Emma is training for a 10-kilometer race. She wants to beat her last 10-kilometer time, which was 1 hour 10 minutes. Emma has already run for 55 minutes. Which inequality can be used to find how much longer she can run and still beat her previous time? (1 hr = 60 min)

Answers

Answer 1

let x be how much longer she can run the race and still beat her previous time

55(min) + x(min) < 1(hr) + 10(min)

55(min) + x(min) < 60(min) + 10(min)

55 + x < 60 + 10

x < 60 + 10 - 55

x < 15(min)

Answer 2

Answer:

Answer is A

Step-by-step explanation: Taking the test so the answer is A


Related Questions

A motorist takes 5 hours
to travel & 300km, how
Long will it take to bravel
720 km at sume
average Speed?

Answers

Answer:

12 hours.

Step-by-step explanation:

A motorist takes 5 hours to travel 300km

This means that his velocity, in km per hour, is given by:

v = 300/5 = 60 km/h

How long will it take to travel 720 km at same average speed?

720 km, 60 an hour. So

720/60 = 12

It will take 12 hours.

Need Help (WILL GIVE BRAINLIEST)

Answers

Answer:

A

Step-by-step explanation:

(y-5) / (7-5) = (x-1) / (2-1)

(y-5) / 2 = x-1

y-5 = 2x -2

y = 2x +3

PLEASE HELP ITS DUE IN AN HOUR!!!!!!

Answers

Answer:

3 units to the right of -5

Step-by-step explanation:

2x+y=5 y=x−1 system of equations please show your work

Answers

sub y = x - 1 into equation 1

2x + x - 1 = 5

3x = 6

x = 2

sub x = 2 into equation 2

y = 2 - 1

y = 1

I need a answer ASAP​

Answers

Answer:

8

Step-by-step explanation:

y = (10x^2 + 3x^4)/ 2x^2

where x is not equal to 0

(20x + 12x)/4x

32x / 4x

= 8

Wayne charges the following for repairing washing machines:
£28 call-out charge + £16 for each half-hour he spends on the repair
If a repair costs £76, how long did it take?

Answers

76-28=48
48/16= 3
1hr and a half

Find the simplified form of the expression. Give your answer in scientific notation.
(8 x 107) (7 x 104)

Answers

(8 x 110 )(7 x 100)
880 x 700
= 616000
=6.16 x 10^5

Is a rhombus a rectangle.
yes or no

Answers

No, it is not a rectangle.

Answer:

No a rhombus is not a rectangle

Step-by-step explanation:

NEED HELP PLEASE

We described numbers in this lesson using both powers of 10 and using standard decimal value. For example, the speed of light through ice can be written as a multiple of a power of 10, such as (2.3)⋅108 meters per second, or as a value, such as 230,000,000 meters per second. Use the number line to answer questions about points A and B.
Describe point B as:

a. A multiple of a power of 10
____ x 10 ^ ____
b. A value
_______

Describe point A as:

a. A multiple of a power of 10
_____ x 10 ^ _____

b. A value
______

Answers

Answer:

Step-by-step explanation:

B = 2×10⁸

A = 3×10⁸

if m 1 =7x and m 4 =3x +20 what is the value of x​

Answers

Answer:

this is a wild guess but  10.

Step-by-step explanation:

Not sure if you're allowed to do this but i added the x's

7x+3x= 10x

   10x+20.

I then subtracted 10 by both sides. That leaves me with 10.

  x =10

 this is a guess i apologize if it's wrong

What are the vertices of AA'B'C'if AABC is dilated by a scale factor of 2? V ACO, 10) 10 00 6 B(8,6) 4 2 C(4,2) th 2 6 8 10 A. A' (0,5), B'(4,3), C' (2, 1) B. A' (0,10), B' (16,6), C' (8, 2) O C. A' (0,20), B'(8, 12), C'(4,4) D. A'(0,20), B (16,12). C'(8,4) < PREVIOUS Type here to search​

Answers

Answer:

[tex]A' = (0,20)[/tex]

[tex]B' = (16,12)[/tex]

[tex]C' = (8,4)[/tex]

Step-by-step explanation:

Given

[tex]A = (0,10)[/tex]

[tex]B =(8,6)[/tex]

[tex]C=(4,2)[/tex]

[tex]k = 2[/tex] --- scale factor

Required

The coordinates of A'B'C'

This is calculated as thus:

[tex]A'B'C' = ABC * k[/tex]

So, we have:

[tex]A' = (0,10) * 2[/tex]

[tex]A' = (0,20)[/tex]

[tex]B' = (8,6) * 2[/tex]

[tex]B' = (16,12)[/tex]

[tex]C' = (4,2)*2[/tex]

[tex]C' = (8,4)[/tex]

what is the value of angle x?​

Answers

Answer:

x=66

Step-by-step explanation:

Hello There!

