex]a = 1, b = -1, c = 2[/tex]

So

[tex]\Delta = b^2-4ac = (-1)^2 - 4(1)(2) = 1 - 8 = -7[/tex]

[tex]x_{v} = -\frac{(-1)}{2} = \frac{1}{2}[/tex]

[tex]y_{v} = -\frac{-7}{4} = \frac{7}{4}[/tex]

The vertex of the function is [tex](\frac{1}{2}, \frac{7}{4})[/tex]

anyone help me, let's prove

Answers

Answer:

In my opinion the limit is equal to 1 not 0, sorry.

Step-by-step explanation:     6  25  13  43

lim n ⇒∞ ((2n - 1)/2n)

lim n ⇒∞ (2n/2n) - 1)/2n)        2n/2n = 1    1/∞  = 0

              =   1  - 0

              =    1

   

when I graphed the function I also got 1

i need help pls it’s timedd!!!!

Answers

Answer:

5.

Step-by-step explanation:

If you were to rotate the triangle, you can apply Pythagoras Theorem.

Therefore,

a^2 = 12^2 - 13^2 (Note: a^2 = a squared)

a^2 = 144 - 169

a^2 = -25.

a     = 5.

Not sure why its negative though im pretty sure its the right answer.

in BCD triangle :

DC^2 = BC^2 + BD^2

13^2 = 12^2 + BD^2

169 = 144 + BD^2

BD^2 = 169 - 144

BD^2 = 25

BD = 5

_______________________

In the other hand we have :

BD^2 = AB × BC

5^2 = AB × 12

AB = 25/12

________________________

Also we have :

AD^2 = AB × AC

AD^2 = 25/12 × ( 25/12 + 12 )

AD^2 = 25/12 × ( 25/12 + 144/12 )

AD^2 = 25/12 × 169/12

AD^2 = 25 × 169 / 12 × 12

AD^2 = 5 × 5 × 13 × 13 / 12 × 12

AD = 5 × 13 / 12

AD = 65 / 12

AD = 5.42

Thus the correct answer is option C

I don’t get this at all

Answers

Answer:

0.21

Step-by-step explanation:

There's 21 kids with a cell phone and no tablet

so 21/100 = 0.21

A payday loan company charges a $90 fee for a $500 payday loan that will be repaid in 16 days.

Treating the fee as interest paid, what is the equivalent annual interest rate?

Answers

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

Interest amount paid on loan = $90

Principal value, amount borrowed = $500

Period, t = 16 days

The equivalent annual interest :

Using the simple interest formula :

simple interest = principal * rate * time

Using, days of year = 365

Plugging in the values into the formula :

90 = 500 * rate * (16/365)

90 = 500 * rate * 0.0438356

90 = 21.917808 * rate

Rate = 90 / 21.917808

Rate = 4.10 = 4.10 * 100% = 410%

If days of year = 360 is used :

90 = 500 * rate * (16/360)

Rate = 90 / 22.222

Rate = 4.05 = 4.105 * 100% = 405%:

Find the value of y and show work

Answers

Answer:

75

Step-by-step explanation:

∠K and ∠ R are congruent (equal)

Triangle Sum Theory - angles of all triangles add to 180

180 - 79 - 26 = 75

Which expression are greater than 1/2? Choose all the apply

Answers

Answer:

25/30

5/8

Step-by-step explanation:

Which fraction is it out of all of these 6/14,5/8,25/30,or 3/6?

to determine which fractions are greater than 1/2, convert the fractions to decimals

to convert to decimals, divide the numerator by the denominator

1/2 = 0.5  less than half

6/14 = 0.43 less than half

5/8 = 0.625 greater than half

25 / 30 = 0.83 greater than half

3 / 6 = 0.5 equal to half

How do you solve x[tex]x^{2} +4x+3=0[/tex]?

Answers

Answer:

[tex]{ \tt{ {x}^{2} + 4x + 3 = 0}} \\ { \tt{(x + 1)(x + 3) = 0}} \\ \\ { \tt{x = - 1 \: \: and \: \: - 3}}[/tex]

Find the measure of WX and show work

Answers

Ans : the measure of WX = 8

Alix is 10 years older than tamia. Alanna is twice as old as tamia. If the sum of their ages is 74, how old is alanna

Answers

Answer:

Alanna is 32 years old

Step-by-step explanation:

Hi there!

We're given that Alix is 10 years older than Tamia and Alanna is twice as old as Tamia.

