Answer:
s = 4.41 g/L.
Explanation:
¡Hola!
En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:
[tex]PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)[/tex]
Lo cual hace que la expresión de equilibrio se calcule como:
[tex]Ksp=[Pb^{2+}][Cl^-]^2[/tex]
Y que en términos de la solubilidad molar, s, se resuelve como:
[tex]1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L[/tex]
Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):
[tex]s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L[/tex]
¡Saludos!
Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. Choose the compound that exhibits hydrogen bonding as its strongest intermolecular force. CH2Br2 CH3NH2 LiF C3H8 CF4
Answer:
The given molecules are:
CH2Br2
CH3NH2
LiF
C3H8
CF4.
Which compound consists of the hydrogen bond as the strongest intermolecular force.
Explanation:
The hydrogen bond is the electrostatic force of attraction that exists between the covalently bonded H-atom of one molecule and a high electronegative atom (N, O, F) of another molecule.
For example, H-bonding in water is represented below:
Among the given molecules,
CH2Br2 does not have H-bond because there is no either N or O or F atom in it.
In LiF also there is no H-atom and no hydrogen bond.
C3H8 also does not have H-bond in it.
CF4 also does not have H-atom or hydrogen bond in it.
The answer is CH3NH2(methylamine).
It has an intermolecular hydrogen bond in it as shown in the attachment.
The dashed line represents the H-bond.
The Kc for the following is 5.0 at 100 degrees Celsius.
If an equilibrium mixture contains 0.53 M NO2 what is the molar concentration of N2O4?
Answer:
1.40M = [N2O4]
Explanation:
Based on the reaction:
2NO2(g) ⇄ N2O4(g)
Kc is defined as:
Kc = 5.0 = [N2O4] / [NO2]²
Where [] are the concentrations in equilibrium of each gas
As the equilibrium concentration of NO2 is 0.53M:
5.0 = [N2O4] / [0.53]²
5.0 = [N2O4] / [0.2809]
5.0*0.2809 = [N2O4]
1.40M = [N2O4]What property can be easily measured in solids, liquids, and gases? (2 points)
Group of answer choices
The temperature of solids, liquids, and gases can be easily measured.
The texture of solids, liquids, and gases can be easily measured.
The color of solids, liquids, and gases can be easily observed.
The texture and temperature can be easily measured for solids, liquids, and gases.
Answer:
I think the answer is A
Explanation:
the temperature of solids , liquids and gases can be easily measured
why is tin tin and aluminum the better choice for canned milk
Answer:
Well, they are very durable unlike other packaging food materials, they can be recycled. But, the internet says allumninum cans are much better. and it could be better because you can keep the canned milk cool (cold) for a long lasting time. (keep it in the fridge if you want it to stay cold even longer)
How do I balance this?
_CuC12 + _NaNO3 → _CU(NO3)2 + _ NaC1
[tex]CuCl_2+2NaNO_3 \rightarrow Cu(NO_3)_2 + 2NaCl[/tex]
*
The crystal structure of salt is
quimica espero que si sea corecta
A mixture of sulfuric acid and nitric acid will produce small quantities of the nitronium ion (NO2 ): The nitronium ion has a central nitrogen atom with a positive charge double bonded to two oxygen atoms on both sides. Each oxygen atom carries two lone pairs of electrons. Does the nitronium ion have any significant resonance structures
Answer:
A mixture of sulfuric acid and nitric acid will produce small quantities of the nitronium ion (NO2 ): The nitronium ion has a central nitrogen atom with a positive charge double bonded to two oxygen atoms on both sides. Each oxygen atom carries two lone pairs of electrons. Does the nitronium ion have any significant resonance structures?
Explanation:
The structure of nitronium ion is shown below:
Any molecule to exhibit resonance, it should have alternating double bonds.
Resonance is the phenomenon in which the structure of a molecule can be represented in two or more forms and each form is called canonical form.
The canonical forms do not differ in the position of atoms and they differ only in the position of double bonds.
For the given molecule, there are no alternating double bonds.
Hence, nitronium ion does not exhibit any significant resonance structures.