∠BAC ≅ ∠CDB because in a parallelogram opposite angles are congruent

So all we have to do is solver for ∠BAC

Remember the sum of the triangles angles is 180 so to find ∠BAC

we subtract the given angles (83 and 31) from  180

180-83-31=66

so ∠BAC = 66

like stated before

∠BAC≅∠BDC so if ∠BAC = 66 then x also equals 66

Answer:

x = 66

Step-by-step explanation:

x = 66 degree

Eloise spent $1.65 on potato salad that costs $0.25 per pound.

How many pounds of potato salad did she buy?

Answers

Answer:

she would be able to buy 6.6

Answer:

its 6.6

Step-by-step explanation:

cause i did that already

Elroy enjoys roller skating and weight training. Let X represent the number of hours he spends roller skating weekly,
and let y represent the number of hours he spends weight training weekly. The mean of X is 5 hours, and the mean
of Y is 7 hours. Which answer choice correctly calculates and interprets the mean of the sum, S = X + Y?

Answers

Answer:

[tex]\mathbf{\mu_S = 12 }[/tex]; [tex]\text{Elroy can expect to roller skate and weight train, on average, 12 }[/tex][tex]\text{hours in a typical week.}[/tex]

Step-by-step explanation:

Given that:

The mean [tex]\mu_X = 5[/tex]

The mean [tex]\mu_Y = 7[/tex]

Where;

[tex]S= X+ Y[/tex]

[tex]\mu_S = \mu _X + \mu_Y \\ \\ \mu_S = 5+7 \\ \\ \mu_S = 12[/tex]

Thus;

[tex]\mathbf{\mu_S = 12 }[/tex];[tex]\text{ Elroy can expect to roller skate and weight train, on average, 12 }[/tex][tex]\text{hours in a typical week.}[/tex]

Answer:

C ♡♡

Step-by-step explanation:

jus took the quiz !!!

A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a Riemann sum, then express the work as an integral and evaluate it.

Exercise (a)

How much work W is done in pulling the rope to the top of the building?

Exercise (b)

How much work W is done in pulling half the rope to the top of the building?

Answers

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = [tex]2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750[/tex]

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

[tex]W_2 = \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5[/tex]

The work done in pulling half the rope, W₂ = 562.5 lb·ft

the difference of two numbers is 7. Three times the greater number is 72. find the numbers​

Answers

Answer:

[tex]\huge\boxed{\tt{x = 24, y = 17}}[/tex]

Step-by-step explanation:

Let the greater number be x and the smaller number be y.

So,

Condition # 1:

x - y = 7 --------------(1)

Condition # 2:

3x = 72 --------------(2)

Taking Eq. (2)

3x = 72

Divide both sides by 3

x = 72 / 3

x = 24

Now, Put x = 24 in Eq. (1)

24 - y = 7

Subtract 24 to both sides

-y = 7 - 24

-y = -17

y = 17

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

The attendance at a baseball game was 400 people. Adult seats sold for $15 and children seats sold for $10. Total ticket sales were $4560. How many of each type of ticket were sold?

Answers

Answer:

112 adult and 288 children

Step-by-step explanation:

x= adult seats

y= children seats

15x + 10y = 4560

x + y = 400 --> y=400-x

so plug 400-x for y in the other equation

15x + 10(400-x)= 4560

now solve this equation

15x + 10(400-x)= 4560 --> 15x + 4000-10x= 4560 --> 15x -10x = 560 --> 5x=560 --> x = 560/5 --> x= 112

now plug in 112 for this equation (x+y=400) --> 112+y=400 --> y= 288

Axis of sym: x =

Vertex: (
,
)

Do not do the domain

Range: Pick one: A. y≥4 B. y<4 C. y≤4 D. y≤−2 E. y<−2

The Range is

Zeros:
and


Equation:

Answers

Answer:

SEE BELOW

Step-by-step explanation:

to understand thisyou need to know about:quadratic functionPEMDASlet's solve:

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

y=a(x-h)²+k

therefore

y=a(x-(-1))²+4y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

[tex]3 = a(1 {)}^{2} + 4[/tex]

simplify exponent:

[tex]3 = a + 4[/tex]

therefore

[tex]a = - 1[/tex]

our vertex form of quadratic equation is

y=-(x+1)²+4

let's simplify it to standard form

simplify square:

[tex]y = - ( {x}^{2} + 2x + 1) + 4[/tex]

simplify parentheses:

[tex]y = - {x}^{2} - 2x - 1 + 4[/tex]

simplify addition:

[tex]y = - {x}^{2} - 2x + 3[/tex]

therefore our answer is D)y=-x²-2x+3

the domain of the function

[tex]x\in \mathbb{R}[/tex]

and the range of the function is

[tex]y\leqslant 4[/tex]

zeroes of the function:

[tex] - {x}^{2} - 2x + 3 = 0[/tex]

