Answer:
The circumference is the perimeter, specifically the perimeter of a circle. It can be solved by using the following formula:
C = 2πr
C stands for circumference.
π stands for pi, or 3.14 (rounded).
r stands for radius.
The radius is the distance from the center point of the circle to any point on the circle. It is denoted by the variable, r, as stated above. It is 1/2 of the diameter.
Answer:
the radius is the line from center to perimeter and circumference is the enclosed boundary
Step-by-step explanation:
radius- is any of the line segments from a circle or spheres center to its perimeter
circumference- the enclosed boundary a curved geometric figure, especially a circle
can anyone help me please? 63 over 7-2x3
Answer:
Below,...
Step-by-step explanation:
Your equation:
[tex]\frac{63}{7-(2*3)} =\frac{63}{7-6} =\frac{63}{1}=63[/tex]
Hope it helps,... Chow,...!
18/20-4/12
Show your work
Answer:
17/30 (0.56)
Step-by-step explanation:
18/20-4/12
Reduce the fraction with 2 and 4: 9/10-1/3
Write all numerators above the least commmon denominator 30: 27-10/30
Subtract: 27-10/30 = 17/30
f(x)=|-3x+4|+5 help?
Answer:
This will plot as an upward "V" with the vertex at x = 4/3, y = 5
Step-by-step explanation:
The absolute value will mean that y can only be positive. y will be at a minimin when the absolute value is zero. To determine that find the x that makes it zero, so
-3x + 4 = 0
-3x = -4
x = 4/3
which makes y = 5 (the minimin)
Put the following equation of a line into slope-intercept form, simplifying all
fractions.
12x + 10y = -60
Answer:
Submit Answer
PLS HELP ASAP
Answer:
here's the answer to your question
How can i solve this?
Answer:
Perimeter is (8x + 4) units.
Step-by-step explanation:
[tex]{ \sf{perimeter = side + side + side}} \\ { \sf{p = (2x + 1) + (7x - 2) + (5 - x)}} \\ { \sf{p = (2x + 7x - x) + (1 - 2 + 5)}} \\ { \sf{p = 8x + 4}}[/tex]
Evaluate the expression when y = -2
- 8y2
I believe this is the expression:
[tex] \displaystyle \large \boxed{ - 8 {y}^{2} }[/tex]
Since we want to evaluate it when y = -2, simply substitute y = -2 in the expression.
[tex] \displaystyle \large{ - 8 {( - 2)}^{2} }[/tex]
Any negative number squared will result in positive, refer below:
[tex] \displaystyle \large{ {( - a)}^{2} = {a}^{2} } \\ \displaystyle \large{ {( - 2)}^{2} = {2}^{2} } \longrightarrow \boxed{4} \\ [/tex]
Hence,
[tex] \displaystyle \large{ - 8(4) = - 8 \times 4} \\ \displaystyle \large \boxed{ -32}[/tex]
Answer:
-32
Step-by-step explanation:
Replace the variable y with -2 in the expression giving -8(-2)^2
Then, square -2 giving us (positive) 4
Lastly, multiply -8 with 4 and get -32 as our answer
(Hopefully this helped you! Feel free to ask again if you need more help. Tell me if the solution is unclear to you)
Which statements about the function are true? Select two options.
The vertex of the function is at (1,–25).
The vertex of the function is at (1,–24).
The graph is increasing only on the interval −4< x < 6.
The graph is positive only on one interval, where x < –4.
The graph is negative on the entire interval
–4 < x < 6.
Answer:
Step-by-step explanation:
x-intercept(s):
( − 4 , 0 ) , ( 6 , 0 )
y-intercept(s):
( 0 , − 24 )
Answer:1 and 2
Step-by-step explanation:right on edge
Find the sum Sn of the first n terms from the given sequence.
1, 1+2, 1+2+3, 1+2+3+4, ...
Please show your work and use Sigma Notation too. Thank you!
