Answer:
thank you for the point too mucheeeYou: Your welcome❤
Find the perimeter of a football field which measures 90m by 60m
Hello!
[tex]\large\boxed{P = 300m}[/tex]
Use the following formula for the perimeter:
P = 2l + 2w, where:
l = length
w = width
Therefore:
P = 2(90) + 2(60)
Simplify:
P = 180 + 120 = 300 m
Answer:
well how about you use common sense 100 yards long on each side 200 yards then add 5o yards since the the that is how wide it is then add another 50 and you get 300 yards then convert that to meters
The distribution of the annual incomes of a group of middle management employees approximated a normal distribution with a mean of $38,000 and a standard deviation of $1,000. About 68 percent of the incomes lie between what two incomes
Answer:
68% is a special
value for these problems
empirical rule suggests ± 1 standard deviation
z = (x - μ)/σ
1 = (x - 38000)/1000
Between $37,000 and $39,000
Step-by-step explanation:
convert the fraction 3/8 to a decimal WITHOUT the use of a calculator. Show your method clearly. SHOW ALL STEPS!
here you go it's too easy
Step-by-step explanation:
Explanation is in the attachment .
Hope it is helpful to you ❣️☪️❇️
evaluate:(0.0001)-¾
Answer:
0.001
Step-by-step explanation:
(0.0001)^-3/4=((0.1)⁴)^-3/4
(0.1)^4×-3/4
0.1^‐3
0.001
2.What is the value of x if x/4 + 12 = 4 ?
Answer:
Step-by-step explanation:
Answer:
hope it will help u
X S2.0.2
A rocket is fired upward with an initial velocity v of 80 meters per second. The quadratic function S(t) = -52 + 80t can be used to find
the heights of the rocket, in meters, at any time t in seconds. Find the height of the rocket 8 seconds after it takes off. During the
course of its flight, after how many seconds will the rocket be at a height of 290 meters?
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Answer:
320 m after 8 seconds5.6 seconds, 10.4 seconds to height of 290 mStep-by-step explanation:
To find the height at 8 seconds, evaluate the formula for t=8.
S(t) = -5t^2 +80t
S(8) = -5(8^2) +80(8) = -320 +640 = 320
The height of the rocket is 320 meters 8 seconds after takeoff.
__
To find the time to 290 meters height, solve ...
S(t) = 290
290 = -5t^2 +80t
-58 = t^2 -16t . . . . . . . divide by -5
6 = t^2 -16t +64 . . . . . complete the square by adding 64
±√6 = t -8 . . . . . . . . . take the square root
t = 8 ±√6 ≈ {5.551, 10.449}
The rocket is at 290 meters height after 5.6 seconds and again after 10.4 seconds.
for a science fair project javier is recording the amount of water that evaporate from a bucket in a month he creates a table like this i will give point for the best answer
week 1 2/16 inch
week 2 1/16 inch
week 3 3/16 inch
week 4 2/16 inch
how much water had evaported from the bucket at the end of week 2
what was the total amount of water that evaported in the four weeks
if javier orignally put 4 inches of water in the bucket how many inches of water were left after the experment was completed
Answer: [tex]\dfrac{3}{16},\ \dfrac{1}{2}, \dfrac{7}{2}\ \text{inch}[/tex]
Step-by-step explanation:
Given
Javier created a table for the amount of water evaporated in each week
After two weeks, the amount of water evaporated is
[tex]\Rightarrow \dfrac{2}{16}+\dfrac{1}{16}\\\\\Rightarrow \dfrac{2+1}{16}=\dfrac{3}{16}\ \text{inch}[/tex]
Total amount of water evaporated in four weeks is
[tex]\Rightarrow \dfrac{2}{16}+\dfrac{1}{16}+\dfrac{3}{16}+\dfrac{2}{16}\\\\\Rightarrow \dfrac{2+1+3+2}{16}=\dfrac{8}{16}\\\Rightarrow \dfrac{1}{2}\ \text{inch}[/tex]
If Javier originally puts 4 inches of water, amount of water left in the bucket
[tex]\Rightarrow 4-\dfrac{1}{2}\\\\\Rightarrow \dfrac{4\times 2}{2}-\dfrac{1}{2}\\\\\Rightarrow \dfrac{8-1}{2}=\dfrac{7}{2}\ \text{inch}[/tex]
A, B and C are collinear points. B is between A and C. AB=12 BC=18 AC=3x Find X.
