each runner in an 8 mile relay races runs 4/5 of a mile. How many runners are on the relay team?

Answer:

6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Vertices are the vertex points. there are 4 vertices at the bottom and 2 vertices at the top which makes 6.

Hope this helps

Answer:

d. higher blood cholesterol causes more severe heart attacks.

Step-by-step explanation:

Two tailed tests are a method for hypothesis testing when data is distributed on the two sides. P value is determined to identify whether the hypothesis is true or false. When rs is 0.89 between blood cholesterols and severity of heart attacks then these is significant relation between them.

Answer:

Area of square = Side²

Step-by-step explanation:

The area of a 2-D region, form, or flattened lamina in the planes is the quantity that represents its extent. On the 2-D surface or 3-D object, surface is its counterpart. A shape's area can be calculated by comparing it to squares of a specific size.

Area of square = Side²

Answer:

a. 97.72% of the observations are less than 33

b. Approximately 977 observations are less than 33.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 25 and a standard deviation of 4.

This means that [tex]\mu = 25, \sigma = 4[/tex]

a. Approximately what percentage of the observations are less than 33?

The proportion is the p-value of Z when X = 33. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{33 - 25}{4}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a p-value of 0.9772

0.9772*100% = 97.72%

97.72% of the observations are less than 33.

b. Approximately how many observations are less than 33?

Out of 1000:

0.9772*1000 = 977.2

Approximately 977 observations are less than 33.

Answer

19.013.153,42629466 giây

Step-by-step explanati

van toc ánh sán  =299.792.458 m/s

s= v*t

t=s/v

t= 5.699.999.999.999.999/299.792.458= 19.013.153,42629466 giây

Answer:

work out 8^2 and then ×1/4

[tex] \frac{1}{4} (8)^{2} = 16 \: not \: 8[/tex]

therefore

[tex] \frac{1}{4} ({8})^{2} (12) = 192[/tex]

Answer:

Letter B, C and E are correct

Step-by-step explanation:

hope this helps

tell if you got it right

Answer:

Letter B, C and E are correct

Step-by-step explanation:

hope this helps

Answer:

1. The first set of number is

1,2,3,4,5

Mean= 1+2+3+4+5/5

= 15/5

= 3

Median= 3

Mode= N/A

The next set of numbers is

2,3,4,5,6,6

Mean= 2+3+4+5+6+6/6

= 26/6

= 4.3

Median=4+5/2

= 9/2

= 4.5

Mode= 6

The next set of number is

6,7,5,4,5,6,2,5

Mean= 2+4+5+5+5+6+6+7/8

= 40/8

= 5

Median= 5+5/2

= 10/2

= 5

Mode= 5

Answer:

b. S = AUB

Step-by-step explanation:

Since the coins are tossed  3 times and each coin has head, H and tail, T(2 sides), the sample space is S = 2 × 2 × 2 = 2³ = 8

All the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH,THT and TTT

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

Since A denote the event that at least 1 of the coins comes to rest with its heads side upwards, the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH and THT

So, A = {HTT, HHT, HHH, THH, TTH, HTH,THT}

Also B denote the event that none of the coins comes to rest with its heads side upwards, that is no heads. The possible outcome is TTT

So, B = {TTT}

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

So, A ∪ B = {HTT, HHT, HHH, THH, TTH, HTH,THT} ∪  {TTT} = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT} = S

So, S = A ∪ B

So, S = A ∪ B does not denote an abuse of notation.

The answer is b.

Answer:

2.45.250- 94.750

= 92. 2975. this is the learners who got the admission

Answer:

1,50,500 students

Step-by-step explanation:

Hope this helps... vote as brainliest

Answer:

1/9 √57

Step-by-step explanation:

the length of HG = √(3√3² - 2√2²)

= √(27-8) = √19

sin L F = HG/GF = √19/ 3√3

= 1/9 √57

12z - 21 = 92

12z - 21 + 21 = 92 + 21

12z = 113

z = 113/12

Answer:

2 -> 3

14 -> -3

7 -> -2

-1 -> 2

Step-by-step explanation:

Given the function

f(x) = x² - 2x - 1

If x = 2

f(x) = 2² - 2(2) - 1

f(x) = 4 - 4 - 1

f(x) = -1

If x = -2

f(x) = (-2)² - 2(-2) - 1

f(x) = 4 + 4 - 1

f(x) = 7

If x = 3

f(x) = 3² - 2(3) - 1

f(x) = 9 - 6 - 1

f(x) = 2

If x = -3

f(x) = (-3)² - 2(-3) - 1

f(x) = 9 + 6 - 1

f(x) = 14

Answer:

A= ~2.55

Step-by-step explanation:

Using Pemdos, or gemdos, you can find you do the exponent first

4^2 = 16

then to everything else in left to right order since they're all multiplication or division

22/7 = ~3.14 * 13 = ~40.86/16 = ~2.55

(I'm using "~" to mean about/rounded to)

Answer:

Step-by-step explanation:

2x − y = 4

2x − 4 = y

y = 2x - 4

negative inverse of slope is perpendicular

y = -1/2 x - 4

~~~~~~~~~~~~~~~~~~~~~~~

point slope form  of a line

(-5, 1) & m = -1/2

1 = -1/2 (-5) + b

1 = 5/2 + b

b = -3/2

Final answer:  y = -1/2 x - 3/2

or if you prefer: 2y + x = -3

(a) By the fundamental theorem of calculus,

v(t) = v(0) + ∫₀ᵗ a(u) du

The particle starts at rest, so v(0) = 0. Computing the integral gives

v(t) = [2/3 u ³ + 2u ²]₀ᵗ = 2/3 t ³ + 2t ²

(b) Use the FTC again, but this time you want the distance, which means you need to integrate the speed of the particle, i.e. the absolute value of v(t). Fortunately, for t ≥ 0, we have v(t) ≥ 0 and |v(t) | = v(t), so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of

∫₀⁸ v(u) du = ∫₀⁸ (2/3 u ³ + 2u ²) du = [1/6 u ⁴ + 2/3 u ³]₀⁸ = 1024

Answer:

C

Step-by-step explanation:

I think you have to call a = 14/32 and b = 7/4

3a = 3 * 14/32 = 42/32

b = 1 3/4 = (4 + 3)/4 = 7/4

42/32 // 7/4                        Invert and multiply

42/32 * 4/7                         Cancel 4 into 32 and 7 into 42

6/8 = 3/4

I make the answer C

Answer:

So the square seems to multiply the first number by three and then divide it by the second number.

So,

14/32 * 3

=

42/32

Simplify

21/16

And now for division, we flip the diveding fraction and multiply.

21/16 * 4/7

Which is after some fraction simplifing:

3/4

Answer:

5

Step-by-step explanation:

x^2 - 10x + 16 = 0

factor

(x - 2)(x - 8) = 0

roots

x = {2, 8}

mean of roots

a = (2 + 8) /2

a = 5

Answer:

1/2

Step-by-step explanation:

numbers taken = 1 to 40

multiples of 2 are = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40}

so there are 20 favourable  outcomes.

probability = 20/40

=1/2

for multiples of 3

multiples = {3,6,9,12,15,18,21,24,27,30,33,36,39}

there are 13 favourable outcomes

probability = 13/40

since there is no 13/40 the answer should be the probability of multiples of 2 i.e 1/2

Answer:

B'(4, 0)

Step-by-step explanation:

B (1, 5)

it translated right 3 units => x'=x+3

down 5 units => y'= y-5

Answer:

the answer should be 120 as the hypotenuse is obtained by √(a²+b²=c² )

Answer:

x = 17

Step-by-step explanation:

We need to find x.

Using Pythagorean theorem

a ² + b ² = c²

Lebels the values , we get

( 15 ) ² + ( 8 )² = ( x ) ²

Expand the exponent

225 + 64 = x²

Add the numbers

289 = x²

Taking square root of both side

√289 = √x²

17 = x.

Hence, the length of side x is 17.

Answer:

(a):

Dannette                   Alphonso

[tex]\bar x_D = 4.33[/tex]                    [tex]\bar x_A = 5.17[/tex]

[tex]M_D = 2.5[/tex]                    [tex]M_A = 5[/tex]

[tex]\sigma_D = 3.350[/tex]                  [tex]\sigma_A = 1.951[/tex]

[tex]IQR_D = 7[/tex]                  [tex]IQR_A = 1.5[/tex]

(b):

Measure of center: Median

Measure of spread: Interquartile range

(c):

There are no outliers in Dannette's dataset

There are outliers in Alphonso's dataset

Step-by-step explanation:

Given

See attachment for the appropriate data presentation

Solving (a): Mean, Median, Standard deviation and IQR of each

From the attached plots, we have:

IQR_A = 1.5 ---- Dannette

[tex]A = \{3,4,4,4,4,5,5,5,5,6,6,11\}[/tex] ---- Alphonso

n = 12 --- number of dataset

Mean

The mean is calculated

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_D = \frac{1+1+1+1+2+2+3+7+8+8+9+9}{12}[/tex]

[tex]\bar x_D = \frac{52}{12}[/tex]

[tex]\bar x_D = 4.33[/tex] --- Dannette

[tex]\bar x_A = \frac{3+4+4+4+4+5+5+5+5+6+6+11}{12}[/tex]

[tex]\bar x_A = \frac{62}{12}[/tex]