The human body contains many elements from the periodic table. It is mostly composed of oxygen and carbon, but trace
elements also have a significant role. The table gives the mass, in kilograms, of some elements found in the human body, based
on a 70.0 kg person.
Atomic number
Element
Mass (kg)
8
oxygen
45.2
6
carbon
12.6
1
hydrogen
7.0
7
nitrogen
2.2
20
calcium
1.3
15
phosphorus
0.78
19
potassium
0.25
16
sulfur
0.18
others
0.60
total
70,0
Potassium makes up what fraction of the mass of the human body?
From the question given above, the following data were obtained:
Oxygen = 45.2 Kg
Carbon = 12.6 Kg
Hydrogen = 7 Kg
Nitrogen = 2 Kg
Calcium = 1.3 Kg
Phosphorus = 0.78 Kg
Potassium = 0.25 Kg
Sulphur = 0.18 Kg
Others = 0.60 Kg
Total = 70 Kg
Fraction of potassium =?We can obtain the fraction of potassium of the mass of the body as follow:
Potassium = 0.25 Kg
Total = 70 Kg
Fraction of potassium =?Fraction of potassium = mass of potassium / Total
Fraction of potassium = 0.25 / 70
Fraction of potassium = 1/280Therefore, the fraction of potassium in the body is 1/280
Learn more: https://brainly.com/question/14760859
8. What does the term 'sustainable mean? *
Answer:
something that can be maintained over a period of time
Answer:
a balance between meeting today's needs.......
Explanation:
is Decanitrogen tetroxide Ionic or Molecular
Answer:
Decanitrogen is molecular
Explanation:
Answer:
Dec a nitrogen is Molecular
Explanation:
hey mate i hope it will help you...!
If the H3O is 4.950 x 10-12 what is the ph?
Answer:
pH = 11.3
Explanation:
From the question given above, the following data were obtained:
Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M
pH =.?
The pH of a solution is defined by the following equation:
pH = –Log [H₃O⁺]
Thus, with the above formula, we can obtain the pH of the solution as follow:
Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M
pH =.?
pH = –Log [H₃O⁺]
pH = –Log 4.950×10¯¹²
pH = 11.3
Helpppp
What is the volume of 2.99 moles of C3H8 at STP?
0.0680L
5.87 L
ОООО
1.52 L
67.0L
Answer:
67.0 L
Explanation:
Step 1: Given data
Moles of C₃H₈: 2.99 molPressure: 1 atm (standard pressure)Temperature: 273.15 K (standard temperature)Step 2: Calculate the volume occupied by 2.99 moles of C₃H₈ at STP
C₃H₈ is a gas. If we assume ideal behavior, 1 mole of C₃H₈ at STP occupies 22.4 L.
2.99 mol × 22.4 L/1 mol = 67.0 L
Given the data you collected for the volume of water displaced by 25.000 g of aluminum, what is the density of aluminum?
A. 3.38 g/cm
B. 13.5 g/mL
C. 2.70 g/cm
D. 0.637 g/mL
Answer:
C. 2.70 g/mL
Explanation:
Density is the ratio between the mass of a substance and the volume it occupies. Based on Archimedes' volume, the displaced volume of the aluminium is the volume it occupies. To solve this question we must find the difference in volume between initial volume of water = 30mL and final volume of water + aluminium = 39.26mL. This difference is the volume of the aluminium. With its mass we can find density:
39.26mL - 30mL = 9.26mL
Density = 25.00g / 9.26mL =
2.70g/mL
Right answer is:
C. 2.70 g/mLwhat is the enthalpy of the overall chemical reaction
Answer:
For a chemical reaction, the enthalpy of reaction (ΔHrxn) is the difference in enthalpy between products and reactants; the units of ΔHrxn are kilojoules per mole
A 24.803 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 79.733 g of water. A 10.560 g aliquot of this solution is then titrated with 0.1077 M HCl . It required 32.37 mL of the HCl solution to reach the methyl red endpoint. Calculate the weight percent NH3 in the aqueous waste.
Answer:
2.37 (w/w)% of NH3 in the fertilizer
Explanation:
The HCl reacts with NH3 as follows:
HCl + NH3 ⇄ NH4Cl
To solve this question we must find the moles of HCl used in the titration = Moles NH3. With its molar mass we can find mass of NH3 and using the dilutions we can find weight percent as follows:
Moles HCl = Moles NH3
32.37mL = 0.03237L * (0.1077mol/L) =
Mass NH3 in the dilution -Molar mass: 17.031g/mol-
0.003486moles NH3 * (17.031g/mol) = 0.05937g NH3
Mass NH3 in the sample:
0.05937g NH3 * (79.733g + 24.803g) / 10.560g =
0.588g NH3
Weight percent:
0.588g NH3 / 24.803g * 100 =
2.37 (w/w)% of NH3 in the fertilizer
What’s the answer to the question
Answer: B
Explanation: im pretty sure my teacher mentioned something about N--h bonds are non polar
Answer:
C
Explanation:
The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), butanoic acid (C3H7COOH), and sodium bromide (NaBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive.
Answer:
The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), butanoic acid (C3H7COOH), and sodium bromide (NaBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive.
Explanation:
The given substances are:
barium chloride(BaCl2),
glucose(C6H12O6),
butanoic acid (C3H7COOH) which is a weak acid,
sodium bromide (NaBr).
The conductivity of a solution is proportional to the number of ions present in a particular solution.
1mol. of BaCl2 in water produces a total three mol. of ions.
[tex]BaCl_2 (aq) -> Ba^2^+(aq) + 2Cl^-(aq)[/tex]
Gluocse is a covalent compound and it does not dissociate into ions in water.
So, it does not conduct electricity.
Butanoic acid is a weak acid. But due to the release of H+ ions it can conduct a very less amount of electricity.
NaBr is an ionic compound and in 1mol. of NaBr in water gives two mol. of ions.
NaBr (aq) -> Na+ (aq) + Br- (aq)
Hence, the order of conductivity among the given substances in aqueous solution is:
BaCl2 > NaBr > butanoic acid > glucose
how to calculate moles
Explanation:
First you must calculate the number of moles in this solution, by rearranging the equation. No. Moles (mol) = Molarity (M) x Volume (L) = 0.5 x 2. = 1 mol.
For NaCl, the molar mass is 58.44 g/mol. Now we can use the rearranged equation. Mass (g) = No. Moles (mol) x Molar Mass (g/mol) = 1 x 58.44. = 58.44 g.
Answer:
Number of moles : Mass (g) ÷ relative atomic mass
When the following aqueous solutions are mixed together, a precipitate forms. Balance the net ionic equation in standard form for the reaction that occurs and determine the sum of the coefficients.
Sodium sulfide and silver nitrate - 3 or 4
Lead(II) nitrate and sodium chloride -3 or 4
Calcium nitrate and potassium carbonate - 3or 4
Barium nitrate and sodium hydroxide -3 or 4
Silver nitrate and sodium chloride -3 or 4
Answer:
For (a): The balanced net ionic equation is [tex]2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)[/tex] and the sum of coefficients is 4
For (b): The balanced net ionic equation is [tex]Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)[/tex] and the sum of coefficients is 4
For (c): The balanced net ionic equation is [tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex] and the sum of coefficients is
For (d): The balanced net ionic equation is [tex]Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)[/tex] and the sum of coefficients is 4
For (e): The balanced net ionic equation is [tex]Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)[/tex] and the sum of coefficients is 3
Explanation:
Net ionic equation is defined as the equations in which spectator ions are not included.
Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.