Since Alix and Alanna's ages are in relation to Tamia's, let's make Tamia's age x

Alix is 10 years older than Tamia, so Alix must be x+10 years old

Alanna is twice as old as Tamia, so she must be 2x years old

We're also given that Alix+Alanna+Tamia=74

When we substitute it with the expressions we have, it becomes:

x+x+10+2x=74

now combine like terms

4x+10=74

subtract 10 from both sides

4x=64

divide both sides by 4

x=16

We found the value of x (Tamia's age)

However, the problem asks for Alanna's age, which we have set as 2x

So Alanna is 2*16, or 32 years old

Hope this helps! :)

Answer:

32 years

Step-by-step explanation:

that is the procedure above

Find x. Round to the nearest tenth: 29° 500ft
X=[?]ft

Answers

9514 1404 393

Answer:

  437.3 ft

Step-by-step explanation:

The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

  cos(29°) = x/(500 ft)

  x = (500 ft)cos(29°)

  x ≈ 437.3 ft

A box with a square base and open top must have a volume of 256000 c m 3 . We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only x , the length of one side of the square base.

Answers

Answer:

Follows are the response to the given question:

Step-by-step explanation:

The volume of the box:

[tex]V = x\times x \times h = 256000 \ cm^3\\\\\to x^2 \times h = 256000\\\\\to h = \frac{256000}{x^2}[/tex]  

The surface area of the open box is:

[tex]A(x) = x \times x + 2 \times (x \times h +x \times h)\\\\A(x) = x^2 + 4 \times x \times h\\\\A(x) = x^2 + \frac{1024000}{x}\\\\\frac{d(x^n)}{dx} = n \times x^{(n - 1)}\\\\[/tex]

Use above formula

[tex]A'(x) = 2 \times x - \frac{1024000}{x^2}\\\\[/tex]

[tex]A'(x) = 0\\\\2\times x - \frac{1024000}{x^2} = 0\\\\2x = \frac{1024000}{x^2}\\\\x^3 = 512000\\\\x = (512000)^{(\frac{1}{3})} = 80\ cm\\\\[/tex]

Now

[tex]A''(x) = 2\times 1 + 2\times \frac{1024000}{x^3}\\\\A''(x) = 2 + \frac{2048000}{x^3}\\\\x = 80 \ cm\\\\A''(80) = 2 + \frac{2048000}{80^3} = 6\\\\[/tex]

therefore [tex]A"(x) > 0,[/tex] x amount of material used in minimum.

[tex]h = \frac{256000}{80^2} = 40\ cm[/tex]


HELP PLEASE IM STUCK!

1. Which of these describes the relation for this set of coordinate pairs?
{(-1, 5), (12, 18), (0, 6), (-3, 3), (4, ?), (?, 11)}
a. x - y = 6 b. f(x) = x +6 c. f(x) = 6 d. y = 6x e. None of these

Answers

Answer:

b) f(x) = x + 6

Step-by-step explanation:

The coordinate (0, 6) makes the y-intercept = 6. Only one of these functions has that intercept: f(x) = x + 6. If you plug in each coordinate the outputted y-value matches up, making this the right answer.

Your manager is trying to determine what forecasting method to use. Based upon the following historical data, calculate the following forecast and specify what procedure you would utilize.MONTH DEMANDJanuary 59February 65March 65April 67May 71June 70July 77August 77September 77October 75November 83December 81Calculate the simple three-month moving average forecast for April through December. What is the forecast for December? (Round your answer to 2 decimal places)a) 78.33b) 74.67c) 76.33d) 77.00Calculate the weighted three-month moving average using weights of 0.50 (t-1), 0.30 (t-2), and 0.20 (t-3) for April through December. What is the forecast for December? (Round your answer to 2 decimal places)a) 79.40b) 77.00c) 76.00d) 73.70Calculate the single exponential smoothing forecast for February through December using an initial forecast (F1=F-January) of 63. (Use alpha of 0.2) What is the forecast for December? (Round your answer to 2 decimal places) a) 66.30b) 74.37c) 72.22d) 71.52Calculate the mean absolute deviation (MAD) for the forecasts made by each technique in April through December. Which forecasting method do you prefer? (Round your answer to 2 decimal places)a) 3-month moving average (4.15)b) 3-month weighted moving average (3.99)c) Exponential smoothing method (alpha=0.30) (3.58)d) 3-month weighted moving average (3.58)

Answers

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the attached file.

