because they need a medium to travel they can travel everywhere if they got the medium
50POINTS!
Using the ideal gas law (PV=nRT) solve for the missing. Variable. R= 0.08206atm*L/mol*k
If 22.9L of an ideal gas was collected at STP. How many moles of the gas were present?
A. 1.02 moles
B. 5.99 moles
C. 3.05 moles
D. 2.74 moles
Answer:
A. 1.02 moles .
Explanation:
Hello!
In this case, given the ideal gas equation, as we need to solve for moles, we divide both sides by RT to get:
[tex]n=\frac{PV}{RT}[/tex]
Thus, by plugging in the pressure and temperature at STP (1.00 atm and 273.15 K respectively) we obtain:
[tex]n=\frac{1.00atm*22.9L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.02mol[/tex]
Therefore, the correct answer is A. 1.02 moles
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Increasing the force on an object _________ its acceleration, if the mass of the object stays the same
A parallel circuit contains four identical lamps. The current through the energy source is 4 A. The total resistance of the circuit is 10 Ω. What is the voltage across the energy source and across each lamp
Answer:
a parallel circuit has two or more paths for current to flow through voltage is the same across each component of the parallel circuit the sum of the current through each path is equal to the total current that follows from the source another definition is in a parallel circuit all components are connected across each other formally exactly two sets of electricity common points a branch in a parallel circuit in a path of electricity current formed by one of the load component
Which is an example of a chemical reaction?
A) Tearing up your last science test.
B) Eating a antacid to calm your upset stomach. C) Rubbing your hands together to warm them. D) Pouring water on a cut to wash off the germs.
Answer:
B) Eating a antacid to calm your upset stomach.
Explanation:
A compound is found to contain 7.962 % silicon , 20.10 % chlorine , and 71.94 % iodine by mass.
a. The empirical formula for this compound is_______ .
b. The molar mass for this compound is 352.8 g/mol. The molecular formula for this compound is:_____
Answer:
A. Empirical formula => SiCl₂I₂
B. Molecular formula = SiCl₂I₂
Explanation:
From the question given above, the following data were:
Silicone (Si) = 7.962 %
Chlorine (Cl) = 20.10 %
Iodine (I) = 71.94 %
Molar mass of compound = 352.8 g/mol
Empirical formula =?
Molecular formula =?
A. Determination of the empirical formula of the compound.
Si = 7.962 %
Cl = 20.10 %
I = 71.94 %
Divide by their molar mass
Si = 7.962 / 28 = 0.284
Cl = 20.10 / 35.5 = 0.566
I = 71.94 / 127 = 0.566
Divide by the smallest
Si = 0.284 / 0.284 = 1
Cl = 0.566 / 0.284 = 2
I = 0.566 / 0.284 = 2
Empirical formula => SiCl₂I₂
B. Determination of the molecular formula of the compound.
Empirical formula => SiCl₂I₂
Molar mass of compound = 352.8 g/mol
Molecular formula =?
Molecular formula = [SiCl₂I₂]ₙ
[SiCl₂I₂]ₙ = 352.8
[28 + (2×35.5) + (2×127)]n = 352.8
[28 + 71 + 254]n = 352.8
353n = 352.8
Divide both side by 353
n = 352.8 / 353
n = 1
Molecular formula = [SiCl₂I₂]ₙ
Molecular formula = [SiCl₂I₂]₁
Molecular formula = SiCl₂I₂
A student collected a 1.28 g sample of Magnesium. How many atoms of Mg are in his sample?
A student did an experiment that called for 1.24 x 1024 molecules of CaO. What is the mass of her reactant?
A student reacted 0.0405 g of glucose (C6H12O6). How many molecules of glucose did he react?
PLEASE HELP ASAP I NEED IT
the answer is true the first one
Marine chemist exam in the mass percent composition of manganese sulfide compound from ocean floor he determined that 60.2% of this compound is sulfur determine the mole ratio between manganese and sulfur
Explanation:
Let the mass of the compound be 100g.
There are 60.2g of sulfur.
Moles of sulfur
= 60.2g / (32.07g/mol) = 1.877mol
There are 100g - 60.2g
= 39.8g of manganese.
Moles of manganese
= 39.8g / (54.94g/mol) = 0.724mol
Mole ratio of manganese to sulfur
= 0.724mol : 1.877mol = 1 : 2.5.
The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process.
2N2O5(g) = 4NO2(g) + O2
[N2O5] Time (s)
0.100 0.00
0.066 200.00
0.044 400.00
a) Find the rate of disappearance of N2O5 from t=0 s to t=200s
b) Find the rate of appearance of NO2 from t=0 s to t =200s
Answer: a) [tex]1.7\times 10^{-4}[/tex]
b) [tex]3.4\times 10^{-4}[/tex]
Explanation:
The reaction is :
[tex]2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)[/tex]
Rate = Rate of disappearance of [tex]N_2O_5[/tex] = Rate of appearance of [tex]NO_2[/tex]
Rate = [tex]-\frac{d[N_2O_5]}{2dt}[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]
Rate of disappearance of [tex]N_2O_5[/tex] = [tex]\frac{\text {change in concentration}}{time}[/tex] = [tex]\frac{0.100-0.066}{200-0}=1.7\times 10^{-4}[/tex]
a) Rate of disappearance of [tex]N_2O_5[/tex] = [tex]-\frac{d[N_2O_5]}{2dt}[/tex]
Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]
b) Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}[/tex]
A) Find the rate of disappearance of [tex]N_2O_5[/tex] from t = 0 s to t = 200s
[tex]Rate = \frac{1}{2}(\frac{-\delta N_2O_5}{\delta t})\\\\Rate = -\frac{1}{2}(\frac{0.066 - 0.100}{200 - 0})\\\\Rate = 8.5*10^{-5}[/tex]
B) Find the rate of appearance of [tex]NO_2[/tex] from t = 0 s to t = 200s
According to rate law,
[tex]\frac{1}{2}(\frac{-\delta N_2O_5}{\delta t}) = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\8.5*10^{-5} = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\\frac{\delta NO_2}{\delta t} = 4 * 8.5*10^{-5}\\\\Rate = 3.4*10^{-4}[/tex]
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6. Primary succession usually occurs after which catastrophic events?
a.) Volcanic eruptions burning down a forest
5. Hurricanes flooding a forest
c. Tomadoes uprooting trees leaving behind the soil
d. Glaciers moving revealing bare rock underneath
Answer: d. Glaciers moving revealing bare rock underneath
Explanation:
Primary succession is what happens when living things colonise an area that was previously uncolonized because it had been destroyed or hadn't been created yet.
When glaciers move on from areas and expose the bare rock underneath, these areas are new and so primary succession will take place as living things begin to colonize this new area.
How many moles are in 4.3 x 10 ^22 molecules of Na3PO4
Answer:
0.071 moles of Na₃PO₄ .
Explanation:
Given data:
Number of molecules of Na₃PO₄ = 4.3× 10²² molecules
Number of moles = ?
Solution:
1 mole contain 6.022 × 10²³ molecules
4.3× 10²² molecules × 1 mol / 6.022 × 10²³ molecules
0.71× 10⁻¹ mol
0.071 mol
The number 6.022 × 10²³ is called Avogadro number.
"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance"
Ramelteon is a hypnotic agent used in the treatment of insomnia: Considering the labeled drawing above, which of the highlighted atoms has a delocalized lone pair? Select all that apply. 1 2 3 Identify the geometry of each atom (except for hydrogen atoms). All sp2-hybridized carbon atoms have geometry. All sp3-hybridized carbon atoms have geometry. The nitrogen atom has geometry. The oxygen atom of the C=O bond has geometry, and the other oxygen atom has geometry.