For (a): Sodium sulfide and silver nitrateThe balanced molecular equation is:
[tex]Na_2S(aq)+2AgNO_3(aq)\rightarrow 2NaNO_3(aq)+Ag_2S(s)[/tex]
The complete ionic equation follows:
[tex]2Na^{+}(aq)+S^{2-}(aq)+2Ag^+(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ag_2S(s)[/tex]
As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]2Ag^{+}(aq)+S^{2-}(aq)\rightarrow Ag_2S(s)[/tex]
Sum of the coefficients = [2 + 1 + 1] = 4
For (b): Lead(II) nitrate and sodium chlorideThe balanced molecular equation is:
[tex]2NaCl(aq)+Pb(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+PbCl_2(s)[/tex]
The complete ionic equation follows:
[tex]2Na^{+}(aq)+2Cl^{-}(aq)+Pb^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+PbCl_2(s)[/tex]
As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Pb^{2+}(aq)+2Cl^{-}(aq)\rightarrow PbCl_2(s)[/tex]
Sum of the coefficients = [2 + 1 + 1] = 4
For (c): Calcium nitrate and potassium carbonateThe balanced molecular equation is:
[tex]K_2CO_3(aq)+Ca(NO_3)_2(aq)\rightarrow 2KNO_3(aq)+CaCO_3(s)[/tex]
The complete ionic equation follows:
[tex]2K^{+}(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2K^+(aq)+2NO_3^-(aq)+CaCO_3(s)[/tex]
As potassium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)\rightarrow CaCO_3(s)[/tex]
Sum of the coefficients = [1 + 1 + 1] = 3
For (d): Barium nitrate and sodium hydroxideThe balanced molecular equation is:
[tex]2NaOH(aq)+Ba(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Ba(OH)_2(s)[/tex]
The complete ionic equation follows:
[tex]2Na^{+}(aq)+2OH^{-}(aq)+Ba^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^+(aq)+2NO_3^-(aq)+Ba(OH)_2(s)[/tex]
As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions
The net ionic equation follows:
[tex]Ba^{2+}(aq)+2OH^{-}(aq)\rightarrow Ba(OH)_2(s)[/tex]
Sum of the coefficients = [2 + 1 + 1] = 4
For (e): Silver nitrate and sodium chlorideThe balanced molecular equation is:
[tex]NaCl(aq)+AgNO_3(aq)\rightarrow NaNO_3(aq)+AgCl(s)[/tex]
The complete ionic equation follows:
[tex]Na^{+}(aq)+Cl^{-}(aq)+Ag^{+}(aq)+NO_3^{-}(aq)\rightarrow Na^+(aq)+NO_3^-(aq)+AgCl(s)[/tex]
As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:
[tex]Ag^{+}(aq)+Cl^{-}(aq)\rightarrow AgCl(s)[/tex]
Sum of the coefficients = [1 + 1 + 1] = 3
In the reaction represented by the equation: N2 + 3H2 → 2NH3, what is the conversion factor of nitrogen to ammonia? Explain by using law of definite proportion
Answer:
10/3
Explanation:
Hope this helps
Answer:
The compound formula for the ammonia is
N
H
3
. It is a colorless gas. It is the result of the chemical reaction between nitrogen and hydrogen gas. The chemical reaction between the gases is shown below:
N
2
+
3
H
2
→
2
N
H
3
NO2 (nitrogen dioxide) is a Greenhouse Gas that can be produced in car engines. The average diesel truck produces 80g of NO2 for every 1000 kilometers it drives. How many moles of NO2 are in 80g of NO2?
Answer:
[tex]1.74molNO_2[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to perform mole-mass relationships by using the molar mass of the involved substance, in this case NO2, which is 46.0 g/mol; then we just set up a conversion factor like the one shown below:
[tex]80g*\frac{1mol}{46g}\\\\1.74molNO_2[/tex]
Regards!
during the process of photosynthesis, green plants produce...
Answer: photosynthesis
Explanation:
Consider the reaction between solid C and O2 gas which makes CO2;
C+02 -> CO2
If we have a 14 L container of O2 gas at a pressure of 3.0 atm and a temperature of 298 K and we add 36 g of solid C to the
container, then how many grams of CO2 will be produced by this reaction?
