exercise 28 a sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.52 mpa and a sample standard deviation of 0.78 mpa.

Answers

Answer 1

A 95% % lower confidence bound for the true average proportional limit stress of all such joints is 8.01.

In the given question, a sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.52 mpa and a sample standard deviation of 0.78 mpa.

We have to calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints.

Sample size: n = 13

Sample mean: x’ = 8.52 mps

Sample standard deviation: s = 0.78 mps

95% lower confidence bound for the true average proportional limit stress of all such joints

Level of Significance (α) = 1-95% = 5% = 0.05

α/2 = 0.025

So the value of t(α/2) = 1.8

The confidence interval = x’± t(α/2)*s/√n

Now putting the value:

The confidence interval = 8.41± (1.8)*(0.78)/√12

The confidence interval = 8.41± (1.8)*(0.226)

The confidence interval = 8.41± 0.4068

The confidence interval = (8.41- 0.4068, 8.41+ 0.4068)

The confidence interval = (8.01, 8.82)

A 95% % lower confidence bound for the true average proportional limit stress of all such joints is 8.01.

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The right question is:

A sample of 12 joint specimens of a particular type gave a sample mean proportional limit stress of 8.41 mpa and a sample standard deviation of 0.78 mpa.

Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.)


Related Questions

Given: ABCD is a parallelogram with AE = 9x−5, AC = 14x + 34. Find AC

Answers

The value of AC according to given equation of Parallelogram is 188 units.

What is parallelogram?

In elementary geometry, a parallelogram may be a  quadrilateral with 2 pairs of parallel sides. the alternative or facing sides of a quadrangle square {measure} of equal length

Main body:

according to question:

AE = 9X-5

AC = 14X+34

as E is midpoint of AC so , we can say

2AE = AC

2(9x-5)= 14x+34

18x-10= 14x+34

4x = 44

x = 11

Now we need to find AC = 14x+34

                                         = 14*11+34

                                         = 188 units

Hence the value of AC according to given equation of Parallelogram is 188 units.

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A train travels at 80 miles per hour. An equation can be written that compares the time (t) with the distance (d). What is the domain and range?

1. The domain is distance (d) and the range is time (t).

2. The domain is time (t) and the range is distance (d).

3. The domain is time (t) and the range is 80.

4. The domain is 80 and the range is time (t).

Answers

The required answer is the domain is time (t) and the range is a distance (d) i.e. Option 2.

What are domain and range?

The value range that can be plugged into a function is known as its domain. In a function like f, this set represents the x values f(x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.

From the given question, and the above definition of domain and range,

the time (t) acts as an x-values or input value and the distance (d) acts as a y-value or output value

Hence, the domain is time (t) and the range is a distance (d) i.e. Option 2.

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