Answer:
The crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) , if the wavelength of maximum absorption for the ion is 600 nm is - 1987.59kJ/mole
Explanation:
Lets calculate -:
Crystal field stabilization energy -
[tex]E=\frac{hc}{\pi }[/tex]
where h = planks constant = [tex]6.626\times10^-^3^4 Js[/tex]
c= velocity of light = [tex]3\times10^8m/second[/tex]
[tex]\pi =wavelength=600nm=600\times10^-^9m[/tex]
[tex]E=\frac{6.626\times10^-^3^4\times3\times10^8}{600\times10^-^9}[/tex]
=[tex]0.033\times10^-^1^6 J/ion[/tex]
= [tex]0.033\times10^-^1^6\times6.023\times10^2^3[/tex]
= [tex]0.198759\times10^7 J/mole[/tex] = [tex]1987.59\times10^3J/mole[/tex]
= [tex]1987.59kJ/mole[/tex]
Thus , the crystal field stabilization energy for the octahedral ion hexacyanomanganate(III) is 1987.59kJ/mole
When an atom is changed into an ion, the is changed
number of protons
b. number of neutrons
number of electrons
d. mass number
Answer:
the number of electrons will end up changing
help people i really need this
which memrane lines the abdomino pelvic cavity
Answer:
The peritoneum
Explanation:
The peritoneum is the serous membrane that surrounds several organs in the abdominopelvic cavity. The tunica vaginalis is the serous membrane, which surrounds the male gonad, the testis. The two layers of serous membranes are named parietal and visceral. Between the two layers is a thin fluid filled space.
hope it helps, and pls answer this https://brainly.com/question/22410918
tysm if u do ill give brainliest :D
when are igneous rocks formed?
A. When layers of mud form inside Earth
B. When layers of mud are compressed
C. When melted rock solidifies
D. When solid rock melts
Answer:
C. When melted rock solidifies.
If energy cannot be created or destroyed, what happens to the kinetic and potential energy?
Answer:
According to the law of conservation of energy, energy cannot be created or destroyed, although it can be changed from one form to another. KE + PE = constant. ... As the car coasts down the hill, it moves faster and so it's kinetic energy increases and it's potential energy decreases. hope this helps
Explanation:
Answer:
They cannot be destroyed or created however,
Explanation:
it can only be transformed or transferred from one form to another.
Uranium, an important component of both nuclear weapons and nuclearreactors, has two major isotopes, U-238, which has a half-life of approximately billion years, and U-235, which has a half-life of approximately million years. Both were present in equal amounts at the time of thecreation of the Earth, billion years ago. How many years after the creationof the Earth had the amount of radiation from uranium decayed to half theamount present at the time of the creation of the Earth
Answer:
Hello your question is poorly written below is the well written question
Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5 billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth
Answer : 140 billion years
Explanation:
Given that :
U-238 h1/2 = 4.5 billion years
U-235 h1/2 = 700 million years
At the beginning both Isotopes where present in equal amount
Determine the T years before the amount of Uranium decays to Half
T = ? N'2 = N1 / 2
we know that N = No ( 1/2 )^h where h = time / half-life time
attached below is the detailed solution of the given problem
the ideal of stationary orbit was first given by?
Answer:
Neil Bohr
Explanation:
Thank me latur✊
HELP ASAP WHATS THE DEFINITION I NEED JT NKW
Answer:
1.Summer solstice 2.seasons 3. winter solstice 4. Equinox
Explanation:
I hope it helps!
Have a great day!
What is a hot spot? Must be in your own words ( please hurry)
Answer:
It depends. what hot spot are you looking for?
Answer:
A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.
Explanation:
Hope this is what you mean be hot spot!
I hope this helps you!
what does pen mean?.
Answer:
P = protons
E = electrons
N = neutrons
remember protons and neutrons (protons are positive and neutrons are neutral as you can already tell by their names) are found at the centre of the nucleus (positive mass). Whilst the electrons (negative) orbit around the shells
What is 2AI(s) + FeO3(s) = Ai2O3(s) + 2Fe(s)
Answer:
it's a double displacement Reaction.
What is thePercent composition of dichlorine heptoxide?
Answer:
The percent composition of dichlorine heptoxide is 38.76% CI and 61.24% O
Answer:
38.76%cl and 61.24%o
Explanation:
the percent composition of dichlorine heptoxide is 38.76%Cl and 61.24%O
How many moles of product are formed? Can someone help me ?
Answer:
It says right under here what to do
Explanation
Determine the moles of product produced by dividing the grams of product by the grams per mole of product. You now have calculated the number of moles of every compound used in this reaction. 41.304 g of NaCl ÷ 58.243 g/mol = 0.70917 moles of NaCl.
What is the function of white blood cells?
A) immunity
b) carry nutrients, waste
C) blood clotting
Answer:
A
Explanation:
They help fight infection and other disease
Answer:
immunity is the answer for this question
Which rank was NOT included in Linnaeus' taxonomy?
Kingdom
Family
Domain
Order
Answer:
Domain
Explanation:
This is because Linnaeus taxonomy is a system of classification which was invented by a swedish Botanist called Carl Linnaeus and it is refered to hierarchy of grouping organisms called taxa. It involve 7 system of classifications and they include Kingdom, Phylum, Class, Order, Family, Genus, and Species.
Choose the best answer
1. Gas A diffuses twice as fast as another gas B. If the density of the gas A is 2, the molecular mass of
(a)2
(b) 4
(c) 8
(d) 16
i think it is
(b) 4
:) hope its correct :)
the article is on newsela called the water cycle
Answer:
Explanation:Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?Canguru comeu algumas folhas de 3 galhos de eucalipto. Cada galho tinha inicialmente20 folhas. Canguru comeu algumas folhas do primeiro galho e depois comeu tantas folhas do segundo galho quantas tinham sido deixadas no primeiro galho. Depois ele comeu 2 folhas do terceiro galho. No total, quantas folhas foram dei-xadas nos 3 galhos?
In general, what is the effect of increased temperature on the solubility of a gas?
A. It is uniform
B.The solubility increases.
C. The solubility decreases
D.The saturation increases
E. The effect cannot be determined
Answer:
C. The solubility decreases.
Explanation:
Took the plato test!
Consider the fatty acid. A carboxylate salt is attached to a 19 carbon chain, where double bonds are present between carbons 5 and 6, between carbons 8 and 9, between carbons 11 and 12, and between 14 and 15. The carboxylate carbon is carbon 1. All double bonds are cis. Which of the designations are accurate for the fatty acid
Answer:
ω-3 fatty acid and 19:4(Δ5,8,11,14)
Explanation:
From the image attached below:
We can see the structure of the delta nomenclature showing the numbers of carbons, numbers of double bonds, and the locations of the double bonds in the structure of the carboxylate salt.
Also, we can see the structure of the fatty acid where; the location of the first double bond from the methyl end is shown.
Hence, the designation which are accurate for these structures are:
ω-3 fatty acid and 19:4(Δ5,8,11,14)
When one gram of liquid water at its boiling point is changed into water vapor
1.
334 J/g is gained from the surrounding environment
2.
334 J/g is released into the surrounding environment
3
2260 J/g is gained from the surrounding environment
4
2260 J/g is released into the surrounding environment
Answer: 2260 J/g is gained from the surrounding environment
When one gram of liquid water at its boiling point is changed into water vapor, 2260 J/g of energy is gained from the surrounding environment.
What is heat of vaporization?Heat of vaporization is the amount of heat that is required by any body during their transition process from liquid state to vapor state, at a particular temperature i.e. no change in temperature during whole process.
During the transition of one gram of liquid water into water vapor at its boiling point of 100°C, 2260 J/g energy is absorbed by the water for the formation of vapor.
Hence, option (3) is correct.
To know more about heat of vaporization, visit the below link:
https://brainly.com/question/26306578
what climate is Colorado in?
A.Most Subtropical Mid-Latitude
B.Polar
C.Moist ContinentaMid-Latitiude
D.Dry
Answer:
b
Explanation:
Answer:
D. Dry
Explanation:
Colorado's combination of high elevation, midlatitude, and continental interior geography results in a cool, dry climate.
Rank the following compounds in order of increasing solubility in water. Items (4 items) (Drag and drop into the appropriate area) No more items Items in order most soluble CaO BaO KCI KI
I have tried CaO> BaO > KCl > KI, this is incorrect.
Answer:
CaO < BaO < KCl <KI
Explanation:
Let us remember that the solubility of an ionic substance in water depends on the magnitude of the lattice energy and the hydration energy. If the hydration energy is equal to or is greater than the lattice energy, the substance dissolves in water.
However, the lattice energy depends on the size of the ions. The smaller the ions in the ionic compound, the higher the lattice energy and the lesser the solubility of the ionic compound.
KI has the least lattice energy and the highest solubility in water while CaO has the highest lattice energy and the least solubility in water.
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?
Answer:
The gas is decreasing at a rate of 50 cubic centimeters per minute.
Explanation:
The Boyle's Law is represented by the following expression:
[tex]P\cdot V = k[/tex] (1)
Where:
[tex]P[/tex] - Pressure, in kilopascals.
[tex]V[/tex] - Volume, in cubic centimeters.
[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.
By definitions of rate of change and implicit differentiation, we derive the following differential equation:
[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)
Where:
[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.
[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.