Answer:
1 and 2
Trigonal planar
Tetrahedral
Trigonal Planar
Linear
Bent ( v- shape)
Explanation:
The highlighted atoms has a delocalized lone pair - 1 and 2
All sp2-hybridized carbon atoms have geometry- Trigonal planar
All sp3-hybridized carbon atoms have geometry - Tetrahedral
The nitrogen atom has geometry - Trigonal Planar
The oxygen atom of the C=O bond has geometry - Linear
and the other oxygen atom has geometry - Bent ( v- shape)
P.S - The correct question is -
Ramelteon has been an aromatic compound with 3 ring structure followed by the aliphatic chain.
The drug has antagonist structure to the melatonin and has been used to treat insomnia by acting as the melatonin representative.
Geometry in the structureThe labelled atom in the structure is oxygen of the pentane ring, nitrogen in the aliphatic chain, and carbonyl oxygen.
The delocalized lone pair has been observed in the compound which has been contributing to the resonating structure. The delocalized lone pair ion the given structure is oxygen of the pentane ring, and nitrogen in the aliphatic chain.
The geometry of the atom has been based on the hybridization and the lone pairs.
The geometry of [tex]\rm sp^2[/tex] hybridized carbon has been trigonal planar. The geometry of [tex]\rm sp^3[/tex] hybridized carbon atom has been tetrahedral. The nitrogen in the chain has trigonal planar geometry. The C=O oxygen has been comprising linear geometry, while the oxygen has bent v shape.
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Which of the statements about liquids and gases are true?
Both liquids and gases have a definite volume.
O The particles in liquids and gases can move past one another
freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.
Which of the statements about liquids and gases are true?
Answer:The particles in liquids and gases can move past one another freely.
#CARRYONLEARNING #STUDYWELLWhich of the statements about liquids and gases are true?
Choosing:Both liquids and gases have a definite volume.
The particles in liquids and gases can move past one another freely
Both liquids and gases have a definite shape.
Neither liquids nor gases have a definite shape.
Answer:The particles in liquids and gases can move past one another freely.
#READINGHELPSWITHLEARNING #CARRYONLEARNING #STUDYWELLWhat is the coefficient, subscript for V, and subscript for O in V2O5
Answer: Coefficient 0
subscript for V 2
subscript for O 5
Explanation: yes
There is no coefficient in V₂O₅ and the subscript of vanadium V is 2 and the subscript of oxygen is 5.
What is vanadium pentoxide ?Vanadium pentoxide is an ionic compound formed by donating electrons from the vanadium metal to oxygen. The chemical formula of vanadium pentoxide is V₂O₅.
The chemical formula of a compound is written in terms of the chemical symbol of each constituent elements and the number of their atoms. The number of atoms is written as subscript for the chemical symbols.
In V₂O₅, there are are 2 vanadium atoms and 5 oxygen atoms. Coefficients are numbers prior to the formula in reaction. Here there is no coefficient and the subscript for V is 2 and that of O is 5.
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According to Image 2, which tectonic plate is composed of the largest percentage of oceanic lithosphere?
A. African Plate
B. Eurasian Plate
C. Indian Plate
D. Nazca Plate
Answer:
I think the answer is A the Afracan plate
Explanation:
hope this helps:)
which of the following is NOT a function of the skeletal system?
A. supports the body
B. gives shape to the body
C. enables the body to move
D. yransports nlood throughout the body
Answer:
A yan hehehehe
salamat puso ma ah
Elemental phosphorus reacts with chlorine gas according to the equation
P4(s)+6Cl2(g)→4PCl3(l)
A reaction mixture initially contains 45.57 g P4 and 130.2 g Cl2.
Once the reaction has reached completion, what mass (in g) of the excess reactant is left?
(Express the mass in grams to three significant figures.)
