Explain how the iron pipes change into rust?

Answer:

C

Explanation:

cause i'm smart

Answer:

D

Explanation:

Because it says tree roots breaking rocks into smaller rocks.

Hope this helped!

Answer:

Decrease occur in the amount and flow of water bodies.

Explanation:

There is decrease in the amount and flow of water from water bodies such as rivers and lakes etc occur when the river is diverted from large water bodies because the water flows to the diverted sides and decrease occurs in the amount of water in the rivers and lakes. Those regions from where this river passes can also be negatively affected due to low amount of water they receives for their daily needs or for cultivation of crops so we can say that this diversion has adverse effect on other populations.

Answer:

B, C

Explanation:

Hope it helps i read it all

Answer:

Explanation:

Heat and temperature are two different but closely related concepts. Note that they have different units: temperature typically has units of degrees Celsius ( ∘ C ^\circ\text C ∘Cdegrees, start text, C, end text) or Kelvin ( Kstart text, K, end text), and heat has units of energy, Joules ( Jstart text, J, end text).

Answer:

The first one is balanced. The second one is not.

Explanation:

The first one is balanced because there are the same amount of elements on the reactant side as there are on the product side. The second one is not balanced because there are not the same amount of elements on the reactant side as there are on the product side. Therefore, it is not balanced

More Detailed: first example

Reactant side (left of arrow)

H: 2

C: 1

O: 3

Product side (right of arrow)

H: 2

C: 1

O: 3

More detailed: second example

Reactant side:

Na: 1

O: 1

H: 1

C: 1

Product side:

Na: 2

O: 4

H: 2

C: 1

the variables needed to balance this equation is 2,1, 1, 1.

Answer:

Option A:

Dig into the zone of aeration

Explanation:

Within the lithosphere of the earth's surface, the zone of aeration is the zone directly above the water table, with a lot of pore spaces within the rocks. These pore spaces contain air and water, which can be used to water the cows.

Once the zone of aeration has been dug into, the farmer can tap into the underground reserve of water, which is stored within the pores of rocks. This water can now sip into the hole that was dug up by the farmer, forming a pond for the cows.

Answer:

15 km/hour

Explanation:

You need to find how fast he was going per hour.

Answer: 15

Divide. 60 ÷ 4

This gives us 15. So, Alex was going 15 mph

Answer:

mi no speak espanol

Explanation:

Answer:

A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.

The Answer Is Sample A

Density -

[tex]density = \frac{mass}{volume} [/tex]

Input The Formula For Both Equations To Find Density.

Sample A -

[tex]d = \frac{40}{10} [/tex]

[tex]d = 4[/tex]

Sample B -

[tex]d = \frac{45}{15} [/tex]

[tex]d = 3[/tex]

0001 M HCl is the same as saying that 1 *10-4 moles of H+ ions have been added to solution. The -log[. 0001] =4, so the pH of the solution =4.

Answer:1 answer number 1

Explanation:

Answer:

0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

H3PO4 + Ba(OH)2 --> Ba3(PO4)2 + H2O

so, (A) H2O + Ba3(PO4)2 is your answer.

Answer:

C

Explanation:

Answer:

gO₂ = 32.32 g

Explanation:

In this case, let's write the general equation:

2H₂ + O₂ -------> 2H₂O

In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.

According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:

gO₂ = 36.36 - 4.04

Hope this helps

Answer:

[tex]from \: avogadros \: hypothesis \\ 1 \: mole \: of \: nitrogen \: reacts \: with \: 3 \: moles \: of \: hydrogen \\ 3 \: litres \: of \: nitrogen \: react \: with \: ( \frac{3 \times 3}{1} ) \\ 9 \: litres \: of \: hydrogen[/tex]

Answer:133.4

c

m

3

Explanation: Explanation:

Molarity is number of moles of solute divided by number of litres of solution.

M

=

n

V

Rearrange for V to give

V

=

n

M

Number of moles of KCl is the mass divided by the molar mass of KCl which is 75.5 g/mol, so (5/75.5) = 0.0667 moles.

Now plug in the numbers:

V

=

n

m

=

0.0667

0.5

=

0.1334

litres

So you need to add 0.1334 litres of 133.4

c

m

3

of water.

(NB: symbol for molarity is upper case M. m is metres).

Answer:

Explanation:

false

Answer:

option d) is the correct answer

Answer:

164.088 g/mol

Explanation: hope this helps

Answer:

Calcium nitrate

Explanation:

164.088 g/mol

give me the brainliest plss

Answer: There is 0.8 liters (L) of water required to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Explanation:

Given: [tex]M_{1}[/tex] = 0.5 M        

[tex]V_{1}[/tex] = 4800 mL

Convert mL into L as follows.

[tex]1 mL = 0.001 L\\4800 mL = 4800 mL \times \frac{0.001 L}{1 mL}\\= 4.8 L[/tex]

[tex]M_{2}[/tex] = 3 M

Formula used to calculate the volume of water required as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula.

[tex]M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 4.8 L = 3 M \times V_{2}\\V_{2} = \frac{0.5 M \times 4.8 L}{3 M}\\= 0.8 L[/tex]

Thus, we can conclude that 0.8 liters (L) of water need to be added to prepare 4800mL of 0.5M NaCl from a 3M NaCl stock solution.

Answer:

the volume is 18.45 L

Explanation:

The computation of the volume when the temperature is increased to 60.0 K is shown below:

Since the gas occupied 12.3 L at a temperature of 40.0 k

And, the volume when the new temperature is 60.0 k

So, the volume is

= 60.0 k × 12.3 L ÷ 40.0 k

= 18.45 L

hence,  the volume is 18.45 L

Answer:

Explanation:

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