Answer:
[tex]m_{CO_2}=75.6gCO_2[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out mandatory for us to calculate the reacting moles of both C and O2 because we are given grams and pressure, temperature and volume, respectively:
[tex]n_C=36gC*\frac{1molC}{12gC}=3.0molC \\\\n_{O_2}=\frac{3.0atm*14L}{0.08206\frac{atm*L}{mol*K}*298K}=1.72molO_2[/tex]
Thus, since C and O2 react in a 1:1 mole ratio, we infer C is in excess, and the grams of CO2 can be calculated with the moles of O2:
[tex]m_{CO_2}=1.72molO_2*\frac{1molCO_2}{1molO_2}*\frac{44.01gCO_2}{1molCO_2} \\\\ m_{CO_2}=75.6gCO_2[/tex]
Best regards!
H2C=CH2 + H2 решение?
Answer:
[tex]CH _{3}CH _{3}[/tex]
Ethane
Give the following for SO2 and BrF5:
(a) Number of domains on central atom (b) Domain geometry (c) Molecular geometry (d) Hybridization of central atom
Answer:
The given molecules are SO2 and BrF5.
Explanation:
Consider the molecule SO2:
The central atom is S.
The number of domains on S in this molecule is three.
Domain geometry is trigonal planar.
But there is a lone pair on the central atom.
So, according to VSEPR theory,
the molecular geometry becomes bent or V-shape.
Hybridization on the central atom is
[tex]sp^{2}[/tex].
Consider the molecule BrF5:
The central atom is Br.
The number of domains on the central atom is six.
Domain geometry is octahedral.
But the central atom has a lone pair of electrons.
So, the molecular geometry becomes square pyramidal.
The hybridization of the central atom is [tex]sp^{3} d^{2}[/tex].
The shapes of SO2 and BrF5 are shown below:
What is the correct answer question
Answer:
B
Explanation:
HELPP
There are 9.23 x 1023 molecules of water in a beaker, how many moles are there?
Answer:
Answer: There are 1.53 moles present in molecules of water in a beaker.
Explanation:
According to the mole concept, there are molecules present in 1 mole of a substance.
So, number of moles present in molecules are calculated as follows.
Thus, we can conclude that there are 1.53 moles present in molecules of water in a beaker.
Explanation:
Aerobic respiration is the cellular process in which
A)
oxygen is added to citric acid, providing energy to the cell.
B)
oxygen is added to NAD+ to form NADH.
C)
oxygen is added to an organic fuel, providing energy to the cell.
D)
oxygen is added to ATP, providing energy to the cell.
Answer:
oxygen is add to ATP providing energy to the cell
After the student closes the cooler, there NOT any inputs or outputs from this system because ________. a. no energy is being transferred into or out of the cooler b. there is no flow of energy across the system boundary c. there is no matter flowing into or out of the system d. all of the above
Answer:
d. All of the above
Explanation:
d. All of the above
The reduced coenzymes generated by the citric acid cycle donate electrons in a series of reactions called the electron transport chain. The energy from the electron transport chain is used for oxidative phosphorylation.
a) Which compounds donate electrons to the electron transport chain?
b) Which of the following is the final electron acceptor?
c) Which of the following are the final products of the electron transport chain and oxidative phosphorylation?
1. H20
2. NADH
3. NAD+
4. ATP
5. ADP
6. O2
7. FADH2
8. FAD
Answer:
a. NADH and FADH₂ donate electrons to the electron transport chain
b. Molecular oxygen, O₂, is the final electron acceptor
c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP
Explanation:
The citric cycle oxidize acetylCoA molecules to carbon dioxide and in the process produce the reduced coenzyme NADH and FADH₂. These reduced coenzymes then are able to donate their electrons to various complexes in the electron transport chain. The flow of these electrons through the electron transport chain is coupled to proton pumping out of the mitochondrial matrix into the intermembrane space. Ultimately, the energy of the proton motive force is used to drive synthesis of ATP from ADP and inorganic phospahte and the electrons are accepted by molecular oxygen to produce water. This process is known as oxidative phosphorylation.
Therefore, the answers to the given questions a, b and c are as follows:
a. NADH and FADH₂ donate electrons to the electron transport chain
b. Molecular oxygen, O₂, is the final electron acceptor
c. The final products of the electron transport chain and oxidative phosphorylation are as follows: NAD+, FAD+, H₂O, and ATP
