En una fábrica de automóviles que trabaja las 24 horas se arman diariamente 24
automóviles tipo Sedan, 16 camionetas tipo SUV, 12 camionetas tipo VAN, 8
Camionetas tipo Pick-up y 2 automóviles deportivos.
Cl costo de producción y el precio de venta de cada vehículo es el siguiente:
Costo de
Vehículo
Precio de
Producción Venta
SEDAN
SEDAN
DEPORTIVO
$140,000 $185.000
SUV
$250,000
$320,000
VAN
$310,000
$400,000
PICK-UP
PICK-UP
$210,000
$285,000
VAN
DEPORTIVO
$400,000
$550,000
SUV
Cada año transcurrido, posterior a su fabricación, el precio de venta de los
vehículos disminuye una octava parte de su valor.
a suponiendo que en un día se vendan los vehículos en igual cantidad de los
que se fabricaron, como podrías calcular la ganancia?
b
Si la fábrica trabajara solo 12 horas, existe una forma de calcular cuántos
vehiculos se fabrican, ¿cuantos se fabricaron en este lapso? Sustenta tu
respuesta

Answer:

x = 1/2

Step-by-step explanation:

3 - 2(x - 1) = 2 + 4x

3 - 2x + 2 = 2 + 4x

-2x + 5 = 2 + 4x

-2x - 4x = 2 - 5

-6x = -3

x = -3/-6

x = 1/2

Answer:

67.63 oz

Step-by-step explanation:

1 liter = 33.814 oz

2 litres = 2 x 33.814 oz = 67.628 oz

Answer:

24 kg

Step-by-step explanation:

The median can be found by putting the numbers in order and then finding the middle value.

In order from least to greatest:

19, 22, 24, 27, 28

24 is the middle value

So, 24 kg is the median.

Answer:

24 kg

Step-by-step explanation:

The median is the number in the middle of the data set. To find the median, arrange the numbers from least to greatest, then locate the middle number.

1. Arrange the numbers from least to greatest

Numbers: 22 kg, 24 kg, 28 kg, 19 kg, 27 kg

Least to greatest: 19 kg, 22 kg, 24 kg, 27 kg, 28 kg

2. Locate the middle number

Cross one number off each end of the set until the middle is reached.

19 kg, 22 kg, 24 kg, 27 kg, 28 kg

Cross off 19 and 28

22 kg, 24 kg, 27 kg

Cross off 22 and 28

24 kg

The middle number has been reached.

median= 24 kg

The median of the measurements is 24 kilograms.

Answer:

[tex]\huge\boxed{9,40,46}[/tex]

Step-by-step explanation:

Let's check it using Pythagorean Theorem:

[tex]c^2 = a^2 + b^2[/tex]

Where c is the longest sides, a and b are rest of the 2 sides

1) 9 , 40 , 46

=> [tex]c^2 = a^2 + b^2[/tex]

=> [tex]46^2 = 9^2 + 40^2[/tex]

=> 2116 = 81 + 1600

=> 2116 ≠ 1681

So, this is not a Pythagorean Triplet

2) 16, 30 and 34

=> [tex]c^2 = a^2 + b^2[/tex]

=> [tex]34^2 = 16^2 + 30^2[/tex]

=> 1156 = 256 + 900

=> 1156 = 1156

No need to check more as we've found the one which is not a Pythagorean Triplet.

Answer:

Option A is the correct option.

Step-by-step explanation:

1. Let h , p and b are the hypotenuse , perpendicular and base of a right - angled triangle respectively.

From Pythagoras theorem,

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

Here, we know that the hypotenuse is always greater than perpendicular and base,

h = 46 , p = 40 , b = 9

⇒[tex] \sf{ {46}^{2} = {40}^{2} + {9}^{2} }[/tex]

⇒[tex]2116 = 1600 + 81[/tex]

⇒[tex] \sf{2116  ≠ 1681}[/tex]

Thus , the relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is not satisfied by h = 46 , p = 40 , b = 9

So, The set of numbers 9 , 40 , 46 is not Pythagorean triple.

------------------------------------------------------

2. 16 , 30 , 34

h = 34 , p = 30 , b = 16

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

⇒[tex] \sf{ {34}^{2} = {30}^{2} + {16}^{2} }[/tex]

⇒[tex] \sf{1156 = 900 + 256}[/tex]

⇒[tex] \sf{1156 = 1156}[/tex]

The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 34 , p = 30 , b = 16

So, the set of numbers 16 , 30 , 34 is a Pythagorean triple.

