Answer:
A) La altura de la repisa sobre el punto donde se lanza la moneda es de aproximadamente 0,42 m
B) La velocidad de la moneda justo antes de que golpee el platillo es de aproximadamente 0,895 m/s hacia abajo
Explanation:
A) Los parámetros dados son;
La distancia horizontal del plato desde donde se lanza la moneda = 2,1 m
La velocidad con la que se lanza la moneda, u = 6,4 m / s
El ángulo al que se lanza la moneda, θ = 60 °
La componente horizontal de la velocidad, vₓ = 6.4 m / s × cos (60°) = 3.2 m/s
El tiempo que tarda la moneda en recorrer una distancia horizontal de 2,1 m, 't' se calcula de la siguiente manera;
t = 2,1 m/(3,2 m/s) = 0,65625 segundos
Por tanto, la altura de la moneda a 0,65625 segundos se da de la siguiente manera;
y = u × sin (θ) × t - (1/2) × g × t²
En t = 0,65625 segundos, obtenemos;
y = 6,4 × sin (60°) × 0,65625 - (1/2) × 9,81 × (0,65625) = 0,41840044589
La altura de la repisa sobre el punto donde se lanza la moneda, y ≈ 0.42 m
B) La velocidad vertical de la moneda justo antes de que golpee el platillo, [tex]v_y[/tex], se da como sigue;
[tex]v_y[/tex] = u × sin(θ) - g·t
∴ [tex]v_y[/tex] = 6.4 × sin(60°) - 9.81 × 0.65625 ≈ -0.895
La velocidad de la moneda justo antes de golpear el platillo, [tex]v_y[/tex] ≈ 0.895 m/s (hacia abajo)
providing trademark protection
Answer:
what are you asking exactly?
In a symbiotic relationship,
a. one organism benefits while its host gets nothing in return.
b. bacteria takes food from your stomach, but does nothing for you.
c. both organisms involved benefit or are neutrally affected.
d. your body produces vitamins and then uses them for nutrition
In a symbiotic relationship, both organisms involved benefit or are neutrally affected. Symbiosis is a close and long-term interaction between two different species.
The term "symbiosis" encompasses mutualism, commensalism, and parasitism. In mutualism, both organisms benefit from the interaction, such as in the case of bees and flowers where bees obtain nectar and pollen while also helping flowers to pollinate.
In commensalism, one organism benefits while the other is neither helped nor harmed, such as remora fish that attach to sharks for transportation and feeding on scraps left by the shark. In parasitism, one organism benefits while the other is harmed, such as ticks that feed on blood from a host animal.
To know more about symbiosis, visit:
https://brainly.com/question/31105472
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An object's velocity/speed increases, multiplied by a factor of 7. What factor would its Kinetic Energy increase by?
Answer:
k.E= 49 ms^-2
Explanation:
k.E= 1/2 mv^2
From that formula of k.E
K.E is directly proportional to the ( velocity)^2
K.E directly proportional to (7)^2
so that k.E increase by 49
You slide out of a car seat and as you touch the metal door a spark jumps between your hand and the door. Describe how the spark formed
Answer: Your body sliding against the car seat created friction, making it created potential energy. The friction is a form of electricity, and the car doors metal is a conductor of electricity. That potential energy was turned into kinetic once the metal attracted the electricity, thus making a spark.
Hope this helps ^_^
Using the information provided in the table, which statement BEST describes the object's motion?
Answer:
the velocity is decreasing therefore acceleration is negative
A 50,000 kg train is rolling on its own down the track at 5 m/s. You grab the rope trailing behind it, and exert a stopping force of 2000 N. How long does it take to stop the train?
Answer:
t = 125 seconds
Explanation:
Given that,
The mass of a train, m = 50,000 kg
Initial speed, u = 5 m/s
Stopping force, F = 2000 N
We know that,
Force, F = ma
Where
a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{50000(0-5)}{-2000}\\\\t=125\ s[/tex]
So, it will take 125 seconds to stop the car.
can someone help?? 4/5
Answer: I may not have the awser but
Explanation: Try calculating 8.932 times
10^22 kg
Answer:
F = 2.68 x 10²³ N
Explanation:
The force between lo and Jupiter is given by Newton's Gravitational Formula:
[tex]F = \frac{Gm_1m_2}{r^2} \\[/tex]
where,
F = Force = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
m₁ = mass of lo = 8.932 x 10²² kg
m₂ = mass of Jupiter = 1.9 x 10²⁷ kg
r = distance between lo and Jupiter = 4.22 x 10⁸ m
Therefore,
[tex]F = \frac{(6.67\ x\ 10^{-11}Nm^2/kg^2)(8.932\ x\ 10^{22}\ kg)(1.9\ x\ 10^{27}\ kg)}{(4.22\ x\ 10^8\ m)^2}[/tex]
F = 2.68 x 10²³ N
Does earths Roation causes gravity?
Answer:
he gravity of Earth, denoted by g, is the net acceleration that is imparted to objects due to the combined effect of gravitation (from mass distribution within Earth) and the centrifugal force (from the Earth's rotation )
Determine the resistance of 100m of copper cable whose cross-sectional area is 1.5mm2
A 20.0 Ohm and 60.0 Ohm resistor
are connected in series to a 9.00 V
battery. What is their equivalent
resistance?
(Unit = Ohms)
Answer:
for resistors in series, add the resistances to get their equivalence. The answer is
80.0 Ohms
What is only found in plant cells??
Cell membrane , nucleus, cell wall , vacuole.
which one !!!
Can someone please help me with history.
Answer:
Yes my name is Axelrod I can help you
What type of specialized cell in the eye is used for detecting low levels of light?
Answer:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.
Answer:
Rods
Explanation:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.
Bajo la acción del viento una puerta gira un ángulo de 90° en 5 s. Calcular su velocidad angular y la velocidad lineal de los puntos del borde
si el ancho de la puerta es de 50 cm. R. 0,314 rad/s, 0,157 m/s.
Jack and Jill are pushing a 3 kg object on a rough surface; the object accelerates at a rate of 5 m/s2. Calculate the force applied by the Jack knowing that Jill is pushing 4 N and the rough surface applies 2 N force on the box as friction force.
Answer:
13 N
Explanation:
From the question,
(F₁+F₂)-F' = ma................ Equation 1
Where F₁= Jack's force, F₂ = Jill's force, F' = Friction force, m = mass of the object, a = acceleration of the object.
Given: F₂ = 4 N, F' = 2 N, m = 3 kg, a = 5 m/s²
Substitute these values into equation 1 and solve for F₁
(F₁+4)-2 = 3×5
(F₁+4)-2 = 15
F₁+4 = 15+2
F₁+4 = 17
F₁ = 17-4
F₁ = 13 N
Hence the force applied by Jack is 13 N
A measure of an object's is a measure of the object's inertia.
Answer: Mass is the quantity of matter in an object. More specifically, mass is a measure of the inertia, or “laziness,” that an object exhibits in response to any effort made to start it, stop it, or otherwise change its state of motion. Weight is the force of gravity on an object.
define one ampere current electricity
Help!!!
Where can the hoses be attached in order to provide water to a fire engine? (There may be more than one correct answer.)
house faucet
hydrant
generator
pumper truck
Answer:
Explanation:
Hydrant
The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 1017 m away from you and 6 × 109 m from each other. You are measuring light with a wavelength of 700 nm. As the light goes through the lens, it diffracts. a. Is it possible, using this telescope, to see the two stars as separate stars? b. What is the minimum possible lens diameter you would need in order to resolve these two stars?
Answer:
a)It is NOT possible using this telescope, to see the two stars as separate stars
b)[tex]d_{min} =28.466m[/tex]
Explanation:
From the question we are told that:
Diameter of lens,[tex]d = 25 cm \approx 0.25 m[/tex]
Distance from both star [tex]D_f= 2*10^{17} m[/tex]
Distance between both stars [tex]D_b= 6*10^9 m[/tex]
Wavelength of light [tex]\lambda =700 nm \approx 700*10^-9 m[/tex]
Generally the equation for angle subtended by the two stars at the lens is mathematically given by
[tex]\theta=\frac{D_f}{D_b}[/tex]
[tex]\theta=\frac{6*10^9}{2*10^{17}}[/tex]
[tex]\theta=3.0*10^{-8} rad[/tex]
Generally the equation for minimum angular separation of two object is mathematically given by
[tex]\theta_{min} = 1.22*\lambda/d[/tex]
[tex]\theta_{min}= \frac{1.22*700*10^-9}{0.25}[/tex]
[tex]\theta_{min}= 3.416*10^-^6 rad[/tex]
Therefore
[tex]\theta < \theta_{min}[/tex]
[tex]3.0*10^{-8} rad< 3.416*10^-^6 rad[/tex]
It is NOT possible using this telescope, to see the two stars as separate stars
b)
Generally the equation for minimum diameter of the lens is mathematically given by
[tex]d_{min} =\frac{ 1.22*\lambda}{\theta}[/tex]
[tex]d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}[/tex]
[tex]d_{min} =28.466m[/tex]
According to Hooke's law, the force exerted by a compressed or stretched spring is proportional to...
Answer:
Hooke's law can be written as:
F = -k*Δx
Where k is a constant that depends on the spring, called the spring constant.
And Δx = (x - x₀) is the displacement of the spring with respect to the rest position x₀
And a proportional equation is something like:
y = c*x
Where c is a constant of proportionality.
In the case of Hooke's law, the constant is K, then the force is proportional to the displacement of the spring with respect to the rest position Δx.
A 3kg object moving at 4 m/s encounters a 20 N resistive force over a duration of 0.20 seconds. The impulse experienced by this object is _____
Answer:
the impulse experienced by this object is 4 Ns
Explanation:
Given;
mass of the object, m = 3 kg
velocity of the object, v = 4 m/s
resistive force, F = 20 N
duration of impact, t = 0.2 s
The impulse experienced by this object is calculated as follows;
J = F x t
J = 20 x 0.2
J = 4 Ns
Therefore, the impulse experienced by this object is 4 Ns
How much work is done when 300 N of force is used to lift the dog 1.5 m?
Answer:
450N
Explanation:
Work done=Force*distance
If a person meets an accident, which of the following factors will have more effect on his Kinetic energy and hence on the fatality of the accident?
A.velocity of the vehicle
B.Mass of the vehicle
Answer:
b
Explanation:
A 1200 kg car accelerats from reat to 10.0 m/s in a time of 4.50 seconds. Calculate the force that thr car's tires exerted on the road.
Answer:
2667 N
Explanation:
Method 1: ImpulseWe can solve this problem by using the impulse formula.
FΔt = mΔv Δt = time interval, m = mass of the car (kg), Δv = change in velocityWe have three known variables, so we can solve for the fourth: F.
Divide Δt from both sides to isolate F.
F = (mΔv)/ΔtSubstitute known values into the equation.
F = [(1200 kg)(10 m/s - 0 m/s)] / 4.5 s F = [(1200)(10)]/4.5 F = 12000/4.5 F = 2666.666667 NThe force that the car's tires exert on the road is 2667 N.
Method 2: Newton's Second LawThe force that the car's tires exert on the road is equivalent to the force that the road exerts on the car due to Newton's Third Law of Motion.
We can calculate the force that the car's tires exert on the road by using the formula F = ma, which was derived from Newton's Second Law of Motion.
F = ma F = force exerted on the car, m = mass of the car (kg), a = acceleration of the car (m/s²)We are given the mass of the car, velocity of the car, and the time in which it accelerated.
We can use this equation for acceleration:
a = Δv/Δt Δv = final velocity - initial velocity (change in velocity), Δt = time intervalThe car started from rest, meaning it had an initial velocity of 0 m/s. Its final velocity was 10 m/s. The time that it took for the car to go from 0 m/s to 10 m/s was 4.5 seconds.
a = (10 m/s - 0 m/s) / 4.50 s a = 10/4.5 a = 2.222... m/s²Now we have two known variables, mass and acceleration. We can solve for the force exerted on the car (and thus, the force the car exerts on the road) using the formula F = ma.
F = ma F = (1200 kg)(2.222... m/s²) F = 1200 · 2.222...F = 2666.666667 NThe force that the car's tires exert on the road is 2667 N.
What is density?
A- How much space an object takes
up
B- The amount of matter in a certain
amount of space
C- How much water an object
displaces
D- How much an object is affected by
gravity
Answer:
B- The amount of matter in a certain
amount of space
Explanation:
Density is the amount of matter an object has in a certain space. To find density, divide the mass of an object by the volume of an object.