For question 1:

Forecast for December:

[tex]\to \frac{(77+75+83)}{3} \\\\ \to 78.33[/tex]

For question 2:

Forecast for December:

[tex]\to (77 \times .5+75 \times 3+83 \times .2) \\\\\to 79.40[/tex]

For question 3:

Forecast for December:

[tex]\to 72.22+(83-72.22)\times 0.2 \\\\\to 74.37[/tex]

For question 4:

So, the 3-month weighted moving average (3.58)

At a price of per ticket, a musical theater group can fill every seat in the theater, which has a capacity of . For every additional dollar charged, the number of people buying tickets decreases by . What ticket price maximizes revenue? Revenue is maximized when the price is

Answers

Answer:

The appropriate answer is "$12".

Step-by-step explanation:

As per the question,

Price per ticket,

= [tex]4+k[/tex]

Number of people,

= [tex]1800-90k[/tex]

Now,

The revenue (R) will be:

= [tex]Price \ per \ ticket\times Number \ of \ people[/tex]

By putting the values, we get

= [tex](4+k) (1800-9k)[/tex]

= [tex]-90k^2+1440k+7200[/tex]

or,

⇒ [tex]R'=1440-180k=0[/tex]

⇒                     [tex]180k=1440[/tex]

⇒                          [tex]k=\frac{1440}{180}[/tex]

                               [tex]=8[/tex]

hence,

The ticket price will be:

= [tex]4+k[/tex]

= [tex]4+8[/tex]

= [tex]12[/tex] ($)

There are 750 identical plastic chips numbered 1 through 750 in a box. What is the probability of reaching into the box and randomly drawing a chip number that is smaller than 627

Answers

Answer:

0.8358 = 83.58% probability of reaching into the box and randomly drawing a chip number that is smaller than 627

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

[tex]P(X < x) = \frac{x - a}{b - a}[/tex]

There are 750 identical plastic chips numbered 1 through 750 in a box

This means that [tex]a = 1, b = 750[/tex]

What is the probability of reaching into the box and randomly drawing a chip number that is smaller than 627?

[tex]P(X < x) = \frac{627 - 1}{750 - 1} = 0.8358[/tex]

0.8358 = 83.58% probability of reaching into the box and randomly drawing a chip number that is smaller than 627

When comparing two box-plots that show the same type of information, what determines agreement within the data?
A.the range of the quartiles in each data set
B.the median of each data set
C.the mean of each data set
D.the number of values in each data set

Answers

Answer:

c.the mean of each data set

Answer:

A

Step-by-step explanation:

if a line with an angle of inclination 120⁰ and passes trough (√3,1),then what is the equation of a line​

Answers

Answer:

The equation of a line, having inclination 120° with positive direction of x-axis, .of x-axis, which is at a distance of 3 units from the origin is​. 1. See answer ... where α is the angle with the positive X-axis, made by the perpendicular line drawn Now, from equation  the equation of the straight line will be.

Step-by-step explanation:

what are functions in math

Answers

A function is an equation for which any x that can be plugged into the equation will yield exactly one y out of the equation.

find f(1)' If u know that
g(1)=1 , g'(1)= -1
h(1)= -2 , h'(1) 3

Answers

Step-by-step explanation:

[tex]f(x) = g(x)h(x)[/tex]

Taking the derivative of f(x), we get

[tex]f'(x) = g'(x)h(x) + g(x)h'(x)[/tex]

Then [tex]f'(1)[/tex] becomes

[tex]f'(1) = (-1)(-2) + (1)(3) = 5[/tex]

Question 11 of 45
Which similarity postulate or theorem can be used to verify that the two
triangles shown below are similar?
12
6 R
X 2 z
O A. Similarity cannot be determined,
B. SSS theorem
O C. AA postulate
D. SAS theorem

Answers

Answer:

You are only given a Side, an Angle, and then a side.  So that is what I would choose.  It can't be AA because you weren't given two angles.  It can't be SSS because you weren't given 3 sides.

Step-by-step explanation:

ΔPQR and ΔXYZ are similar due to the SSS theorem.

Option B is the correct answer.

What is triangle congruency?

There are ways to prove that two triangles are congruent.

- Side-Side-Side (SSS) Congruence.

The three sides of one triangle are equal to the corresponding three sides of another triangle.

- Side-Angle-Side (SAS) Congruence.

The two sides and the included angle of one triangle are equal to the corresponding two sides and included angle of another triangle.

- Angle-Side-Angle (ASA) Congruence.

The two angles and the included side of one triangle are equal to the corresponding two angles and included side of another triangle.

- Angle-Angle-Side (AAS) Congruence.

We have,

Similar triangles are triangles that have the same shape but may have different sizes.

Two triangles are similar if their corresponding angles are equal, and their corresponding sides are proportional.

When two triangles are similar, they have the same shape, but one may be larger or smaller than the other.

Now,

ΔPQR and ΔXYZ

PQ/XY = 12/4 = 3

PR/XZ = 6/2 = 3

Since the two sides are proportional,

QR/YZ will be proportional.

Now,

PQ/XY = PR/XZ = QR/YZ

ΔPQR and ΔXYZ are similar due to the SSS theorem.

Thus,

ΔPQR and ΔXYZ are similar due to the SSS theorem.

Learn more about triangle congruency here:

https://brainly.com/question/12413243

#SPJ7

A square-based tent covers an area of 64 square feet. What is the length of one side of the tent?

Answers

Answer:

8 feet

Step-by-step explanation:

A square's area can be expressed as l², with l representing one side of the tent. Therefore, as our area is 64, we can say that 64 = l². Taking the square root of both sides, we get that √64 = l, and l = 8 feet

Nếu cắt mặt cầu bởi một mặt phẳng chiếu đứng thì hình chiếu bằng của giao tuyến là:

Answers

Answer:

Im sorry I can't understand you

I need help with this.

Answers

9514 1404 393

Answer:

  $400

Step-by-step explanation:

The word "per" in math often means "divided by". To find price per square foot, find price divided by square feet.

  $700,000/(1750 ft²) = $400 /ft²

The price per square foot of House 4 was $400.

answer only one question​ No 1 only​

Answers

-10369

too lazy but that's the exact value

Answer:

Step-by-step explanation:

(-2)³ *(-4)² * 3⁴ = (-8) * 16 * 81

                      = -10368

I need help please I dont understand

Answers

It’s like this. Mark as brainliest!! Much appreciated

Segment [tex]$s_1$[/tex] has endpoints at [tex]$(3+\sqrt{2},5)$[/tex] and[tex]$(4,7)$[/tex]. Segment [tex]$s_2$[/tex] has endpoints at [tex]$(6-\sqrt{2},3)$[/tex] and[tex]$(3,5)$[/tex]. Find the midpoint of the segment with endpoints at the midpoints of [tex]$s_1$[/tex] and [tex]$s_2$[/tex]. Express your answer as [tex]$(a,b)$[/tex].

Answers

Answer:

The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).

Step-by-step explanation:

Midpoint of a segment:

The coordinates of the midpoint of a segment are the mean of the coordinates of the endpoints of the segment.

Midpoint of s1:

Using the endpoints given in the exercise.

[tex]x = \frac{3 + \sqrt{2} + 4}{2} = \frac{7 + \sqrt{2}}{2}[/tex]

[tex]y = \frac{5 + 7}{2} = \frac{12}{2} = 6[/tex]

Thus:

[tex]M_{s1} = (\frac{7 + \sqrt{2}}{2},6)[/tex]

Midpoint of s2:

[tex]x = \frac{6 - \sqrt{2} + 3}{2} = \frac{9 - \sqrt{2}}{2}[/tex]

[tex]y = \frac{3 + 5}{2} = \frac{8}{2} = 4[/tex]

Thus:

[tex]M_{s2} = (\frac{9 - \sqrt{2}}{2}, 4)[/tex]

Find the midpoint of the segment with endpoints at the midpoints of s1 and s2.

Now the midpoint of the segment with endpoints [tex]M_{s1}[/tex] and [tex]M_{s2}[/tex]. So

[tex]x = \frac{\frac{7 + \sqrt{2}}{2} + \frac{9 - \sqrt{2}}{2}}{2} = \frac{16}{4} = 4[/tex]

[tex]y = \frac{6 + 4}{2} = \frac{10}{2} = 5[/tex]

The midpoint of the segment with endpoints at the midpoints of s1 and s2 is (4,5).

PLEASE HELP ME WILL GIVE BRAINLIEST

Answers

Answer:

Reason 5

Step-by-step explanation:

Reason 1 and 2 are Given

Reason 3 is Reflexive

Reason 4 is Side-Side-Side congruency

Answer:

Reason 5

Step-by-step explanation:

It helps to know what CPCTC means and how it's used.

CPCTC means "corresponding parts of congruent triangles are congruent."

To use it, you must first either prove two triangles to be congruent or be given that two triangles are congruent.

Once you have the congruent triangles, then you state that two corresponding parts of those triangles are congruent, and you use CPCTC as the reason.

In step 4, the triangles are proven congruent by SSS.

Then CPCTC can be used as reason 5 for stating that the corresponding angles A and C are congruent.

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