The Sequence:
1 , 1+2 , 1+2+3 , 1+2+3+4, ...
here, every term is an AP. finding the general formula for the sum of the elements of each term is:
Sₙ = [tex]\frac{x}{2}(2a + (x-1)d)[/tex] [where x = number of term, a = first term and d = common difference]
here, the first term is always 1 and so is the common difference.
Sₙ = [tex]\frac{x}{2}(2 +x-1)[/tex]
Sₙ = [tex]\frac{x}{2}(1 +x)[/tex] = [tex]\frac{1}{2}(x + x^{2})[/tex]
which is the formula for a general term in our series
now, we need to find the sum of the first n terms of this series
[tex]\displaystyle\sum_{x=1}^{n} [\frac{1}{2}(x + x^{2})][/tex]
[tex]\displaystyle\frac{1}{2} [\sum_{x=1}^{n} (x) + \sum_{x=1}^{n}(x^{2})][/tex]
in this formula, for the first term, it's just an AP from x = 1 to x = n
for the second term, we have a general formula [tex]\frac{n(n+1)(2n+1)}{6}[/tex]
[tex]\frac{1}{2}[\frac{n}{2}(2a + (n-1)d)+ \frac{n(n+1)(2n+1)}{6} ][/tex]
in this AP (first term), the first term and the common difference is 1 as well
[tex]\frac{1}{2}[\frac{n}{2}(2 + n-1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]
[tex]\frac{1}{2}[\frac{n}{2}(n+1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]
[tex][\frac{n}{4}(n+1)+ \frac{n(n+1)(2n+1)}{12} ][/tex]
[tex]\frac{n}{4}(n+1) [1+\frac{(2n+1)}{3} ][/tex]
[tex]\frac{n}{4}(n+1) [\frac{(3+2n+1)}{3} ][/tex]
[tex]\frac{n}{4}(n+1) [\frac{(2n+4)}{3} ][/tex]
[tex]\frac{n}{2}(n+1) [\frac{(n+2)}{3} ][/tex]
[tex]\frac{n(n+1)(n+2)}{6}[/tex]
which is the sum of n terms of the given sequence
Simplify each expression
Answer:
[tex]3. \: \: ( \frac{7}{8} ) ^{2} = \frac{ {7}^{2} }{ {8}^{2} } = \frac{49}{64} = 0.765 [/tex][tex]5. \: \: 8 + 5(7) = 8 + 35 = 43[/tex]
I hope I helped you^_^
At Bob's binders, a set of 3 notebooks costs $4.20. At Pam's Paper Place a set of 4 notebooks costs $5.20. What is the unit price of the notebooks at each store? Which is the better buy?
Step-by-step explanation:
At Bob's binders, the unit price = $4.20 ÷ 3
= $1.40
At Pam's Paper Place the unit price = $5.20 ÷ 4 = $1.30
the better buy is at Pam's Paper place
Find the value of x,y and z
Answer:
hope it helps, appreciate if you can give brainliests
[tex]\frac{\sqrt{a+b} }{\sqrt{a-b} } +\frac{\sqrt{a-b} }{\sqrt{a+b} }[/tex]
Answer:
[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]
Step-by-step explanation:
Step-by-step explanation:
[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]
[tex]thank \: you[/tex]
Find the equivalent equation that results from adding 5 to both sides first and then multiplying
both sides by 2. Show each step. You do not have to solve the equation at the end.
Answer:
5d = 30
Step-by-step explanation:
1. first you need to add 5 to both sides
d-4+5 = 2+5
2. then you need to combine like terms
d+1 = 7
3. after that you have to multiply both sides by 5
5(d+1) = 7(5)
4. simplify
5d + 5 = 35
-5 -5
5d = 30
A ball is thrown into the air with an upward velocity of 80 feet per second. The function
h = -16t2 + 80t models the height h, in feet, of the ball at time t, in seconds. When will the ball reach the ground?
after 3 seconds
after 4 seconds
after 5 seconds
after 6 seconds
Best explanation gets Brainliest!!