Answer:
C- How much water it displaces
Explanation:
How do you calculate the total resistance in a series circuit with more than one resistor
Answer:
You add up all the individual resistances of the resistors in the series circuit to get the total resistance of the circuit
Explanation:
A series circuit is a circuit that has most of its components connected end-to-end
following what was stated above, in a series circuit, the resistors are connected end to end. This means that the current that flows out from one of the resistors flows into the next one. As a result of this, the current through all the resistors is the same.
To get the total equivalent resistance in a series circuit, you add up all the individual resistances of the resistors in the series circuit. This should give you the total resistance in the circuit.
i.e
Total resistance = R1 + R2 + R3 ....
can someone please solve this
Answer:
The gravity is pulling the diver downwards but the rotation of the body means gravity cant pull him down as quickly
Explanation:
7. Telescope efficiency depends on the area of the primary mirror, while angular resolution scales as 1/D, where D is the diameter of the telescope. State which is true concerning the objects observed with a 30m telescope, versus a 10m telescope. A) The 30 m telescope can observe objects 30 times fainter, and with 3 times the resolution of the 10 m telescope. B) The 30 m telescope can observe objects with 1/9 the angular diameter, and 9 times fainter than, the 10 m telescope. C) The 30 m telescope can observe objects 9 times fainter, and with 3 times smaller angular size, than the 10 m telescope. D) The 30 m telescope can observe objects 3 times fainter, and with 3 times smaller angular size, compared to the 10 m telescope.
Answer:
Option C, The 30 m telescope can observe objects 9 times fainter, and with 3 times smaller angular size, than the 10 m telescope.
Explanation:
As we know,
The surface brightness of the object viewed through telescope is proportional to the square of the diameter of the lens
Thus, Brightness ([tex]B_{30}[/tex]) of 30 m telescope would be proportional to [tex]30^2[/tex]
Brightness of 10 m ([tex]B_{10}[/tex]} telescope would be proportional to [tex]10^2[/tex]
Thus, the ration of the two would be
[tex]\frac{B_{30}}{B_{10}} = \frac{30^2}{10^2} \\\frac{B_{30}}{B_{10}} = \frac{9}{1} \\B_{30} = 9 * B_{10}[/tex]
Thus, brightness of 30 m telescope would be able to view 9 times fainter object as compared to the 10 m telescope.
Also , 30 m telescope would be able to view 3 times smaller angular sized object as compared to the 10 m telescope
Hence, option C is correct
When a substance is poured from one container to another, its shape changes but its volume does not, what state of matter is the substance in?
A. Plasma
B. Liquid
C. Gas
D. Solid
Answer: When a liquid substance is poured into a vessel, it takes the shape of the vessel, and, as long as the substance stays in the liquid state, it will remain inside the vessel. Furthermore, when a liquid is poured from one vessel to another, it retains its volume (as long as there is no vaporization or change in temperature) but not its shape.
Explanation: A solid has a definite shape and volume. A liquid has a definite volume, but takes the shape of its container. A gas lacks either a defined shape or volume. Plasma is similar to a gas in that its particles are very far apart, but a gas is electrically neutral and plasma has a charge.
Answer:
B
Explanation:
Liquid
When a bouncy ball is dropped from a second floor window, at what point is the kinetic energy highest?
A. Just after the ball dropped
B. Just before the ball hits the ground for the first time
C. After the ball has bounced several time
D. after the ball bounces away into the bushes, never to be found again
Answer:
Explanation:
Because the total energy available to the ball doesn't change whatsoever during its entire trip from the window to the ground,
TE = KE + PE which says that the total energy available to a system is equal to the kinetic energy of the system plus the potential energy, and that this value will not ever change (because energy cannot be created or destroyed. Sound familiar?) If the ball is being held still before it is dropped from some height off the ground, it is here that the total energy can be determined, and that total energy at this point is all potential, since the ball is not moving while someone is holding it and getting ready to drop it. The SECOND it starts to fall, the potential energy begins to be converted to kinetic. As the potential energy is losing value, the kinetic is gaining it at the same rate (again, energy doesn't just disappear; it has to go somewhere. Here, it goes from potential to kinetic a little at a time). When the ball finally hits the ground, or an INSTANT BEFORE it hits the ground, the potential energy is 0 because the height of something on the ground has a height of 0. At this instant, right before the ball hits the ground, is where the KE is the greatest. All the energy at that point has been converted from potential to kinetic.
Long story short, choice B is the one you want.