Then, we clear the rate of change of the volume within (2):
[tex]P\cdot \dot V = -\dot P\cdot V[/tex]
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]
The gas is decreasing at a rate of 50 cubic centimeters per minute.
In Which State of matter are molecules moving the slowest
A. Solid
B. Liquid
C. Gas
Answer:
Solid
Explanation:
Molecules in solids only vibrate in place, while the other two have moving molecules
Which compound is the conjugate base in the following reaction :H2SO4 + H2O —> HSO4 + H30+
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Answer: HSO4-
Explanation:
I hope this helped!
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2C2H2 + 502 = 4CO2 + 2H20
when 20000g of 2C2H2 + 5O2 = how much 4CO2?
Answer:
6.761 × 10⁴ g
Explanation:
Step 1: Write the balanced combustion reaction
2 C₂H₂ + 5 O₂ ⇒ 4 CO₂ + 2 H₂O
Step 2: Calculate the moles corresponding to 20000 g of C₂H₂
The molar mass of C₂H₂ is 26.038 g/mol.
20000 g × 1 mol/26.038 g = 768.11 mol
Step 3: Calculate the moles of CO₂ produced from 768.11 moles of C₂H₂
The molar ratio of C₂H₂ to CO₂ is 2:4.
768.11 mol C₂H₂ × 4 mol CO₂/2 mol C₂H₂ = 1536.2 mol CO₂
Step 4: Calculate the mass corresponding to 1536.2 moles of CO₂
The molar mass of CO₂ is 44.01 g/mol.
1536.2 mol × 44.01 g/mol = 6.761 × 10⁴ g
5.07 x 10^24 atoms of antimony is how many moles?
8.98 mol
7.99 mol
4.82 mol
8.42 mol
Answer:
8.42 moles (3 sig. figs.)
Explanation:
Given 5.07 x 10²⁴ atoms of antimony (Sb) => ? moles Sb
1 mole of any substance contains 6.02 x 10²³ particles ( atoms or molecules)
∴ Think in terms of 'how many 6.02 x 10²³'s are in 5.07 x 10²⁴ atoms Sb?
That is => moles Sb = 5.07 x 10²⁴ atoms Sb / 6.02 x 10²³ atoms Sb/mole Sb
= 8.42192691 moles Sb (calculator answer) ≅ 8.42 moles (3 sig. figs.)
can u identify a chemical equation for the saponification of olive oil as per your experiment?
I
At which point in its swing does the pendulum have the least gravitational potential energy
Answer:
a
Explanation:
a
Ethanol in the body is oxidized to acetaldehyde by liver alcohol dehydrogenase (LADH). Other alcohols are also oxidized by LADH. For example, methanol, which is mildly intoxicating, is oxidized by LADH to the quite toxic product of formaldehyde. The toxic effects of ingesting methanol (a component of many commercial solvents) can be reduced by administering ethanol. The ethanol acts as a competitive inhibitor of methanol by displacing it from LADH. This provides sufficient time for the methanol to be harmlessly excreted by the kidneys. If an individual has ingested 30 mL of methanol (a lethal dose), how much 100 proof whiskey (50% ethanol by volume) must be imbibed to reduce the activity of her LADH towards methanol to 5% of its original value? The adult human body contains ~40L of aqueous fluids throughout which ingested alcohols are rapidly and uniformly mixed. The densities of ethanol and methanol are both 0.79 g/cm3. Assume the KM values of LADH for ethanol and methanol to be 10-3 M and 10-2 M, respectively, and that Ki = KM for ethanol
Answer: The changes are the mL of methanol ingestion (30mL) and the proof of the whiskey (40% ethanol; 80 proof), and the percentage of reduction (1%). I applied the formulas from the last post in reference to this question but am completely lost. The formulas used last time were: 2. Formulas Applied alpha=1 + ([etOH]/KetOH) (V[meOH]/V[etOH])= (Vmax*[meOH]/KmeOH+[meOH])/(Vmax*[meOH]/alpha*KmeOH+[meOH]) which reduces to (V[meOH]/V[etOH])=(alpha*KmeOH+[meOH])/(KmeOH+[meOH]) 3. My attempt Molarity of methanol: 30mL; which equates to 23.7g of methanol; in 40L that is equal to 0.5925 g/L Dividing the molecular weight by 32.04g/mol I get 0.0184925 which is approximately 0.02M; Km is 0.01M Since the molar mass of methanol and ethanol are two fold, I can multiply the g/l by 4. However, unlike the previous problem, I cannot multiply by 2 because I do not have 50% EtOH, so because 40 is less than 50 I assume to multiply by 2.5 yielding: (30mL)(4)(2.5)=300mL 300mL of EtOH to effectively reduce the Methanol to 1%.