Answer:
[tex]x =10[/tex]
Step-by-step explanation:
Given
[tex]AB = 12[/tex]
[tex]BC = 18[/tex]
[tex]AC = 3x[/tex]
Required
Solve for x
Since B is in between both points, then:
[tex]AC = AB + BC[/tex]
This gives
[tex]3x = 12 + 18[/tex]
[tex]3x = 30[/tex]
Divide by 3
[tex]x =10[/tex]
me to
ICS A
V
t
V
30
A vehicle accelerates from 0 to 30 m/s in 10 seconds on a
straight road, then travels 15 seconds at a constant velocity.
Next it slows down, coming to a stop in 5 seconds. The car
waits 10 seconds, and then backs up for 5 seconds
accelerating from 0 to -10 m/s. Draw a graph showing the
vehicle's velocity vs time by following these steps.
20
What is the velocity of the vehicle at 0 seconds?
v m/s
Velocity (m/s)
es
10
40
20 30
Time (s)
Elementary
-10
S
Secondary
< Previous Activity
enuity.com/ContentViewers/Frame Chain/Activity
US 1:09
B
13 ft.
5 ft.
A
C
12 ft.
Find the value of Cos (B) =
Answer: the answer is 12/13
Ellen, Nick, and Ryan went shopping together. One of them bought a hat, another bought sunglasses, and another bought a belt. One paid $6, another paid $8, and another paid $10.
1) Nick bought the hat.
2) Ellen spent $8.
3) The belt did not cost $10.
4) Ryan spent the most. Which of the following is true?
(a) Nick bought the hat for $10.
(b) Ellen bought the belt for $8.
(c) Ryan bought the sunglasses for $8.
(d) Ryan bought the belt for $10
(e) Ryan bought the hat for 56.
Answer:
see down
Step-by-step explanation:
d is correct answer
is this a direct variation
y=2x + 3
pls give an explanation if you don’t have one still pls give an answer
Answer:
No.
Step-by-step explanation:
y/x has to be the same number no matter what except at point (0 0) which it must also include for it to be a direct variation.
*y=2x+3 is not a direct variation because you can not write it as y/x=k where k is some constant number. If we were y=2x, then yes since y/x=2.
*You could also take two points and see if they are proportional. That is, you can see if y2/x2 gives the same value as y1/x1 where (x1,y1) and (x2,y2) are points on the line y=2x+3. This must work for every pair of points on the linear relation except at x=0 (where you would or should have y=0 if it is directly proportional).
Let's try it out. If x=1, then y=2(1)+3=5.
5/1=5
If x=2, then y=2(2)+3=7
7/2=3.5
As you can see 5 doesn't equal 3.5.
*For it to be a direct variation, it also must contain the point (0,0) and be a diagonal line when graphed. It can also be written in form y=kx where k is a constant number. This fails two of the the things I mentioned. It doesn't contain point (0,0) because y=2(0)+3=3 not 0. It cannot be written in form y=kx because of the plus 3.
If it were y=2x, then the answer would be yes.
The length of a rectangle is 6 inches more than the width. The perimeter is 28 inches. Find the length and the width (in inches).
Answer:
The length of the rectangle is 10 inches, and the width is 4 inches.
Step-by-step explanation:
Given that the length of a rectangle is 6 inches more than the width, and the perimeter is 28 inches, the following calculation must be performed to find the length and the width:
(X + X + 6) x 2 = 28
2X + 2X + 12 = 28
4X = 28 - 12
X = 16/4
X = 4
Therefore, the length of the rectangle is 10 inches, and the width is 4 inches.
A bottle maker believes that 23% of his bottles are defective. If the bottle maker is accurate, what is the probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%
Answer:
0.9802 = 98.02% probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
A bottle maker believes that 23% of his bottles are defective.
This means that [tex]p = 0.23[/tex]
Sample of 602 bottles
This means that [tex]n = 602[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.23[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.23*0.77}{602}} = 0.0172[/tex]
What is the probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%?
p-value of Z when X = 0.23 + 0.04 = 0.27 subtracted by the p-value of Z when X = 0.23 - 0.04 = 0.19.