[tex]\bar x_A = 5.17[/tex]  --- Alphonso

Median

The median is calculated as:

[tex]M = \frac{n + 1}{2}th[/tex]

[tex]M = \frac{12 + 1}{2}th[/tex]

[tex]M = \frac{13}{2}th[/tex]

[tex]M = 6.5th[/tex]

This implies that the median is the mean of the 6th and the 7th item.

So, we have:

[tex]M_D = \frac{2+3}{2}[/tex]

[tex]M_D = \frac{5}{2}[/tex]

[tex]M_D = 2.5[/tex] ---- Dannette

[tex]M_A = \frac{5+5}{2}[/tex]

[tex]M_A = \frac{10}{2}[/tex]

[tex]M_A = 5[/tex]  ---- Alphonso

Standard Deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]

So, we have:

[tex]\sigma_D = \sqrt{\frac{(1 - 4.33)^2 +.............+(9- 4.33)^2}{12}}[/tex]

[tex]\sigma_D = \sqrt{\frac{134.6668}{12}}[/tex]

[tex]\sigma_D = 3.350[/tex] ---- Dannette

[tex]\sigma_A = \sqrt{\frac{(3-5.17)^2+............+(11-5.17)^2}{12}}[/tex]

[tex]\sigma_A = \sqrt{\frac{45.6668}{12}}[/tex]

[tex]\sigma_A = 1.951[/tex] --- Alphonso

The Interquartile Range (IQR)

This is calculated as:

[tex]IQR =Q_3 - Q_1[/tex]

Where

[tex]Q_3 \to[/tex] Upper Quartile       and        [tex]Q_1 \to[/tex] Lower Quartile

[tex]Q_3[/tex] is calculated as:

[tex]Q_3 = \frac{3}{4}*({n + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*(12 + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*13th[/tex]

[tex]Q_3 = 9.75th[/tex]

This means that [tex]Q_3[/tex] is the mean of the 9th and 7th item. So, we have:

[tex]Q_3 = \frac{1}{2} * (8+8) = \frac{1}{2} * 16[/tex]           [tex]Q_3 = \frac{1}{2} * (5+6) = \frac{1}{2} * 11[/tex]

[tex]Q_3 = 8[/tex] ---- Dannette                 [tex]Q_3 = 5.5[/tex] --- Alphonso

[tex]Q_1[/tex] is calculated as:

[tex]Q_1 = \frac{1}{4}*({n + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*({12 + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*13th[/tex]

[tex]Q_1 = 3.25th[/tex]

This means that [tex]Q_1[/tex] is the mean of the 3rd and 4th item. So, we have:

[tex]Q_1 = \frac{1}{2}(1+1) = \frac{1}{2} * 2[/tex]                  [tex]Q_1 = \frac{1}{2}(4+4) = \frac{1}{2} * 8[/tex]

[tex]Q_1 = 1[/tex] --- Dannette                   [tex]Q_1 = 4[/tex] ---- Alphonso

So, the IQR is:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR_D = 8 - 1[/tex]                                     [tex]IQR_A = 5.5 - 4[/tex]

[tex]IQR_D = 7[/tex] --- Dannette                      [tex]IQR_A = 1.5[/tex] --- Alphonso

Solving (b): The measures to compare

Measure of  center

By observation, we can see that there are outliers is the plot of Alphonso (because 11 is far from the other dataset) while there are no outliers in Dannette plot (as all data are close).

Since, the above is the case; we simply compare the median of both because it is not affected by outliers

Measure of  spread

Compare the interquartile range of both, as it is arguably the best measure of spread, because it is also not affected by outliers.

Solving (c): Check for outlier

To check for outlier, we make use of the following formulas:

[tex]Lower =Q_1 - 1.5 * IQR[/tex]

[tex]Upper =Q_3 + 1.5 * IQR[/tex]

For Dannette:

[tex]Lower = 1 - 1.5 * 7 = -9.5[/tex]

[tex]Upper = 8 + 1.5 * 7 = 18.5[/tex]

Since, the dataset are all positive, we change the lower outlier to 0.

So, the valid data range are:

[tex]Valid = 0 \to 18.5[/tex]

From the question, the range of Dannette's dataset is: 1 to 9. Hence, there are no outliers in Dannette's dataset

For Alphonso:

[tex]Lower = 4 - 1.5 * 1.5 =1.75[/tex]

[tex]Upper = 5.5 + 1.5 * 1.5 =7.75[/tex]  

So, the valid data range are:

[tex]Valid = 1.75\to 7.75[/tex]

From the question, the range of Alphonso's dataset is: 3 to 11. Hence, there are outliers in Alphonso's dataset

Step-by-step explanation:

7x-21 = 5x +15

7x-5x = 15 + 21

2x = 36

x = 36/2

x = 18

Answer:

x=18

Step-by-step explanation:

Distribute 7 through the parentheses

7x-21=5(x+3)