Mass (in g) of the excess reactant (P₄) left = 7.626 g
Further explanationGiven
Reaction
P4(s)+6Cl2(g)→4PCl3(l)
45.57 g P4 and 130.2 g Cl2
Required
mass (in g) of the excess reactant left
Solution
mol P₄ (MW=124 g/mol) :
45.57 : 124 = 0.3675
mol Cl₂(MW=71 g/mol) :
130.2 : 71 = 1.834
mol : coefficient of reactant : P₄ : Cl₂ :
= 0.3675/1 : 1.834/6
= 0.3675 : 0.306
Cl₂ as limiting reactant(smaller ratio)
Reacted mol of P₄ (as an excess reactant):
=1/6 x 1.834
= 0.306
Unreacted mol of P₄ :
= 0.3675 - 0.306
= 0.0615
Mass of P₄(left) :
= 0.0615 x 124
= 7.626 g
The pressure exerted by the atmosphere at sea level is 14.7 Libs per square inch how many pounds of force are pressing on a rectangle with an area of 76.3cm^2
Pounds of force pressing on a rectangle : F = 173.86 lbs
Further explanationGiven
P at sea level = 14.7 lbs/in²
Area of rectangle : A = 76.3 cm²
Required
Pounds of force
Solution
P = F/A
F= P.A
Conversion :
1 cm² = 0.155 in²
76.3 cm² = 11.827 in²
Input the value :
F = 14.7 lbs/in² x 11.827 in²
F = 173.86 lbs
(9) How many moles of oleum in 1780. g of oleum? - Write an equation to summarize the process.
Answer:
1. 10moles
2. Find the summarized equation below
Explanation:
Mole = mass ÷ molar mass
Molar mass of oleum (H2S2O7) = 1(2) + 32(2) + 16(7)
= 2 + 64 + 112
= 178g/mol
According to the information provided, the mass of oleum is 1780g, hence, the number of moles in it is:
Mole = 1780/178
Mole = 10moles
2. The summarized equation of the contact process is:
1) S + O2 → SO2
2) 2SO2 + O2 → 2SO3
3) SO3 + H2SO4 (conc. sulfuric acid) → H2S2O7
4) H2S2O7 + H2O → 2H2SO4 (dilute sulfuric acid)
The wormwood plant is known for having leaves that taste bitter and have a strong odor. What advantage would these qualities give the
wormwood plant?
A. It would be more likely to repel other plants.
B. It would be less likely to be grown for use by humans.
C. It would be less likely to be eaten by insects.
D. It would be more likely to attract birds.
Answer:
C. It would be less likely to be eaten by insects.
Explanation:
The bitter taste and strong odor of the wormwood plant would repel the insects from eating the plant.
This is an adaptation by the tree to prevent is from being destroyed by the insect that would feed on its leaves. The bitter taste would not be edible for the insect to feed on. Also, the strong odor will not be attractive for the insects. So, the tree is well adapted to survive any insect invasion.If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the structure Y---:X:------Y could be abbreviated as XY2Z2.Classify these structures by the hybridization of the central atom. XY4Z2, XY4Z, XY5Z, XY2Z3, XY2Z, XY3Z, XY2Z2, XY3Z2,XY2,XY3,XY4,XY5,XY6
Answer:
XY4Z2- dsp2
XY4Z- sp3d
XY5Z- sp3d2
XY2Z3- sp3d
XY2Z- sp2
XY3Z- sp3
XY2Z2- sp3
XY3Z2- sp3d
XY2 - sp
,XY3- sp2
XY4- sp3
,XY5- sp3d
XY6- sp3d2
Explanation:
In the answer box I have shown the hybridization patterns of the various arrangement of bond pairs and lone pairs.
Hybridization was put forward to explain the shapes of molecules under the valence bond theory. All molecules having the same hybridization pattern are based on the same geometry. Deviations from the expected geometry may arise due to the presence of lone pairs.
100 Points PLZ HELP!
Using the ideal Gas Law (PV=nRT), solve for the missing variable. R=0.08206 atm*L/mol*k
At what temperature will 0.654 moles of neon gas occupy 15.66 liters and 0.899 atmospheres?
Answer:
C
Explanation:
What is CaF2(aq) + Rb
Answer:
RbF2 + Ca
Explanation:
Since Rb is located in IIA as well as Ca, Rb has ion form Rb2+
Hence CaF2 + Rb → RbF2 +Ca
Please be reminded, this answer may not be 100% correct
How can your knowledge of acids and bases
help you approach this problem to keep your soil
viable?