X = 0.27
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.27 - 0.23}{0.0172}[/tex]
[tex]Z = 2.33[/tex]
[tex]Z = 2.33[/tex] has a p-value of 0.9901
X = 0.19
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.19 - 0.23}{0.0172}[/tex]
[tex]Z = -2.33[/tex]
[tex]Z = -2.33[/tex] has a p-value of 0.0099
0.9901 - 0.0099 = 0.9802
0.9802 = 98.02% probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%
Can someone please help?
Step-by-step explanation:
So, so, to attempt this, we need to use the formula :-
2 (l + b) × h ---> For Lateral surface area
2(30+30) h = 7200
2×60×h = 7200
120 × h = 7200
h = 7200/120
h = 60 cm
Now, volume = l×b×h
= 30×30×60
= 54000 cm³ is the required answer.
Hope it helps! :D
The diameter of one circle is represented by 12x. The diameter of another circle is represented by 6x2y what is the ratio of the radiu of the two circles. 2:x3y 2x:y x:2y 2:xy
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Answer:
(d) 2 : xy
Step-by-step explanation:
A common factor of 6x can be removed from the elements of the ratio. The ratio of radii is the same as the ratio of diameters.
12x : 6x²y = (6x)(2) : (6x)(xy) = 2 : xy
Answer:D
Step-by-step explanation:
A committee raised 7/9 of their target goal last year and another 1/9 of the goal this year. What fraction of their goal has been raised
First, find 40% of 3,000:
0.40 * 3000 = 1200
So they raised 1200 so far.
Now subtract 1200 from the total they want to raise:
3000 - 1200 = 1800
So they need $1,800 more to meet their goal.
Answer:
8iriiruruj
Step-by-step explanation:
u4u the UK. We have a good idea to advertise the UK. I have been a
Tom's graduation picnic costs $4 for every attendee. At most how many attendees can there be if Tom budgets a total of $36 for his graduation picnic?
Think about tossing two coins.
What is
P (H on first coin)? ………………………….
P (H on second coin)? ……………………..
List the paired outcomes for tossing two coins: ………………………………
How many ways are there for two coins to land? ………………………
What is P (HH)? …………………………
Given:
Two coins are tossed.
To find:
1. P(H on first coin)?
2. P(H on second coin)?
3. List the paired outcomes for tossing two coins.
4. How many ways are there for two coins to land?
5. What is P(HH)?
Solution:
If a a coin is tossed, then we have to possible outcomes, i.e., heads (H) and tails (T).
It is given that two coins are tossed.
1. The probability of getting a heads on first coin is:
[tex]P(H \text{ on first coin})=\dfrac{1}{2}[/tex]
2. The probability of getting a heads on second coin is:
[tex]P(H \text{ on second coin})=\dfrac{1}{2}[/tex]
3. If two coins are tossed, then the total possible outcomes are:
[tex]\{HH,HT,TH,TT\}[/tex]
4. The number of ways for two coins to land is 4.
5. The probability of the heads on both tosses is:
[tex]P(HH)=\dfrac{1}{4}[/tex]
Therefore, the required solution are:
1. [tex]P(H \text{ on first coin})=\dfrac{1}{2}[/tex]
2. [tex]P(H \text{ on second coin})=\dfrac{1}{2}[/tex]
3. List of possible outcomes is [tex]\{HH,HT,TH,TT\}[/tex].
4. Number of possible outcomes is 4.
5. [tex]P(HH)=\dfrac{1}{4}[/tex]
Solve the given system by the substitution method.
3x + y = 14
7x - 4y = 20
Answer:
(4, 2 )
Step-by-step explanation:
Given the 2 equations
3x + y = 14 → (1)
7x - 4y = 20 → (2)
Rearrange (1) making y the subject by subtracting 3x from both sides
y = 14 - 3x → (3)
Substitute y = 14 - 3x into (2)
7x - 4(14 - 3x) = 20 ← distribute parenthesis and simplify left side
7x - 56 + 12x = 20
19x - 56 = 20 ( add 56 to both sides )
19x = 76 ( divide both sides by 19 )
x = 4
Substitute x = 4 into (3) for corresponding value of y
y = 14 - 3(4) = 14 - 12 = 2
solution is (4, 2 )
Answer:
[tex]3x + y = 14 \\ y = 14 - 3x \\ substitute \: y \: into \: equation \: 2\\ 7x - 4(14 - 3x) = 20 \\ 7x - 56 + 12x = 20 \\ 19x = 76 \\ x = \frac{76}{19} =4 \\ y = 14 - 3( 4 ) = 2 \\ [/tex]
Help me find the domain and range please!
