Explain what forces act on human body in equilibrium.​

Answers

Answer 1
“In mechanics, equilibrium has to do with the forces acting on a body. When no force is acting to make a body move in a line, the body is in translational equilibrium; when no force is acting to make the body turn, the body is in rotational equilibrium. A body in equilibrium at rest is said to be in static equilibrium.”

Related Questions

Bicyclist travels at an average velocity of 11.2 km/h [W]. How far will the bicyclist travel in 175 minutes?

Answers

Answer:

32.67km

Explanation:

~= round off

11.2km/h~3.11m/s

175minutes=10500s

10500*3.11~32, 666.67m

=32.66667km

~ 32.67km

A car drives 150 km SE and then 50 km due N. What is the car's displacement?

Answers

Answer:

If the car travels 150 kilometers to the Southeast, and then 50 kilometers to the North, it is understood that the car does not travel the same way out as it does back. Therefore, the car's displacement will be the sum of both distances traveled, that is, 150 + 50, which is equal to 200. Therefore, the car traveled about 200 kilometers from its starting point.

Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.

Answers

Answer:

v₃ = 1.625 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.

Since the collision is inelastic, the two bodies are joined after the collision.

P = m*v [kg*m/s]

m = mass [kg]

v = velocity [m/s]

where:

P = lineal momentum [kg*m/s]

Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.

Pbefore = Pafter

(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃

where:

m₁ = mass one = 5 [kg]

v₁ = velocity of the mass one = 2 [m/s]

m₂ = mass two = 3 [kg]

v₂ = velocity of the mass two = 1 [m/s]

v₃ = velocity of the combined masses after the collision [m/s]

Now replacing we have:

(5*2) + (3*1) = (5 + 3)*v₃

10 + 3 = 8*v₃

v₃ = 13/8

v₃ = 1.625 [m/s]

How long would it take a 500. W electric motor to do 15010 J of work?

Answers

time = energy / power = 15010 / 500 = .... seconds

Moderate injuries are generally __________.
A.
life-threatening
B.
soft tissue injuries
C.
bumps and bruises
D.
too serious for first aid


Please select the best answer from the choices provided.

A
B
C
D

Answers

Answer:

B. soft tissue injuries

Explanation:

i took the test on edge and its really the only one that would make sense if you payed attention to the lesson  :)

As the rate of radioactive decay becomes smaller half life become...

Answers

the decay half-life of a radioactive material can be changed. Radioactive decay happens when an unstable atomic nucleus spontaneously changes to a lower-energy state and spits out a bit of radiation. This process changes the atom to a different element or a different isotope.

Find an expression for the center of mass of a solid hemisphere, given as the distance R from the center of the flat part of the hemisphere. Express your answer in terms of R. Express the coefficients using three significant figures.

Answers

Answer:

z_c = ⅜R

Explanation:

If we assume that the hemisphere has uniform density, we can express the centre of mass as;

z_c = (ρ/M)∫∫∫ z•dV

We know that density(ρ) = mass(M)/volume(V)

Thus, Vρ = M

And volume of hemisphere = 2πr³/3

Thus;

2Vρπr³/3 = M

So;

z_c = (ρ/(2Vρπr³/3))∫∫∫ z•dV

Where r = R in this case.

ρ will cancel out to give;

z_c = (3/(2πr³))∫∫∫_V (z•dV)

In spherical coordinates,

r is radius

Φ = angle between the point and the z − axis

θ = azimuthal angle

Therefore, the integral becomes what it is in the attached image.

I've completed the explanation as well in the attachment.

Can someone please help me with this problem. I’ve tried but I can’t seem to figure it out.

Answers

The last one, Tension = 30N, Normal force = 20 N

Please help with this physics question

Answers

The correct answer is A continúe moving with constant velocity

How many bonds can antimony form?

Answers

Answer:

An antimony can form 3 bonds

Let me know if this helps

Thanks!

:)

Explanation:

Sean, whose mass is 60 kg, is riding on a 5.0 kg sled initially traveling at 8.0 m/s. He brakes the sled with a constant force, bringing it to a stop in 4.0 s. What force does he apply?

Answers

Answer:

130N

Explanation:

according to Newtons second law;

F = ma

F = m(v-u)/t

m is the mass = 60+5 = 65kg

v is the final velocity = 0m/s

initial velocity = 8m/s

time t = 4.0s

F = 65(8)/4

F = 65*2

F = 130N

Hence he applied a force of 130N

A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance traveled by the biker?

100 m

80 m

30 m

48 m

PLZ heeeeelp ​

Answers

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Substituting into the equation;

[tex]a = \frac{6 - 0}{6}[/tex]

[tex]a = \frac{6}{6}[/tex]

Acceleration, a = 1m/s²

To find the distance covered in the first phase;

Solving for distance, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting the values into the equation;

[tex] S = 0(6) + \frac {1}{2}*1*(6)^{2}[/tex]

[tex] S = 0 + \frac {1}{2}*1*36[/tex]

[tex] S = 0.5 *36[/tex]

Distance, S1 = 18m

For the second phase, time T2 = 5 secs;

Mathematically, speed is given by the equation;

[tex]Speed = \frac{distance}{time}[/tex]

Making distance the subject of formula, we have;

[tex]Distance, S = speed * time[/tex]

Substituting into the above equation;

[tex]Distance, S = 6 * 5[/tex]

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

Therefore, the total distance traveled by the biker is 48m.

A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
A) 9.80 Ns
B) 3.50 Ns
C) 7.00 Ns
D) 5.60 Ns
E) 1.40 Ns

Answers

Answer:

The magnitude of the impulse delivered to the baseball is 7.0 Ns

Explanation:

Given;

mass of the foul ball, m = 0.14 kg

initial velocity, u = 40 m/s

final velocity, v = 30 m/s in perpendicular direction

Impulse is given as change in momentum;

initial momentum in horizontal direction, Pi = mu

Pi = 0.14 x 40 = 5.6 Ns

final momentum in perpendicular direction, Pf = mv

Pf = 0.14 x 30

Pf = 4.2 Ns

The resultant impulse is given by;

J² = 5.6² + 4.2²

J² = 49

J = √49

J = 7.0 Ns

Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns

What are the 6 basic machines, and what are they and what can the be, and look like.

Answers

Answer:

Pulleys, levers, inclined planes, wedges, screws, and wheel and axle.

Explanation:

An electron (restricted to one dimension) is trapped between two rigid walls 1.40 nm apart. The electron's energy is approximately 19 eV. (a) What is the quantum number n for the energy state that the electron occupies? (b) Based on the quantum number you found in part (a), calculate a more precise value for the electron's energy in eV), expressed to at least three significant figures. (Use any physical constants or unit conversions to at least four significant figures in your calculations.) _________ eV

Answers

Answer:

a)    n = 9.9       b)      E₁₀ = 19.25 eV

Explanation:

Solving the Scrodinger equation for the electronegative box we get

         Eₙ = (h² / 8m L²2) n²

where l is the distance L = 1.40 nm = 1.40 10⁻⁹ m and n the quantum number

 In this case En = 19 eV let us reduce to the SI system

          En = 19 eV (1.6 10⁻¹⁹ J / 1 eV) = 30.4 10⁻¹⁹ J

          n = √ (In 8 m L² / h²)

let's calculate

          n = √ (8  9.1 10⁻³¹ (1.4 10⁻⁹)²  30.4 10⁻¹⁹ / (6.63 10⁻³⁴)²

          n = √ (98)            n = 9.9

since n must be an integer, we approximate them to 10

b) We substitute for the calculation of energy

        In = (h² / 8mL2² n²

        In = (6.63 10⁻³⁴) 2 / (8 9.1 10⁻³¹  (1.4 10⁻⁹)² 10²

        E₁₀ = 3.08 10⁻¹⁸ J

we reduce eV

      E₁₀ = 3.08 10⁻¹⁸ j (1ev / 1.6 10⁻¹⁹J)

      E₁₀ = 1.925 101 eV

      E₁₀ = 19.25 eV

the result with significant figures is

        E₁₀ = 19.25 eV

b. Interpret Data Solution A has a pH of 1.6.
Solution B has a pH of 4. Which solution
has a greater concentration of hydrogen
ions? Explain.