Answer:
After 5 seconds
Step-by-step explanation:
One is given the following expression to model to the flight path of a ball:
[tex]h=-16t^2+80t[/tex]
In this problem, one is asked to find the time at which the ball lands on the ground. The easiest way to do so is to factor the expression. Take out factors that both terms have in common. The one will set the equation equal to zero, as this is the height at which one wants to find the time for. Finally, use the zero product property to solve. The zero product property states that any number times zero equals zero. Apply these ideas to the given function:
[tex]h=-16t^2+80t[/tex]
Factor the expression; both terms have a common factor of (-16t):
[tex]h=-16t^2+80t[/tex]
[tex]h=-16t(t-5)[/tex]
Set the equation equal to zero to solve for when the ball has a height of zero or rather lands on the ground:
[tex]h=-16t(t-5)[/tex]
[tex]0=-16t(t-5)[/tex]
Now use the zero product property, this states that any number times zero equals zero. Set each of the factors equal to zero, and solve to find the value of (t) for which the factor will equal zero:
[tex]0=-16t(t-5)[/tex]
[tex]0=-16t[/tex] [tex]t - 5 =0[/tex]
Solve for the value (t) using inverse operations,
[tex]0=-16t[/tex] [tex]t - 5 =0[/tex]
(divide by (-16) (add (5))
[tex]0=t[/tex] [tex]t=5[/tex]
As one can see, the ball started on the ground, therefore at (0) seconds, its height was (0). Then, after (5) seconds the ball landed on the ground, therefore, after (5) seconds its height was again (0).
Distance between (-2,-2) and (8,-6)
Answer:
Distance btw (-2, -2) and (8, -6) is (10, -4)
Step-by-step explanation:
I. Give (-2, -2) is A and (8, -6) is B
B - A = 8 - (-2) in x
= -6 - (-2) in y
So B - A = 10, -4
II. You can prove the answer by A.value + (10, -4) = B.value
Hope that help :D
Hi ;-)
[tex]\text{A}=(-2,-2) \ \text{and} \ \text{B}=(8,-6)\\\\|AB|=\sqrt{(8-(-2))^2+(-6-(-2))^2}\\\\|AB|=\sqrt{(8+2)^2+(-6+2)^2}\\\\|AB|=\sqrt{10^2+(-4)^2}\\\\|AB|=\sqrt{100+16}\\\\|AB|=\sqrt{116}\rightarrow\boxed{|AB|=2\sqrt{29}} \ (\text{because} \ 116=4\cdot29)[/tex]
If the divisor is 60, what is the least four-digit dividend that would not have a remainder?
Answer:
2400
which is not having any remainder as 2400÷60=40
Step-by-step explanation:
Fimd the hcf of 144,384 and 432 by division method.
48..................
The radius of the circle below is 5 inches. What is the diameter of the circle?
Answer:
10 inches
Step-by-step explanation:
radius = 5 inches
Diameter = radius x 2 = 5 x 2 = 10 inches
whats number 26.
..............................
Answer:
y = 1/3mx + b
Step-by-step explanation:
x = 3(y - b)/m
~Multiply m to both sides
mx = -3b + 3y
~Add 3b to both sides
mx + 3b = 3y
~Divide everything by 3
1/3mx + b = y
y = 1/3mx + b
Best of Luck!
[tex]\\ \rm\longmapsto x=\dfrac{3(y-b)}{m}[/tex]
[tex]\\ \rm\longmapsto mx=3(y-b)[/tex]
[tex]\\ \rm\longmapsto mx=3y-3b[/tex]
[tex]\\ \rm\longmapsto 3y=mx+3b[/tex]
[tex]\\ \rm\longmapsto y=\dfrac{1}{3}mx+b[/tex]
The angle,2Θ, lies in the third quadrant such that cos2Θ=-2/5. Determine an exact value for tanΘ . Show your work including any diagrams if you plan to use them. (3 marks)
Answer:
[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]
Step-by-step explanation:
1. Approach
One is given the following information:
[tex]cos(2\theta)=-\frac{2}{5}[/tex]
One can rewrite this as:
[tex]cos(2\theta)=-0.4[/tex]
Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.
Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]). Substitute the given information into the ratio and simplify.
2. Solve for [tex](cos(\theta))[/tex]
Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).
[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]
Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).