Answer:
Domain: (-∞, 1]
Range: (-∞, 3]
Step-by-step explanation:
The function starts at point (1, 3) and goes to the left and down forever.
Domain: (-∞, 1]
Range: (-∞, 3]
Answer:
Domain: [tex](-\infty, 1][/tex]
Range: [tex](-\infty, 3][/tex]
Step-by-step explanation:
The domain of a function represents the range of x-values that are part of the function, read left to right. We can see that the function goes forever to the left and stops at [tex]x=1[/tex] when we read left to right. Therefore, the domain of this function is [tex]\boxed{(-\infty, 1]}[/tex].
The point at [tex]x=1[/tex] is a filled-in solid dot so it is included as part of the function. Use square brackets to denote inclusive.
The range of a function represents all y-values that are part of the function, read bottom to top. The function continues down forever and stops at [tex]y=3[/tex] when read bottom to top. Therefore, the range of this function is [tex]\boxed{(-\infty, 3]}[/tex]. Similar to the domain, we use a square bracket on the right to indicate that [tex]y=3[/tex] is included in the function. If the dot was not filled-in, then we would use a parenthesis to indicate that [tex]y=3[/tex] would not be part of the function.
A venture capital company feels that the rate of return (X) on a proposed investment is approximately normally distributed with mean 30% and standard deviation 10%.
(a) Find the probability that the return will exceed 55%.
(b) Find the probability that the return will be less than 25%
(c) What is the expected value of the return?
(d) Find the 75th percentile of returns.
Answer:
a) 0.0062 = 0.62% probability that the return will exceed 55%.
b) 0.3085 = 30.85% probability that the return will be less than 25%
c) 30%.
d) The 75th percentile of returns is 36.75%.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean 30% and standard deviation 10%.
This means that [tex]\mu = 30, \sigma = 10[/tex]
(a) Find the probability that the return will exceed 55%.
This is 1 subtracted by the p-value of Z when X = 55. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{55 - 30}{10}[/tex]
[tex]Z = 2.5[/tex]
[tex]Z = 2.5[/tex] has a p-value of 0.9938
1 - 0.9938 = 0.0062
0.0062 = 0.62% probability that the return will exceed 55%.
(b) Find the probability that the return will be less than 25%
p-value of Z when X = 25. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{25 - 30}{10}[/tex]
[tex]Z = -0.5[/tex]
[tex]Z = -0.5[/tex] has a p-value of 0.3085
0.3085 = 30.85% probability that the return will be less than 25%.
(c) What is the expected value of the return?
The mean, that is, 30%.
(d) Find the 75th percentile of returns.
X when Z has a p-value of 0.75, so X when Z = 0.675.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.675 = \frac{X - 30}{10}[/tex]
[tex]X - 30 = 0.675*10[/tex]
[tex]X = 36.75[/tex]
The 75th percentile of returns is 36.75%.
The number 55 is attached to a two-digit number to its left and the formed 4-digit number is divisible by 24. What could be the 2-digit number? List all options.
Given:
The number 55 is attached to a two-digit number to its left and the formed 4-digit number is divisible by 24.
To find:
The 2-digit numbers.
Solution:
Let the two digit number be [tex]ab[/tex]. Then the 4 digit number will be [tex]55ab[/tex].
We know that the number [tex]55ab[/tex] lies in the range 5500 to 5599.
Now,
[tex]5500=229\times 24+4[/tex]
It means, [tex]5500-4=5496[/tex] is divisible by 24. So, the numbers lie in the range 5500 to 5599 and divisible by 24 are:
[tex]5496+24=5520[/tex]
[tex]5520+24=5544[/tex]
[tex]5544+24=5568[/tex]
[tex]5568+24=5592[/tex]
Therefore, the possible 2-digit numbers are 20, 44, 68, 92.
