Ernie Rolph borrowed ​$6700 at 4​% annual simple interest. If exactly 1 year later he was able to repay the loan without​ penalty, how much interest would he​ owe? Ernie will owe ​$___ in interest.

Answer:

-36

Step-by-step explanation:

3*12=36

she is going down (negative) so, it is -36

not sure if this is what you are asking for, if not try this

0-12-12-12=-36

Answer:

6(x-3)

Step-by-step explanation:

the common number for 6 and 18 is 6 so if you extract that from the expression then it turns to 6(x-3) which cannot be factored further

Answer:

Option B:  6(x - 3)

Step-by-step explanation:

Answer:

The answer is: Leo's phone had the greater initial trade-in value. Tonya's phone decreases at an average rate slower than the trade in value of Leo's phone.

Step-by-step explanation:

I got it right. Hope this helps.

The initial trade-in value of Tonia's phone is greater when compared with Leo's    

There is a decrease in the trade-in value of Leo's phone at an average slower rate

[tex]f(x) = 490\times 0.88[/tex]

[tex](x)[/tex] ⇒ [tex]g(x)[/tex]

[tex]0[/tex] ⇒ [tex]480[/tex]

[tex]2[/tex] ⇒ [tex]360[/tex]

[tex]4[/tex] ⇒ [tex]470[/tex]

Now we will solve with the greater initial value

The initial value is when x = 0. So, we have

[tex]f(x) = 490 \times o.88^x\\\ f(o) = 490 \times 0.88 ^0\\f(0 =490 \times 1 \\f(o) = 490[/tex]

From leos table

[tex]g(0) = 480\\f(0) > g(o)\\i.e \\490 > 480[/tex]

So Tonia had a greater initial value

Solving (b): The phone with a lesser rate

y [tex]y = a b ^ x[/tex]

An exponential function is:

where [tex]b \rightarrow rate[/tex]

For Tonia

[tex]b = o.88[/tex]

For Leo we have

[tex](x_{1} , y_{1} )= (0,480)\\(x_{1}, y_{1} ) = (2, 360)[/tex]

So the equation becomes

[tex]y = ab ^x \\480 = ab ^0 \\and \\360 = ab ^2[/tex]

On solving

[tex]480 = a \times 1\\a = 480[/tex]

[tex]360 = ab ^ 2[/tex]

so it becomes

[tex]480 = 360 \times b ^2 \\[/tex]

On dividing both sides by [tex]480[/tex]  we get

[tex]b ^ 2 = 0.87[/tex]

[tex]b ^ 2 = 0.75[/tex]

On taking square root we get

[tex]b = 0.87[/tex]

In comparison, we get Leo's rate is slower.

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Answer: 0.98

Step-by-step explanation:

given data:

probability they won a game = 58% = 0.58

since outcome of games are independent, and percentage would remain same as 2014.

probablility that Dodgers wins atleast 1 of their next 7 games

= 1 - p

= 1 - ( 0.58 )^ 7

= 1 - 0.02208

= 0.98

probabikotun that Dodgers would win one of their next seven games is 0.98

Answer:

X= 15

Step-by-step explanation:

the above equation will be used to determine the value of x.

the above equation will be used to determine the value of x.

6x-12= 2x+20+18

6x-2x = 20+12+18

4x= 60.

X= 60/4

X= 15

x = 15

Answer:

Explained below.

Step-by-step explanation:

(a)

The first and third quartiles of bowling scores are as follows:

Q₁ = 125 and Q₃ = 156

Then the inter quartile range will be:

IQR = Q₁ - Q₃

      = 156 - 125

      = 31

Any value lying outside the range (Q₁ - 1.5×IQR, Q₃ + 1.5×IQR) are considered as unusual.

The range is:

(Q₁ - 1.5×IQR, Q₃ + 1.5×IQR) = (125 - 1.5×31, 156 + 1.5×31)

                                               = (78.5, 202.5)

The bowling score of 200 lies in this range.

Thus, the bowling score of 200 is usual.

(b)

Compute the probability that the mean bowling score will be smaller than 150 as follows:

[tex]P(\bar X<150)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}<\frac{150-155}{16/\sqrt{40}})[/tex]

                  [tex]=P(Z<-1.98)\\=1-P(Z<1.98)\\=1-0.97615\\=0.02385\\\approx 0.024[/tex]

Thus, the probability that in a sample of 40 bowling scores, the mean will be smaller than 150 is 0.024.

(c)

It is provided that, the lower the golf score the better.  

So, the best 5% of scores would be the bottom 5%.

That is, P (X > x) = 0.05.

⇒ P (Z > z) = 0.05

⇒ P (Z < z) = 0.95

⇒ z = 1.645

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\1.645=\frac{x-77}{3}\\\\x=77+(3\times 1.645)\\\\x=81.935\\\\x\approx 82[/tex]

Thus, the score is 82.

(d)

A z-scores outside the range (-2, +2) are considered as mild outlier and the z-scores outside the range (-3, +3) are considered as extreme outlier.

Compute the z-score for the golf score of 70 as follows:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

  [tex]=\farc{70-77}{3}\\\\=\frac{-7}{3}\\\\=-2.33[/tex]

As the z-score for the golf score of 70 is less than -2, it is considered as a mild outlier.

Answer:

A. No conclusion can be drawn regarding the means because the box plots only show medians and quartiles.

Step-by-step explanation:

A box display tells represents a five-number summary that consists of the minimum value, lower quartile, median, upper quartile and maximum value. It could also tell you which data point is an outlier, if there are any.

Mean value for a data set that can hardly be ascertained or derived from a box plot display itself.

Therefore, the statements regarding the means of both data sets that is most likely true is: "A. No conclusion can be drawn regarding the means because the box plots only show medians and quartiles."

Answer:

0.05m^2

Step-by-step explanation:

5 divided by 100

Answer: 0%

Step-by-step explanation:

There's 40 students, and 40 students read physics. That means that every student reads physics. So, no student could read only chemistry.

Answer: Yes they form a proportion. The given equation is a true equation.

==========================================

Explanation:

The idea is that if we have

a/b = c/d

then that it is the same as

a*d = b*c

This is known as cross multiplication. We'll use this rule to get

15/12 = 4.5/3.6

15*3.6 = 12*4.5

54 = 54

We got the same value on both sides, meaning that the last equation is true. Consequently, it means the first equation is true as well (all three equations are true).

--------

You could also use your calculator to see that

15/12 = 1.25

4.5/3.6 = 1.25

showing that 15/12 = 4.5/3.6 is a true equation and the ratios form a proportion.

Answer:

15/12=4.5/3.6 = True

Step-by-step explanation:

Simplify the following:  Left-hand

15/12

Hint: | Reduce 15/12 to lowest terms. Start by finding the GCD of 15 and 12.

The gcd of 15 and 12 is 3, so 15/12 = (3×5)/(3×4) = 3/3×5/4 = 5/4:

Answer: 5/4

______________________________

Approximate the following:

4.5/3.6

Hint: | Express 4.5/3.6 in decimal form.

4.5/3.6 = 1.25:

Answer:  1.25 = 5/4

Answer:

1)

[tex] \sqrt{( \sqrt{} 3 {}^{2} } + 1 {}^{2} )[/tex]

[tex] \sqrt{4} = 2[/tex]

then the angle,

[tex] \tan( \alpha ) = - 1 \div \sqrt{3} = 330[/tex]

in radians,

[tex]11\pi \div 6[/tex]

hope this helps for the next questions

Complete Question

Find the indicated area under the curve of the standard normal​ distribution, then convert it to a percentage and fill in the blank.

About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

About_____% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

Answer:

About 97.219% of the area is between z = - 2.2 and z = 2.2 (or within 2.2 standard deviations of the mean).

Step-by-step explanation:

From the question given we can see that they both are the same so 1  will just solve one

   Now the area under this given range can be represented mathematically as

  [tex]P ( -2.2 < z < 2.2) = P(z < 2.2 ) - P(z < -2.2 )[/tex]

Now  from the z-table  

        [tex]p(z < 2.2 ) = 0.9861[/tex]

and

        [tex]p(z < - 2.2 ) = 0.013903[/tex]

So

     [tex]P ( -2.2 < z < 2.2) = 0.9861 - 0.013903[/tex]

     [tex]P ( -2.2 < z < 2.2) = 0.97219[/tex]

So converting to percentage  

     [tex]P ( -2.2 < z < 2.2) = 0.97219 * 100[/tex]

    [tex]P ( -2.2 < z < 2.2) = 97.219 \%[/tex]

Answer:

7200ft/per Hour divide it by mile ( 5280) makes 1.363 so maybe 1.4 Miles

Step-by-step explanation:

Work Shown:

1 mile = 5280 feet

1 hour = 3600 seconds (since 60*60 = 3600)

[tex]2 \text{ ft per sec} = \frac{2 \text{ ft}}{1 \text{ sec}}\\\\2 \text{ ft per sec} = \frac{2 \text{ ft}}{1 \text{ sec}}*\frac{1 \text{ mi}}{5280 \text{ ft}}*\frac{3600 \text{ sec}}{1 \text{ hr}}\\\\2 \text{ ft per sec} = \frac{2*1*3600}{1*5280*1} \text{ mph}\\\\2 \text{ ft per sec} = \frac{7200}{5280} \text{ mph}\\\\2 \text{ ft per sec} \approx 1.363636 \text{ mph}\\\\[/tex]

The result is approximate and the "36" portion repeats forever.

Answer:

The error is the use of wrong trigonometric ratio formula.

Sine was used instead of tangent.

It should be: [tex] tan(A) = \frac{36}{84} [/tex]

Step-by-step explanation:

Side length, 36, is opposite to <A. Side length, 84, is the adjacent side. Therefore, the right trigonometric ratio formula to use is:

[tex] tan(A) = \frac{opposite}{adjacent} [/tex]

[tex] tan(A) = \frac{36}{84} [/tex]

[tex] A = tan^{-1}(\frac{36}{84}) [/tex]

m<A ≈ 23°

The error made was the use of wrong trigonometric ratio formula.

Answer:

8-2x

Step-by-step explanation:

2 distributed over the entire expression equals 8-2x

Answer:

the answer is b

Step-by-step explanation:

Answer:

x= -3     x = 1/2     x=-2

Step-by-step explanation:

f(x)=(x+3) (2x-1)(x+2)

Set equal to zero

0 =(x+3) (2x-1)(x+2)

Using the zero product property

x+3 =0   2x-1 =0    x+2 =0

x= -3    2x =1       x = -2

x= -3     x = 1/2     x=-2

Answer:

y = x-4

Step-by-step explanation:

The y intercept is -4

We have 2 points so we can find the slope

( 0,-4) and(4,0)

m = ( y2-y1)/(x2-x1)

    = ( 0- -4)/ (4-0)

    = 4/4

   =1

The slope intercept form is

y = mx+b

y = 1x-4

y = x-4

Answer:

a) dV(s)  =  15,386 cm³

b) dS(s) = 4,396 cm²

c) dV(s)/V(s) = 1,07 %    and   dS(s)/ S(s)  =  0,71 %

Step-by-step explanation:

a) The volume of the sphere is

V(s) = (4/3)*π*x³        where x is the radius

Taking derivatives on both sides of the equation we get:

dV(s)/ dr  =  4*π*x²    or

dV(s)  =  4*π*x² *dr

the possible propagated error in cm³ in computing the volume of the sphere is:

dV(s)  = 4*3,14*(7)²*(0,025)

dV(s)  =  15,386 cm³

b) Surface area of the sphere is:

V(s) = (4/3)*π*x³  

dV(s) /dx  =  S(s) = 4*π*x³

And

dS(s) /dx  = 8*π*x

dS(s) = 8*π*x*dx

dS(s) = 8*3,14*7*(0,025)

dS(s) = 4,396 cm²

c) The approximates errors in a and b are:

V(s) =  (4/3)*π*x³     then

V(s) = (4/3)*3,14*(7)³

V(s) = 1436,03 cm³

And  the possible propagated error in volume is from a)  is

dV(s)  =  15,386 cm³

dV(s)/V(s)  = [15,386 cm³/1436,03 cm³]* 100

dV(s)/V(s) = 1,07 %

And for case b)

dS(s) = 4,396 cm²

And the surface area of the sphere is:

S(s) =  4*π*x³        ⇒   S(s) =  4*3,14*(7)²    ⇒ S(s) = 615,44 cm²

dS(s) = 4,396 cm²

dS(s)/ S(s)  =  [ 4,396 cm²/615,44 cm² ] * 100

dS(s)/ S(s)  =  0,71

Answer:

[tex]51\frac{4}{17}[/tex]

Step-by-step explanation:

If we add all of the fractions together, we 'd get 55/17 of an hour. The question is to find how many hours she spent exercising. Well, for that we'd just need to see how many seventeens fit inside 55. We could divide, but that'd lead us to a really long, weird number.

Since 17*3=51, we know that in total, three seventeens fit inside 55. Yet, there's still remainders.

55-51=4

So, our answer would be 51 (how many 17s go into 55) and 4/17 (the remainder.)

Hope this helps!! <3 :)

Answer:

It’s symmetric property

Answer:

Symmetry

Step-by-step explanation:

The guy above me

Answer:

Step-by-step explanation:

(5+(-4))/2 = 1/2 or 0.5

(-7 + 6)/2 = -1/2 or -0.5

the solution is D

(0.5, -0.5)

Answer:

Step-by-step explanation:

Hello, please consider the following.

m and n are the two numbers.

m + n = 24, right?

n = 2 m

We replace n in the first equation, it comes

m + 2m =24

3m = 24 = 3*8

So, m = 8 and n = 16

Thank you

The first number is 8 and second number is 16.

Equation is the defined as mathematical statements that have a minimum of two terms containing variables or numbers is equal.

Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.

Given that the sum of two numbers is twenty-four

The second number is equal to twice the first number

Let x and y are the two numbers.

According to the question,

m + n = 24,

n = 2m

Substitute the value of n in the first equation,

m + 2m =24

3m = 24

m = 24/3

m = 8

Substitute the value of m in the n = 2m

So, n = 2(8)

n = 16

Hence, the first number is 8 and second number is 16.

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Answer:

Step-by-step explanation:

60°=2×30°

one angle is double the angle of the same right angled triangle.

so hypotenuse is double the smallest side.

Hypotenuse=10

smallest side=10/2=5

third side =√(10²-5²)=5√(2²-1)=5√3

The equation is represented 3 units to the left of the complex plane and 2 units up.

A complex equation is an equation that involves complex numbers when solving it. A complex number is a number that has both a real part and an imaginary part.

Well to see how this is represented, we first need to multiply it out so we can see how it looks when it is simplified!

[tex]=(3-2i)(i^2)\\\\\\i^2=-1\\\\\\=(3-2i)(-1)\\\\\\=(-3+2i)[/tex]

We know that on a complex plane, our imaginary numbers are represented on the vertical axis.

So the original expression, (3-2i) would have been 3 units to the right on a complex graph and 2 units downward!

The equation I input above should be pretty straightforward, but one thing I didn't mention was that i^2 should = -1 when dealing with complex numbers!

Therefore, the equation 3-2i * i^2 is equal to -3 + 2i, this is graphed 3 units to the left and to units upward!

