f(3) = 12 for a geometric sequence that is defined

recursively by the formula f(n) = 0.5 ∙ f(n – 1), where

n is an integer and n > 0.

Write the equation in explicit form.



Answers

Answer 1

Answer:

[tex]f(n) = 96 * 0.5^n[/tex]

Step-by-step explanation:

Given

[tex]f(3) = 12[/tex]

[tex]f(n) = 0.5 * f(n-1)[/tex]

Required

Write as an explicit function

When n = 3, we have:

[tex]f(3) = 12[/tex]

[tex]f(3) = 0.5 * f(3-1)[/tex]

[tex]f(3) = 0.5 * f(2)[/tex]

Substitute: [tex]f(3) = 12[/tex]

[tex]12 = 0.5 * f(2)[/tex]

Solve for f(2)

[tex]f(2) = 12/0.5[/tex]

[tex]f(2) = 24[/tex]

So, we have;

[tex]f(3) = 12[/tex]

[tex]f(2) = 24[/tex]

Since it is a geometric sequence, calculate the common ratio (r)

[tex]r = \frac{f(3)}{f(2)}[/tex]

[tex]r = \frac{12}{24}[/tex]

[tex]r = 0.5[/tex]

Calculate the first term using:

[tex]r = \frac{f(2)}{f(1)}[/tex]

Solve for f(1)

[tex]f(1) = \frac{f(2)}{r}[/tex]

[tex]f(1) = \frac{24}{0.5}[/tex]

[tex]f(1) = 48[/tex]

The explicit function is then calculated as:

[tex]f(n) = f(1) * r^{n-1[/tex] ----nth term of a gp

[tex]f(n) = 48 * 0.5^{n-1[/tex]

Split the exponent

[tex]f(n) = 48 * \frac{0.5^n}{0.5^1}[/tex]

[tex]f(n) = 48 * \frac{0.5^n}{0.5}[/tex]

[tex]f(n) = 96 * 0.5^n[/tex]


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------------------------------------------------------------------------

                                 >  thick, white, pepperoni  

                 White  >  >  thick, white, cheese          

                                 >  thick, white, vegetarian

Thick  > >

                                 > thick, red, pepperoni  

                   Red  >   >  thick, red, cheese

                                 > thick, red, vegetarian

------------------------------------------------------------------------

                                 > thin, white, pepperoni

                  White  >  > thin, white, cheese

                                  > thin, white, vegetarian

Thin  > >

                                > thin, red, pepperoni

                   Red  >  >  thin, red, cheese

                                >  thin, red, vegetarian

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