Instructions: Drag and drop the correct name for each angle. Each angle has more than one name so be sure to identity all the correct names
Answer/Step-by-step explanation:
Recall: an angle can be named in three different ways:
i. Using one letter which is the vertex of the angle. i.e. if the vertex of the angle is A we can name the angle as <A.
ii. Using the number of the labelled angle. i.e. is the angle is labelled 2, we can name it <2
iii. Using the three letters of the angles with the vertex angle in the middle. i.e. if the three points that form an angle are A, B, C and the vertex is B, we can name the angle as <ABC.
✔️Let's name the each angle given according:
1. <G, <3, and <FGH
2. <D, <4, and <CDE
3. <S and <TSR (the number seems blur and difficult to read. Whatever number is used to label the angle is what you'd use in naming the angle)
Find the distance between the two points.
(3,-9) and (-93,-37)
Answer:
d(A,B)=100
Step-by-step explanation:
The distance between two points A([tex]x_A,y_A[/tex]) and B=([tex]x_B,y_B[/tex]) is:
d(A,B)=[tex]\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}[/tex]
In this case:
[tex]x_B = - 93\\x_A = 3\\y_B = -37\\y_A = -9[/tex]
In this case:
[tex]d(A,B)=\sqrt{( - 93 -3)^2+( - 37 - (-9))^2} =\\=\sqrt{( - 96)^2+(-28)^2} =\\=\sqrt{9.216+784} \\=\sqrt{10000}=\\=\sqrt{10^4} =\\=100[/tex]
Which are correct representations of the inequality -3(2x-5) <5(2 - x)? Select two options.
Answer:
-6x+15 < 10-5x
x>5
third equation, first graph
Step-by-step explanation:
3. Express the strength of a solution both as a ratio and as a percentage if
2 L of the solution contain 400 mg of solute.
Answer:
1 : 5000
0.02%
Step-by-step explanation:
A solution = solute + solvent
A 2 Litre solution = (2 * 1000) = 2000 mg
Having, 400 mg of solute ;
Recall ;
1 mg = 0.001 ml
400 mg = (0.001 * 400) = 0.4 ml
The strength of the solution :
Amount of solute / Amount of solution
0.4 / 2000
As a ratio :
0.4 / 2000 = (0.4 * 10) / (2000*10) = 4 / 20000 = 1 / 5000 = 1 : 5000 (as a ratio)
0.4 / 2000
= 0.0002
(0.0002 * 100%) = 0.02% (As a percentage)
Perimeter of a square with side 4 square root of 5
Answer:
16[tex]\sqrt{5}[/tex]
Step-by-step explanation:
[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]
16[tex]\sqrt{5}[/tex]
The perimeter of the square is 16√5 units.
We have,
The concept used here is straightforward: to find the perimeter of a square, you sum the lengths of all four sides because all sides of a square are equal in length.
In this case, the side length is given as 4√5, so you multiply it by 4 to calculate the total perimeter.
To find the perimeter (P) of a square with a side length of 4√5 units, you simply add up all four sides of the square, as all sides of a square are equal in length.
So,
P = 4 * side length
P = 4 * 4√5
P = 16√5 units
Thus,
The perimeter of the square is 16√5 units.
Learn more about squares here:
https://brainly.com/question/22964077
#SPJ3
It has been determined that 60% of the people in a certain midwest city who are responsible for preparing the evening meal have no idea what they are going to prepare as late as 4PM in the afternoon. A recent survey was conducted from 1000 of these individuals. For the sampling distribution of the sample proportion to be reasonably Normal, the sample must have been obtained in the right way (ideally, a simple random sample) and the sample size must be large (so that at least 10 or more successes and failures). Are these conditions met
Answer:
Random sample, [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], so yes, both conditions were satisfied.
Step-by-step explanation:
60% of the people in a certain midwest city who are responsible for preparing the evening meal have no idea what they are going to prepare as late as 4PM in the afternoon.
This means that [tex]p = 0.6[/tex]
A recent survey was conducted from 1000 of these individuals.
This means that [tex]n = 1000[/tex]
Also, a random sample, so the first condition was satisfied.
The sample size must be large (so that at least 10 or more successes and failures).
[tex]np = 1000*0.6 = 600 \geq 10[/tex]
[tex]n(1-p) = 1000*0.4 = 400 \geq 10[/tex]
So yes, both conditions were met.
Parallel lines
What is the segment
Answer:
Step-by-step explanation:
