Factor :2x^(5)-9x^(4)+6x^(3)+22x^(2)-20x-25

Answer:

12

Step-by-step explanation:

All the denominators are factors of 12.

Answer:

x= 4                x = -5

Step-by-step explanation:

3(x – 4)(x + 5) = 0

Using the zero product property

(x – 4)=0      (x + 5) = 0

x= 4                x = -5

What are the solutions to the equation 3(x – 4)(x + 5) = 0?

x = –4 or x = 5

x = 3, x = 4, or x = –5

x = 3, x = –4, or x = 5

x = 4 or x = –5

Answer:

D. x = 4 or x = –5

Step-by-step explanation:

Answer:

The measure of central tendency, mean and median are approximately equal for the boys indicating that the data of the boys is more evenly spread while standard deviation of the girls data is less than those of the boys indicating that the data for the girls is less widely spread.

Step-by-step explanation:

The given data are;

,             1       2       3      4     5      6       7    8      9      10

Girls,    50    32     15    56   81    50     18    81    22    55

Boys,   75     41     25    22    7     0      43    12    45    70

Sorting the data gives;

Girls,     15,   18,     22,   32,  50,   50,   55,  56,    81,  81

Boys,     0,     7,     12,     22, 25,    41,    43, 45,     70, 75

For the even numbered sample data size, the first quartile, Q₁ is found by sharing the data into two and finding the median of the left half which  gives;

10/2 = 5 on each half

The first quartile, Q₁, is the median of the left 5 data points which is the 3rd data point = 22 for girls and 12 for boys

The third quartile, Q₃, is found in similar method to be the 8th data point which is 56 for girls and 45 for boys

The median = 50 for girls and 33 for boys

Therefore, the interquartile ranges are;

IQR = 56 - 22 = 34 for girls, 45 - 12 = 33 for boys

We check for outliers.

Q₁ - 1.5×IQR = 22 - 1.5*34 = -29

Q₃ + 1.5×IQR = 56 + 1.5*34 = 107

We check the mean of both data samples as follows;

Average for the girls = 46

Average for the boys = 34

Standard deviation for girls = 23.99

Standard deviation for girls = 25.43

Therefore, the measure of central tendency is more accurate for the boys indicating that the data of the boys is more evenly spread while the data for the girls is less widely spread.

Answer:

first number after the decimal point

Step-by-step explanation:

after the decimal point is the tenths, hundredths, and thousandths place.

0.1 - tenths

0.09 - hundredths

0.006 - thousandths

Answer:

The answer is 5

Step-by-step explanation:

divide 10 by two and get 5

Answer:

[tex]x = 5[/tex]

Step-by-step explanation:

We have the equation [tex]2x = 10[/tex], we can try and isolate x by dividing both sides by 2.

[tex]2x \div 2 = 10\div2\\x = 5[/tex]

Hope this helped!

Answer:

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747)

Step-by-step explanation:

The given expression is -5·t² + 5·t + 24

To factorize the expression by completing the square method, we equate the expression to zero to get;

-5·t² + 5·t + 24 = 0

WE divide by -5 to get;

t² - t - 24/5 = 0

t² - t = 24/5

t² - t + 1/4 = 24/5 + 1/4

(t - 1/2)² = 5.05

t - 1/2 = ±√5.05

t = 1/2 + √5.05, 1/2 - √5.05

The factorized expression becomes;

(t - 1/2 + √5.05) and (t - 1/2 - √5.05)

Which gives;

(t - 2.747) ×(t - 1.747)

The factorized expression is (-5) × (t - 2.747) ×(t - 1.747).

Answer:

1.7 million in Northern Ireland

Step-by-step explanation:

Simply do the difference between the number of people in the UK, minus the number of people in everywhere else except northern Ireland. That is:

60.2 M - 50.4 M - 5.1 M - 3.0 M = 1.7 M

Answer:

[tex]\boxed{1.7 million}[/tex]

Step-by-step explanation:

Hey there!

To find the amount of people who lived in Northern Ireland in 2005 we need to subtract the total 60.2 mil by the England, Scotland, and Wales people.

50.4 + 5.1 + 3

= 58.5

Now we can set up the following equation,

NI = 60.2 - 58.5

NI = 1.7 million

Hope this helps :)

Answer:

4 ft/sec

Step-by-step explanation:

Hope it helps

Answer:

y = [tex]\frac{1}{4}[/tex] x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

y - 4 = [tex]\frac{1}{4}[/tex] (x - 8) ← distribute

y - 4 = [tex]\frac{1}4}[/tex] x - 2 ( add 4 to both sides )

y = [tex]\frac{1}{4}[/tex] x + 2 ← in slope- intercept form

Answer:

False I think

Step-by-step explanation:

Answer:

The y-values repeat in various functions (for example: quadratic function: y=x²; y=4 for x=2 and for x=-2)  

Answer:

3000 words

Step-by-step explanation:

450 words in 3 minutes is 150 words in 1 minute. 20 minutes = 1 times 20.          

1 minute = 150 words so 150 words times 20 minutes = 3000 words.

Answer:

10

Step-by-step explanation:

How you find LCD (lowest common denominator) is that you have to look at the denominator (the bottom number) and try to find the lowest multiple between both of the numbers that is on the bottom (in this case it is 2 and 5). Sometimes you have to multiply both denominators together to get a LCD.

Example of multiplying two denominators together to get an LCD:

1/3 and 1/13 LCD is 39 because you multiply 3 and 13.

1/5 and 1/4 LCD is 20 because you multiply 5 and 4.

Answer:

81 sq units.

Step-by-step explanation:

Given that Triangles DOG, ION and IDO are congruent and isosceles.

Let Sides NO = IO = DO = GO = [tex]x[/tex] units

Let the sides of squares FLIN, DIES and DRAG = [tex]a[/tex] units

So, NF = FL = LI = NI = IE = ES = SD = DI = DR = RA = AG = GD = [tex]a[/tex] units

Given that perimeter of each of Triangles DOG, ION and IDO = 55 units

Sum of sides of triangle = [tex]2x+a=55 ...... (1)[/tex]

and Perimeter of 11 sided polygon DRAGONFLIES = 127 units

The perimeter of the polygon includes the sides (only outer sides are included):

DR, RA, AG, GO, ON, NF, FL, LI, IE, ES and SD

[tex]2x+9a = 127......(2)[/tex]

Solving equations (2) and (1) by subtracting (1) from equation (2):

[tex]8a = 72\\\Rightarrow a = 9 units[/tex]

Area of a square DRAG = [tex]Side^2[/tex] = [tex]9^2 = \bold{81\ sq\ units}[/tex]

Answer:

81

Step-by-step explanation:

dont ask, i just know

Answer:

88 cm

Step-by-step explanation:

Perimeter = 2πr

=2(14)(22/7)

= 88 cm

Answer:

87.97cm

Step-by-step explanation:

This question is asking to solve for the circumference.

The formula for the circumference of a circle is:  [tex]\pi*diameter[/tex]

To work this out you would first need to multiply the radius of 14 by 2, this gives you 28cm. This is because the radius is half of the diameter.

The final step is to multiply pi by the diameter of 28, this gives you 87.97cm (87.9645943). This is because the formula for the circumference of a circle is [tex]\pi * diameter[/tex].

1) Multiply 14 by 2.

[tex]14*2=28[/tex]

2) Multiply pi by the diameter.

[tex]\pi*28^2=87.97 cm[/tex]

Answer:

LOOK BELOW

Step-by-step explanation:

I would not call the explanation a formula

All you have to do to solve mean or average is add all of the numbers up and divide by the total amount of numbers

so for example

0,2,4,0,2,3,2,8,6  <-------- lets find the mean/average

0+2+4+2+3+2+8+6= 27/amount of numbers

amount of numbers=9

(count the zeros too!)

27/9=3

3 is the mean or average!!!

Answer:

1522km^2

Step-by-step explanation:

To solve this, first convert the percentage to a decimal. That would be .0475.

Now subtract that from 1.0 to get the factor it decreases by. This would be 1-.0475 = .9525

Multiply 2600 x (.9525)^11 = 1522.258 which rounds to 1522 km^2

Answer:

The area will be 1292.98 km² after 11 years.

Step-by-step explanation:

To find what decreases by 4.57% each year in kilometers:

2600 × 4.57/100 = 26 × 4.57

= 118.82 km²

To find the area after 11 years:

118.82 × 11 = 1307.02

2600 - 1307.02 = 1292.98 km²

1292.98 km² is the answer.

Answer:

kinetic energy body when it hits the ground is 98000 joule

1000joule = 1 kilojoule

, kinetic energy body when it hits the ground is 98  kilo-joule

Step-by-step explanation:

conservation of energy states that total energy of a system remains constant.