------------------------------------------------------

3. 10, 24 , 26

h = 26 , p = 24 , b = 10

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

⇒[tex] \sf{ {26}^{2} = {24}^{2} + {10}^{2} }[/tex]

⇒[tex] \sf{676 = 576 + 100}[/tex]

⇒[tex] \sf{676 = 676}[/tex]

The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and h i.e h = 26 , p = 24 , b = 10

So, the set of numbers 10, 24 , 26 is the Pythagorean triple.

-----------------------------------------------------

4. 50 , 120 , 130

h = 130 , p = 120 , b = 50

[tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex]

⇒[tex] \sf{ {130}^{2} = {120}^{2} + {50}^{2} }[/tex]

⇒[tex] \sf{16900 = 14400 + 2500}[/tex]

⇒[tex] \sf{16900 = 16900}[/tex]

The relation [tex] \sf{ {h}^{2} = {p}^{2} + {b}^{2} }[/tex] is satisfied by the particular values of h , p and b i.e h = 130 , p = 120 , b = 50

So, the set of numbers 50, 120 , 130 is the Pythagorean triple.

-----------------------------------------------------

In this way, to satisfy the Pythagoras Theorem , the hypotenuse ( h ) , perpendicular ( p ) and the base ( b ) of a right - angles triangle should have the particular values in order. These values of h , p and b are called Pythagorean triple.

Hope I helped!

Best regards!!

Answer:

Add information

Step-by-step explanation:

According to mu understanding, this is the part (B) of the question. If you could provide the first part, I can complete it because some useful information is left out.

Answer:

y = - 140

Step-by-step explanation:

Given that y varies jointly as x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = - 180 when z = 15 and x = - 3, thus

- 180 = k × - 3 × 15 = - 45k ( divide both sides by - 45 )

4 = k

y = 4xz ← equation of variation

When x = 7 and z = - 5, then

y = 4 × 7 × - 5 = - 140

Answer:

The 4th term = a+3d = 0,

or a = -3d.

The 25th term = a+24d = -3d+24d = 21d. ...

the 25th term is 3 times the 11th term. Proved.

Answer:

a^25 = 3 x a^11 .

Step-by-step explanation:

Given a^4 = 0

That is (a + 3d) = 0

⇒ a = - 3d ........... (1)

nth term of AP is given by an = a + (n – 1)d

a^11 = a + 10d = – 3d + 10d = 7d  [From (1)]

a^25 = a+ 24d = – 3d + 24d = 21d  [From (1)]

Hence

The answer is a^25=3 x a^11

Answer:

Step-by-step explanation:

y = - 5x + 30  and  x = 10  ⇒  y = -5•10 + 30 = -50 + 30 = -20

x = 10  and y = -20   ⇒  (10, -20)

Answer:

Its B. (10, –20)

Step-by-step explanation:

I just took the quiz on edge

Answer:

Step-by-step explanation:

Assuming that the shape of the table be rectangular in nature.

Area of the study table = Length * Breadth

Area of the study table = 2m * 1.25m

Area of the study table = 200cm * 125cm (since 100cm = 1m)

Area of the study table = 25000cm²

If the study table is decorated with square design of size 10cm x 10cm, the area of one square design is 100 cm².

The number of such square designs = Area of the study table/area of one square design

The number of such square designs = 25000cm²/100cm²

The number of such square designs = 250

Hence the number of such design is 250

Answer:

Jake ran 10 1/6 miles in total

Step-by-step explanation:

4 1/4 + 2 2/3 - (4 1/4-1).

                  v

6 11/12 + 3 1/4

          v

6 11/12 + 3 3/12 = 10 1/6

Jake ran 10 1/6 miles in total (Mon, Tues, Wed).

Answer:

61/6 or 10.1666666667

Step-by-step explanation:

Monday = 4  1/4

Tuesday = 2  2/3

Wednesday = Monday - 1

=> Monday = 17/4 miles

=> Tuesday = 8/3 miles

=> Wednesday = 17/4 - 4/4 = 13/4 miles.

=> (17/4 + 13/4) + 8/3

=> 30/4 + 8/3

=> Take the LCM of the denominators.

=> LCM = 12

=> 90/12 + 32/12

=> 122/12

SImplify 122/12

=> 61/6 or 10.1666666667

Answer:

The answers to the question above are given below:

Step-by-step explanation:

Question: What is a discrete probability​ distribution?

Answer

A discrete distribution is very important in data research as it shows in tabular form the probabilities that can be found in a list of distribution values and their individual probabilities in counted data. Usually, from the pool of distribution of numbers, the discrete distribution shows the probability of having countable numbers out of the pool.

Question: Choose the correct answer below. A. A discrete probability distribution exclusively lists probabilities. B. A discrete probability distribution lists each possible value a random variable can​ assume, together with its probability. C. A discrete probability distribution lists each possible value a random variable can assume. D. None of the above

The correct answer is: option B "discrete probability distribution lists each possible value a random variable can​ assume, together with its probability."

Question: What are the two conditions that determine a probability​ distribution?

The correct answer is:

1. Since each value may not be zero, each probability must include between 0 and 1.

2. When probabilities are totaled, it must give 1.

Answer:

the correct answer is x=5

Answer:

66k+9

Step-by-step explanation:

Let's simplify step-by-step.

5(10k+1)+2(2+8k)

Distribute:

=(5)(10k)+(5)(1)+(2)(2)+(2)(8k)

=50k+5+4+16k

Combine Like Terms:

=50k+5+4+16k

=(50k+16k)+(5+4)

=66k+9

Answer:

=66k+9

HOPE THIS HELPS!!!!!! :)

<3333333333

Answer:

So the quotient of [tex]\frac{x^{2} + x - 6}{x^{2} -6x + 5} X \frac{x^{2} + 2x - 3}{x^{2} -7x + 10}[/tex] has (x + 3)² in the numerator and (x + 5)² in the denominator.

Step-by-step explanation:

[tex]\frac{x^{2} + x - 6}{x^{2} -6x + 5} X \frac{x^{2} + 2x - 3}{x^{2} -7x + 10}[/tex]

Factorizing the expressions we have

[tex]\frac{x^{2} + 3x -2x - 6}{x^{2} -x - 5x + 5} X \frac{x^{2} + 3x - x - 3}{x^{2} -2x -5x + 10}[/tex]

[tex]\frac{x(x + 3)- 2(x + 3)}{x(x -1) - 5(x - 1)} X \frac{x(x + 3) - 1(x + 3)}{x(x - 2) - 5(x - 2)}[/tex]

[tex]\frac{(x + 3)(x - 2)}{(x - 5)(x - 1)}X\frac{(x + 3)(x - 1)}{(x - 2)(x - 5)}[/tex]

Cancelling out the like factors, (x -1) and (x - 2), we have

[tex]\frac{(x + 3)(x + 3)}{(x - 5)(x - 5)}[/tex]

= [tex]\frac{(x + 3)^{2} }{(x + 5)^{2} }[/tex]

So the quotient of [tex]\frac{x^{2} + x - 6}{x^{2} -6x + 5} X \frac{x^{2} + 2x - 3}{x^{2} -7x + 10}[/tex] has (x + 3)² in the numerator and (x + 5)² in the denominator.

Answer:

19 throws.

Step-by-step explanation:

For her success rate to be 80% in 37 throws she must make  0.8 * 37

= 29.6 throw - that is 30 to nearest throw.

So for the next 20 throws she must make  30 - 11 = 19 throws.

The profit made by Gavin at the end of the game is $0.87 per bottle.

The profit can be calculated by taking the difference of selling price and the cost price.

Given that,

The number of bottles bought for $18.50 is 48 and sold for $1.25 each.

Then, the cost for one bottle is 18.50/48 = $0.38.

As per the question the profit made can be calculated as the difference of selling price and cost price as,

Profit = Selling price - Cost Price

         =  1.25 - 0.38

         = $0.87

Hence, the profit earned by Gavin is given as $0.87 for each bottle.

To know more about profit click on,

https://brainly.com/question/7544724

#SPJ6

━━━━━━━☆☆━━━━━━━

▹ Answer

30 miles

▹ Step-by-Step Explanation

Multiply mph by hours:

15 mph * 2 hrs = 30 miles

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

Answer:

Amadi is 86m far from Becky

Amadi is on the bearing of 78° .

Step-by-step explanation:

From the information given ,

let I represent Ikyume

A represent Amadi  and B represent Becky

From the information in the diagrammatic expression shown below:

Using cosine rule;

i² = a² + b² - 2ab cos (I)

i² = 42² + 62² - 2(42×62) cos (110°)

i² =  1764 + 3844 - 5208 (- 0.342)

i² =  1764 + 3844 -  ( - 1781.136)

i² = 1764 + 3844 + 1781.136

i² = 7389.136

i = [tex]\mathtt{\sqrt{7389.136}}[/tex]

i = 85.96

i [tex]\simeq[/tex] 86 m

Amadi is 86m far from Becky

From  point I , 12° = 12° at point A (alternate  angles)

In that quadrant = 90 - 12° = 78°

Therefore, Amadi is on the bearing of 78° .