[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]
[tex]-0.4=2(cos^2(\theta))-1[/tex]
Inverse operations,
[tex]-0.4=2(cos^2(\theta))-1[/tex]
[tex]0.6=2(cos^2(\theta))[/tex]
[tex]0.3=cos^2(\theta)[/tex]
[tex]\sqrt{0.3}=cos(\theta)[/tex]
Since this angle is found in the third quadrant its value is actually:
[tex]cos(\theta)=-\sqrt{0.3}[/tex]
3. Solve for [tex](sin(\theta))[/tex]
Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).
[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]
Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).
[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]
[tex]-0.4=1-2(sin^2(\theta))[/tex]
Inverse operations,
[tex]-0.4=1-2(sin^2(\theta))[/tex]
[tex]-1.4=-2(sin^2(\theta))[/tex]
[tex]0.7=sin^2(\theta)[/tex]
[tex]\sqrt{0.7}=sin(\theta)[/tex]
Since this angle is found in the third quadrant, its value is actually:
[tex]sin(\theta)=-\sqrt{0.7}[/tex]
4. Solve for [tex](tan(\theta))[/tex]
One can use the following identity to solve for [tex](tan(\theta))[/tex];
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]
Substitute the values on just solved for and simplify,
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]
[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]
Rationalize the denominator,
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]
[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]
[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]
6x + 3y - 9 when
x = 6, y = 9
Answer:
63
Step-by-step explanation:
6x + 3y - 9
x = 6
y = 9
6(6) + 3(9)
36 + 27
= 63
What is the y-intercept, given the equation: y=x^2+2x−8?
Write your response as an ordered pair.
Answer:
y-intercept is (0, -8)
Step-by-step explanation:
[tex]y = {x}^{2} + 2x - 8[/tex]
At y-intercept, x is zero
substitute x as zero:
[tex]y = {(0)}^{2} + 2(0) - 8 \\ y = 0 + 0 - 8 \\ y = - 8[/tex]
Find the length of the missing side ( nearest tenth
Answer:
43.4 yd
Step-by-step explanation:
[tex]45^{2}[/tex]-[tex]12^{2}[/tex]
2025-144=1881
[tex]\sqrt{1881}[/tex]
43.37049
43.4
A design for a banner includes a striped background. The stripes are colored in the repeating order: yellow, blue, orange, green, and purple. What calor is the 37th stripe?
Answer:
purple.orang.blue.yellow and green
purple.orang.blue.yellow and green
Can you guys help me find a flag that has at least one reflection and a translation in it? If not, then two flags that show these transformations.
This is very urgent and I need to get it done soon, whoever is willing to help me I'll mark you as brainliest. Thank you!
Answer:
The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical
Step-by-step explanation:
The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.
How does reflection across axis work?When a graph is reflected along an axis, say x axis, then that leads the graph to go just in opposite side of the axis as if we're seeing it in a mirror.
If we study it more, you will find that its symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.
If you're reflecting a point (x,y) along x axis, then its abscissa will stay same but ordinates will negate. Thus (x,y) turns to (x, -y)
Similarly, if you're reflecting a point (x,y) along y axis, the resultant image of the point will be (-x,y)
Therefore, The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.
Learn more about reflection;
https://brainly.com/question/12950057
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PLEASE HELP ME!!!
There are 21 squares in all. How many squares are covered? Mark the correct answer.
A:6 B:9 C:12 D:18
Points A, B, and C are collinear. Point B is between A and C. Find the length indicated.
Answer:
TR = 23
Step-by-step explanation:
first we have to find TS, so we subtract 16 from 4 to get 12. then we can add 12 and 11 to get TR
Which number is NOT plotted correctly on the number line?
Write as an algebraic expression five times the sum of a number and 4
Answer:
5(x+4)
Step-by-step explanation:
It's basically asking for the sum of a number and four to be multiplied by 5. Since the sum is made up of the unknown number and four, you'd put four and the unknown number in parenthesis while putting five on the outside, making it 5(x+4).
Please no links because they dont work :).
Answer:
semoga jawapan ini dapat membantu