[tex] \sf divide \: both \: sides \: by \: - 1[/tex]

[tex] {x}^{2} + 2x - 3 = 0[/tex]

[tex] \implies \: {x}^{2} + 3x - x + 3 = 0[/tex]

factor out x and -1 respectively:

[tex] \sf \implies \: x(x + 3) - 1(x + 3 )= 0[/tex]

group:

[tex] \implies \: (x - 1)(x + 3) = 0[/tex]

therefore

[tex] \begin{cases} x_{1} = 1 \\ x_{2} = - 3\end{cases}[/tex]

Lei is icing some cupcakes. She has 3/4 cups of frosting. Each cupcake needs 3/16 cup of frosting. How many can she frost?

Answers

Answer:

4

Step-by-step explanation:

3/4÷3/16

3/4×16/3

3•16=48

4×3=12

48÷12=4

Find AB If AC = 12 and BC = 35

Answers

Answer:

37

Step-by-step explanation:

a² =b²+ç²a²=12²+35²a=√1369a=37

. On a playground, there are 25
children, either riding on seesaws,
two per seesaw, or swinging on tire
swings, three per swing. If the total
number of seesaws and swings
combined is 9, what is the maximum
number of tire swings on the
playground?
A. 1
B. 2
C. 7
D. 8

Answers

I think the answer is C

What is the difference between change in quantity and change in quantity demanded? ​

Answers

A change in demand means that the entire demand curve shifts either left or right. A change in quantity demanded refers to a movement along the demand curve, which is caused only by a chance in price.

can someone help me with this please​

Answers

Answer:

4

This figure has 4 lines of symmetry.

Please help!! No links

Answers

9514 1404 393

Answer:

  10.5

Step-by-step explanation:

Corresponding sides of similar triangles are proportional, so ...

  ZX/ZY = CA/CB

  ZX = Zy(CA/CB) = 14(3/4)

  ZX = 10.5

The sum of two numers is 58. The smaller number is 14 less than the larger number. What are the two numbers?

Answers

36, and 22.
Bc it equals 58, and 22 is 14 less than 36.

A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company produces. He knows from numerous previous samples that this service life is normally distributed with a mean of 500 hours and a standard deviation of 20 hours. On three recent production batches, he tested service life on random samples of four headlamps, with these results.

Sample Service Life (hours)
1 495 500 505 500
2 525 515 505 515
3 470 480 460 470

1. What is the sample mean service life for sample 2?

a. 460 hours
b. 495 hours
c. 515 hours
d. 525 hours

2. What is the mean of the sampling distribution of sample means for whenever service life is in control?

a. 250 hours
b. 470 hours
c. 495 hours
d. 500 hours
e. 515 hours

Answers

Answer:

1. c. 515 hours

2.  c. 495 hours

Step-by-step explanation:

Sample mean:

Sum of all values in the sample divided by the number of values.

1. What is the sample mean service life for sample 2?

Sample 2 has four values, which are:

525 515 505 515

So

[tex]M = \frac{525+515+505+515}{4} = 515[/tex]

The answer is given by option C.

2. What is the mean of the sampling distribution of sample means for whenever service life is in control?

3 samples, 12 total values. We find the mean of all these values. So

[tex]M = \frac{495+500+505+500+525+515+505+515+470+480+460+470}{12} = 495[/tex]

The answer is given by option C.

8th grade math, please help.

Answers

9514 1404 393

Answer:

  282.74 units³

Step-by-step explanation:

Put the given dimensions in the volume formula and do the arithmetic.

  V = πr²h

  V = 3.14159(3²)(10) ≈ 282.74 . . . units³

Solve. h+ 10.6 = -10.6 h= what ​

Answers

Answer:

h= -21.2

Step-by-step explanation:

Subtract 10.6 from both sides to isolate the h

h + 10.6 = -10.6    - 10.6    -10.6h= -21.2

Now lets check the answer

-21.2 + 10.6 = -10.6

-10.6 = -10.6 ✅

I hope this helps!

Find legit BD

I need help for my assignment

Answers

Answer:

BD = 4

Step-by-step explanation:

∆BAD is congruent to ∆CAD based on the AAS Congruence Theorem.

Therefore:

BD = CD

3x + 1 = 5x - 1 (substitution)

Collect like terms

3x - 5x = -1 - 1

-2x = -2

Divide both sides by -2

x = -2/-2

x = 1

✔️BD = 3x + 1

Plug in the value of x

BD = 3(1) + 1

BD = 3 + 1

BD = 4

50 POINTS + BRAINLIEST

PLEASE DONT STEAL POINTS THIS IS MY 2ND TIME ASKING THIS QUESTION

Answers

Answer:

16

Step-by-step explanation:

Hope you pass good luck to you!

It’s 16 simply because the middle line in the box and whisker plot is over 16
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