Answer:

Step-by-step explanation:

45=3×3×5

60=2×2×3×5

L.C.M=180

2| 180

2|90

3|45

3|15

3|5

180=2×2×3×3×5

third number=2×3=6

or 2×2×3=12

or2×3×3=18

or 2×2×3×3=36

so third number can be one of  6,12,18,36

Answer:

1 mile

Step-by-step explanation:

in 20 minutes Stuart has gone 1 mile

in 20 minutes Brandy has gone 4 miles

therefore they meet 1 mile from Stuart's house

Answer:

1 mile

Step-by-step explanation:

Answer:

d = √10

Step-by-step explanation:

[tex]K(-1, -3) , L(0, 0).\\\\d=\sqrt{((x_2-x_1)^2+ (y_2-y_1)^2) } \\\\x_1 =-1\\\\y_1 =-3\\\\x_2 =0\\\\y_2 =0 \\\\d = \sqrt{(0-(-1))^2+(0-(-3))^2}\\\\ d = \sqrt{(0+1)^2+(0+3)^2}\\\\ d = \sqrt{(1)^2 + (3)^2}\\\\ d = \sqrt{1 + 9}\\\\ d = \sqrt{10} \\[/tex]

Answer:

[tex]\huge\boxed{|KL|=\sqrt{10}\approx3.2}[/tex]

Step-by-step explanation:

The formula of a distance between two points (x₁; y₁) and (x₂; y₂):

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

We have K(-1; -3) and L(0; 0). Substitute:

[tex]|KL|=\sqrt{(0-(-3))^2+(0-(-1))^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}}[/tex]

Look at the picture.

We have the right triangle with the legs 3 and 1.

Use the Pythagorean theorem:

[tex]leg^2+leg^2=hypotenuse^2[/tex]

substitute:

[tex]3^2+1^2=|KL|^2\\\\|KL|^2=9+1\\\\|KL|^2=10\to|KL|=\sqrt{10}[/tex]

Answer:

As x decreases in value.f(x) decreases in value.......

Answer:

(-2y-6)(-3y-8)

= 6y²+16y+18y+48

= 6y²+ 34 y +48

Hope this helps

if u have question let me know in comments ^_^

Answer:

Here is your answer!!!

Step-by-step explanation:

-2y(-3y-8)-6(-3y-8)

6y^2+16y+18y+48

6y^2+34y+48

Answer:

The cube only belongs to the x and not 2x.

The statement will only be true if there is a bracket around the 2x.

log₃(2x)³= 3log₃2x

logarithm power rule:

logₐ(x)^y = y ∙ logₐ(x)

Answer:

see explanation

Step-by-step explanation:

Given

[tex]log_{5}[/tex] 2x³

= [tex]log_{5}[/tex] 2 + [tex]log_{5}[/tex] x³

= [tex]log_{5}[/tex] 2 + 3[tex]log_{5}[/tex] x

Answer:

-4.

Step-by-step explanation:

y = 3x - 7; x = 1.

y = 3(1) - 7

= 3 - 7

= -4

Hope this helps!

Answer:

y = - 4

Step-by-step explanation:

y=3x-7

Let x =1

y = 3*1 -7

y = 3-7

y = - 4

Answer:

-15

Step-by-step explanation:

-7p+10p-16=6p+36-7

3p-16=6p+29

3p-6p=29+16

-3p=45

p=45/-3

p=-15

Answer:

the 4th and 6th one

Step-by-step explanation:

A function is when there are x- and y-values but each x value has only 1      y-value

Simple: If the x-value is repeated its not a function

Answer:

Step-by-step explanation:

1,2,3

Answer:

4 2^(1/3) or 5.0396841995794926590688424291129134022810058588060319203279004486... decimal

Step-by-step explanation:

Simplify the following:

(2^(1/3))^7

Hint: | For all a>=0, (a^(1/3))^m = a^(m/3). Apply this to (2^(1/3))^7.

Multiply exponents. (2^(1/3))^7 = 2^(7/3):

2^(7/3)

Hint: | Separate the exponent of 2^(7/3) into integer and fractional parts.

2^(7/3) = 2^(6/3 + 1/3) = 2^(6/3)×2^(1/3):

2^(6/3) 2^(1/3)

Hint: | Divide 6 by 3.

6/3 = (3×2)/3 = 2:

2^2 2^(1/3)

Hint: | Evaluate 2^2.

2^2 = 4:

Answer:  4 2^(1/3) or 5.0396841995794926590688424291129134022810058588060319203279004486... decimal

Answer:

48 km/h

Step-by-step explanation:

80/50*30=48 km/h