Answers

Answer:

Solution A has a pH of 6 and solution B has a pH of 8. Which of the following is true regarding the concentration of hydrogen ions in each solution? A) A has 100 times greater H+ concentration than B. B) B has 100 times greater H+ concentration than A. C) A has 7/9 of the H+ concentration of B. D) A has 9/7 of the H+ concentration of B. E) none of these

Explanation:

Hey im super sorry if i get this wrong :)

A horizontal force of 100 N is applied to move a 50-kg cart (initially at rest) across a 10 m level surface. What is the final kinetic energy of the cart?

Answers

The net force on the cart is 100 N in the direction of its motion, so by Newton's second law we can find the acceleration a applied to it:

100 N = (50 kg) a

a = (100 N) / (50 kg)

a = 2 m/s²

The cart starts at rest and travels a distance of 10 m, so that its final velocity v satisfies

v ² - 0² = 2 (2 m/s²) (10 m)

v ²= 40 m²/s²

and so the cart ends up with kinetic energy

KE = 1/2 m v ² = 1/2 (50 kg) (40 m²/s²) = 1000 J

What is the momentum of 100 kg running at 4m/s north?

Answers

The momentum is known as mass x velocity then u should say that it will be 400 kg m/s

If you cannot exert enough force to loosen a bolt with a wrench, which of the following should you do?

Question 5 options:

1.) Tie a rope to the end of the wrench and pull on the rope.
2.) Use a wrench with a longer handle.
3.) You should exert a force on the wrench closer to the bolt.
4.) Use a wrench with a shorter handle.

Answers

Answer:

2.) Use a wrench with a longer handle.

Explanation:

It is suggested to use a wrench with longer handle if you cannot exert enough force to loosen a bolt with a wrench.

In doing this work, the torque which is the force that can turn the screw is not enough;

      Torque  = force x distance

If we increase the distance or the length of the handle, we can generate more torque to overcome the force needed.

At 96° F the saturation density of air is 0.04 kg/m3. If the weather report says the relative humidity is 90 % when the temperature is 96°F, the humidity is

Answers

Answer:

The value is  [tex]H = 0.036 \ kg/m^3[/tex]

Explanation:

From the question we are told that

   The saturation density of air is [tex]\rho = 0.04 \ kg/m^3[/tex]

   The temperature for this saturation density to occur  [tex]T_s = 96^o F[/tex]

    The relative humidity at this temperature is  [tex]R_h = 90\% = 0.90[/tex]

Generally the relative humidity is mathematically represented as

      [tex]R_H = \frac{H}{\rho}[/tex]

Here H represents humidity

=> [tex]0.90 = \frac{H}{0.04}[/tex]

=>  [tex]H = 0.90 * 0.04[/tex]

=>  [tex]H = 0.036 \ kg/m^3[/tex]

A thin spherical shell has a radius of 0.70 m. An applied torque of 860 N m gives the shell an angular acceleration of 4.70 rad/s2 about an axis through the center of the shell. What is the rotational inertia of the shell about the axis of rotation

Answers

Answer:

[tex]I=182.97\ kg-m^2[/tex]

Explanation:

Given that,

Radius of a spherical shell, r = 0.7 m

Torque acting on the shell, [tex]\tau=860\ N[/tex]

Angular acceleration of the shell, [tex]\alpha =4.7\ m/s^2[/tex]

We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :

[tex]\tau=I\alpha[/tex]

I is the rotational inertia of the shell

[tex]I=\dfrac{\tau}{\alpha }\\\\I=\dfrac{860}{4.7}\\\\I=182.97\ kg-m^2[/tex]

So, the rotational inertia of the shell is [tex]182.97\ kg-m^2[/tex].

Rita wants to make some toast for breakfast, which she knows involves a chemical change to the bread.
She puts a slice of bread in the toaster, but, after 10 minutes, she notices that the sides of the bread are
black. What caused this chemical change to go too far?
A. an increase in temperature
B. a decrease in temperature
C. the size of the bread
D. the type of bread

Answers

Answer:

A

Explanation:

The toaster was too high so its the increase in eat

An artery with cross sectional area of 1 cm2 branches into 20 smaller arteries each with 0.5 cm2 cross sectional area. If the velocity of blood in the thicker artery is v, what is the velocity of the blood in the thinner arteries

Answers

Answer:

The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

Explanation:

To find the velocity of the blood we need to use the continuity equation:

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]   (1)  

Where:

n: is the number of branches

A: is the cross-sectional area

v: is the velocity

For artery 1, we have:

n₁ = 1, A₁ = 1 cm², v₁ = v

For the 20 arteries (2), we have:

n₂ = 20, A₂ = 0.5 cm², v₂ =?

By using equation (1):

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]

[tex] 1 cm^{2}*v = 20*0.5 cm^{2}*v_{2} [/tex]

[tex] v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v [/tex]

Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

I hope it helps you!      

An old-fashioned tire swing exerts a force on the branch and a torque about the point where the branch meets the trunk. If you hang the swing closer to the trunk, this will ____ the force and ____ the torque.

Answers

Answer:

not change, decrease

Explanation:

Torque refers to the measure of the force that enables an object to rotate about an axis.

An old-fashioned tire swing exerts a force on the branch and a torque about the point where the branch meets the trunk. If you hang the swing closer to the trunk, this will not change the force and decrease the torque.

A tire swing when old can have aa small force. An old-fashioned tire swing exerts a force on the branch and a torque about the point where the branch meets the trunk. If you hang the swing closer to the trunk, this will not change, the force and decrease the torque.

It is stated that when the net force and  the net torque are zero,  the block is in static  equilibrium.

IT also state that when the net force is zero,  but the net torque is not  zero, the object is will not be in static equilibrium

 

For one too be able to change angular momentum, a torque must act on it over some timeframe.

Learn more from

https://brainly.com/question/22498107

If you push a heavy box at rest, you must exert some force before it begins to move. Once its moving, you don’t have to as much force. Which of Newton’s three laws explains this?

Answers

Answer:

momentum does

Explanation:

Which action would decrease the strength of attraction between a magnet and an iron object
A. Moving the magnet farther away from the iron object
B. Moving the iron object closer to the magnet
C. Decreasing the number of electrons on the magnet
D. Increasing the number of electrons on the magnet

Answers

Answer:

a. moving the magnet farther away and an iron object.

Explanation:

Answer:A

Explanation:

A p e x

A certain star has a temperature twice that of the Sun and a luminosity 70 times greater than the solar value. What is its radius, in solar units

Answers

Answer:

[tex] R = 2.1R_{\bigodot} [/tex]

                         

Explanation:                          

The radius (R) is related to temperature (T) and the luminosity (L) as follows:    

[tex] L = T^{4} \times R^{2} [/tex]      

By solving the above equation for R we have:

[tex] R = \frac{\sqrt{L}}{T^{2}} [/tex]

With [tex]L = 70L_{\bigodot}[/tex] and [tex]T = 2T_{\bigodot}[/tex] we have:

[tex] R = \frac{\sqrt{70L_{\bigodot}}}{(2T_{\bigodot})^{2}} [/tex]

[tex] R = \frac{\sqrt{70}}{(2)^{2}} [/tex]

[tex] R = 2.1R_{\bigodot} [/tex]

Therefore, the radius is 2.1 times that of the Sun.

I hope it helps you!

Which form of energy has the most potential globally

a) Solar energy

b) Bio energy

c) Wind energy

d) Geothermal energy

Answers

Answer:

i think the answer is solar,

Explanation:

because it is a natural resource im sorry if im wrong

things that affects the demand for electricity

Answers

New inventions like :
Solar panel
Wind mill
And etc .

Full moon is located______

a. farthest from the Sun

b. at a 90 degree angle with the Sun and Earth

c. closest to the Sun

Answers

Answer:

Im going to take an educated guess and say its B.

Explanation:

A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

What is a Full moon?

A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.

When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.

Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

To learn more about the Full moon, refer to the link:

https://brainly.com/question/15032553

#SPJ2

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