Move the variable to the left -hand side and change its sign

7x-21-5x=15

Collect like terms

2x=15+21

divide both sides of the equation by 2

x=18

Answer:

m = 6

n = 2√3

Step-by-step explanation:

Reference angle = 30°

Hypotenuse = 4√3

Opposite = n

Adjacent = m

✔️To find m, apply CAH:

Cos θ = Adj/Hypo

Substitute

Cos 30° = m/4√3

4√3 × Cos 30° = m

4√3 × √3/2 = m (cos 30 = √3/2)

(4*3)/2 = m

6 = m

m = 6

✔️To find n, apply SOH:

Sin θ = Opp/Hypo

Substitute

Sin 30° = n/4√3

4√3 × Sin 30° = n

4√3 × ½ = n (Sin 30 = ½)

2√3 = n

n = 2√3

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]3v + 8 \geq 22[/tex]

»»————-　★　————-««  

Here’s why:

⸻⸻⸻⸻

[tex]\boxed{\text{Breaking down the phrase...}}\\\\\text{Three times a number, v, added to eight is greater than or equal to twenty-two. }\\------------------\\\rightarrow \text{"Three times a number, v..."} - 3v \text{ This expresses the product of '3' and 'v'.}\\\\\rightarrow \text{"added to eight..."} - + 8 \text{ The product gets added to eight.}\\\\--------------\\\text{The First Part Is:}}\\\\3v + 8\\---------------\\\rightarrow \text{is greater than or equal to twenty-two. } - \geq 22[/tex]

[tex]\text{The value of '3v + 8' is greater than or equal to 22.}\\---------------\\\text{\underline{Putting it together, we would have:}}\\\\\boxed{3v + 8 \geq 22}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

Step-by-step explanation:

1. Do not see a figure, and unsafe to download and execute .docx.

2. Vectors LM<5,-5>, NM<3,3>, NL<2,-8>

Since LM.NM = 15-15 = 0, LM and NM are orthogonal, hence the given points form a right triangle.

3. A parallelogram has opposite sides parallel.

Slope PQ = (4-2) / (-1 - -6) = 2/5

Slope RS = (2-0) / (2- -3) = 2/5

Therefore PQ || RS

Slope PS = (2-0)/(-6- -3) = -2/3

Slope QR = (4-2)/(-1 -2) = -2/3

Therefore PS | QR

Since opposite sides are parallel, PQRS is a parallelogram

Answer:

Step-by-step explanation:

1. There are 31 complete are almost complete squares.

Top line is about 3.5 squares

Right side is about 1.8

Bottom about 3.5 and left side about 1.2.

Total approximately 41 square units.

2. If it is a right triangle then 2 sides will be perpendicular.

Slope of LM = (-1-4)/(3 +2 = -1

Slope of MN = (-4+1)/ -3 = -3/-3 = 1.

So as the product of the slope = -1 * 1 = -1 the angles between LM and MN is a right angle and LMN is a right triangle.

Answer:

276 cm^2

Step-by-step explanation:

Separate figure into triangular and rectangular prisms.

SA of triangular prism (finding each area of a face and add them all up)

4 x 5 = 20 cm^2

13 x 4 = 52 cm^2

1/2 x 12 x 5 = 30 cm^2

1/2 x 12 x 5 = 30 cm^2

20 + 52 + 30 + 30 = 132 cm^2

SA of triangular prism is 132 cm^2

SA of rectangular prism (do the same thing):

12 x 4 = 48 cm^2

12 x 3 = 36 cm^2

12 x 3 = 36 cm^2

3 x 4 = 12 cm^2

3 x 4 = 12 cm^2

48 + 36 +36 + 12 + 12 = 144

Add the SA OF BOTH PRISMS:

144 + 132 = 276 cm^2

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and  ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

Find the centre of the circle.

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

      [tex]Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})[/tex]

                 [tex]=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)[/tex]

Find the radius of the circle.

[tex]Radius = \frac{Diameter }{2}[/tex]

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

[tex]Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}[/tex]

               [tex]=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6[/tex]

Therefore,

    [tex]Radius ,r = \frac{6}{2} = 3[/tex]

Standard equation of a circle:

[tex](x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.[/tex]

Therefore , equation of the circle ;

                    [tex](x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9[/tex]