Potential energy of body = mgh

m = mass

g = gravitational pull = 9/8 m/s^2

h = height

kinetic energy = 1/2 mv^2

where v is the velocity of body

________________________________________

Total energy for this at any point is sum of potential energy and kinetic energy

total energy at height h

v= 0

PE = 250*9.8*40= 98,000

KE = 1/2 m0^2  = 0

total energy at when ball hits the ground

h=0

PE = 250*9.8*0 =

KE = 1/2 mv^2  

_______________________________________\

Applying conservation of energy

Total energy at height h = total energy at ground

98000 = KE

Thus, kinetic energy body when it hits the ground is 98000 joule

1000joule = 1 kilojoule

, kinetic energy body when it hits the ground is 98  kilo-joule

Answer:

d. $50,499

Step-by-step explanation:

Given:

S = 40,000 (1.06)^t

Where,

t=4 years

S=40,000(1.06)^4

=40,000(1.26247696)

=50,499.0784

To the nearest dollar

S=$50,499

The answer is d. $50,499

Answer:

[tex]\dfrac{1}{6561}[/tex]

Step-by-step explanation:

Given the expression [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex], Using the laws of indices to simplify the expression. The following laws will be applicable;

[tex]a^m*a^n = a^{m+n}\\(a^m)^n = a^{mn}\\[/tex]

[tex]a^{-m} = 1/a^m[/tex]

Given [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex]

open the parenthesis

[tex]= (2^{-2})^{-3}(3^{4})^{-3}* (2^{-3})^2(3^2)^2\\\\= 2^{-2*-3}* 3^{4*-3} * 2^{-3*2} * 3^{2*2}\\\\= 2^6 * 3^{-12} * 2^{-6} * 3^4\\\\collecting \ like \ terms\\\\= 2^6 * 2^{-6} * 3^{-12} * 3^4\\\\= 2^{6-6} * 3^{-12+4}\\\\= 2^0 * 3^{-8}\\\\= 1 * \frac{1}{3^8}\\ \\= \frac{1}{6561}[/tex]

[tex](x+3)(x-5)=x^2-5x+3x-15=x^2-2x-15[/tex]

Answer:

Step-by-step explanation:

Use FOIL method

(x + 3)(x - 5) = x*x  + x *(-5)  + 3*x +  3*(-5)

                    = x² - 5x  +3x - 15  {add like terms}

                    = x² - 2x -15

Answer:

Cody should run approximately 19.978 meters along the shore before jumping into the water in order to save the child.Thus,

Step-by-step explanation:

Consider the diagram below.

In this case we need to minimize the time it takes Cody to save the child.

Total time to save the child (T) = Time taken along the shore (A) + Time taken from the shore (B)

The formula to compute time is:

[tex]time=\frac{distance}{speed}[/tex]

Compute the time taken along the shore as follows:

[tex]A=\frac{x}{4}[/tex]

Compute the time taken from the shore as follows:

[tex]B=\frac{\sqrt{70^{2}+(40-x)^{2}}}{1.1}[/tex]

Then the total time taken to save the child is:

[tex]T=\frac{x}{4}+\frac{\sqrt{70^{2}+(40-x)^{2}}}{1.1}[/tex]

Differentiate T with respect to x as follows:

[tex]\frac{dT}{dx}=\frac{d}{dx}[\frac{x}{4}]+\frac{d}{dx}[\frac{\sqrt{70^{2}+(40-x)^{2}}}{1.1}][/tex]

    [tex]=\frac{1}{4}-\frac{1}{1.1}\cdot \frac{(40-x)}{\sqrt{70^{2}+(40-x)^{2}}}[/tex]

Equate the derivative to 0 to compute the value of x as follows:

                              [tex]\frac{dT}{dx}=0[/tex]

[tex]\frac{1}{4}-\frac{1}{1.1}\cdot \frac{(40-x)}{\sqrt{70^{2}+(40-x)^{2}}}=0\\\\\frac{1}{1.1}\cdot \frac{(40-x)}{\sqrt{70^{2}+(40-x)^{2}}}=\frac{1}{4}\\\\4\cdot (40-x)=1.1\cdot [\sqrt{70^{2}+(40-x)^{2}}]\\\\\{4\cdot (40-x)\}^{2}=\{1.1\cdot [\sqrt{70^{2}+(40-x)^{2}}]\}^{2}\\\\16\cdot (40-x)^{2}=1.21\cdot [70^{2}+(40-x)^{2}}]\\\\16\cdot (40-x)^{2}-1.21\cdot (40-x)^{2}=5929\\\\14.79\cdot (40-x)^{2}=5929\\\\(40-x)^{2}=400.88\\\\40-x\approx 20.022\\\\x\approx 40-20.022\\\\x\approx 19.978[/tex]

Thus, Cody should run approximately 19.978 meters along the shore before jumping into the water in order to save the child.

Answer:

The middle of the sailboat is approximately 268.8 feet from the shore.