HELP NOW
Answer:
How can we make use of acids or bases to remove heavy metals from soils? We can remove heavy metals from soil by adding acid and catching the solution that drains through. Acids can react with metals turning metalic compounds which can be dissolved by water and washed away. Improve crop yields?
Explanation:
carbon dioxide is in a steel tank at 20 degrees celsius and 10 liters. what is the volume on the gas when the tank is heated to 100 degrees celsius?
Answer:
12.73 L
Explanation:
Given that,
Initial temperature, [tex]T_i=20^{\circ}=20+273=293\ K[/tex]
Initial volume, [tex]V_i=10\ L[/tex]
We need to find the volume on the gas when the tank is heated to 100 degrees celsius or 373 K.
We know that volume is directly proportional to the temperature of the gas. Using above relation,
[tex]\dfrac{V_i}{T_i}=\dfrac{V_f}{T_f}\\\\V_f=\dfrac{V_iT_f}{T_i}[/tex]
Putting all the values,
[tex]V_f=\dfrac{10\times 373}{293}\\\\V_f=12.73\ L[/tex]
So, the final volume of the gas is 12.73 L.
Arrange the compounds below in decreasing order of the ionic character of the bonds in them.
a. CsF
b. OF2
c. SrF2
d. F2
Answer: [tex]CsF[/tex] > [tex]SrF_2[/tex] > [tex]OF_2[/tex] > [tex]F_2[/tex]
Explanation:
The percent ionic character is used to determine if a bond is more ionic or covalent. More is the percent ionic character, the more ionic the molecule is. If the electronegativity difference between two elements is higher than 1.7 it will be considered as ionic.
The electronegativity difference for CsF is (3.98-0.79) = 3.19
The electronegativity difference for [tex]OF_2[/tex] is = (3.98-3.44) = 0.54
The electronegativity difference for [tex]SrF_2[/tex] is (3.98-0.95) = 3.0
The electronegativity difference for [tex]F_2[/tex] is 0.
Thus decreasing order of ionic character of the bonds is CsF > [tex]SrF_2[/tex] > [tex]OF_2[/tex] > [tex]F_2[/tex]
94.9 grams of Br is equivalent to how many moles of Br?
Answer:
The answer is 79.904.
Explanation:
We assume you are converting between grams Br and mole.
You can view more details on each measurement unit:
molecular weight of Br or mol
The SI base unit for amount of substance is the mole.
1 grams Br is equal to 0.012515018021626 mole.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between grams Br and mole.
Type in your own numbers in the form to convert the units!
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If the density of a certain oil is 0.8gcm3. What is the mass of 10 cm3 sample of this oil?
report your answer with one significant figure.
Taking into account the definition of density, the mass of the sample of oil with a volume of 10 cm³ and a density of 0.8 [tex]\frac{g}{cm^{3} }[/tex] is 8 grams.
Definition of densityDensity is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
[tex]density=\frac{mass}{volume}[/tex]
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
Mass of the sample of oilIn this case, you know that:
Density= 0.8 [tex]\frac{g}{cm^{3} }[/tex]Volume= 10 cm³Replacing in the definition of density:
[tex]0.8 \frac{g}{cm^{3} } =\frac{mass}{10 cm^{3} }[/tex]
Solving:
mass= 0.8 [tex]\frac{g}{cm^{3} }[/tex] × 10 cm³
mass= 8 g
In summary, the mass of the sample of oil with a volume of 10 cm³ and a density of 0.8 [tex]\frac{g}{cm^{3} }[/tex] is 8 grams.
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the movement of cold, nutrient-rich water from the deep ocean to the ocean surface is known as?
Answer:
Upwelling! Its the process where the deep cold water rises to the surface! :)
Explanation:
Hope this helps! :)
Answer:
upwelling
Explanation:
The element in Period 4 and Group 14 of the Periodic Table would be classified as a
Answer:
Chalcogen
Explanation:
