Evaluate 7 Σ n=1 2(-2)^n-1.

Rick should order part number G371-7 So the option A is the correct Answer

What is a part number ?

Part designs or materials are identified by part numbers, which are sometimes abbreviated as PN, P/N, part no., or part #. Its goal is to make referencing to that thing simpler. A part number clearly identifies a part design both inside and occasionally outside of a single organization. For instance, it is simpler to identify a screw as "HSC0424PP" rather than "Hardware, screw, machine, 4-40, 3/4" long, pan head, Phillips." The part number in this illustration is "HSC0424PP," which may be prefixed in database fields as "PN HSC0424PP" or "P/N HSC0424PP."

A serial number is a specific identifier of a specific instantiation of a part design, much as a part number identifies a component design (regardless of its instantiations). To put it another way, a part number designates each specific (physical) item as having been manufactured to a specific, original design;

As part number G371-7 fits perfectly to the desired requirement of float diameter of less than 8 inches, weigh more than 1 pound, and fit a 5/16-SAE spud connection that's why it is the correct answer

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Answer: 8

Step-by-step explanation:

8 times 8 is 64

Answer:

4.) a.) 2.01 b.) 404.01

6.) a.) 152.17 b.) 18412.17 c.) 153.14 d.) 18565.60

Step-by-step explanation:

To solve, use the exponential growth formula [tex]A_t=A_0(1+\frac{r}{p})^t[/tex] where

[tex]A_t[/tex] = Amount as a function of time

[tex]A_0[/tex] = Original amount

[tex]r[/tex] = rate

[tex]p[/tex] = period

[tex]t[/tex] = time

For question 4, let

[tex]A_0=400\\r=0.06\\p=12\\t=2[/tex]

So,

[tex]A_t=400(1+\frac{0.06}{12})^2\\A_t=400(\frac{201}{200})^2\\A_t=400(1.01)\\A_t=404.01[/tex]

So, the second-period interest would be 404.01-402=2.01

Question 6 can be solved using the same formula, but let

[tex]A_0=18260\\r=0.025\\p=\frac{12}{4}=3\\t_1=1\\t_2=2[/tex]

So,

[tex]A_t=18260(1+\frac{0.025}{3})^1\\A_t=18260(\frac{121}{120})^1\\A_t=18412.17[/tex]

The first-period interest would be 18412.17-18260=152.17

For the second-period, use [tex]t_2[/tex]:

[tex]A_t=18260(1+\frac{0.025}{3})^2\\A_t=18260(\frac{121}{120})^2\\A_t=18260(1.02)\\A_t=18565.60[/tex]

The second-period interest would be 18565.60-18412.17=153.43

The total pressure experienced by a diver working 15m below surface of sea is 150000 Pa.

Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed.

We need to find the total pressure experienced by a diver working 15m below surface of sea.

P = h·ρ·g

P = pressure

h = depth = 15 m

ρ = density = 1g/cm³=1000kg/m³

g = acceleration due to gravity = 10 m/s²

Substitute the values in the formula of total pressure.

P=1000×15×10

P=150000Pa

Hence, 150000Pa is the total pressure experienced by a diver working 15m below surface of sea.

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In order to regain the amount of water Joe losed during practice he should drink 10 cups of water.

A pound is equivalent to 453.59 mg, whereas a cup is equivalent to 236.59 ml.

You may roughly calculate that 2 cups equal 1 pound of water. The density should be 1 mg/ml if the fluid is mostly water.

The number of cups will be,

6 pounds * 453.59 (mg/pounds) * (1mg/ml) / (236.59 ml/cups)

= 10 cups .

Water is a crucial component for all living things, including people and other animals. Naturally, the water must go somewhere when it ascends the plant. Water loss will result from water evaporation (transpiration in plants)

Our breath, skin, urine, and sweat all cause water loss. A person's body will typically consume 2.5 L of water every day and expend the same amount. Your body will "inform you" you are thirsty and need to drink water if you get dehydrated (Figure 5). You have undoubtedly also noticed that when you drink less water, your pee is more concentrated.

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The improper fraction 7/8 has no value in the options given

To do this, we must divide the dividend by the divisor in order to change an improper fraction to a mixed number. After division, the acquired quotient becomes the whole numerals, the remainder becomes the new numerator, and the denominator remains the same, resulting in a mixed number.

To convert 7/8 into decimal number;

7/8 = 0.875

2 1/2 = 2.5

1 5/8 = 1.625

4% = 0.04

5 5/8 = 5.625

In the given options, none of them has a value of 7/8

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Percent decrease from 100 to 82 is 18% decrease.

Calculating the % decrease from 100 to 82,

[tex]\frac{82-100}{100}[/tex]×100%

[tex]\frac{-18}{100}[/tex]×100%

on simplifying we get,

-18%

here, negative sign indicates that there is a decrease of percentage.

Hence, we get 18% decrease from 100 to 82.

How to calculate Percent decrease?

Do the % growth and reduction calculations. By dividing the new number by the initial value, the percentage is computed.

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Answer:All I know is that it’s not < or > but It might be ≤

Step-by-step explanation: Bye the way, you can only give brainliest when there is two questions.

[tex]\leq[/tex]

Step-by-step explanation:

The missing statements and reasons to proof that ∠1 is supplementary to ∠3 are:

S1: Line m is parallel to line n.

S2: ∠1 = ∠2

R3:  Corresponding angles postulate

R5: Supplement Postulate

S7:  m∠1 + m∠3 = m∠2 + m∠3

What are Supplementary Angles?

Supplementary angles, when added together will give us a sum of 180°.

Linear pair angles and corresponding angles are supplementary.

Thus, to prove that ∠1 is supplementary to ∠3:

We are given that lines m and n are parallel.

∠1 and ∠3 are corresponding angles.

So therefore, ∠1 = ∠3 by the corresponding angles postulate.

∠2 and ∠3 are linear pair, their sum therefore equals 180° based on the definition of supplementary angles.

Based on the substitution property, we have the following:

m∠2 + m∠3 = m∠1 + m∠3

m∠1+m∠3=180°

Therefore, ∠1 is supplementary to ∠3 based on the definition of supplementary.

The missing statements and reasons to proof that ∠1 is supplementary to ∠3 are:

S1: Line m is parallel to line n.

S2: ∠1 = ∠2

R3:  Corresponding angles postulate

R5: Supplement Postulate

S7:  m∠1 + m∠3 = m∠2 + m∠3

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Using the Cramer's Rule, the solution of the given system of equation is (-17/11, 48/11)

The given system of equations are

10x+4y=2

-6x+2y=18

Solving the equations by using Cramer's rule.

We know that, the solution of a system of linear equations in two unknowns

a(1)x+b(1)y = c(1)

a(2)x+b(2)y = c(2)

is given by ∆x=∆1, and ∆y=∆2.

where,

[tex]\Delta=\text{det}\left [ \begin{matrix} a(1)&b(1) \\ a(2) & b(2)\end{matrix} \right ], \Delta(1)=\text{det}\left [ \begin{matrix} c(1)&b(1) \\ c(2) & b(2)\end{matrix} \right ]\text{ and }\Delta(2)=\text{det}\left [ \begin{matrix} a(1)&c(1) \\ a(2) & c(2)\end{matrix} \right ][/tex]

Since the given equations are;

10x+4y=2

-6x+2y=18

Now,

[tex]\Delta=\text{det}\left [ \begin{matrix} 10&4 \\ -6 & 2\end{matrix} \right ][/tex]

∆ = [(10×2)-(-6×4)]

∆ = 20+24

∆ = 44

[tex]\Delta(1)=\text{det}\left [ \begin{matrix} 2&4 \\ 18 & 2\end{matrix} \right ][/tex]

∆(1) = [(2×2)-(18×4)]

∆(1) = 4-72

∆(1) = -68

[tex]\Delta(2)=\text{det}\left [ \begin{matrix} 10&2 \\ -6 & 18\end{matrix} \right ][/tex]

∆(2) = [(10×18)-(-6×2)]

∆(2) = 180+12

∆(2) = 192

By Cramer's Rule,

∆x = ∆(1)

44 × x = -68

x = -68/44

x = -17/11

Now,

∆y = ∆(2)

44 × y = 192

y = 192/44

y = 48/11

Hence, the solution of the given system of equation is (-17/11, 48/11).

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The right question is:

Solve the system if possible by using Cramer's rule. If Cramer's rule does not apply, solve the system by using another method. Write all numbers as integers or simplified fractions.

10x+4y=2

-6x+2y=18

To get a number point 1 is impossible for any of the team to reach at the end of the described tournament.

As given in the question,

Total number of footballs teams = 3

Each team plays once with other team

Let three teams are Team1, Team2, and Team3

Team1 plays with Team2 and Team3

Team2 will play with Team3

Winning points = 3

Losing team points = 0

Withdraw teams points = 1

To reach in finals suppose Team1 plays with Team2 and Team3 and win

Points of team1 = 3 + 3

                         = 6points

As team plays once with other team , Team1 is out of the game.

Team2 and Team3 play with each other

To reach at the end of the tournament one team has to win let it be Team2

Points of Team2 = 3

Points of Team3 = 0

No withdraw game is possible to reach into finale.

Therefore, point 1 is impossible for any team to reach at the end of the tournament.

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The vertex (0,2) of the parabola's vertex shape, which can expand upward or downward, equals (x - 0)² + 2.

What is parabola?

Any point on a parabola is at an equal distance from both the focus, a fixed point, and the directrix, a fixed straight line. A parabola is a U-shaped plane curve.

What is a vertex form of an equation?

An equation's conventional vertex form is written as:

f(x) = (x-h)² + k where;

(h, k) is the vertex

Vertex (0,2) should be replaced in the equation's vertex form.

f(x) = (x - 0)² + 2

As a result, vertex (0,2) of the parabola with an opening up or down is equal to (x - 0)² + 2.

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When 36 reindeer are chosen at random, the probability that the mean weight is less than 100 kg is 0.1492.

A standard error is the standard deviation of its sampling distribution or an interpretation of that standard deviation.

Given,

Mean of the weights = 102.4 kg

Standard deviation = 13.9 kg

To determine the probability that the mean weight of 36 reindeer will be less than 100 kg, first compute the standard error using the formula,standard error, [tex]\sigma_x=\frac{\sigma}{\sqrt{n}}[/tex]

Where, [tex]\sigma[/tex]=standard deviation

n= number of reindeer

substitute the values in the formula,

[tex]\sigma_x=\frac{13.9}{\sqrt{36}}\\\\\sigma_x=2.31667[/tex]

Now,

[tex]P(x < 100)=P(x < \frac{100-102.4}{2.316})\\\\=P(z < -1.04)[/tex]

from z-score table,

=0.1492

Thus, the probability the their mean weight is less than 100 kg is 0.1492.

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Your question is incomplete, here is the complete question.

The weight of male reindeer of the R. Santa Claus subspecies is normally distributed with mean 102.4 kg and standard deviation 13.9 kg

if 36 reindeer are randomly selected, what is the probability their mean weight is less than 100kg?

Theres no point 'Z', so i'm gussing you want the angle of <KLJ?

<K and <M are the same, therefore <M = 130

<J + <K + <M + <L = 360

130 + 130 = 260,  360 - 260 = 100

<J and <L are the same

<MJK = 50 and <KLM = 50

<KLM/2 = <KLJ

50/2 = 25

Answer:

See attached image

Step-by-step explanation:

You can graph lines on a website called desmos graphing calculator!

Answer:

Step-by-step explanation:

you replace x with anything you want I will do 0. Then the the first point is (0,-4). Now I am gonna replace x with something else like 4. The second point is (4,8), now connect the two points and you got a line.

Answer:

B

Step-by-step explanation:

Determine the equation of the line given by the table and compare with given options.

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (2, 9) and (x₂, y₂ ) = (7, 19) ← 2 ordered pairs from the table

m = [tex]\frac{19-9}{7-2}[/tex] = [tex]\frac{10}{5}[/tex] = 2 , then

y = 2x + c ← is the partial equation of the line

to find c substitute any ordered pair from the table into the partial equation.

using (6, 17 ), that is x = 6, y = 17 , then

17 = 12 + c ⇒ c = 17 - 12 = 5

y = 2x + 5 ← equation of line from table, with y- intercept c = 5

thus the function with a y- intercept greater than the table line is B

The area of the rhombus is  49√6. Option B

The formula for calculating the area of a rhombus is expressed as;

Area = pq/2

Where;

p and q are the diagonals of the rhombus

From the diagram shown, let's determine the value of p

Using the trigonometric identity;

Tan θ = opposite/adjacent

Substitute the values into the formula, we have;

tan 60 = p/7

Find the value of tan 60 and then substitute

√3 = p/7

cross multiply

p = 7√3

But;

Area = 7√3 × 7√3/2

Area = 49√6

Hence, the value is 49√6

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Answer: 19.71 Million.

The f-distribution's curve is positively skewed. Hence, the statement is true.

We have to check whether the statement is true and false.

The given statement is "The f-distribution's curve is positively skewed."

We can compare two populations using a F statistic thanks to the F distribution. The F distribution can be used to detect whether there is a significant difference in the variance between the means of two populations for ANOVA testing. Regression analysis can also make use of the F distribution to assess how well various models fit together.

The F distribution's graph is always positive and slanted to the right, while the form might vary based on the numerator and denominator degrees of freedom.

The f-distribution's curve is positively skewed. Hence, the statement is true.

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Function representing the sequence will be f(n) = (23 - 3n

The first five terms of an arithmetic sequence are as 20, 17, 14, 11, 8....

Let n represents the number of term and f(n) the the term in the sequence.

Then we have to find the function that represents the sequence.

As we know explicit formula of an arithmetic sequence is given by

Or the function representing the sequence will be

f(n) = a + (n-1)d

where a represents first term of the sequence a = 20

and common difference d = 17-20 = (-3).

Now the function which represents this sequence will be

f(n) = 20 + (n-1)(-3) = 20 - 3n + 3 = 23 - 3n

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The point estimate of the proportion of the population adults who think that today's children will be better off than their parents is 0.24.

The point estimate of P, is defined as the proportion of successes in the sample.

P' = X/N ; where X = number of successes; N = total trials.

Here, N = 1000

According to the Child outlook file, number of "yes" = 240.

Hence, P' = 240/1000

P' = 0.24

Therefore, the point estimate of the proportion of the population adults who think that today's children will be better off than their parents is 0.24.

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The number of tractors lent by the first, second and third stations results in a system of three simultaneous equations which indicates;

The first originally station had 39 tractors, the second station had 21 tractors and the third station originally had 12 tractors

Simultaneous equations are a set of two or more equations that have common variables.

Let x represent the number of tractors at the first station, let y represent the number of tractors at the second tractor station, and let z, represent the number of tractors at the third tractor station

According to the details in the question, after the first transaction, we get

Number of tractors at the first station = x - y - z

Number of tractors at the second station = y + y = 2·y

Number of tractors at the third station = z + z = 2·z

After the second transaction, we get;

Number of tractors at the first station = 2·x - 2·y - 2·z

Number of tractors at the second station = 2·y - (x - y - z) - 2·z = 3·y - x - z

Number of tractors at the third station = 2·z + 2·z = 4·z

After the third transaction, we get;

Number of tractors at the first station = 2 × (2·x - 2·y - 2·z) = 4·x - 4·y - 4·z

Number of tractors at the second tractor station = 6·y - 2·x - 2·z

Number of tractors at the third tractor station = 4·z - (2·x - 2·y - 2·z) - (3·y - x - z) = 7·z - x - y

The three equations after the third transaction are therefore;
4·x - 4·y - 4·z = 24...(1)

6·y - 2·x - 2·z = 24...(2)

7·z - x - y = 24...(3)

Multiplying equation (2) by 2 and subtracting equation (1) from the result we get;

12·y - 4·x - 4·z - (4·x - 4·y - 4·z) = 16·y - 8·x = 48 - 24 = 24

16·y - 8·x = 24...(4)

Multiplying equation (3) by 2 and multiplying equation (2) by 7, then adding both results, we get;

14·z - 2·x - 2·y = 48

42·y - 14·x - 14·z = 168

42·y - 14·x - 14·z + (14·z - 2·x - 2·y) = 48 + 168

40·y - 16·x = 216...(5)

Multiplying equation (4) by 2 and then subtracting the result from equation (5), we get;