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Answer:

0.5

1 divide by 2 = 0.5

Answer:

6

Step-by-step explanation:

18 : 9 · 3 = 2 · 3 = 6

Answer:

Z=9

Step-by-step explanation:

Insert A into A+Z=14

5+z=14

Subtract 5 on both sides, to find Z.

-5     -5

z=9

(a) Let [tex]A(t)[/tex] denote the amount of sugar in the tank at time [tex]t[/tex]. The tank starts with only pure water, so [tex]\boxed{A(0)=0}[/tex].

(b) Sugar flows in at a rate of

(0.07 kg/L) * (7 L/min) = 0.49 kg/min = 49/100 kg/min

and flows out at a rate of

(A(t)/1080 kg/L) * (7 L/min) = 7A(t)/1080 kg/min

so that the net rate of change of [tex]A(t)[/tex] is governed by the ODE,

[tex]\dfrac{\mathrm dA(t)}[\mathrm dt}=\dfrac{49}{100}-\dfrac{7A(t)}{1080}[/tex]

or

[tex]A'(t)+\dfrac7{1080}A(t)=\dfrac{49}{100}[/tex]

Multiply both sides by the integrating factor [tex]e^{7t/1080}[/tex] to condense the left side into the derivative of a product:

[tex]e^{\frac{7t}{1080}}A'(t)+\dfrac7{1080}e^{\frac{7t}{1080}}A(t)=\dfrac{49}{100}e^{\frac{7t}{1080}}[/tex]

[tex]\left(e^{\frac{7t}{1080}}A(t)\right)'=\dfrac{49}{100}e^{\frac{7t}{1080}}[/tex]

Integrate both sides:

[tex]e^{\frac{7t}{1080}}A(t)=\displaystyle\frac{49}{100}\int e^{\frac{7t}{1080}}\,\mathrm dt[/tex]

[tex]e^{\frac{7t}{1080}}A(t)=\dfrac{378}5e^{\frac{7t}{1080}}+C[/tex]

Solve for [tex]A(t)[/tex]:

[tex]A(t)=\dfrac{378}5+Ce^{-\frac{7t}{1080}}[/tex]

Given that [tex]A(0)=0[/tex], we find

[tex]0=\dfrac{378}5+C\implies C=-\dfrac{378}5[/tex]

so that the amount of sugar at any time [tex]t[/tex] is

[tex]\boxed{A(t)=\dfrac{378}5\left(1-e^{-\frac{7t}{1080}}\right)}[/tex]

(c) As [tex]t\to\infty[/tex], the exponential term converges to 0 and we're left with

[tex]\displaystyle\lim_{t\to\infty}A(t)=\frac{378}5[/tex]

or 75.6 kg of sugar.

Answer:

5 11/20

Step-by-step explanation:

1 3/4 + 3 4/5

Get a common denominator of 20

1 3/4 * 5/5   + 3  4/5 *4/4

1 15/20    + 3  16/20

4 31/20

Rewriting

4 + 20/20 + 11/ 20

4+1 + 11/20

5 11/20

Answer:

The two lines do not intersect, and are parallel to one another on a graph.

Step-by-step explanation:

A system of equations consists of two or more equations with two or more variables. The solution to these variables must satisfy all of the variables in the equations in the system at the same time. Usually, all the equations in the system are considered and solved simultaneously. A linear equation might have a unique solution, an infinite solution, or no solution at all.

A system with exactly one solution is called a consistent system, and it is said to be independent, and the graph of its lines intersects at the point that is the solution to the equations. A system with an infinite number of solution is said to be dependent and the lines are coincident on a graph.

If a system has no solution, it is said to be inconsistent . The graphs of the lines do not intersect, and the lines are parallel to one another on the graph.

For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.

The standard form of writing linear equation is expressed as y = mx + b

m is the slope of the line

b is the y-intercept

For two lines of linear equations to have no solution, they must be parallel to each other i.e they must have the same slope.

For instance, the system of equations y = 2x + 7 and y = 2x - 3 have no solutions because they have the same slope.

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