Step-by-step explanation:

Let the distance from shore to the middle of the boat be represented by x, the angle of elevation of Sandra from the shore to the top of the boat mast  is 7°. Applying the required trigonometric function to this question, we have;

Tan θ = [tex]\frac{opposite}{adjacent}[/tex]

Tan 7° = [tex]\frac{23}{x}[/tex]

⇒  x = [tex]\frac{23}{Tan 7^{0} }[/tex]

       = [tex]\frac{23}{0.12279}[/tex]

      = 268.7515

∴ x = 268.8 feet

The middle of the sailboat is approximately 268.8 feet from the shore.

Each edge of the cube is 20cm. If it stayed on the edges it would need to walk on 3 edges for a total distance of 3 x 20 = 60 cm.

If it walked diagonally across the front face and then one edge it would travel:

Diagonal = sqrt(20^2 + 20^2) = 28.28

Total distance waling a diagonal and then an edge = 28.28 + 20 = 48.28 cm

The shortest distance would be diagonally across the front face then the edge to point B and the distance would be 48.28 cm.

Answer:

  $514.91

Step-by-step explanation:

You want to save a total of ...

  5 × $1235.78

You want to do this over a 12-month period. So, you want to save 1/12 of this total each month. The amount you're saving each month is ...

  5(1235.78)/12 = 514.908333... ≈ 514.91

You must save $514.91 each month to reach the goal.

Answer: $514.91

Step-by-step explanation:

($1,235.78)(5 months)=$6,178.90

6,178.90/12 months=$514.91

(just for clarity: the other person is right, just wanted to show a simpler way to achieve the answer. gl :)

Answer:

-12°C

Step-by-step explanation:

6AM = 2°C

8AM= -2°C

10AM= -6°C

12AM= -8°C

2PM= -12°C

the temperature in degrees Celsius at 2:00 pm would be -14°C.

To find the temperature in degrees Celsius at 2:00 pm, we need to determine the number of hours that have passed from 6:00 am to 2:00 pm, and then calculate the temperature decrease accordingly.

From 6:00 am to 2:00 pm, a total of 8 hours have passed (6 hours from 6:00 am to 12:00 pm, and 2 hours from 12:00 pm to 2:00 pm).

Given that the temperature drops 2 degrees Celsius each hour, we can multiply the number of hours (8) by the rate of temperature decrease (2 degrees/hour):

Temperature decrease = 8 hours × 2 degrees/hour = 16 degrees

Starting with a temperature of 2°C at 6:00 am, if the temperature drops 16 degrees Celsius over 8 hours, we can subtract 16 from the initial temperature:

Temperature at 2:00 pm = 2°C - 16°C = -14°C

Therefore, the temperature in degrees Celsius at 2:00 pm would be -14°C.

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The vertical line test helps us see that we have a function. Note how it is not possible to draw a single straight line through more than one point on the curve. Any x input leads to exactly one y output. This graph passes the vertical line test. Therefore it is a function.

The function is not one-to-one because the graph fails the horizontal line test. Here it is possible to draw a single straight horizontal line through more than one point on the curve. The horizontal line through y = 2 is one example of many where the graph fails the horizontal line test, meaning the function is not one-to-one.

The term "one-to-one" means that each y value only pairs up with one x value. Here we have something like y = 2 pair up with multiple x values at the same time. This concept is useful when it comes to determining inverse functions.

Answer:

a-2b= -1.6x-2.0

Step-by-step explanation:

[tex]a=1.4-2x\\b=-0.2x+1.7\\a-2b= (1.4-2x)-2(-0.2x+1.7)\\a-2b= 1.4-2x+0.4x-3.4\\a-2b=-1.6x-2.0\\[/tex]

{By, substituting the values of a and b in a-2b , we can find the value of a-2b}

Answer:

x ≈ 4.125 ft

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

[tex]\frac{11}{x}[/tex] = [tex]\frac{8}{3}[/tex] ( cross- multiply )

8x = 33 ( divide both sides by 8 )

x = 4.125 ft

Answer:

Step-by-step explanation:

we use cosine formula

2×15×10×cos(180-66)=15²+10²-AC²

-300 cos 66=225+100-AC²

AC²=325+300 cos 66

[tex]AC=\sqrt{325+300 cos 66} \approx 21.14 ~m/s[/tex]

The distance from A to C is 21.14. The correct option is A.

Trigonometry is the branch of mathematics which set up a relationship between the sides and angles of right-angle triangles.

Velocity is defined as the ratio of the distance moved by the object at a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.

Given that the velocity of a train relative to the ground is represented by the distance from A to B in the diagram. The velocity of a ball thrown inside the train at an angle of 66° relative to the train is represented by the distance from B to C.

The distance A to C will be calculated as,

2×15×10×cos(180-66)=15²+10²-AC²

-300 cos 66=225+100-AC²

AC=√(325+300 cos 66)

AC = 21.17 m/s

Therefore, the distance from A to C is 21.14. The correct option is A.

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