40·y - 16·x - (32·y - 16·x) = 216 - 48 = 168

8·y = 168

y = 168/8 = 21

The number of tractors initially at the second station, y = 21

16·y - 8·x = 24, therefore, 16 × 21 - 8·x = 24

8·x = 16 × 21 - 24 = 312

x = 312 ÷ 8 = 39

The number of tractors initially at the first station, x = 39

7·z - x - y = 24, therefore, 7·z - 39 - 21 = 24

7·z = 24 + 39 + 21 = 84

z = 84/7 = 12

The number of tractors initially at the third station, z = 12

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An Amazon package shipped to Samantha. with height of 15cm, length of 100cm, and width of 20 cm, the volume of the package is

Volume of a box is calculated by the product of length, width and height OR area multiplied by height

The area is solve by the product of length and width

area = length * width

length = 100  

width = 20

area = 100 * 20

area = 2000 square cm

volume =  area * height

volume = 2000 * 15

volume = 30 000 cubic cm

The volume of the package is 30 000 square cm

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The roots of x² - 9x + 38 are x = (9 + i√71 )/ 2 and x = (9 - i√71 )/ 2

Polynomial is an equation written as the sum of terms of the form kx^n.

where k and n are positive integers.

We have,

x² - 9x + 38 = 0

It is in the form of ax² + bx + c

a = 1

b = -9

c = 38

Using the determinant formula to find the roots.

x = -b ± √(b² - 4ac) / 2a

x = 9 ± √(81 - 152) / 2

x = 9 ± i√71 / 2

x = (9 + i√71 )/ 2 and x = (9 - i√71 )/ 2

Thus,

The roots are x = (9 + i√71 )/ 2 and x = (9 - i√71 )/ 2

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Explanation of why Priya's conclusion is correct.

What is a function?

An association between a number of inputs and outputs is called a function. Exactly one output is connected to each input in a function, which is an association of inputs. Every function has a range, co-domain, and domain.

Given the functions;

Simplifying,

f(x)=10x² and

g(x)=6x

The coefficient of variable x :

10 and 6,

where 10> 6.

And the value of x:

x² > x, for all x.

As x continues to grow, the values of f will be greater than the values of g.

Therefore, Priya's conclusion is correct.

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The system of equations is:

3a + 2r + 7b = 21

2a + 6r + b = 29

a + 4r + 5b = 23

What is an equation?

An equation is a mathematical statement that proves two mathematical expressions are equal in algebra, and this is how it is most commonly used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated.

a = price of apples

r = price of oranges (I used r instead of letter o since o can be confused with zero)

b = price of bananas

Sally went to the grocery store and bought 3 lbs. of apples, 2 lbs. of oranges, and 7 lbs. of bananas for $21.

3a + 2r + 7b = 21

Kevin bought 2 lbs. of apples, 6 lbs. of oranges and 1 lb. of bananas for $29.

2a + 6r + b = 29

Heather bought 1 lb. of apples, 4 lbs. of oranges and 5 lbs. of bananas for $23.

a + 4r + 5b = 23

The system of equations is:

3a + 2r + 7b = 21

2a + 6r + b = 29

a + 4r + 5b = 23

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The number that must be multiplied by each side of the equation 2/5x=10 to produce the equivalent equation is x = 4.

An equation is a statement that illustrates the variables given. In this case, two or more components are taken into consideration to describe the scenario. It should be noted that equivalent equations are the same.

Algebraic equations with equivalent solutions or roots are called equivalent equations. An equivalent equation is one that is created by adding or subtracting the same quantity or expression from both sides of a given equation. An equation is equivalent if both sides are multiplied or divided by the same non-zero number. If two systems of equations have the same solution, they are equivalent.

The equation is illustrated as:

2/5 = x/10

Cross multiply

5x = 2 × 10

5x = 20

Divide

x = 20 / 5

x = 4

The value or x is 4.

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The value of (a) r that make sense is 6 in. and (b) the value of A that make sense is 113.1 in²

You should understand that the pizza is fit inside the square box making all circumference of the circle to touch all the sides of the square box

The quadratic function reads

A= πr²

Where A= Area of circle,

π = 22/7

and r= radius of the circle

A= (22/7)*6

Width of the box is 12

Therefore 12/2 = r=6

A= (22*6*6)/7

A=113.1 in²

In conclusion, he value of (a) r that make sense is 6 in. and (b) the value of A that make sense is 113.1 in²

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